PLEASE HELP, IM CONFUSED AND THIS IS A LATE ASSIGNMENT

There are two forces acting on the rock: the force of gravity pulling it downward and the force of the boulder supporting it from underneath.

The force of gravity is the gravitational attraction between the rock and the Earth. It pulls the rock downward with a force equal to its weight, which is given by the equation Fg = mg, where Fg is the force of gravity, m is the mass of the rock, and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The concept of forces explains why the rock stays on top of the boulder because the forces are balanced. The force of gravity pulling the rock downward is equal and opposite to the force of the boulder supporting it from underneath. As a result, the rock remains in equilibrium, or a state of balance, on top of the boulder. If either force were to change, the equilibrium would be disrupted, and the rock would either fall to the ground or be pushed off the boulder.

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The two gases that could be components of water are indeed hydrogen and oxygen.

Evidence to support this claim:

1. The chemical formula for water is H2O, which means that it is composed of two hydrogen atoms and one oxygen atom.

2. The table of elements shows that hydrogen (H) and oxygen (O) are both elements that exist in nature.

3. The atomic mass of hydrogen (1.008) and oxygen (15.999) matches the molecular mass of water (18.015).

4. Water is produced when hydrogen gas (H2) is burned in the presence of oxygen gas (O2), according to the following equation: 2H2 + O2 → 2H2O.

Overall, the evidence supports the conclusion that hydrogen and oxygen are the two gases that could be components of water.

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(a) The frequency ratio between the two frequencies fi = 256 Hz and f2 = 320 Hz is:

[tex]\frac{f_2}{f_i} = \frac{320}{256} = \frac{5}{4} = 1.25[/tex]

So the frequency ratio is 1.25.

(b) Adding the interval of a fifth to f2 = 320 Hz gives:

fs = f2 * (3/2) = 320 * (3/2) = 480 Hz

The frequency ratio fs/fi is:

[tex]\frac{f_s}{f_i} = \frac{480}{256} = \frac{15}{8} = 1.875[/tex]

So the frequency ratio is 1.875.

(c) To find the frequency of f3, we need to add the interval of a fourth to f2:

f3 = f2 * (4/3) = 320 * (4/3) = 426.67 Hz

Therefore, the frequency of f3 is 426.67 Hz.

Answer: Given data

The resistance of the first resistor is R1 = 4 ohm

The resistance of the second resistor is R2 = 5 ohm

The potential difference of the battery is V = 9 V

The resistors are connected in series. The expression for the equivalent resistance is given as:

The expression for the current in the 4-ohm resistor is given as:

Thus, the magnitude of the current flows through the 4-ohm resistor is 1 A.

Explanation:

Answer:

Explanation:

Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:

v_f^2 = v_i^2 + 2ad

where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)

and

d = v_i t + (1/2)at^2

where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.

First, we need to resolve the initial velocity into its vertical and horizontal components:

v_i_x = v_i cos(30°) = 121.1 m/s

v_i_y = v_i sin(30°) = 70.0 m/s

Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:

v_f = v_i_y + at

0 m/s = 70.0 m/s + (-9.8 m/s^2)t

t = 7.14 s

Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:

d = v_i_y t + (1/2)at^2

d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2

d = 247.5 m

Therefore, the peak height of the football is 247.5 meters.

Answer:

In this problem, the harp string is fixed at both ends, so it is a standing wave with nodes at both ends and an antinode in the center. The frequency of the wave is given as 440 Hz, and the length of the string is 30.5 cm.

(a) To find the wavelength of the wave, we can use the formula:

λ = 2L/n

where λ is the wavelength, L is the length of the string, and n is the number of nodes. In this case, n = 2 (since there are nodes at both ends) and L = 30.5 cm, so we have:

λ = 2(30.5 cm)/2 = 30.5 cm

Therefore, the wavelength of the wave is 30.5 cm.

(b) To find the speed of the wave on the string, we can use the formula:

v = fλ

where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength. In this case, f = 440 Hz and λ = 30.5 cm, so we have:

v = (440 Hz)(30.5 cm) = 13420 cm/s

Therefore, the speed of the wave on the string is 13420 cm/s

Explanation:

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An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.

The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:

1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.

2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.

3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.

4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.

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The speed of the wave would be0.48 m/s.

The speed of a wave is given by the formula:

v = λ/T

where v is the wave speed, λ (lambda) is the wavelength, and T is the period.

To solve this problem, we need to know the wavelength of the wave. We can find the wavelength using the formula:

λ = 2L

where L is the length of the rope. Substituting L = 6 m, we get:

λ = 2 × 6 m = 12 m

Now we can use the formula for wave speed:

v = λ/T

Substituting λ = 12 m and T = 25 s, we get:

v = 12 m/25 s = 0.48 m/s

Therefore, the speed of the wave is 0.48 m/s.

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Answer: D. It needs a medium to travel.

Explanation:

One way to categorize waves is on the basis of the direction of movement of the individual particles of the medium relative to the direction that the waves travel. Categorizing waves on this basis leads to three notable categories: transverse waves, longitudinal waves, and surface waves.

To find the angular momentum of an electron in the hydrogen atom, we can use the formula:

L = n * h / (2 * π)

where L is the angular momentum, n is the principal quantum number, h is Planck's constant, and π is a mathematical constant approximately equal to 3.14159.

First, we need to determine the value of n for the electron in the 3.4 eV energy state. We can use the formula for the energy of an electron in a hydrogen atom:

E = -13.6 eV / n^2

where E is the energy of the electron and -13.6 eV is the energy of the electron in the ground state of the hydrogen atom.

Solving for n, we get:

n^2 = (-13.6 eV) / E

n^2 = (-13.6 eV) / (3.4 eV)

n^2 = 4

n = 2

Therefore, the electron is in the second energy level of the hydrogen atom.

Now, we can calculate the angular momentum using the formula above. Substituting the values, we get:

L = 2 * h / (2 * π)

L = h / π

We can approximate π as 3.14159 and use the value of Planck's constant as h = 6.626 x 10^-34 J s. Substituting these values, we get:

L = (6.626 x 10^-34 J s) / (3.14159)

L = 2.104 x 10^-34 J s

Therefore, the angular momentum of the electron in the second energy level of the hydrogen atom is 2.104 x 10^-34 J s.

The translational speed of the barrel at the bottom of the hill is 28.1 m/s.

Translational speed is the speed of an object in a straight line. It is different from rotational speed, which is the speed of an object’s rotation. Translational speed is a measure of how quickly an object is moving in a specific direction. It is calculated by dividing the distance traveled by the time it took to travel that distance.

The barrel's initial potential energy can be calculated using the equation U = mgh, with m being the mass of the barrel (21.0 kg),
g being the acceleration due to gravity (9.80 m/s2),
and h being the height of the barrel above the bottom of the hill (31.0 m). Therefore, the barrel's initial potential energy is U = 21.0 kg × 9.80 m/s2 × 31.0 m = 6259.8 J.
At the bottom of the hill, the barrel's potential energy is zero, since it is at the lowest point.
Therefore, the barrel's total mechanical energy is equal to its kinetic energy.
Since the kinetic energy of an object is given by K = ½mv2,
where m is the mass of the barrel and v is its velocity,
we can calculate the barrel's velocity at the bottom of the hill by rearranging the equation to v = √(2K/m).
Substituting in the values for the barrel's mass (21.0 kg) and its total mechanical energy (6259.8 J) gives us v = √(2 × 6259.8 J / 21.0 kg) = 28.1 m/s.
Therefore, the translational speed of the barrel at the bottom of the hill is 28.1 m/s.

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Answer:

Explanation:

What is the gravitational force between them?

To calculate the gravitational force between two objects, we can use the formula:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

Plugging in the given values, we get:

F = (6.6743 x 10^-11 N * m^2 / kg^2) * (2000000 kg) * (3000000 kg) / (50 m)^2

F = 0.8046 N

Therefore, the gravitational force between the two asteroids is approximately 0.8046 N.

Answer:

One is that atmospheric pressure is dramatically reduced at high altitudes, so a helium balloon expands as it rises and eventually explodes. If you inflate a balloon beyond its limits at room temperature, it will break into small pieces up to about ten centimetres long

Explanation:

Answer:

-2 m/s and the average acceleration is 2 m/s².

Explanation:

To find the average velocity of particle P over the time interval 1<=t<=3 sec, we need to use the following formula:

average velocity = (final displacement - initial displacement) / (final time - initial time)

In this case, the initial time is 1 sec and the final time is 3 sec. Therefore, the initial displacement is:

x(1) = 1² - 6(1) = -5

And, the final displacement is:

x(3) = 3² - 6(3) = -9

Now, we can substitute the values in the formula:

average velocity = (-9 - (-5)) / (3 - 1) = -2 m/s

To find the average acceleration of particle P over the time interval, we need to use the following formula:

average acceleration = (final velocity - initial velocity) / (final time - initial time)

We know that the initial time is 1 sec, the final time is 3 sec, and the initial velocity is the velocity at time t=1 sec. Therefore, the initial velocity is:

v(1) = 2t - 6 = 2(1) - 6 = -4 m/s

We also know that the final velocity is the velocity at time t=3 sec. Therefore, the final velocity is:

v(3) = 2t - 6 = 2(3) - 6 = 0 m/s

Now, we can substitute the values in the formula:

average acceleration = (0 - (-4)) / (3 - 1) = 2 m/s²

Therefore, the average velocity of particle P over the time interval 1<=t<=3 sec is -2 m/s and the average acceleration is 2 m/s².

Explanation:

Total distance travelled is   60 + 20 = 80 km

He went 60....then turned around and headed back 20 km

  so his displacement ( distance from starting point) is 60 - 20 = 40 km

Answer: b. force per unit area.

Explanation:

Answer:

Explanation:

The electric flux through a surface is given by the equation:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

We are given Φ = 4.44 N⋅m2/C, A = 6.66×10−4 m2, and θ = 60.0∘. Substituting these values into the equation above and solving for E, we get:

E = Φ / (Acos(θ))

= 4.44 N⋅m2/C / (6.66×10−4 m2cos(60.0∘))

= 1.62×10^4 N/C

Therefore, the magnitude of the electric field is 1.62×10^4 N/C.

The magnitude of the electric field is 13,320 N/C.

The electric flux through a surface is defined as the product of the electric field and the area of the surface projected perpendicular to the electric field. Mathematically, we can write:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

Here in the Question,

We are given the electric flux Φ = 4.44 N·m^2/C, the area A = 6.66×10^-4 m^2, and the angle θ = 60.0°. We can solve for the magnitude of the electric field E by rearranging the equation as follows:

E = Φ / (A*cos(θ))

Substituting the given values, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*cos(60.0°))

Simplifying the denominator, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*0.5)

E = 13,320 N/C

Therefore, 13,320 N/C is the magnitude of the electric field.

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Answer: Each macromolecule is broken down by a specific enzyme. For instance, carbohydrates are broken down by amylase, sucrase, lactase, or maltase. Proteins are broken down by the enzymes pepsin and peptidase, and by hydrochloric acid. Lipids are broken down by lipases.

Explanation:

Hope this will help

Answer:

Explanation:

We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:

s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m

So the length of the driveway is 3.8 meters.

Answer:

The student used 24000 Joules of energy.

Explanation:

We can use the Energy Power equation to solve this example.

[tex]\sf E=Pt[/tex]

Where

[tex]\sf E[/tex] is the energy in Joules (J)

[tex]\sf P[/tex] is the power in Watts (W)

[tex]\sf t[/tex] is the time in seconds (s)

Numerical Evaluation

In this example we are given

[tex]\sf P=800\\t=30[/tex]

Substituting our given values into the equation yields

[tex]\sf E=800 \cdot 30[/tex]

[tex]\sf E=24000[/tex]

24000 Joules  

[tex]\Large\bold{SOLUTION}[/tex]

To calculate the energy used by the student in this scenario, we can use the formula:

[tex]\sf{Energy\: (in\: Joules) = Power\: (in\: Watts) \times Time\: (in\: seconds)}[/tex]

Given that the student uses an 800 W microwave for 30 seconds, we can plug in these values to the formula:

[tex]\sf Energy = 800\: W \times 30\: s = 24,000\: J[/tex]

Therefore, the student uses 24,000 Joules of energy in this scenario.

[tex]\rule{200pt}{5pt}[/tex]

Answer:

Abundance on Earth is not necessary for calculating the age of something using radioactive dating methods.

In contrast, the amount of radioactive isotope within a sample and its half-life are crucial for determining the age of the sample using radioactive dating methods. The amount of sample, such as 100g, is also important for determining the quantity of radioactive isotopes present, which is used in the calculation of the age of the sample.

The truck's acceleration is 3.0m/s² and the momentum of the truck is  144000 kg m/s.

It is the rate at which the speed and direction of a moving object vary over time.

We can use the following equation to calculate the acceleration of the truck:

a = (v - u) / t

where

a = acceleration

v = final velocity = 18.0 m/s

u = initial velocity = 0 m/s (the truck starts from rest)

t = time taken = 6.00 s

Substituting the values, we get:

a = (18.0 m/s - 0 m/s) / 6.00 s

a = 3.00 m/s²

Therefore, the acceleration of the truck is 3.00 m/s².

We can use the following equation to calculate the momentum of the truck:

p = m * v

where

p = momentum

m = mass of the truck = 8000.0 kg

v = final velocity = 18.0 m/s

Substituting the values, we get:

p = 8000.0 kg * 18.0 m/s

p = 144000 kg m/s

Therefore, the momentum of the truck after it has reached its final velocity is 144000 kg m/s.

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If F₁ has a greater magnitude than F₂, the box will accelerate backward because the net force is in the backward direction (1st option)

To obtain the direction in which the box will move, we shall determine the net force acting on the box. This is illustrated below:

Assumption:

Net force = Magnitude of force 1 (F₁) - Magnitude of force 2 (F₂)

Net force = F₁ - F₂

Net force = 40 - 25

Net force = 15 N backward

From the above illustration, we can see that the net force is 15 N backward.

Thus, we can conclude from the box will accelerate backward (1st option)

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Answer:

We can use the concept of buoyancy to solve this problem.

The weight of the metal block in air is equal to the force of gravity acting on it, which is given as 60 Newtons. When the block is immersed in paraffin wax, it displaces a certain volume of wax equal to its own volume, and experiences an upward force due to buoyancy that partially cancels out the force of gravity acting on it.

The buoyant force acting on the block is given by the formula:

buoyant force = weight of fluid displaced

= density of fluid x volume of fluid displaced x acceleration due to gravity

The weight of the metal block in the paraffin wax is then equal to the difference between the weight of the block in air and the buoyant force acting on it.

Let's calculate the volume of the metal block first:

density of metal block = 900 kg/m³

weight of metal block in air = 60 N

acceleration due to gravity = 9.81 m/s²

weight of metal block = density of metal block x volume of metal block x acceleration due to gravity

volume of metal block = weight of metal block / (density of metal block x acceleration due to gravity)

= 60 N / (900 kg/m³ x 9.81 m/s²)

= 0.006536 m³

Now, let's calculate the weight of the metal block in the paraffin wax:

density of paraffin wax = 800 kg/m³

buoyant force = density of fluid x volume of fluid displaced x acceleration due to gravity

= 800 kg/m³ x 0.006536 m³ x 9.81 m/s²

= 51.02 N

weight of metal block in paraffin wax = weight of metal block in air - buoyant force

= 60 N - 51.02 N

= 8.98 N

Therefore, the weight of the metal block when it is immersed in paraffin wax of density 800 kg/m³ is 8.98 Newtons.

The tension in the rope is 196.2 N. The rope is exerting a force of 196.2 N on the object to keep it stationary.

Assuming that the mass is not accelerating, the tension in the rope must be equal to the weight of the mass. The weight of the mass can be found using the formula:

weight = mass x acceleration due to gravity

where acceleration due to gravity is approximately 9.81 m/s².

Therefore, the weight of the mass is:

weight = 20 kg x 9.81 m/s² = 196.2 N

Since the mass is held stationary, the tension in the rope must be equal to the weight of the mass, which is 196.2 N. So the tension T in the rope is 196.2 N.

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The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules

To find the work done by the gas, we can use the formula:

W = PΔV

where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.

At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.

The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.

Substituting these values into the formula, we get:

W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J

Therefore, the work done by the gaseous system is 21,600 joules (J).

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Answer:

4.6x10^4 joules

Explanation:

Answer:

When exercising in the heat, it's important to take precautions to prevent heat-related illnesses. Two things you should always do when exercising in the heat are:

1.Stay hydrated: Drink plenty of water before, during, and after your workout to avoid dehydration. Sip water frequently, even if you don't feel thirsty.

2.Take breaks and rest in the shade: If you start feeling dizzy, lightheaded, or excessively fatigued, take a break in a cool, shaded area. Resting can help your body cool down and prevent heat exhaustion or heat stroke.

Explanation:

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When the box is at rest, the tension in the rope is equal to the weight of the box. The tension in the rope is 588 N.

In physics, tension refers to the pulling force that is transmitted through a string, cable, rope, etc when it is pulled tight by forces acting at both ends. Tension is a vector quantity, and measured in units of newtons (N) or pounds (lbs).

A. When the box is at rest, the tension in the rope is equal to the weight of the box, which is given by:

Tension = Weight of the box = mg = (60.0 kg)*(9.81 m/s²) = 588 N

Thus, the tension = 588 N.

B. When the box moves up at a steady 4.80 m/s, the tension in the rope is equal to the force required to lift the box against gravity, which is given by:

Tension = Weight of the box + Force to lift the box = mg + ma = (60.0 kg)*(9.81 m/s²) + (60.0 kg)*(4.80 m/s²) = 1,167.6 N

Therefore, the tension in the rope is 1,167.6 N.

C. When the box has velocity along the y-axis = 5.00 m/s and is speeding up at 5.40 m/s², the tension in the rope is given by the equation:

Tension = Weight of the box + Force to accelerate the box = mg + ma = (60.0 kg)*(9.81 m/s²) + (60.0 kg)*(5.40 m/s²) = 1,199.4 N

Therefore, the tension in the rope is 1,199.4 N.

D. When the box has velocity along y-axis = 5.00 m/s and is slowing down at 5.40 m/s², the tension in the rope is given by the equation:

Tension = Weight of the box - Force to decelerate the box = mg - ma = (60.0 kg)(9.81 m/s²) - (60.0 kg)(5.40 m/s²) = 981.6 N

Therefore, the tension in the rope is 981.6 N.

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