Physics College

Please help! Its due date is in 10 minutes!!​

Please Help! Its Due Date Is In 10 Minutes!!

Answers

Answer 1

Answer:

the circle on left shows the needle to the right (north pole). the circle on the right shows the needle to the right again.

Explanation:

the needle always goes to north

Related Questions

find the magnetic filed strength at acenter of a soleneind with 500 turns and acurrent of 5A the permability of free space 4× 10-7n/m​

Answers

Answer:

The magnetic field strength at the center of a solenoid can be found using the formula:

B = u_0 * N * I / L

where B is the magnetic field strength, u_0 is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns in the solenoid, I is the current flowing through the solenoid, and L is the length of the solenoid.

Given:

N = 500 turns

I = 5 A

u_0 = 4π × 10^-7 T·m/A

Since we don't know the length of the solenoid, we can't calculate the magnetic field strength.

What is the wavelength of this graph? *
A. 1
B.2
C.3
D.4​

Answers

The wavelength of the graph is 2 m (option B)

How do i determine the wavelength of the graph?

Wavelength is defined as the distance between two successive crest or trough of a wave.

However, a crest is the point of maximum value of upward displacement while the trough is the minimum or lowest point in the wave displacement.

Now, we shall determine the wavelength of the graph. Details below:

Trough 1 = 1 mTrough 2 = 3Wavelength =?

Wavelength = Trough 2 - trough 1

Wavelength = 3 - 1

Wavelength = 2 m

Thus, the wavelength is 2 m (option B)

Learn more about wavelength:

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Which of the following provides the best evidence that waves can pass each
other and remain unaffected?
A) Light scatters in multiple directions when it strikes a rough, uneven surface.
B) A pebble dropped into a still pond will create evenly spaced ripples that radiate
outward.
C)The speed of sound increases in proportion to the medium through which it travels.
D) Radio broadcasts at many frequencies can be sent and received at the same time.

Answers

The solution is D It is possible to simultaneously send and receive radio broadcasts on a variety of frequencies.

This is so that electromagnetic wavelengths, such as radio waves, can flow through one another without interfering with one another.

Electromagnetic waves: what are they?

A type of wave called an electromagnetic wave is made up of oscillating electric and magnetic fields that move through space.

They are sometimes referred to as electromagnetic radiation or EM waves.

What other instances of electromagnetic energy?

Electromagnetic waves, for instance, include:

the gamma rays

Waves of light

- Radio waves (which are used in communications)

- X-rays

- Infrared and ultraviolet rays (accompanied by Sun rays)

- Waves used in radio and television.

To know more about electromagnetic waves visit:

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PLEASE HELP ME! Which statement is the best interpretation of the ray diagram shown?

A) A convex lens forms a larger, virtual image.
B) A convex lens forms a larger, real image.
C) A convex mirror forms a larger, real image.
D) A convex mirror forms a larger, virtual image.

Answers

the answer is assumed to be A

A car slows down at -5.00m/s^2 until it comes to a stop traveling 15.0m. How much time did it take to stop? (Unit=s)

40 points!!!!1

Answers

Answer: 2.45 s

Explanation;

To solve this problem, we can use one of the equations of motion:

final velocity² = initial velocity² + 2 × acceleration × distance

Since the car comes to a stop, the final velocity will be 0 m/s. We are given the acceleration (-5.00 m/s²) and the distance (15.0 m). We need to find the initial velocity first, and then we can find the time it took to stop.

0 = initial velocity² + 2 × (-5.00 m/s²) × 15.0 m

Solving for the initial velocity:

initial velocity² = 2 × 5.00 m/s² × 15.0 m = 150.0 m²/s²
initial velocity = √150.0 m²/s² ≈ 12.25 m/s

Now we can use another equation of motion to find the time it took to stop:

final velocity = initial velocity + acceleration × time

0 = 12.25 m/s + (-5.00 m/s²) × time

Solving for the time:

time = (12.25 m/s) / (5.00 m/s²) ≈ 2.45 s

So, it took approximately 2.45 seconds for the car to come to a stop.

Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge

Answers

The force between two charges can be calculated using Coulomb's law, which states that the force (F) between two charges (q1 and q2) is proportional to the product of their charges and inversely proportional to the square of the distance (r) between them:

F = k * (q1 * q2) / r^2

where k is Coulomb's constant (9 x 10^9 N m^2 C^-2).

In this problem, we have two equal and opposite charges, so we can assume that q1 = -q2 = q. The distance between them is 40 mm, which is 0.04 m. We are given that the force between them is 0.5 N. Therefore, we can set up an equation:

0.5 N = k * (q * q) / (0.04 m)^2

Simplifying and solving for q:

q^2 = (0.5 N * (0.04 m)^2) / k
q^2 = (0.5 N * (0.04 m)^2) / (9 x 10^9 N m^2 C^-2)
q^2 = 8.88 x 10^-12 C^2
q = sqrt(8.88 x 10^-12 C^2)
q = 2.98 x 10^-6 C

Therefore, the magnitude of each charge is 2.98 x 10^-6 C.
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