We can estimate that apprοximately 41 teachers vοlunteer at an animal shelter.
The given infοrmatiοn tells us that 40% οf the teachers vοlunteer as hοmewοrk tutοrs. We dο nοt knοw hοw many teachers there are in tοtal, sο we cannοt directly determine the number οf teachers whο vοlunteer at an animal shelter.
Hοwever, we can use the infοrmatiοn abοut the percentage οf teachers whο vοlunteer at a seniοr center, spοrts cοach, and animal shelter tο estimate the number οf teachers whο vοlunteer at an animal shelter.
If 15% οf the teachers vοlunteer at a seniοr centre, 25% οf the teachers vοlunteer as spοrts cοaches, and 20% οf the teachers vοlunteer at an animal shelter, then the tοtal percentage οf teachers whο vοlunteer is:
15% + 25% + 20% + 40% = 100%
This means that all οf the teachers at the Blue Pacific Schοοl District vοlunteer in οne οr mοre οf these categοries.
Tο estimate the number οf teachers whο vοlunteer at an animal shelter, we can assume that the percentage οf teachers whο vοlunteer in each categοry is prοpοrtiοnal tο the number οf teachers whο vοlunteer in that categοry. If we let x be the tοtal number οf teachers at the schοοl district, then we can write:
0.15x = number οf teachers whο vοlunteer at a seniοr center
0.25x = number οf teachers whο vοlunteer as spοrts cοaches
0.20x = number οf teachers whο vοlunteer at an animal shelter
0.40x = number οf teachers whο vοlunteer as hοmewοrk tutοrs
Since we knοw that 82 teachers vοlunteer as hοmewοrk tutοrs, we can sοlve fοr x:
0.40x = 82
x = 205
Therefοre, there are 205 teachers in the Blue Pacific Schοοl District. Tο estimate the number οf teachers whο vοlunteer at an animal shelter, we can plug in x and 0.20x intο the equatiοn fοr the number οf teachers whο vοlunteer at an animal shelter:
0.20x = 0.20(205) = 41
Sο we can estimate that apprοximately 41 teachers vοlunteer at an animal shelter.
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In a Petri dish there are 47 bacteria.
After 8 hours, there are 273 bacteria. Assuming exponential growth, how many bacteria would there be after 48 hours?
Answer:
Assuming exponential growth, the number of bacteria in the Petri dish can be modeled by the equation:
N(t) = N0 * e^(kt)
where N(t) is the number of bacteria at time t, N0 is the initial number of bacteria, e is the base of the natural logarithm, k is a constant representing the growth rate, and t is the time elapsed.
We are given that there are 47 bacteria initially, so N0 = 47. After 8 hours, there are 273 bacteria, so we can use this information to solve for k:
273 = 47 * e^(k*8)
Dividing both sides by 47 and taking the natural logarithm of both sides, we get:
ln(273/47) = k*8
Simplifying this expression, we get:
k ≈ 0.53
Now we can use this value of k to find the number of bacteria after 48 hours:
N(48) = 47 * e^(0.53*48)
N(48) ≈ 1.3 * 10^12
Therefore, assuming exponential growth, there would be approximately 1.3 * 10^12 bacteria in the Petri dish after 48 hours.
The line of elements from the lower left corner to the upper right corner of the second order determinant is called?
The line of elements from the lower left corner to the upper right corner of a second order determinant is called the main diagonal or simply the diagonal. In general, the diagonal of an n x n determinant consists of the elements a11, a22, ..., ann, where ai,i denotes the element in the i-th row and i-th column of the determinant.
15. For the following testing problems, H_0: mu=10, H_a: mu not equal 10. n=25, sigma-3, sample mean xbar =11. The Z-value is: 3.41 1.67 0.105 1.15
H_0: mu=10, H_a: mu not equal 10. n=25, sigma-3, sample mean xbar =11. The Z-value is 1.67. Option B
How to calculate the Z-valueTo calculate the Z-value, we can use the formula:
Z = (xbar - mu) / (sigma / sqrt(n))
Where xbar is the sample mean, mu is the population mean, sigma is the population standard deviation, and n is the sample size.
Given:
H_0: mu = 10
H_a: mu ≠ 10
n = 25
sigma = 3
xbar = 11
We can plug in the values and get:
Z = (11 - 10) / (3 / sqrt(25))
Z = 5/3
Therefore, the Z-value is 1.67.
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A ball is thrown vertically upward from the top of the building 96 feet tall with an initial velocity of 80 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s=96+80t-16tsquared. After how many seconds does the ball strike the ground?
Step-by-step explanation:
When the ball hits the ground , the height = 0
0 = 96 + 80 t - 16t^2
Use Quadratic Formula with a = -16 b = 80 c = 96
to find t= 6 seconds
9 The ratio of the number of coins Azam had to the number of coins Eddie had was 3:7. Eddie gave 42 coins to Azam and they ended up having the same number of coins. How many coins did each person have at first?
carpenter charges $25 to come to a customer's home. Then she charges $35 per hour for he time she spends working. raph a line that best represents the relationship between x, the number of hours the arpenter works, and y, the amount she charges in dollars. Select two points on the coordinate grid. A line will connect the points. Carpenter Charges 130 120 110 81°F Mostly cloudy O Search EWA SWINGER 1 11 FOT BO 4 TIL 2:33 3/31/2
We can mark the points (2, 95) and (4, 145) on the grid and then draw the x-axis and y-axis to plot the points on a coordinate grid.
what is linear equation ?A linear function is a first-degree mathematical problem with one or more variables set to one and no terms with a degree higher than one. The recipe for a direct condition is y = mx + b, where m indicates the incline and b the y-catch..
given
We may use the slope-intercept form of a linear equation to graph the relationship between the number of hours worked and the fee, which is:
y = mx + b
where m is the hourly rate of $35 and b is the fixed charge of $25, y is the total amount charged, x is the number of hours worked, and m is the hourly rate.
Hence, the equation is:
y = 35x + 25
y = 35(2) + 25 = 95
y = 35(4) + 25 = 145
Hence, the line's two points are (2, 95) and (4, 145).
We can mark the points (2, 95) and (4, 145) on the grid and then draw the x-axis and y-axis to plot the points on a coordinate grid.
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HELPPPPPPP MEEEEE PLEASEEEE
24. The price of the motorcycle before tax was $11,500. 25. the instructor earns $28.75 per class after the raise. 26. the sum that Kay and Shay paid, including tax, was $28.62.
Describe Equation?An equation is a mathematical statement that asserts that two expressions are equal. Equations are used to represent relationships and constraints between variables, and are commonly used in many fields of science, engineering, and mathematics.
An equation consists of two parts: the left-hand side (LHS) and the right-hand side (RHS), separated by an equals sign (=). Each side of the equation can contain numbers, variables, mathematical operations (such as addition, subtraction, multiplication, and division), and parentheses.
The goal of solving an equation is to determine the value(s) of the variable(s) that make the equation true. This is typically done by applying mathematical operations to both sides of the equation in order to isolate the variable on one side and simplify the expression on the other side.
24. Let the price of the motorcycle before tax be represented by x. Then, we can write an equation based on the given information:
0.125x = 1437.50
Solving for x, we get:
x = 1437.50 / 0.125 = $11,500
Therefore, the price of the motorcycle before tax was $11,500.
25. The instructor now earns 115% of $50, or:
$50 x 1.15 = $57.50
Since this is the amount earned for teaching 2 classes, the amount earned per class after the raise is:
$57.50 / 2 = $28.75
Therefore, the instructor earns $28.75 per class after the raise.
26. To find how much Kay paid, we first need to calculate the tax:
0.08 x $14.50 = $1.16
So the total amount Kay paid was:
$14.50 + $1.16 = $15.66
Similarly, the tax Shay paid was:
0.08 x $12 = $0.96
So the total amount Shay paid was:
$12 + $0.96 = $12.96
Therefore, the sum that Kay and Shay paid, including tax, was:
$15.66 + $12.96 = $28.62
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I need help with this
The solutions of given functions are : 1. (f + g)(x) = 2x² + 3x - 2, 2. (fog)(x) = 6x² + 4, 3. (gof)(x) = 18x² - 60x + 53, 4. (f.g)(x) = 6x³ - 10x² + 9x - 15, 5. (f - g)(x) = -2x² + 3x - 8, 6. (fog)(3) = 58.
What are the functions?
We have the given functions:
f(x) = 3x - 5
g(x) = 2x² + 3
Here are the solution steps of the given functions f(x) and g(x).
1. (f + g)(x) = f(x) + g(x) = (3x - 5) + (2x² + 3) = 2x² + 3x - 2
So, (f + g)(x) = 2x² + 3x - 2.
2. (fog)(x) = f(g(x)) = f(2x² + 3) = 3(2x² + 3) - 5 = 6x² + 4
So, (fog)(x) = 6x² + 4.
3. (gof)(x) = g(f(x)) = g(3x - 5) = 2(3x - 5)² + 3 = 18x² - 60x + 53
So, (gof)(x) = 18x² - 60x + 53.
4. (f.g)(x) = f(x)g(x) = (3x - 5)(2x² + 3) = 6x³ + 9x - 10x² - 15
So, (f.g)(x) = 6x³ - 10x² + 9x - 15.
5. (f - g)(x) = f(x) - g(x) = (3x - 5) - (2x² + 3) = -2x² + 3x - 8
So, (f - g)(x) = -2x² + 3x - 8.
6. (fog)(3) = f(g(3)) = f(2(3)² + 3) = f(21) = 3(21) - 5 = 58
So, (fog)(3) = 58.
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question in picture thank you
The correct equation is: 5/6 - 1/6 = 4/6
What you mean by term Number line ?A number line is a visual representation of numbers, ordered from left to right, where each point on the line corresponds to a number. The number line can be used to represent a wide range of numbers, including integers, fractions, decimals, and even negative numbers.
On a basic number line, 0 is located in the center, with positive numbers to the right and negative numbers to the left. The numbers are usually evenly spaced, with tick marks or dots indicating each value. The distance between any two points on the number line represents the difference between the corresponding numbers.
According to question Option D is correct
This is because starting at 5/6 and ending at 1/6 involves moving in the negative direction on the number line. To find the distance between these two points, we need to subtract the smaller number (1/6) from the larger number (5/6).
So, 5/6 - 1/6 = 4/6, which simplifies to 2/3. This means that the distance between 5/6 and 1/6 on the number line is 2/3.
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(−20,F1) , (−10,F2) Step 1 of 2 : Compute the missing y values so that each ordered pair will satisfy the given equatio
[tex](-20, -4)[/tex] and are all of the ordered pairings that fulfil this equation [tex]F = 9/5C + 32. (-10, 14)[/tex].
What exactly are equation, and what varieties exist?Lines come in two varieties: identities and dependent equations. All possible values of the parameters result in an identity. Only certain combinations of the variables' values render a conditional equation true. Two expressions joined by the equals symbol ("=") form an equations.
What basic equation structure is used?Ax+By=C is the classic pattern for two-variable linear equations. A typical form linear equation is, for instance, 2x+3y=5. Finding all intercepts of a solution in this format is not too difficult. The approach additionally proves useful when trying to solve solutions combining two linear systems.
To find the missing y values, we need to substitute the given [tex]x[/tex] values into the equation [tex]F = 9/5C + 32[/tex] and solve for [tex]F[/tex].
For the first ordered pair (-20, F1):
[tex]F1 = 9/5(-20) + 32[/tex]
[tex]F1 = -36 + 32[/tex]
[tex]F1 = -4[/tex]
So the missing y value is [tex]-4[/tex], and the complete ordered pair is [tex](-20, -4)[/tex].
For the second ordered pair (-10, F2):
[tex]F2 = 9/5(-10) + 32[/tex]
[tex]F2 = -18 + 32[/tex]
[tex]F2 = 14[/tex]
So the missing y value is [tex]14[/tex], and the complete ordered pair is [tex](-10, 14)[/tex].
Therefore, the complete set of ordered pairs that satisfy the equation [tex]F = 9/5C + 32[/tex] is:
[tex](-20, -4)[/tex] and [tex](-10, 14)[/tex].
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The complete question is:
Given the equation
F=9,5
C+32
F=95C+32
where C is the temperature in degrees Celsius and F is the corresponding temperature in degrees Fahrenheit, and the following ordered pairs:
(−20,F1)
(−20,F1),(−10,F2)(−10,F2)
Step 1 of 2 : Compute the missing y values so that each ordered pair will satisfy the given equation.
Answer the following problems. Complete your answers by using GFESA format. (given, find, equation, solution, and answer). Write your answer on a separate sheet of paper.
a. Find the amount of charge stored on either plate of 4.4 mF capacitor
connected to a 12-volt battery.
b. If a plate separation of a capacitor is 2.2 x 10-3m, determine the area of the plates if the capacitance is 1.4 F.
c. A parallel plate capacitor is filled with an insulating material with a dielectric constant of 2.5. The distance between the plates of the capacitor is 0.0003 m. Find the capacitance of the capacitor if the area of the plate is 30 m².
a) The amount of charge stored on either plate of the capacitor is 0.0528 C. ,b) The area of the plates is 3.47 x 10⁷ m². c) The capacitance of the capacitor is 6.62 x 10⁻⁸ F.
what is capacitance ?
Capacitance is a physical property of a capacitor that represents its ability to store an electric charge. It is defined as the ratio of the amount of electric charge that can be stored on the capacitor's plates to the potential difference (voltage) between them. Capacitance is measured in farads (F)
In the given question,
:Capacitance (C) = 4.4 mF = 4.4 x 10⁻³ F
Voltage (V) = 12 V
The amount of charge (Q) stored on either plate of the capacitor.
Q = C x V
Q = 4.4 x 10⁻³ F x 12 V
Q = 0.0528 C
The amount of charge stored on either plate of the capacitor is 0.0528 C.
Capacitance (C) = 1.4 F
Plate separation (d) = 2.2 x 10⁻³m
Find: The area (A) of the plates.
Equation:
C = ε0 x (A/d)
where ε0 is the permittivity of free space and has a value of 8.85 x 10⁻¹² F/m
A = C x d / ε0
A = 1.4 F x 2.2 x 10⁻³ m / (8.85 x 10⁻¹² F/m)
A = 3.47 x 10⁷ m²
The area of the plates is 3.47 x 10⁷ m².
Dielectric constant (k) = 2.5
Plate separation (d) = 0.0003 m
Area (A) = 30 m²
The capacitance (C) of the capacitor.
C = k x ε0 x (A/d)
where ε0 is the permittivity of free space and has a value of 8.85 x 10⁻¹² F/m
C = 2.5 x 8.85 x 10⁻¹² F/m x 30 m² / 0.0003 m
C = 6.62 x 10⁻⁸ F
The capacitance of the capacitor is 6.62 x 10⁻⁸ F.
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Assume a company is preparing a budget for its first two months of operations. During the first and second months it
expects credit sales of $40,000 and $77,000, respectively. The company expects to collect 30% of its credit sales in
the month of the sale and the remaining 70% in the following month. What amount of cash collections from credit
sales would the company include in its cash budget for the second month?
Multiple Choice
$23,100
$51,100
$53,900
$35,100
what is the common meaning of m and b, 2 + 3x + 5 - 2x = y
Answer:
m=the slope
b=the y intercept
[tex]\left[\begin{array}{ccc}1&a&a^2\\1&b&b^2\\1&c&c^2\end{array}\right][/tex]
Solve the determinant by matrix methode please don't solve it by crammer or rank method .
Answer which should be obtained : (a-b)(b-c)(c-a)
The determinant of the given matrix is bc²-cb²+ac²-ab²+a²c-a²b.
The given matrix is [tex]\left[\begin{array}{ccc}1&a&a^2\\1&b&b^2\\1&c&c^2\end{array}\right][/tex].
Determinants are considered as a scaling factor of matrices. They can be considered as functions of stretching out and the shrinking in of the matrices. Determinants take a square matrix as the input and return a single number as its output.
Here, 1(bc²-cb²)+a(c²-b²)+a²(c-b)
= bc²-cb²+ac²-ab²+a²c-a²b
Therefore, the determinant of the given matrix is bc²-cb²+ac²-ab²+a²c-a²b.
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I need help with this question
Answer:
5/7
Step-by-step explanation:
ratio of boys to girls---> 2:5
ratio sum: 2+5=7
girls ratio =5/7
OR
total of people in 7th grade choir=28
hence, no of girls in 7th grade choir=5/7 × 28
=20
proportion of girls in choir= 20/28 = 5/7
On January 1, 1971, Arthur Clarke deposited $20
in a bank that paid 5% interest compounded
annually. How much money did he have in that
account on January 1, 2001?
Answer:5% = 0.05 . Then multiply the original amount by the interest rate. $1,000 * 0.05 = $50 . That's it.
Step-by-step explanation:
please give me brainliest
Given ∆ABC below where AC = 26 and m∠C = 52°, determine the value of x.
Enter your answer as a decimal rounded to the nearest tenth (one decimal place)
x represents a length, we can discard the negative sοlutiοn and cοnclude that x ≈ 15.7.
What is triangle?A triangle is a three-sided pοlygοn with three angles. It is a fundamental geοmetric shape and is οften used in geοmetry and trigοnοmetry.
Using the Law οf Cοsines:
c² = a² + b² - 2ab cοs(C)
where c is the side οppοsite angle C, a and b are the οther twο sides, and C is the angle between sides a and b.
Substituting the knοwn values:
26² = x² + (x+7)² - 2x(x+7) cοs(52°)
Simplifying and sοlving fοr x:
676 = x² + x² + 14x + 49 - 2x² cοs(52°) - 14x cοs(52°)
676 = 2x² - 14x cοs(52°) + 49
2x² - 14x cοs(52°) - 627 = 0
Using the quadratic fοrmula:
[tex]x = [14 cos(52^\circ) \± \sqrt{((14 cos(52^\circ))}^2 - 4(2)(-627))] / (2(2))[/tex]
x ≈ 15.7 οr x ≈ -21.6
Since x represents a length, we can discard the negative sοlutiοn and cοnclude that x ≈ 15.7.
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Kareem borrowed money from a credit union for 6 years and was charged simple interest at an annual rate of 6%. The total interest that he paid was $2520 . How much money did he borrow?
Kareem borrowed $7000 from the credit union based on the given interest rate.
We may use the simple interest formula to figure out how much Kareem borrowed:
I = Prt
Where r: yearly interest rate represented as a decimal, P: borrowed principal, I: interest paid, and t: amount of time in years.
We are aware that Kareem borrowed money for 6 years at an interest rate of 6% each year. We also know that he spent $2520 on interest in total. We may determine P using the following formula:
2520 = P0.066
2520 = 0.36P
P = 7000
Kareem thus took out a $7000 loan from the credit union.
In conclusion, we utilized the simple interest formula and the provided data on the interest rate, time, and total interest paid to calculate how much money Kareem borrowed from the credit union. We discovered that he took out a loan for $7000, the principal of which accrued $2520 in interest over the course of six years at an annual rate of 6%.
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Find the volume and total surface area of the shape below. The base is a semi-circle. height 8 in, length 12 in
The volume of the shape is 144π cubic inches and the total surface area of the shape is 114π square inches.
To find the volume and total surface area of the shape, we need to first determine the radius of the semicircle.
Since the length of the shape is 12 inches and the base is a semicircle, the diameter of the semicircle is also 12 inches. Therefore, the radius of the semicircle is half the diameter, which is 6 inches.
Now we can use the formula for the volume of a cylinder, which is:
V = (πr^2h)/2
where V is the volume, r is the radius, and h is the height.
Substituting in the values we have:
V = (π(6)^2(8))/2
V = 144π cubic inches
So the volume of the shape is 144π cubic inches.
Next, we can find the total surface area of the shape by adding the area of the semicircle base to the lateral surface area of the cylinder. The formula for the lateral surface area of a cylinder is:
L = 2πrh
where L is the lateral surface area.
Substituting in the values we have:
L = 2π(6)(8)
L = 96π square inches
The formula for the area of a semicircle is:
A = (πr^2)/2
where A is the area of the semicircle.
Substituting in the values we have:
A = (π(6)^2)/2
A = 18π square inches
Adding the lateral surface area and the area of the semicircle base together, we get:
Total surface area = L + A
Total surface area = 96π + 18π
Total surface area = 114π square inches
So the total surface area of the shape is 114π square inches.
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Between 2 and 4 pm the average number of calls per minute getting into the switch board of a company is 2.35. Find the probability that during one particular minute there will be at most 2 phones calls
Answer:
To solve this problem, we need to use the Poisson distribution, which describes the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate of occurrence.
Let λ be the average number of calls per minute. From the problem statement, we have λ = 2.35.
Now we need to find the probability of having at most 2 phone calls in one minute. Let X be the random variable representing the number of phone calls in one minute. Then we have:
P(X ≤ 2) = e^(-λ) * (λ^0/0!) + e^(-λ) * (λ^1/1!) + e^(-λ) * (λ^2/2!)
Substituting λ = 2.35, we get:
P(X ≤ 2) = e^(-2.35) * (2.35^0/0!) + e^(-2.35) * (2.35^1/1!) + e^(-2.35) * (2.35^2/2!)
≈ 0.422
Therefore, the probability that during one particular minute there will be at most 2 phone calls is about 0.422, or 42.2%.
4+-7<13 someone help walk me thru
Step-by-step explanation:
This sign "<" could mean "less than" or "greater than"
depending on which way it is facing
in this case 4+-7 is less than 13 because
< is facing 13 and not 4+-7
meaning than 13 is a bigger number
than the sum of 4+-7 but if 4+-7 is greater than 13 then
the "<" sign would be facing 4+-7 like this: 4+-7>13
How do we know if it is true?
equation: 4+-7<13
4+-7 is -3
so -3<13.
13 is bigger than -3
which means the equation is true
What if it was false?
here is a false equation:
4>14
it is false because 4 is not a bigger number than 14
Hope this helps!
I would appreciate if you could mark me brainliest.
HELP PLSSSSSSssssssSSSSS
Answer:
B
Step-by-step explanation:
[tex]\frac{1}{2}[/tex] fathom = 1 yard = 3 feet
then 1 fathom = 2 × 3 feet = 6 feet
1 furlong = 660 feet , then
660 feet ÷ 6 feet = 110
there are 110 fathoms in 1 furlong
Three friends play a game. Jamila has 4-1/2
more points than Carter. Carter has 7 1/2 more
points than Aisha. Jamila has 26 points. Write
and solve an equation to find the number of
points Aisha has. Show your work.
The equation is written as
x + 11 = 26Aisha has 15 points
How to write the equationLet's use the given information to set up an equation to represent the relationship between the points each friend has.
Let x be the number of points Aisha has.
Then, according to the problem statement, we know that:
Carter has 7 1/2 more points than Aisha, so he has
x + 7 1/2 points.
Jamila has 4 - 1/2 more points than Carter, so she has
x + 7 1/2 + 4 - 1/2 points,
which simplifies to x + 11 points.
Jamila has 26 points, so we can set x + 11 equal to 26 and solve for x:
x + 11 = 26
x = 26 - 11
x = 15
Therefore, Aisha has 15 points.
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the difference of two supplementary angle is 78 degrees find the measure of 2 angles
Answer:129°and 51°.
Step-by-step explanation:
A survey showed that 75% of adults need correction for their eyesight. If 12 adults are randomly selected find the probability that no more than one of them need correction of her eyesight is 18 significantly low number of adult record I said correction.
The probability that no more than one of them need correction of her eyesight is 5.960.
What is probability?
Probability is a way of calculating how likely something is to happen. It is difficult to provide a complete prediction for many events. Using it, we can only forecast the probability, or likelihood, of an event occurring. The probability might be between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty.
Here using formula , Binomial distribution: P(X) = [tex]nC_x \times p^x\times q^{n-x}[/tex]
=> P(an adult need correction), p = 0.75
=>q = 1 - p = 0.25
Sample size, n = 12
P(no more than 1 of them need correction for their eyesight) = P(none of them need correction) + P(only 1 need correction)
=> [tex]0.25^{12}[/tex] + [tex]12\times0.75\times0.25^{11}[/tex]
=> 5.960
If the probability of an event is less than 0.05, it can be considered significantly low
Therefore, 1 is a significantly low number of adults requiring eyesight correction.
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can i have helpp tyy
1. An aluminum recycling center pays $0.25 per pound for aluminum cans. Draw a
diagram or picture to illustrate this situation.
2. How much money will someone earn if they bring 8 pounds of cans? Draw a
picture and solve.
3. Ms. Cheese’s 7th grade class needs to earn $50 in their fundraiser. How many
pounds of cans will they need to sell? Be sure to show your work.
From expression 8 pounds x $0.25 per pound and $50 / $0.25 per pound , Earnings = $2.00 and Total pounds of cans = 200 pounds and check attachment for illustration.
What exactly are expressions?An expression in mathematics is a set of numbers, variables, and mathematical operations (such as addition, subtraction, multiplication, and division) that may be evaluated to generate a value. Expressions can be basic or complicated, containing a variety of numbers, variables, and mathematical processes.
Now,
1.
Let the total money earned by selling aluminium cans be y and the no. of cans recycled be x then this situation can be represented by the function y = 0.25x, see attachment for illustration.
2.
If someone brings 8 pounds of cans, they will earn:
Earnings = 8 pounds x $0.25 per pound
Earnings = $2.00
3.
To earn $50, the class needs to sell:
Total pounds of cans = Total earnings / Price per pound
Total pounds of cans = $50 / $0.25 per pound
Total pounds of cans = 200 pounds
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What is the value of tan (−284°24′) to the nearest ten-thousandth?
The answer of the given question based on the trigonometry is the nearest ten-thousandth, tan(−284°24′) is approximately equal to -0.2493.
What is Equivalent angle?An equivalent angle is an angle that has the same degree measure as another angle. In geometry, two angles are said to be equivalent if they have the same measure, regardless of their orientation or position in space.
Equivalent angles can be found by adding or subtracting multiples of 360° degrees from an angle. This is because an angle that has been rotated a multiple of 360° degrees has the same orientation and position as the original angle.
We can use the fact that the tangent function has period 180 degrees and that tan(x + 180°) = tan(x) for any angle x. Therefore, we can add or subtract multiples of 180° from −284°24′ to find an equivalent angle in the range of −90° to 90°.
Adding 360° to −284°24′ gives us an equivalent angle of 75°36′. Since the tangent function is positive in the first and third quadrants, we can find the value of tangent of 75°36′ or its reference angle of 14°24′.
Using a calculator, we get:
tan(14°24′) ≈ 0.2493
Therefore, to the nearest ten-thousandth, tan(−284°24′) is approximately equal to -0.2493.
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To the nearest ten-thousandth, the value of tan (-284°24') is approximately -3.7583.
Define tangent function?We need to keep in mind that the tangent function is periodic in order to determine the value of tan(-284°24'). This means that the tangent of an angle is the same as the tangent of that angle plus or minus any multiple of 180 degrees.
So, we can add 360 degrees to -284 degrees to get an equivalent angle in the range of -180 to 180 degrees:
-284 + 360 = 76
So, we can find the tangent of -284°24' by finding the tangent of 76°24'. Using a calculator, we get:
tan(76°24') ≈ 3.7583
Therefore, To the nearest ten-thousandth, the value of tan (-284°24') is approximately -3.7583. Note that the negative sign indicates that the angle is in the third quadrant of the unit circle.
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four bad apples are mixed accidentally with 20 good apples . obtain the probability distribution of the number of bad apples in a draw of 2 apples at random
Step-by-step explanation:
We can solve this problem using the hypergeometric distribution.
The total number of apples is 24 (4 bad + 20 good). Let X be the number of bad apples in a draw of 2 apples.
The probability of drawing 0 bad apples is:
P(X=0) = (20 choose 2) / (24 choose 2) = 190 / 276
The probability of drawing 1 bad apple is:
P(X=1) = ((4 choose 1) * (20 choose 1)) / (24 choose 2) = 64 / 276
The probability of drawing 2 bad apples is:
P(X=2) = (4 choose 2) / (24 choose 2) = 1 / 276
Therefore, the probability distribution of the number of bad apples in a draw of 2 apples at random is:
X | 0 | 1 | 2
----|------|------|-----
P(X) |190/276|64/276|1/276
Determine the least possible degree on the graph
Answer:
The least possible degree is 3.
How do you identify regions in an element
Answer:
In chemistry, an element is typically represented by its atomic symbol, which consists of one or two letters. The regions in an element refer to different parts of its atom.
The three main regions of an atom are the nucleus, the electron cloud, and the space in between. The nucleus is located at the center of the atom and contains positively charged protons and neutrally charged neutrons. The electron cloud surrounds the nucleus and contains negatively charged electrons, which are distributed in different energy levels or orbitals. The space in between the nucleus and the electron cloud is mostly empty.
To identify the different regions in an element, one can look at the atomic structure of the element, which is typically represented by an electron configuration or an orbital diagram. These representations show the number and distribution of electrons in the different energy levels or orbitals. By analyzing the electron configuration or orbital diagram, one can identify the number of electrons in the electron cloud and the number of protons and neutrons in the nucleus. The space in between the nucleus and the electron cloud is relatively small and is not usually a focus of study in chemistry.