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Answer:

(4,-2)

Step-by-step explanation:

Answer:

Step-by-step explanation:

1 quart =  2 pints  =  4 cups

1 pint = 2 cups

1/2 pint =  1  cup    .....so.....

First question

5 quarts  =  10 pints

10 * (3/4)  =  7.5 pint   contianers   will fill it  3/4  full  

7.5   pints   =    7  pints   +  1 cup

The number of times the diameter of Uranus is larger than the diameter of Mars is 7.5 times

From the question, we have the following parameters that can be used in our computation:

The diameters of Uranus and Mars

These diameters are given as

Diameter of Uranus: 5.11×10^4 kilometers

Diameter of Mars: 6.79×10^3 kilometers

Express the diameters properly

So, we have the following representation

Diameter of Uranus: 5.11 × 10⁴ kilometers

Diameter of Mars: 6.79 × 10³ kilometers

This means that

Number of times larger = Diameter of Uranus/Diameter of Mars

Substitute the known values in the above equation, so, we have the following representation

Number of times larger = 5.11 × 10⁴ kilometers/6.79 × 10³ kilometers

Evaluate the quotient

So, we have the following representation

Number of times larger = 7.5

Hence, the number of times is 7.5

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Answer:

25%

Step-by-step explanation:

55 + 12 + 88 + 45 + 9 + 91=300/12=25=25%

Answer:

y = 2x - 9

Step-by-step explanation:

y2 - y1 / x2 - x1

9 - (-1) / 9 - 4

10 / 5

= 2

y = 2x + b

-1 = 2(4) + b

-1 = 8 + b

-9 = b

Answer:

x = 38

Step-by-step explanation:

180 - 68 = 112

122 + 20 + x = 180

142 + x = 180

180 - 142 = x

x = 38

Have a nice day!

The triangle in the figure can be proved by ASA, SAS, and AAS

Triangles are said to be congruent when the sides and angles equal in accordance to to the triangle congruency rules

Some of the rules include

Side -  Side - Side = SSS

Side - Angle - Side = SAS

Angle - Side - Angle = ASA

Angle - Angle - Side = AAS

Hypotenuse and one leg = HL

The problem requires the prove by ASA, SAS, and AAS to ensure that the the triangles are congruent.

Alternate angles in the figure are also equal

According to the ASA rule, two triangles are said to be congruent if any two angles and the side located between the angles of one triangle are equal to the corresponding two angles and side located between the angles of the second triangle.

The Angle-Angle-Side (AAS) Congruence Theorem states that two angles and a non-included side in one triangle must be congruent with two angles and the equivalent non-included side in another triangle for the triangles to be congruent.

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Elimination is a method of solving a system of equations using addition or subtraction to eliminate one of the variables.

Here we will use the elimination method to solve a system of three equations with three variables.

Let's say we have three equations with three variables x, y and z.

Equation 1:  ax + by + cz = d

Equation 2:  ex + fy + gz = h

Equation 3:  ix + jy + kz = l

We will start by multiplying the first equation by a number that will make the coefficients of y in the two equations the same.

Let's say we choose to multiply the first equation by -f, so that we get:

-fax -fby -fcz = -fd

Now we add the two equations to eliminate y:

ax + by + cz + (-fax -fby -fcz) = d -fd

ax -fax + by -fby + cz -fcz = d -fd

(a -f)x + (b -f)y + (c -f)z = d -fd

Now we can multiply the second equation by a number that will make the coefficients of z in the two equations the same. Let's say we choose to multiply the second equation by -k, so that we get:

-kex -kfy -kgz = -kh

Now we add the two equations to eliminate z:

(a -f)x + (b -f)y + (c -f)z + (-kex -kfy -kgz) = d -fd -kh

(a -f)x + (b -f)y + (c -f)z -kex -kfy -kgz = d -fd -kh

(a -f -k)x + (b -f -k)y = d -fd -kh

We can now solve this equation for x:

x = (d -fd -kh - (b -f -k)y) / (a -f -k)

Now we can substitute this expression for x in any of the original equations and solve for y:

Let's choose to substitute in the first equation:

ax + by + cz = d

(d -fd -kh - (b -f -k)y) / (a -f -k) + by + cz = d

y = (d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k) -cz) / (b -f -k)

Now we can substitute this expression for y in any of the original equations and solve for z:

Let's choose to substitute in the second equation:

ex + fy + gz = h

e(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k)) + f(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k)) + gz = h

gz = h -e(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k)) -f(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k))

z = (h -e(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k)) -f(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k))) / g

Now we have

x = (d -fd -kh - (b -f -k)y) / (a -f -k)

y = (d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k) -cz) / (b -f -k)

z = (h -e(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k)) -f(d -fd -kh - (a -f -k)(d -fd -kh) / (b -f -k))) / g

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Answer:

c) 2.2 feet

Step-by-step explanation:

1) Iris' puppy is 2 1/5 feet long. Which

decimal represents Iris' puppy's length?

c) 2.2 feet

Answer: 5 ft

Step-by-step explanation:

Given

The path of the swimmer is given by

[tex]h=-0.1d^2+0.1d+3[/tex]

The swimmer can go horizontally depends upon the depth

So, find the maximum depth by taking derivative w.r.t height

[tex]h'=-0.2d+0.1[/tex]

Put derivative equal to 0

[tex]\Rightarrow -0.2d+1=0\\\\\Rightarrow d=\dfrac{1}{0.2}\\\\\Rightarrow d=5\ ft[/tex]

thus, the swimmer can go up to a distance of 5 ft.

Answer:

uhhugvtrctreex

Step-by-step explanation:

Step-by-step explanation:

credits are also on there

Answer:

Length * Height * Width, or V = L * H * W. Ex: V = 5 in.

Answer:

28

Step-by-step explanation:

We are given the area of a base and the width of the prism.

Volume = area of base * width

Volume = 8/3 * 21/2 = 28

Answer:

Tori spends $342.00 on coffee over 9 months

Step-by-step explanation:

38 x 9 = 342

= $342.00

Answer:

times it by

Step-by-step explanation:

3×3=9, 9×3=27, 27×3=81, 81×3=243

sorry if this isn't the answer your looking for.

On solving the provided question we can say that *629 = n - 99 is an equation. The textbook contains 728 pages*.

An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.

In other words, the geometry book is 99 pages LONGER than the algebra book, which is 99 pages SHORTER. The solution can be obtained using this equation. I'm sorry, but 530 is not the solution.

629 = n - 99 is an equation. The textbook contains 728 pages*.

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Answer: 1/9 of the cake

Step-by-step explanation:

Charlie ate 2/3 of the cake which means that what is left to give the friends is:

= 1 - 2/3

= 1/3 of the cake

This was divided equally amongst three friends so the expression would be:

= 1/3 ÷ 3

This can also be written as:

= 1/3 * 1/3

= 1/9

Each friend got 1/9 of the cake.

Answer:

1/9 of the cake

Step-by-step explanation:

1  -  2/3    =   1/3   left

(1/3)  / 3   =    1/9   =  what each friend got

In  one fell  swoop  we  have  ( 1 - 2/3)  / 3     =   1/9

Answer:

The percentage rate is 4.5%

Step-by-step explanation:

The simple interest earned in this situation is $1270 - $1000, or $270.

the simple interest formula is i =prt.

Here, i = $270 = ($1000)(r)(6 yr).

                $270

Then r = ------------------- = 0.045

                $1000(6 yr)

The percentage rate is 4.5%

Answer:

7

Step-by-step explanation:

[36 + ( 3 × 2 ) ] ÷ 6 = 7

Answer:

7

Step-by-step explanation:

[ 36 + ( 3 × 2 ) ] ÷ 6

= [ 36 + 6 ] ÷ 6

= [ 42 ] ÷ 6

= 7

Answer:

ED = AB = 25√3

Step-by-step explanation:

Let ED = AB = X

DC = 100 - BC

Tan 60 = [tex]\frac{\sqrt{3} }{1} = \frac{ED}{DC}[/tex] = [tex]\frac{X}{100-BC}[/tex]

[tex]\sqrt{3} (100-BC) = X[/tex]

Tan 30 = [tex]\frac{1}{\sqrt{3} } = \frac{AB}{BC} = \frac{X}{BC}[/tex]

[tex]\frac{BC}{\sqrt{3} } = X[/tex]

[tex]\sqrt{3} (100-BC) = \frac{BC}{\sqrt{3} } \\3(100-BC) = BC\\300 - 3BC = BC\\300 = BC + 3BC\\300 = 4BC \\75 = BC[/tex]

X = [tex]\frac{BC}{\sqrt{3} } = \frac{75}{\sqrt{3} }\\[/tex]

X = 25√3

The height of the tree to the nearest hundredth of a meter is 10.5 meters.

The length of Jai's shadow = length of tree's shadow - distance of standing of Jai

Length of Jai's shadow = 39.55 - 34.1

Performing subtraction on Right Hand Side of the equation

Length of Jai's shadow = 5.45 meters

Tan theta = height of tree/length of shadow = height of Jai/length of his shadow

height of tree/39.55 = 1.45/5.45

Keep the values in formula

Height of tree = 39.55×1.45/5.45

Performing multiplication

Height of tree = 57.35/5.45

Performing division

Height of tree = 10.5 meters

Thus, the height of tree is 10.5 meters.

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Answer:

28 classes

Step-by-step explanation:

84/3 = 28 classes

Answer:

28 classes didn't learn about the Holocaust

Step-by-step explanation:

If there are 84 classes and two-thirds learned about the Holocaust that means that you have to divide by three.

84 ÷ 3 = 28

Then, you can check your answer by multiplying 28 × 3 = 84

Answer:

Left triangle: 12.5 cm

Right triangle: 21 cm

Trapezoid: 50 cm

Total: 83.5

Step-by-step explanation:

Left triangle: The formula to find the area of a triangle is 1/2bh, in which b=base and h=height. The base of the left triangle is 5 cm and the height is 5 cm. 5*5=25. 25/2=12.5 cm.

Right triangle: Once again, use the area formula for a triangle. The base of the right triangle is 6 cm and the height is 5+2=7. 6*7=42. 42/2=21 cm.

Trapezoid: The formula to find the area of a trapezoid is a+b/2(h) in which a and b are the top and bottom of the trapezoid and h=height. In this case, a=9 cm and b=5+6=11 cm. The height is 5 cm. 9+11=20. 20/2=10. 10*5=50 cm.

Add all of the areas. 12.5+21+50=83.5. So, the total area is 83.5 cm.

Answer:

Quadrant I

Step-by-step explanation:

b/c both are on the right side that means they are positive

Answer:

b and d

Step-by-step explanation:

slope is  -0.632 which is quite literally what d is saying, (on terms of graphs) for every 1 square over it goes -0.63 squares down

Answer:

78

Step-by-step explanation:

13! / 11! · 2!

13 x 12 / 2

13 x 6 = 78

With standard deviation of 2 pounds, the range of weight 99.7% of dogs have will be approximately 24–36 pounds.

The term "standard deviation" (or "σ") refers to a measurement of the data's dispersion from the mean. A low standard deviation indicates that the data are grouped around the mean, whereas a high standard deviation shows that the data are more dispersed.

We have given,

Mean weight of Eskimo dogs is μ = 30 pound

Standard deviation of Eskimo dogs is σ = 2 pound

The range of weights would 99.7% of the dogs have,

R =  μ ± 3σ

R = 30 ± 3*2

R = 30 ± 6

R = (30 - 6) , (30 + 6 )

R = 24, 36

With standard deviation of 2 pounds, the range of weight 99.7% of dogs have will be approximately 24–36 pounds.

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Answer:

ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

ahhhhhhhhhhhhhhhhhhhhhhhhh

answ

Answer:

Use this link

Step-by-step explanation:

https://www.calculatorsoup.com/calculators/math/mixednumbers.php copy and paste