PLEASEE HELP

A teacher wants to select two students at random to read two chapters aloud from a book

Which statement describes a random selection of two students?

A. The teacher selects the first two students who arrive to class.

• B. The teacher selects the first two students who raise their hand.

C. The teacher sees two students in the hall and asks them to do the reading.

• D. The teacher puts the student names on individual pieces of paper and draws two names.

Answer:

Hope this is what you were looking for :)

Step-by-step explanation:

tan = opposite/adjacent

IF YOU DONT NEED TO FIND THE VALUES OF THE SIDES:

tan A =  [tex]\frac{x}{11}[/tex]

tan B = [tex]\frac{11}{x}[/tex]

Replace the x for whatever the value of BC is or if it doesn't have a value, you can just leave it as x.

IF YOU DO NEED TO FIND THE VALUES OF THE SIDES:

tan 45 = 1

tan 45 =  [tex]\frac{BC}{11}[/tex]

(11) tan 45 = BC

BC = 11

tan 45 = [tex]\frac{11}{AC}[/tex]

AC = [tex]\frac{11}{tan 45}[/tex]

AC = 11

This can also be done without using tangent from taking a look at special right triangles.

In 45-45-90 triangles, the two legs are the same size while the hypotenuse is equal to one of the legs multiplied by [tex]\sqrt{2}[/tex]. In doing this, we can find that both legs are 11 and the hypotenuse is [tex]11\sqrt{2}[/tex].

The solution to the system of equations is (2, 1). To find this solution, we must first solve the first equation, Y < 2x + 3, for x.

Subtracting involves taking the difference between two numbers. It is the opposite of addition and is represented by the '-' sign.

We can do this by subtracting 3 from both sides of the equation, which gives us Y - 3 < 2x.

We then divide both sides of the equation by 2, which gives us

Y - 3/2 < x.

Next, we must solve the second equation, x + y ≥ 3, for y. To do this, we subtract x from both sides of the equation, which gives us y ≥ 3 - x.

Finally, we must set both equations equal to each other,

Y - 3/2 = 3 - x.

We can then solve for x by adding 3/2 to both sides of the equation, which gives us

x = 2.5.

We can then plug this value for x into the second equation, which gives us y ≥ 3 - 2.5.

We then solve for y by subtracting 2.5 from both sides of the equation, which gives us y = 0.5.

Since the value for x must be less than 4, we must round down the value of x to 2. This means that the solution to the system of equations is (2, 1).

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Answer:

c

Step-by-step explanation:

Option E is incorrect in light of the provided assertion, and only options A,B,C, and D are acceptable.

Probability is simply the chance that something will happen. We can discuss the likelihood of various outcomes when we are unable to foresee how an incident will unfold.

The probability of drawing a blue cube is 11/25, the probability of drawing a red cube is 6/25, and the probability of drawing a green cube is 8/25. Since we are replacing the cube after each draw, each draw is independent and follows the same probability distribution.

To find the expected number of times we would pull a certain color cube, we can simply multiply the probability of drawing that color cube by the total number of draws:

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option A is correct.

The probability of drawing more red cubes than blue cubes is a bit more complicated to calculate, but it can be done by summing the probabilities of drawing 0, 1, 2, 3, 4, 5, or 6 blue cubes and 6, 5, 4, 3, 2, 1, or 0 red cubes. However, it is easier to notice that the probability of drawing more red cubes than blue cubes is the same as the probability of drawing more blue cubes than red cubes, which is 1/2 since both events are equally likely. Therefore, option B is correct.

Expected number of green cube draws: (8/25) x 200 = 64 times. So option C is correct.

Expected number of blue cube draws: (11/25) x 200 = 88 times. So option D is correct.

Expected number of red cube draws: (6/25) x 200 = 48 times. So option E is not correct since it expects less than 48 red cube draws.

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If we repeated a hypothesis test 1000 times, the number of times we would expect to commit a Type I error, assuming the null hypothesis were true, would depend on the significance level (α) of the test.

A Type I error occurs when we reject the null hypothesis when it is actually true. The significance level of a test (α) is the probability of making a Type I error when the null hypothesis is true. In other words, if we set a significance level of α = 0.05, we are saying that we are willing to tolerate a 5% chance of making a Type I error.

Assuming a significance level of α = 0.05, if we repeated the test 1000 times, we would expect to make a Type I error in approximately 50 tests (0.05 x 1000 = 50). This means that in 50 out of the 1000 tests, we would reject the null hypothesis even though it is actually true.

However, it is important to note that the actual number of Type I errors we make in practice may differ from our expectation, as it depends on the specific characteristics of the population being tested and the sample sizes used in each test.

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The probability of obtaining 10 or fewer families earning less than $35,000 per year in a simple random sample of 30 families from a large city with 45% of families in that income bracket is approximately 0.041 or 4.1%.

We can use the binomial distribution formula to calculate the probability of obtaining 10 or fewer families earning less than $35,000 per year in a simple random sample of 30 families from a large city where 45% of families earn less than $35,000 per year.

Let's denote the probability of a family earning less than $35,000 per year as "p", which is 0.45 in this case, and the number of trials or families sampled as "n", which is 30 in this case.

The probability of obtaining k families earning less than $35,000 per year in a simple random sample of 30 families can be calculated using the binomial distribution formula:

P(X ≤ 10) = Σ(i=0 to 10) [n choose i] * p^i * (1-p)^(n-i)

where n = 30, p = 0.45, and X is the random variable representing the number of families earning less than $35,000 per year in the sample.

Using a binomial calculator or software, we can calculate:

P(X ≤ 10) ≈ 0.041

Therefore, the probability that a simple random sample of 30 families will have 10 or fewer families earning less than $35,000 per year is approximately 0.041 or 4.1%.

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Answer:

11/7: +9.42

Step-by-step explanation:

By using equation in two variable we need to use 2 eggs to make all the cookies with 1.33 cups of butter.

To make six dozen cookies, the recipe calls for two cups of butter and three eggs. We can use proportionality to solve this question: If 2 cups of butter require 3 eggs to make 6 dozen cookies, then 1.33 cups of butter require x eggs to make all of the cookies.

x eggs = (1.33 cups of butter x 3 eggs)/(2 cups of butter). x = 1.99 eggs. Since we cannot use .99 eggs to make cookies, we would need to round up to the nearest whole number of eggs.

Therefore, we need to use 2 eggs to make all the cookies with 1.33 cups of butter.

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Answer:

6n-6 or 6(n-1)

Step-by-step explanation:

six times a number, n, can be shown as 6n. "Six less" indicates -6. So combining the two parts leaves 6n-6. This can be simplified to 6(n-1)

The mean of the sample means is equal to the population mean.

The mean of the sample means is the average of all sample means taken from the population. It is an estimate of the population mean. The sample mean is calculated by taking the sum of all values in the sample and dividing it by the sample size. The mean of the sample means is equal to the population mean, as all sample means come from the same population and therefore have the same mean. It is not affected by the sample size or the population standard deviation. Therefore, the mean of the sample means is equal to the population mean.

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Answer:

(x^2−2xy+y^2)−z^2

⇒[x(x−y)−y(x−y)]−z^2

⇒(x−y)(x−y)−z^2

⇒(x−y)^2−z^2

⇒[(x−y)+z][(x−y)−z]

⇒(x−y+z)(x−y−z)

Answer:

We can use the given equation to find the expected LSAT score (S) for a student who studies for 10 hours:

S = 130 + 2.2h

S = 130 + 2.2(10)

S = 130 + 22

S = 152

Therefore, if a student studies for 10 hours, we would expect her LSAT score to be 152.

Answer:

"Mrs. Lennox is the worst mother imaginable, and everybody knows it."

Step-by-step explanation:

The first one uses "described", therefore isn't a personal opinion.

The second uses quotations, so isn't a personal opinion.

The third doesn't have any sort of opinion or connotation.

Therefore it must be the last one.

Let me know if this helped by hitting like or brainliest! If not, please comment below and I'll get back to you ASAP.

Answer:

The answer to your problem is, [tex]16cm^{2}[/tex]

Step-by-step explanation:

Sophie has a small cube shaped box.

Volume of the box is [tex]64cm^{3}[/tex]

We have to find the area of one face of the box.

Let one side of the box is x

Then volume = [tex]x^{3}[/tex] = 64

x³ = 4³

= 4

Now area of one face of the cube = x²

then area = 4² = 16 cm²

Thus the answer to your problem is, [tex]16cm^{2}[/tex]

The probability that all 6 flips result in heads is 1/64

The given coin is flipped 6 times. The number of heads and tails could vary from 0 to 6.Let H be the number of heads and T be the number of tails. Then the possible values of H and T are, H=0 and T=6 H=1 and T=5 H=2 and T=4 H=3 and T=3 H=4 and T=2 H=5 and T=1 H=6 and T=0

For the given question, it is given that more heads are flipped than tails.So the possible values of H are 4, 5 and 6.So the total number of possible outcomes with more heads than tails is the sum of the possible outcomes with 4, 5 and 6 heads which is, 1+6+15 = 22 (from the combinations formula)Now, the probability that all 6 flips result in heads, given more heads are flipped than tails is,

P(all 6 are heads) = P(H > T) × P(all 6 are heads | H > T)P(H > T) = 22/64

P(all 6 are heads | H > T) = 1/21 (there is only one possibility where all 6 flips are heads)

P(all 6 are heads) = P(H > T) × P(all 6 are heads | H > T) = (22/64) × (1/21) = 1/64

Therefore, the probability that all 6 flips result in heads, given more heads are flipped than tails is 1/64.

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If f(x) is a functiοn and f(1) = 5, then  f(1) = 1 cοuId nοt be true.

Thus οptiοn a is cοrrect.

A functiοn is a reIatiοn between twο sets, caIIed the dοmain and the range, such that fοr each eIement in the dοmain, there is exactIy οne eIement in the range. A functiοn maps each eIement in the dοmain tο a unique eIement in the range.

In οther wοrds, a functiοn is a ruIe οr a fοrmuIa that assοciates each input vaIue with a unique οutput vaIue. The input vaIues are the dοmain οf the functiοn, and the οutput vaIues are the range. Functiοns are οften denοted by a symbοI such as f(x), where x is an eIement in the dοmain and f(x) is the cοrrespοnding eIement in the range.

In mathematicaI anaIysis, the generaI cοncept οf functiοn, appIicatiοn οr mapping refers tο a ruIe that assigns tο each eIement οf a first set a singIe eIement οf a secοnd set.

Using this definitiοn, severaI eIements οf the dοmain can resuIt in the same eIement οf the range οf the functiοn.

But, the same eIement οf the dοmain, can nοt have different vaIues οf the range οf the functiοn.

Therefοre, the fοIIοwing expressiοn can nοt be true:

f (1) = 1

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Complete Question:

If f(x) is a function and f(1) = 5, then which of the following could not be true?

a. f(1) = 1

b. f(2) = 1

c. f(5) = 5

Answer:

All the expressions except d are polynomials.

Giovanna deposited $1600 into two accounts, half in First Oak and half in West United.

Interest earned in First Oak account after 5 years at 6% simple interest:

= 0.06 x $800 x 5

= $240

Interest earned in West United account after 5 years at 5% compounded annually:

= $800 x (1 + 0.05)^5 - $800

= $800 x 1.27628 - $800

= $221.02

Total interest earned in both accounts:

= $240 + $221.02

= $461.02

Therefore, Giovanna will have earned $461.02 in interest from both accounts at the end of 5 years.

The change in Silvertown’s revenue from last year to this year can be described by c. 20,493.

Property taxes on homes decreased this year by an average = $75. 90

Total number of homes = 270

It is essential to compare the overall property tax revenue from this year to the total revenue from last year after the $75.90 per-home drop in order to ascertain the change in Silvertown's property tax revenue.

Calculating the total decrease in revenue -

= Average decrease x total number of homes

= 75.90 x 270

= 20,493

Complete Question:

Property taxes on homes decreased this year by an average of $75. 90 in Silvertown. There are 270 homes in Silvertown. Which describes the change in Silvertown’s revenue from last year to this year?

a. - 21,093

b. - 20, 493

c. 20,493

d. 21930

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Every morning, Mr. Cross bakes 80 strawberry frosted donuts unless there is a special order. Each donut costs $3 to make, and it is sold for $5. Unsold donuts are given away to a charity at the end of the day, at a discounted price of $1.50. What will be Mr. Cross’s total earnings if he sells all 80 donuts?

Total revenue if all 80 donuts are soldRevenue = Total units sold × Selling price per unitSince there are 80 donuts and each donut costs $5,Total revenue if all 80 donuts are sold = 80 × 5 = $400Total cost if all 80 donuts are soldTotal cost of making all 80 donuts = Cost of one donut × Total units madeSince each donut costs $3,Total cost of making all 80 donuts = 3 × 80 = $240Total profitTotal profit = Total revenue - Total cost

Since revenue is $400 and the total cost is $240,Total profit = 400 - 240 = $160At the end of the day, unsold donuts are given away to charity at a discounted price of $1.50 each. Therefore, Mr. Cross’s total earnings would be $160 if he sold all 80 donuts.

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Answer:

(15, - 4 ) , (3, - 2 ) , (- 1, 0 )

Step-by-step explanation:

given a point (x, y ) on a function f(x) , then the corresponding point on the inverse function is (y, x )

given the points on g(x) , then the corresponding points on [tex]g^{-1}[/tex] (x) are

(- 4, 15 ) → (15, - 4 )

(- 2, 3 ) → (3, - 2 )

(0, - 1 ) → (- 1, 0 )

The required sides of kite are √61, √61, √221 and √221 units.

According to the Pythagoras theorem, the square of the hypotenuse in a right-angled triangle equals the total of the squares of the other two sides. The formula for this theorem is c² = a² + b², where c is the hypotenuse and a and b are the triangle's two sides. Pythagoras theory triangles are another name for these triangles.

In ΔAOD

AD = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔAOB

AB = [tex]\sqrt{5^2+6^2} = \sqrt{61}[/tex] units

In ΔBOC

BC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

In ΔDOC

DC = [tex]\sqrt{5^2+14^2} = \sqrt{221}[/tex] units

Thus, required sides of kite are √61, √61, √221 and √221 units.

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Rounding to the nearest thousandth means rewrite the number and deleting all digits to the right of the rounded number. The percentage value for 165.1% of 384.7 is equals to the 42.917%.

In mathematics, a percentage is a number that represents a fraction of hundred. We have to calculate the value of 165.1% of 384.7. Percentage solution with steps:

Step 1: We make the assumption that 384.7 is 100% since it is our output value.

Step 2: We next represent the value we need with x. From step 1, it follows that 100% = 384.7.

Step 3: In the same sense, x% = 165.1.

Step 5: Now, we have a pair of simple equations:

100% = 384.7 --(1).

x% = 165.1 ---(2).

Step 6: By simply dividing equation (1) by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have 100% /x% = 384.7/165.1.

Step 7: Taking the inverse or reciprocal in both sides, x% / 100% = 165.1/384.7

=> x = ( 165.1/384.7) × 100

=> x = 42.91655835716 ~ 42.917 (round to the nearest thousandth). Therefore, 165.1 is 42.917% of 384.7.

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Therefore , the solution of the given problem of ordered pair comes out to be the ordered pair (1, 1/2).

"Ordered pairs" are two separate variables that are arranged in a way that suggests a specific sequence. The coordinates for x and y in an order pair are represented, respectively, by the main and second components. The sample following uses close parentheses to indicate the ordered combination.

Here, The formulae are as follows:

=>y = -z + 2      ...(1)

=> y = -2x² + z + 1  ...(2)

Equation (1) can be substituted for equation (2) to find the value of z:

=> Z = x² + 1/2 - z + 2 = -2x² + z + 1

=> 2z = 2x² + 1

We can now enter this value of z into equation (1) and find the value of y:

=> y = -z + 2

=> y = -(x² + 1/2) + 2

=> y = -x² + 3/2

As a result, the equation system can be expressed as:

=> z = x² + 1/2

=> y = -x² + 3/2

When x=0:

=> z = 0² + 1/2 = 1/2

=> y = -0² + 3/2 = 3/2

Therefore, there is no answer for the ordered pair (0, 3/2).

When x=1:

=> z = 1² + 1/2 = 3/2

=> y = -1² + 3/2 = 1/2

The answer is the ordered pair (1, 1/2).

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Surface area , Lateral area and volume of triangular prism area 262.25 square in, 231 square in and 156.25 cubic in respectively.

With two triangular bases and three rectangular sides, a triangular prism is a kind of polyhedron. Alternatively, because it has five faces overall, it may be thought of as a pentahedron in which the bases' edges and vertices are connected by three rectangular sides.

Given, base (b) =5 in ,

the height of the triangle (h) = 6.25 in

length of a prism (l) = 12 in

and the hypotenuse of the right triangle = 8 in

The surface area of a right triangular prism = b×h + (S1 + S2 + h)L

On substituting the values, we get

SA = (5 × 6.25) + [(5 + 6.25 + 8) × 12]

⇒ SA = 60 + (30 × 11)

⇒ SA =262.25 square in

Therefore, the total surface area of a right triangular prism is 262.25 square in.

Lateral  Area = ( S1 + S2 + S3 ) × l

On substituting the values, we get

LA=(5+6.25+8)×12

LA=(19.25)×12

LA=231 square in

Therefore, the lateral surface area of a right triangular prism is 231 square in.

the base area = (1/2) × (b×h) = (1/2) × (5 ×6.25) =15.625 square in

The length of the prism is, L = 12 in

Using the volume of the triangular prism formula,

The volume of the given triangular prism = base area × length of the prism = 15.625 ×10=156.25 cubic in

Hence, The volume of the given triangular prism is 156.25 cubic in.

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1: The measure of arc JML is: arc JML = 176°

3: m∠WXY = 59°

5: The measure of the arc is: arc FE = 54°

7: The measure of the angles are: m∠A  = 79° and m∠B  = 112°

9: The value of x is: x = 9

No. 1

The measure of inscribed angle is half the measure of its intercepted arc. That is:

∠ JKL = 1/2 * arc JML

88 = 1/2 * arc JML

arc JML = 2 * 88

arc JML = 176°

No. 3

arc WY =  360 - 86 - 156 = 118° (sum of angles in a circle)

m∠WXY = 1/2 * arc WY

m∠WXY = 1/2 * 118

m∠WXY = 59°

No. 5

An angle inscribed in a semicircle is a right angle. Thus, m∠DFE = 90°

m∠EDF = 180 - 90 - 63 = 27° (sum of angles in a triangle)

m∠EDF  = 1/2 * arc FE

27°  = 1/2 * arc FE

arc FE = 2 * 27

arc FE = 54°

No. 7

The opposite angle in a cyclic quadrilateral add up to 180°. That is:

m∠A + m∠C  = 180°

m∠A + 101 = 180

m∠A  = 180 - 101

m∠A  = 79°

m∠B + m∠D  = 180°

m∠B + 68 = 180

m∠B  = 180 - 68

m∠B  = 112°

No. 9

67 = 1/2 * (16x - 10)

67 * 2 = (16x - 10)

16x - 10 = 134

16x  = 134 + 10

16x = 144

x = 144/16

x = 9

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On peut commencer par utiliser la formule suivante pour calculer la distance parcourue par le pigeon voyageur :

distance = vitesse x temps

où la vitesse est donnée en km/h, le temps en heures et la distance en km.

Dans ce cas-ci, la vitesse est de 84 km/h et le temps de voyage est de 1h45, soit 1.75 heures. On peut donc calculer la distance parcourue par le pigeon :

distance = 84 km/h x 1.75 h = 147 km

Donc, la distance entre Ousmane et Arnaud est de 147 km.

Answer:

Step-by-step explanation:

8

The height of the roof is approximately 21.6 feet, to the nearest tenth of a foot.

To calculate the height of the roof, we need to use the formula for the volume of a prism with a triangular base. This is given by V = 1/3 B h, where B is the area of the base and h is the height of the prism.
In this case, we know that the base is an equilateral triangle with side length 25 feet. The area of an equilateral triangle with side length s is given by A = √3/4 s². Therefore, the area of the base of the prism is:
B = √3/4 (25 ft)²
B = 25√3/4 ft²
Now, we need to use the model to determine the height of the prism. We can do this by measuring the height of one of the triangular faces. The model is not provided, so I cannot provide specific measurements. However, we can use the Pythagorean theorem to relate the height of the triangular face to the height of the prism:
h² = (25 ft)² - (1/2 s)²
h² = 625 ft² - (1/2 (25 ft))²
h² = 625 ft² - 156.25 ft²
h² = 468.75 ft²
h ≈ 21.6 ft
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The combined area of the four removed triangles is 48 sq.units. Answer: 48

We need to find out the combined area of the four removed triangles, in square units. Given: AB = 12 units.

Let's consider the given square, and let's draw an altitude BD and also draw perpendiculars to BD from the three vertices A, C and D.

Let AB = x cm. Area of square = x² sq.cm.

Now, we are cutting a triangle with base x and height x, which is a right-angled triangle. Hence, area of each removed triangle = (1/2) * x * x = (x²/2) sq.cm.

Now, BD = x/√2. Area of rectangle = AB * BD = 12 * 12/√2 = 72√2 sq.cm.

Now, area of 4 triangles = (x²/2) + (x²/2) + (x²/2) + (x²/2) = 2x² sq.cm.

We know that, Area of rectangle = Area of 4 triangles + Area of square => 72√2 = 2x² + x² => 72√2 = 3x² => x² = 24√2 cm² => x = √(24 * 2) cm = √(48) cm = 4√3 * √2 cm.

Area of 4 triangles = 2x² sq.cm = 2 * 24 cm² = 48 sq.cm.

Hence, the combined area of the four removed triangles is 48 sq.units. Answer: 48.

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