plz help me find the slope​

Plz Help Me Find The Slope

Answers

Answer 1

Answer:

4/5

Step-by-step explanation:

Find 2 defined points like (-2,0)(3,4) in other to reach the point (3,4) from (-2,0) it moves 5 times front and 4 times up  

Up is Y value

Front is X value

To solve it is adding the value that you get from moving it in this case

5 front X equals to 5

4 up Y equals to 4

Then is 4/5

because the formula is Y/X


Related Questions

y - 4 = 3. what is y = ???

Answers

Hi ;-)

[tex]y-4=3\\\\y=3+4\\\\\boxed{y=7}[/tex]

Answer:  7  

.....7-4=3

Find the orthogonal decomposition of vector b = 9, 0, 0 with respect to vector a = 4, −5, 0 . (Your instructors prefer angle bracket notation < > for vectors.)

Answers

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

From the Question we are told that

Vector [tex]\vec b = <9, 0, 0>[/tex]

Vector [tex]\vec a = <4, -5, 0>[/tex]

Generally in the orthogonal decomposition of b to a we have

[tex]\vec b=\vec b"+\vec b'[/tex]

Where

[tex]\vec b"=(\frac{\vec b*\vec a}{\vec *\vec a})*\vec a[/tex]

[tex]\vec b"=(\frac{ <9, 0, 0>*<4, -5, 0>}{<4, -5, 0>*<4, -5, 0>})*<4, -5, 0>[/tex]

[tex]\vec b"=<\frac{4}{5},\frac{-8}{5},0>[/tex]

Therefore

[tex]b'= \vec b- \vec b"\\\\b'=<4,0,0>-<\frac{4}{5},\frac{-8}{5},0>[/tex]

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

in Conclusion

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

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You are trying to make a hole in one on the miniature golf green
3
3
5
7
9 X
a. Write an absolute value function that represents the path of the golf ball.
3
$ (z) = – 31x/+6
b. Write the function in part (a) as a piecewise function.
f(x) =
if x < 6
if x26

Answers

a. f(x) = |4 - 2x/3|. You could write abs(4 - 2x/3)

b. f(x) = 2x/3 if x < 6
f(x) = 8 - 2x/3 if 6 <= x <= 9

c. Mr. champing travels 20 km duo East and then 25 km due west. respect to find his position with respect to his starting point. ​

Answers

He will be 5 km west of his starting point

PLEASE HELP ME FAST I WILL GIVE 30 POINTS AND BRAINLIEST AND HEART
Questions 10-12
f(x)= 3x-13
g(x)= 2x^2-4x-5
h(x)=4^x-7

10. Find (f - g) (x)
11. Find (f - h) (x)'
12. Find (f + g) (x)

Answers

(f–g)(x)= (3x-13) – (2x²–4x–5)= –2x²+7x-8

(f–h)(x)= (3x-13) – ( 4^x –7) = 3x – 4^x–6

(f+g)(x)= (3x-13) + (2x²–4x–5) = 2x²–x – 18

I hope I helped you^_^

*Plz it due today HELP!!!!!!Justin has been collecting baseball cards for years. He bought 137 cards the first year
and 143 cards the second year. He plans on putting them in a binder that will hold seven
cards per page. How many pages must the binder have to hold Justin's collection? *Plz tell me what the math action word is I need to box it*

Answers

Answer:

40

Step-by-step explanation:

137+143=280

280/7= 40

Answer:

Division/dividing/divide

Step-by-step explanation:

If Justin has 280 baseball cards, and if each page will only hold 7 cards per page, then by dividing 280 by 7 (280÷7) would equal to 40 pages.

Which expression is equivalent to 180?​

Answers

Answer:

[tex] \sqrt{2.2.3.3.5} [/tex]

[tex]\sqrt{2.2.3.3.5}[/tex] is equivalent to [tex]\sqrt{180}[/tex]. Correct option is 1. First, we look for perfect square factors within 180. We can factor 180 as follows: [tex]\(180 = 2^2 \times 3^2 \times 5\)[/tex]

Next, we can group the perfect square factors together:

[tex]\(180 = (2 \times 3)^2 \times 5\)[/tex]

Since we are taking the square root of 180, we can rewrite it as the square root of its perfect square factors multiplied by the remaining non-perfect square factor:[tex]\(\sqrt{180} = \sqrt{(2 \times 3)^2 \times 5}\)[/tex]

The square root of a perfect square is just the value of the number itself:

[tex]\(\sqrt{180} = 2 \times 3 \times \sqrt{5}\)[/tex]

Finally, we can simplify the expression by multiplying the numbers outside the square root [tex]\(\sqrt{180} = 6\sqrt{5}\)[/tex]

So, the expression [tex]\(6\sqrt{5}\)[/tex] is equivalent to [tex]\(\sqrt{180}\)[/tex], and it represents the positive square root of 180 with any perfect square factors taken outside the square root sign.

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Geometry WS (Angle Addition Postulate) (20 pts)

Answers

Answer:

x = 17°

m∠MKL = 116°

m∠JKL = 159°

Step-by-step explanation:

JKM = 43

MKL = 8x - 20

JKL = 10x - 11

Since JKL is the whole angle, JKM + MKL = JKL

43 + 8x - 20 = 10x - 11

Add 20 to both sides:

43 + 8x = 10x + 9

Subtract 8x from both sides:

43 = 2x + 9

Subtract 9 from both sides:

34 = 2x

x = 17°

MKL = 8(17) - 20

MKL = 116°

JKL = 10(17) - 11

JKL = 159°

And to check 159 - 116 = 43

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

c) Convert 120 into quinary equivalent.​

Answers

Assuming 120 is a base 10 numeral, then

120 = 100 + 20 = 4×5² + 4×5¹

so you have

120₁₀ = 440₅

What is the period of the function y=tan (n/4(x-n/3)? 3 units 4 units 6 units 8 units

Answers

Answer:

8

Step-by-step explanation:

The function u given me is

[tex] \tan( \frac{\pi}{4} (x - \frac{\pi}{3} ) )[/tex]

The period of a function is represented by

[tex] \frac{2\pi}{ |b| } [/tex]

where b is the coefficient of the x variable.

The coefficient is pi/4 so

[tex] \frac{2\pi}{ \frac{\pi}{4} } = 8[/tex]

8 is the answer.

Answer: 4 units

Step-by-step explanation:

The function f(x)=x^2+2 is not one to one. Determine a restricted domain that makes it one to one and find the inverse function

Answers

Answer:

Hope it helped

Step-by-step explanation:

The restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

What is inverse of a function?

An inverse function or an anti function is defined as a function, which can reverse into another function.

Now the given quadtratic function is,

f(x) = x² + 2

Now vertex of the given quadratic function is (0,2)

Thus the range of the function is [2,∞)

If we restrict the domain of this function to either (-∞,0} or [0.∞), it will become one to one function.

Now the inverse function is given as,

y = x² + 2

Upon interchanging x and y, we get:

x = y² + 2

⇒ y² = x - 2

or, y = ±[tex]\sqrt{x-2}[/tex]

Hence, the inverse function would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

Thus, the restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

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Permudahkan 3/5xy × (-25x²y)

Simplify 3/5xy × (-25x²y)

A) -35x³y²
B) -35x²y²
C) -15x³y²
D) -15x²y²​

Answers

Answer:

C) -15x³y²

Step-by-step explanation:

[tex] \frac{3}{5} xy \: \times ( - 25 {x}^{2} y)[/tex]

[tex] = \frac{3}{5} \times ( - 25) \times x \times {x}^{2} \times y \times y[/tex]

[tex] = - 15 \times {x}^{3} \times {y}^{2} [/tex]

[tex] = - 15 {x}^{3} {y}^{2} (ans)[/tex]

the answer is C)!

i hope this helps! ;)

Please help me
Find this value ​

Answers

Answer:

<CAB =30°

Step-by-step explanation:

<DAB=80°

<DAC=50°

<DAB=<DAC+<CAB

<CAB=<DAB-<DAC

=80°-50°

=30°

6x+6=-5+3x+17

I need help

Answers

Answer:

Get all the terms with x on the left. Get all the terms without x on the right. Simplify by adding and subtracting the terms without x and adding and subtracting the terms with x. Finally divide to get the value of x.

Step-by-step explanation:

6x+6 =- 5+3x+17

6x+6 -6 =- 5+3x+17 -6

6x = 5+3x+11

6x = 3x + 16

6x - 3x = 3x + 16 -3x

3x = 16

3x / 3 = 16 / 3

x = 15/3 + 1/3

x = 5 1/3

x = 5.33333...

multiply : (5x+3a) (5x-3a)​

Answers

(a+b)(a-b)=a²-b²

(5x+3a)(5x-3a)
=(5x)²-(3a)²
=25x²-9a²

Hope my answer helped u :)

0.6m=____mm . answer the question

Answers

Answer:

600

Step-by-step explanation:

since 1m=1000mm

It’s 600mm
If you need an explanation how ill explain in the comments

find the possible formula for the nth term of sequence 7 11 15 9​

Answers

Answer:

7, 11, 15, 19, 23, ... To get the terms in the original sequence, we need to add on 3 to each of the terms in the 4n sequence. Hence, the general formula for the nth term of the original sequence is 4n + 3.

hope this helped!!!

to complete a continuing pattern,identify pattern rule.true or false?​

Answers

Answer:

true

Step-by-step explanation:

slope 1/6 , x-intercept at -1

Answers

Answer:

[tex]{ \underline{ \sf{6y = x + 1 }}}[/tex]

Step-by-step explanation:

[tex]y = mx + c[/tex]

m is slope

c is y intercept.

at x-intercept, y = 0

[tex]0 =( \frac{1}{6} \times - 1 )+ c \\ \\ c = \frac{1}{6} [/tex]

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the given line is 6y=x+1.

What is the equation of a line?

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

Given that the slope of the equation of the line is 1/6, while the x-intercept is at -1. Therefore, if we substitute the coordinate of the intercept and the slope in the equation in the general equation of the line. We will see,

y = mx + c

0 = (1/6)(-1) + c

0 = -1/6 + c

c = 1/6

Now, the equation of the line can be written as,

y = (1/6)x + (1/6)

y = (x/6) + (1/6)

y = (x+1)/6

6y = x + 1

Hence, the equation of the given line is 6y=x+1.

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can someone please give me an example of a position and motion of objects in space​

Answers

Answer:

position of objects in space

for example: up, down, in front, behind, between, left, right.

motion of objects in space

for example: Stars, planets, moons.

Which of the following represents the relationship
between h and C ?
A) C = 5h
3
B) C = - +5
4
C= +5
C) C = 3h + 5
D) h = 3C

Answers

Answer:

I think its c I hope I'm right

a shea cd player costs $80 last year and $112 this year. what was the percent of increase in its price

Answers

Answer:

40% increase

Step-by-step explanation:

c = final value - initial value

     ------------------------------------

                initial value

112 - 80 = 32

32 / 80 = 0.4

0.4 = 40%

Guys help me in this question pls

Answers

Answer:

40+x+5 = 3x +15

2x= 30

x=15

Their present ages are 15 and 55

Factor out the greatest common factor. If the greatest common factor is 1, just retype the
polynomial.
9d^ 2 - 27d^ 5 + 45d^ 3

Answers

Answer:

Below.

Step-by-step explanation:

The GCF of 9 , 27 and 45 = 9.

GCF of the d terms is d^2.

So the GCF of the whole expression is 9d^2.

Factors are 9d^2( 1 - 3d^3 + 5d)

[tex]\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }[/tex]

Answers

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

the area of a children’s square playground is 50m squared, what is the exact length of the playground

Answers

Area=50m^2

Let side be a

[tex]\\ \rm\Rrightarrow Area=a^2[/tex]

[tex]\\ \rm\Rrightarrow a^2=50[/tex]

[tex]\\ \rm\Rrightarrow a=\sqrt{50}[/tex]

[tex]\\ \rm\Rrightarrow a=7.1m[/tex]

Answer:

[tex]\displaystyle 5\sqrt{2}\:m.[/tex]

Step-by-step explanation:

Sinse squares are equal in length all around, this formula applies:

[tex]\displaystyle s^2 = A → \sqrt{50} = \sqrt{s^2} \\ \\ 5\sqrt{2} = s[/tex]

Therefore, the length of the playground is [tex]\displaystyle 5\sqrt{2}[/tex] metres.

* Just in case you could not figure out how to find the square root of fifty, here is how using perfect squares:

[tex]\displaystyle \sqrt{50} → \sqrt{2 \times 25} \\ \\ 5\sqrt{2}[/tex]

Sinse we are dealing with measurements, we only want the NON-NEGATIVE root.

I am joyous to assist you at any time.

Subtract.
5/23 - 4/23
(Type an integer or fraction.)

Answers

Answer:

1/23

Step-by-step explanation:

5/23 - 4/23 would be 1/23. When the denominators of the fractions are the same, you can just subtract the numerators.

edward has $48 to spend at the grocery store. six cases of soda he has $21 left. how much does one case of soda cost? brainly

Answers

Answer: $4.50

Step-by-step explanation:

48-21=27

27 divided by 6= 4.50

Therefore each case costs 4.50

Answer:

$4.50

Step-by-step explanation:

48 - 21

27

divide by 6

4.50

In x² , what is the 2 called?

a radical

a subscript

an exponent

an imaginary number

none of these

Answers

Answer:

an exponent

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

Answer:

an exponent

Step-by-step explanation:

hope it helps:)

Complete the set of ordered pairs for the relation.

{(x, y): y = 2 |x + 1| and x {-2, -1, 0, 1, 2}}.

(-2, __)

-2
-3
2

Answers

Answer:

Step-by-step explanation:

[tex]U=\{(x,y)\ \zeta\ y=|x+1| \ and\ x \in \{-2,-1,0,1,2\}\ \}\\\\\begin{array}{|c|c|}x&y\\---&---\\-2&2\\-1&0\\0&2\\1 & 4\\2&6\\---&---\\\end{array}\\\\U=\{(-2,2),(-1,0),(0,2),(1,4),(2,6)\}\\[/tex]

Answer:

2 / (-2,2)

Step-by-step explanation:

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