Please help! Hurry!!

Area of the prism

= (4x3)/2 x 5

= 30 cm^3

Before we start, we gotta acknowledge that one pound is 16 oz.

Okay, so to solve this we need to make a ratio. We know there are 567 calories for every 9 oz. That'll look like 567/9. And to compare this to pounds we have to convert those three pounds to ounces by multiplying: 3*16 = 48. So now we can grab that ratio and use cross multiplication to find the answer:

567/9 = x/48

9x = 567*48

9x = 27216

x = 3024

So there are 3024 calories in three pounds of the ice cream.

There are 3024 calories in a certain type of ice cream.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

We know one pound is equal to 16 ounces.

So, 9 ounces is equal to 9/16 pounds.

Given, There are 567 calories in nine ounces of certain ice cream.

So, There are 567 calories in (9/16) pounds of certain ice cream.

Or, (567)/(9/16).

= 567×(16/9).

= 1008 calories in one pound.

Therefore, There is 1008×3 = 3024 calories in 3 pounds of ice cream.

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Answer:

In part B the answer is 71.

Step-by-step explanation:

In the 3 lines the 2 uppermost and downer most lines look like they make up a 90 degree angle.. since the first one is 19 all we have to do is 90 - 19 which equals 71. Sorry I do not know the answer to part A :(

Check the picture below.

since the cliff is 48 feet tall, thus that its initial height.

[tex]~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&8\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&48\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+8t+48[/tex]

well, as you can see in the picture, its maximum is at its vertex, so

[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+8}x\stackrel{\stackrel{c}{\downarrow }}{+48} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 8}{2(-16)}~~~~ ,~~~~ 48-\cfrac{ (8)^2}{4(-16)}\right)\implies \left(\cfrac{1}{4}~~,~~48-\cfrac{64}{-64} \right)[/tex]

[tex]\left( \frac{1}{4}~~,~~48+1 \right)\implies \stackrel{\textit{the ball is at highest}}{\left(\frac{1}{4}~~,~~\stackrel{\downarrow }{49} \right)}[/tex]

well, it hits the ground when y = 0.

[tex]\stackrel{h(t)}{0}=-16t^2+8t+48\implies 0=8(-2t^2+t+6)\implies 2t^2-t-6=0 \\\\\\ (2t+3)(t-2)=0\implies t= \begin{cases} -\frac{3}{2}\\\\ 2~~\textit{\large \checkmark} \end{cases}[/tex]

notice, we didn't use the negative value, since "t" must be greater than 0.

Answer:

The least amount is 75 dollars.

The biggest amount is 125 dollars

Step-by-step explanation:

The absolute value function will help us determine a  range of possible values since we do not know the exact amount of money.

Defining the function.

Let x be the exact amount of money in my pocket, we can define the equation

And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation.  So we can write:

We have a difference inside an absolute value, since we know the difference must be either +25 or -25.

Solving for x

Using the definition of absolute value we have

So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is

Solving for x give us

If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition

Solving for x give us

So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.

Answer:

He can make eight 3-pancake servings.

Step-by-step explanation:

6 eggs make 12 pancakes.

12 eggs make 24 pancakes.

24 divided by 3 is 8.

[tex]\dfrac{(-9-11)/(-4)}{-7^2+(11 \times 2^2)}\\\\=\dfrac{(-20)/(-4)}{-49+44}\\\\=\dfrac{5}{-5}\\\\=-1[/tex]

[tex]~~~~~~~\cos x = \dfrac{ \text{Base}}{\text{Hypotenuse}}\\ \\\\\implies \cos x= \dfrac{9}{18}\\\\\\\implies \cos x = \dfrac 12\\\\\\\implies x= \cos^{-1} \left( \dfrac 12\right)\\ \\ \\\implies x = 60^{\circ}[/tex]

Answer:

1/10 is smallest. With fractions, as the bottom number(denominator) gets bigger, the fraction is actually getting smaller.

Answer:

10

Step-by-step explanation:

To find the area you multiply the length times the width. 5 x 2 = 10.

Answer:

b^7

Step-by-step explanation:

when you multiply numbers that have powers, you add them instead of multiplying.

Answer:

30 cm

Step-by-step explanation:

just times it by three because theres three sides

Answer:

second one

s/(2πh) = r

Step-by-step explanation:

You want to put the unknown value you are solving on 1 side and rest on the other side. In this case, you have to have r alone on one side.

s=2πrh

Since they are all multiplied with r, you divide them all on both sides to send them to other side.

s/(2πh) = 2πrh/ (2πh)

cancel out right side and it leaves r alone.

s/(2πh) = r

Answer:

D

Step-by-step explanation:

D because they are on the same line and that would make them infinite

Answer:

[tex] r = 8.58~cm [/tex]

Step-by-step explanation:

[tex] S = \dfrac{n}{360^\circ}2\pi r [/tex]

[tex] 38.95~cm = \dfrac{260^\circ}{360^\circ}2\pi r [/tex]

[tex] 38.95~cm = 4.5378r [/tex]

[tex] r = 8.58~cm [/tex]

Answer:

$128.10

Step-by-step explanation: (8 * 16.95) - 7.50(135.6) - 7.50128.1

Hopefully this helps you if you don't mind clicking brainliest :)

We are given that:

Circumference = 19.4 cm

Formula:

2πr = Circumference

Rewrite the equation:

The "r" variable represents the radius of the circle. Thus, we need to isolate it on one side to determine the radius. This can be done with the four mathematical operations (+  -  ×  ÷). Since the "÷" is included, we can divide both sides by 2π to isolate the "r" variable.

Divide both sides by 2π:

Substitute the radius as 22/7:

Answer:

wait in comments.................

Answer:

From wheelie bags and hard shell cases, to duffel bags, backpacks, hybrid packs, and day backs, there is a huge amount of choices when it comes to travel luggage Step-by-step explanation:

Answer:

10

Step-by-step explanation:

→ Find the difference in x coordinates

8 - 2= 6

→ Find the difference in y coordinates

-1 - 7 = -8

→ Use Pythagoras

√6² + (-8)² = 10

Answer: [tex]x < -\frac{24}{5}[/tex]

Step-by-step explanation:

You have:

[tex]-\frac{5}{6} x-3 > 1[/tex]

Add 3 to both sides to get:

[tex]-\frac{5}{6} x > 4[/tex]

Multiply both sides by 6 to get:

[tex]-{5} x > 24[/tex]

Divide both sides by -5. When you divide an inequality by a negative number, you must switch the signs. Therefore:

[tex]x < -\frac{24}{5}[/tex]

Answer:

The equation is saying multiply or add negative 5/6 to x, then subtract by positive 3 which makes the number go upwards, but not making it positive, and lastly, the equation is saying the result will be greater than 1.

One of the values for x is 5, because...

[tex]-\frac{5}{6} * 5 = -4\frac{1}{6} - 3 = 7\frac{1}{6} > 1[/tex]

With that information, the statement is now complete and true. If you make 5 or anything more than 5 the value for x, the statement will still be true.

Note that I just used 5 as one of the solutions. There are many more than that.

We are told to the write the given expression in standard form ;

[tex]{:\implies \quad \sf \dfrac{6.6\times 10^{-2}}{3.3\times 10^{-4}}}[/tex]

Rewrite as ;

[tex]{:\implies \quad \sf \dfrac{66\times 10\times 10^{-2}}{33\times 10\times 10^{-4}}}[/tex]

[tex]{:\implies \quad \sf \dfrac{2\times 10^{-2}}{10^{-4}}}[/tex]

[tex]{:\implies \quad \sf 2\times \dfrac{10^{-2}}{10^{-4}}}[/tex]

[tex]{:\implies \quad \sf 2\times 10^{-2-(4)}\quad \qquad \bigg\{\because \dfrac{a^m}{a^n}=a^{m-n}\bigg\}}[/tex]

[tex]{:\implies \quad \sf 2\times 10^{-2+4}}[/tex]

[tex]{:\implies \quad \boxed{\bf{2\times 10^{2}}}}[/tex]

This is the required answer

Answer:

1848 grams of cheese.

Step-by-step explanation:

1 oz = 28 g.

28 x 22 = 616 g

616 g x 3 = 1848 g

Donna should buy 1848 grams of cheese.

Answer:

Step-by-step explanation:

Remark

The purple lines cross but once. A solution to a set of functions counts how many times the functions cross. Since these two lines cross but once, there is only 1 solution.

If the lines are parallel, they never cross. That means there are no solutions.

If you are given 2 equations and one is the same line as the second one, then there are an infinite number of solutions.

Hi!

Solutions to systems of equations are only where the lines intersect at a point.

That means that if the lines cross over at any point, they have a solution. Lines that don't have a solution -- parallel lines -- do not cross over.

In this graph, we can see that it crosses over at only one point.

That means that this system of equations has exactly one solution.

For a similar problem, see:

https://brainly.com/question/13956905

Answer:

Non of the Above

Step-by-step explanation:

You are an Alpha male its atleast 2500ft

An expression is defined as a set of numbers, variables, and mathematical operations. The expression that can represent u/v is -x³+x²-1.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The expression which can represent the u/v can be found in the following manner,

[tex]\dfrac {u}{v} = \dfrac{x^5-x^4+x^2}{-x^2}\\\\\dfrac {u}{v} = \dfrac{x^2(x^3-x^2+1)}{-x^2}\\\\\dfrac {u}{v} = \dfrac{(x^3-x^2+1)}{-1}\\\\\dfrac {u}{v} = -x^3+x^2-1[/tex]

Thus, the expression that can represent u/v is -x³+x²-1.

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Answer:

C

Step-by-step explanation:

From the line of the best fit y = 5.2x -0.4 for the considered data, the residual for x = 5 is given by: Option A: -1.6

Suppose the given input output pair be (x,y) (actual data point)

Then suppose the prediction be y' from the line of best fit for that input x.

Then the residual value will be calculated for that point as:

Residual value = Actual value - Predicted value

Residual = y - y'

Here, we're given the data as:

         x                         y

         1                          8

         2                        13

         3                        18

         4                        23

         5                        24

The line of best fit for this data is [tex]y= 5.2x -0.4[/tex]

For x = 5, the real corresponding y value is 24, and the predicted value is:

[tex]5.2(5) -0.4 = 25.6[/tex]

Thus, the residual for x=5 is: y - y' = 24 - 25.6 = -1.6

Thus, from the line of the best fit y = 5.2x -0.4 for the considered data, the residual for x = 5 is given by: Option A: -1.6

Learn more about residual here:

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Answer:

The answer is A: -1.6

Step-by-step explanation:

Doing the assignment on edge rn and got the question right

[tex]\textit{ellipse, horizontal major axis} \\\\ \cfrac{(x- h)^2}{ a^2}+\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2- b ^2} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{(x+4)^2}{400}~~ + ~~\cfrac{(y+3)^2}{144}~~ = ~~1\implies \cfrac{[x-(-4)]^2}{20^2}~~ + ~~\cfrac{[y-(-3)]^2}{12^2}~~ = ~~1 \\\\\\ \begin{cases} h=-4\\ k=-3\\ a=20\\ b=12 \end{cases}\qquad \qquad c=\sqrt{20^2-12^2}\implies c=\sqrt{256}\implies \boxed{c=16} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{center}{(-4,-3)}\qquad vertices \begin{cases} (\stackrel{-4-20}{-24}~~,~~-3)\\\\ (\stackrel{-4+20}{16}~~,~~-3) \end{cases}\qquad foci \begin{cases} (\stackrel{-4-16}{-20}~~,~~-3)\\\\ (\stackrel{-4+16}{12}~~,~~-3) \end{cases}[/tex]

The lines PC and PB are the secant and the tangent lines of the circle, while the proportion involving PA, PB, and PC is PA * PC = PB²

The triangles are given as:

Δ PAB and Δ PBC

Both triangles have a common point at P.

This means that:

∠P ≅ ∠P --- reflexive property of congruent angles

Also, the angles at C and B are congruent:

This is represented as:

∠B ≅ ∠C

Both triangles have a common side length PB.

Hence, the triangles are similar by ASA similarity theorem

The similarity theorem in (a) is the ASA similarity theorem.

This means that:

PA : PB = PB : PC

Express as fraction

[tex]\frac{PA}{PB} = \frac{PB}{PC}[/tex]

Cross multiply the expressions

PA * PC = PB * PB

Evaluate the product

PA * PC = PB²

Hence, the proportion involving PA, PB, and PC is PA * PC = PB²

Read more about secant and tangent lines at:

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