Answer:
3rd image, 2nd image, 1st image, 4th image
Explanation:
Not an easy question, tricky one
Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE). U = kQq/r
EPE is positive in this case due to unlike charges.
Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)
Hence. zoom in on the magnitude first.
3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.
Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.
For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.
Pls help :(( I need help!! Its physics! motion and forces!
Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.
The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.
Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.
I need help i don’t want to go to summer school
what change do you need to make when comparing objects going upward against gravity versus downward with gravity?
A. Different amount of time in motion
B. Different length of displacement
C. Different sign + or - on the acceleration
D. Different changes to velocity
If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).
Therefore, your answer should be C. Different sign + or - on the acceleration.
I hope this helps!
PLEASE HURRY I GIVE BRAINLIST and extra points !!!!!!
1 What happens to the energy from the light when the material changes?
2 What happens to the energy from the light when the material does not change?
Answer:
2 stays the same 1 it will go bad or go good depends on which material you use
Two protons are held a distance d apart. The electrostatic force and the gravitational force that one proton exerts on the other are Fe and Fg, respectively. Which of the following correctly compares the magnitude and direction of these forces?
Fe > Fg, opposite direction
a. Fe > Fg, same direction
b. Fe < Fg opposite direction
c. Fe < Fg same direction
Answer:
Explanation:
charge on each proton = 1.6 x 10⁻¹⁹ C
mass of proton = 1.67 x 10⁻²⁷ kg
Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²
= 23.04 x 10⁻²⁹ / d²
Gravitational force of attraction = G Mm / d²
M = m = 1.67 x 10⁻²⁷ kg
Gravitational force of attraction Fg = 6.67 x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²
= 18.60 x 10⁻⁻⁶⁵ / d²
So Fg is far less than Fe and former is attractive , later is repulsive .
Fe > Fg, opposite direction , is the answer .
Q12. How big is a Moon? How big is a Mars? What is therefore the weight of the person from Q11 on the Moon? What is the person's weight on Mars?
Answer:
The moon is 1,079.4 mi.
Mars is 2,106.1 mi
Multiply your weight by the moon's gravity relative to earth's, which is 0.165. Solve the equation. In the example, you would obtain the product 22.28 lbs. So a person weighing 135 pounds on Earth would weigh just over 22 pounds on the moon
Being that Mars has a gravitational force of 3.711m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on mars. So an object or person on Mars would weigh 37.83% its weight on earth.
Explanation:
~Hope this helps
Which increases the rate of soil formation?
A. mixed layers
B. more precipitation
C. cooler temperatures
D. very hard parent material
Answer:
a
Explanation:
Answer: b. more precipitation
Explanation:
Q.2. Assertion: When distance between two bodies is doubled and also mass of each body is doubled. then the gravitational force between them remains the same. Reason: According to Newton's law of gravitation, force is directly proportional to the product of mass of the two bodies and inversely proportional to square of the distance between them. ent to
Answer:
True:
F1 = G M1 M2 / R^2
F2 = G (2 M1) * (2 M2) / (2 R)^2
F1 = F2
the valu
In an experiment the value of thickness of a
wire was found to be 1.54, 1.53, 1.44, 1.54, 1.56
and 1.45 in successive measurements. Then the
percentage error is
(1) 28%
(2).09 %
(3) 9%
(4) 2.8%
Answer:
[tex]\% Error = 2.6\%[/tex]
Explanation:
Given
[tex]x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45[/tex]
Required
Determine the percentage error
First, we calculate the mean
[tex]\bar x = \frac{\sum x}{n}[/tex]
This gives:
[tex]\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}[/tex]
[tex]\bar x = \frac{9.06}{6}[/tex]
[tex]\bar x = 1.51[/tex]
Next, calculate the mean absolute error (E)
[tex]|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}[/tex]
This gives:
[tex]|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}[/tex]
[tex]|E| = \sqrt{\frac{1}{6}*0.0132}[/tex]
[tex]|E| = \sqrt{0.0022}[/tex]
[tex]|E| = 0.04[/tex]
Next, calculate the relative error (R)
[tex]R = \frac{|E|}{\bar x}[/tex]
[tex]R = \frac{0.04}{1.51}[/tex]
[tex]R = 0.026[/tex]
Lastly, the percentage error is calculated as:
[tex]\% Error = R * 100\%[/tex]
[tex]\% Error = 0.026 * 100\%[/tex]
[tex]\% Error = 2.6\%[/tex]
An electron accelerates through a 12.5 V potential difference, starting from rest, and then collides with a hydrogen atom, exciting the atom to the highest energy level allowed. List all the possible quantum-jump transitions by which the excited atom could emit a photon and the wavelength (in nm) of each.
Answer:
Explanation:
An electron accelerates through a 12.5 V potential difference, starting from rest, so it will acquire kinetic energy of 12.5 eV .
In hydrogen atom energy of n th orbit in terms of eV is given as follows
En = -13.6 / n² eV
Total energy of 1 st orbit E₁ = - 13.6 eV
Total energy of 2 st orbit E₂ = - 13.6 eV / 2² = - 3.4 eV
Total energy of 3 st orbit E₃ = - 13.6 eV / 3² = - 1.5 eV
Total energy of 4 st orbit E₄ = - 13.6 eV / 4² = - 0.85 eV
E₄ - E₁ = 13.6 - 0.85 = 12.75 eV
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV .
The electron has energy of 12,5 eV so it can excite electron from E₁ to E₃ . .
Jump possible = E₃ to E₂ , E₂ to E₁ and E₃ to E₁
Energy of E₃ to E₂ = 3.4 - 1.5 eV = 1.9 eV
wavelength = 1237 / 1.9 nm = 651 nm
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
wavelength = 1237 / 12.10 nm = 102.23 nm
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV
wavelength = 1237 / 10.2 nm = 121.27 nm
wavelength of photon possible are 651 nm , 121.27 nm , 102.23 nm .
How much force is needed to accelerate a 100 kilogram car 5 meters per second?
The force needed to accelerate the mass of 100 kg is 500 N.
What is force?Force is the product of mass and acceleration. The S.I unit of force is Newton (N).
To calculate the amount of force needed to accelerate the mass of 100 kg, we use the formula below.
Formula:
F = ma.................. Equation 1Where:
F = Forcem = Mass a = AccelerationFrom the question,
Given:
m = 100 kga = 5 m/s²Substitute these values into equation 1
F = 100×5F = 500 NHence, the force is 500 N.
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A 62.3 kg base runner begins his slide into second base while moving at a speed of 4.49 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s². What is the magnitude of the mechanical energy lost due to friction acting on the run- ner?
Answer:
628 J
Explanation:
ME = PE + KE
PE = mgh = 0, because h = 0
KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J
KEf (final KE) = 0, because v-final = 0
All the initial ME, which is all KE, converts to thermal E due to friction
30. How do you make a conclusion?
when a resistor is connected to a battery, current flows through the resistor. If the voltage of the battery is doubled, the current will be?
Resistors limits the current/amps but keep the voltage the same.
What happens if you connect the resistor to the battery?You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.
Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.
So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,
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which of the following changes will increase the period of an oscillating spring mass system?
a. an increase in the mass on the spring.
b. an increase in the initial displacement of the spring. c. an increase in the spring constant.
d. more than one of the above.
e. none of the above.
explain your answer.
NO LINKS.
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.
Someone please help me with this question
How are mass and weight different?
Answer:
The mass is the amount of matter in something. Weight is mass times gravitational field strength and so also includes gravity. Mass is measured in grams (g) and weight is measured in Newtons (N)
While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run, 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s² Answer in units of J.- answer :7100J part 2 of 2 What is his final velocity? Answer in units of m/s.
Answer:
12.3 m/s
Explanation:
To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:
7100 = 1/2 (63.2 kg) v^2
Therefore, v^2 = 7100/31.6
v = √(7100/31.6)
v = 12.3 m/s
Ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A. Is the momentum conserved in the collision? Why?
The mass of ball B and the final velocity of ball A can complement the conservation of linear momentum. The answer is yes.
What is Momentum ?Momentum can simply be defined as the product of mass and velocity. It is a vector quantity.
Given that ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A.
In an elastic head-on collision, momentum is mostly always conserved. That is, the sum of the momentum before collision will be equal to the sum of the momentum after collision.
Mathematically, MaUa = MaVa + MbVb
Is the momentum conserved in the collision?
The answer is yes!
Why?
Because we need to consider the mass of the ball B and the final velocity of the ball A.
Therefore, In consideration of the mass of the ball B and the final velocity of the ball A, we can say that the momentum is conserved.
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Tritium, the 3H atom, consists of a nucleus of one proton and two neutrons with a single electron. It is unstable and decays via beta emission to singly ionized helium, 3 He , consisting of a nucleus of two protons and one neutron with a single electron. This decay takes place instantaneously and thus there occurs a sudden doubling of the Coulomb interaction between the atomic electron and the nucleus. If the tritium atom is in its ground state when it decays, determine the probability that the 3He atom is in its ground state immediately after the decay.
Required:
Determine the probability that the 3H^+ atom is in its ground state immediately after decay.
Answer: hello your question is poorly written attached below is the complete question
P( ³₂He₊ ) at ground state = 1
Explanation:
Determine the probability that the 3He atom is in its ground state after decay
From the attached solution the coulomb interaction of ( ³₂He) is double that of H³ . given that coulomb interaction is attractive ( -ve ) this will make the product to become more stable hence the product ( ³₂He₊ ) will be gotten at the ground state
i.e. P( ³₂He₊ ) at ground state = 1
attached below is a detailed solution
A ruler partially hangs over the end of a bench. It is supported at one end and made to vibrate at the other end in an attempt to display simple harmonic motion. If the ruler has an amplitude of 0.22 cm and makes twelve complete vibrations in 0.12 seconds, how far does the end of the ruler travel in 4.7 seconds?
During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.45m/s2 . When it is 230m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity (air resistance can be ignored).
1- How high is the rocket when the canister hits the launch pad, assuming that the rocket does not change its acceleration?
2- What total distance did the canister travel between its release and its crash onto the launch pad?
Answer:
Explanation:
Time elapsed to reach the height of 230 m be t
s = ut + 1/2 at²
230 = .5 x 3.45 t²
t = 11.55 s
velocity at height of 230 m
v = u + at
= 0 + 3.45 x 11.55 = 39.84 m/s
This velocity will be attained by canister .
time to reach zero velocity at the top position t
v = u - gt
0 = 39.84 - 9.8 t
t = 4.06 s
height travelled by canister during this 4.06 s
v² = u² - 2gH
0 = 39.84² - 2 X 9.8 H
H = 80.98 M
Total height attained by canister = 80.98 + 230 = 310.98 m
Time of fall by canister t
s = 1/2 gt²
310.98 = .5 x 9.8 t²
t = 7.97 s
Total time taken by canister to reach the ground after its release from rocket
= 4.06 + 7.97 = 12.03 s
Distance travelled by rocket in 12.03 s
s = ut + 1/2 a t²
= 39.84 x 12.03 + .5 x 3.45 x 12.03²
= 479.27 + 249.64
= 728.91 m
height of rocket required = 230 + 728.91
= 958.91 m
2 )
Distance travelled by canister between its release and fall on the ground
= 80.98 + 80.98 + 230
= 391.96 m.
A sign which weighs 38.3 N is supported symmetrically by two cables which make an angle of 1.0 degrees with the horziontal. A single cable will pull upward on the sign with a force of how may Newtons?
The single cable will pull upward on the sign with a force of 38.3 N.
What is single cable?Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.
This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.
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Can anyone help with this?
Answer:
Explanation:
Add a horizontal line. An object that is not moving has no change in distance with respect to time.
It takes one year for ______.
a.earth to circle the sun one time
b.earth to rotate on its axis one time
c. The sun to circle earth one time
d.the sun to rotate on its axis one time
Answer: A. Earth to circle the sun one time.
What is another way to describe the vector 100 m/s down
Answer:
Describe how one-dimensional vector quantities are added or subtracted.
Critical angle of glass is 42 .what does it mean?
Answer:
i think..its fraction that its have multiple fractions on it..if you minus the 397 000-355 it should be 381+ so i say if you get the 5 multiply it by 9!! so you will get it!
Explanation:
HOPE IT HELPS!!
PLS THIS IS DUE IN 2 MINUTES
Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?
Answer:
The toy car
Explanation:
the real car is parked so yeah but maybe in some way technically the real car has more "momentum"
both of yall are right and wrong its b and d
Answer:
Yup
Explanation:
Hi, can anyone help me with this question I have?
Assume a tornado is in the vicinity of your neighborhood. Which would
be the most useful information to determine your safety - speed or
velocity? Explain your answer.
Answer:
speed
Explanation:
you need to move fast so the tornado can't reach you
Which model below describes the processes of Gamma radiation?
A
B.
C.
D.
Answer:
C
Explanation: