Answer:
B. Arc blast
Explanation:
Arc blast are as a result of rapid injection of electrical energy into an arc. These shock waves and arc blast pressure wave at low level can lead to damage of eardrums at lower levels and cardiac arrest at high levels.
Strong magnetic fields created by high currents (> 100 kA) can result to equipment destruction. These arc blast hazards are mostly found in high-energy power circuits and large capacitor banks.
A beaver build a dam behind the dam water forms a pond what effects could this have on the organisms living in the ecosystem
Answer:
The analysis for the particular situation is described elsewhere here.
Explanation:
Whenever a beaver constructs just one dam, this same dam ambushes or targets the water or liquid underneath to construct a pond. Aquatic plants but also organisms, including lily pads, spring up throughout the body of water, as well as fallen leaves or harmful chemicals subsequently sinks to the ground to break down, becoming such a bacterial festive substance.You wish to cool a 1.83 kg block of tin initially at 88.0°C to a temperature of 57.0°C by placing it in a container of kerosene initially at 24.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m3 and 2,010 J/(kg · °C), and the specific heat of tin is 218 J/(kg · °C).
Answer:
0.273 liters are needed to accomplish this task without boiling.
Explanation:
The minimum boiling point of kerosene is [tex]150\,^{\circ}C[/tex]. According to this question, we need to determine the minimum volume of liquid such that heat received is entirely sensible, that is, with no phase change.
If we consider a steady state process and that energy interactions with surrounding are negligible, then we get the following formula by the Principle of Energy Conservation:
[tex]\rho_{k}\cdot V_{k}\cdot c_{k}\cdot (T-T_{k,o}) = m_{t}\cdot c_{t}\cdot (T_{t,o}-T)[/tex] (1)
Where:
[tex]\rho_{k}[/tex] - Density of kerosene, measured in kilograms per cubic meter.
[tex]V_{k}[/tex] - Volume of kerosene, measured in cubic meters.
[tex]c_{k}[/tex], [tex]c_{t}[/tex] - Specific heats of the kerosene and tin, measured in joule per kilogram-Celsius.
[tex]T_{k,o}[/tex], [tex]T_{t,o}[/tex] - Initial temperatures of kerosene and tin, measured in degrees Celsius.
[tex]T[/tex] - Final temperatures of the kerosene-tin system, measured in degrees Celsius.
Please notice that the block of tin is cooled at the expense of the temperature of the kerosene until thermal equilibrium is reached.
From (1), we clear the volume of kerosene:
[tex]V_{k} = \frac{m_{t}\cdot c_{t}\cdot (T_{t,o}-T)}{\rho_{k}\cdot c_{k}\cdot (T-T_{k,o})}[/tex]
If we know that [tex]m_{t} = 1.83\,kg[/tex], [tex]c_{t} = 218\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{t,o} = 88\,^{\circ}C[/tex], [tex]T_{k,o} = 24.0\,^{\circ}C[/tex], [tex]T = 57\,^{\circ}C[/tex], [tex]c_{k} = 2010\,\frac{J}{kg\cdot ^{\circ}C}[/tex] and [tex]\rho_{k} = 820\,\frac{kg}{m^{3}}[/tex], then the volume of the liquid needed to accomplish this task without boiling is:
[tex]V_{k} = \frac{(1.83\,kg)\cdot \left(218\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (88\,^{\circ}C-57\,^{\circ}C)}{\left(820\,\frac{kg}{m^{3}} \right)\cdot \left(2010\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (57\,^{\circ}C-24\,^{\circ}C)}[/tex]
[tex]V_{k} = 2.273\times 10^{-4}\,m^{3}[/tex]
[tex]V_{k} = 0.273\,L[/tex]
0.273 liters are needed to accomplish this task without boiling.
how to draw a
electronics configuration
Answer:do you know how to draw a electronics configuration
Explanation:
1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are
separated by 0.30 m. What is the force between the two charges?
Answer:
The Force between the two charges is an attractive force of 16,000N
Explanation:
Expression for the electric force between the two charges is given by
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = - 2.0x10^-4C
q2 = + 8.0x10^-4C
r = 0.30 m
Substitute the given values in the above expression -
One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)
The attraction force is:
F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2
F= 16,000N
The force between the two charges will be 16,000 N.It is the force exerted by one charge on another charge.
What is electric force?The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.
The given data in the problem is;
q₁ is the megnitude of charge 1= - 2.0x10⁻⁴ C
q₂ is the megnitude of charge 2 = + 8.0x10⁻⁴ C
k is the propotionallity constant = 9 x 10⁹ Nm² / C²
r is the seperated distance = 0.30 m
F is the electric force=?
The electric force is found as;
[tex]\rm F = \frac{K q_14q_2}{r^2} \\\\ \rm F = \frac{9 \times 10^9 \times 2.0 \times 10^{-4}}{(0.30)^2} \\\\ \rm F = 16,000N[/tex]
Hence the force between the two charges will be 16,000 N.
To learn more about the electric force refer to the link;
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Calculate the pressure in pascals if a 200N force is applied to an area of 0.5m2.
Answer:
400Pa
Explanation:
use pressure = force/area
[tex]\\ \rm\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \rm\longmapsto Force=Pressure(Area)[/tex]
[tex]\\ \rm\longmapsto Force=200(0.5)[/tex]
[tex]\\ \rm\longmapsto Force=100N[/tex]
In a refrigerator, energy is used to make thermal energy flow from the inside of the refrigerator to the outside. Use a law of thermodynamics to explain why thermal energy will not move in this direction naturally.
Explanation:
According to the Second Law of Thermodynamics, heat will always flow spontaneously from hot to cold, and never the other way around. A refrigerator causes heat to flow from cold to hot by inputting work, which cools the space inside the refrigerator. thermal energy is transferred from the cool air inside the refrigerator to the warmer air in the kitchen. ... As a liquid, the refrigerant absorbs thermal energy from the cool air inside the refrigerator and changes to a gas.
The water-balloon weighs 4.9 N. gravitational field strength = 9.8 N/kg Calculate the mass of the water-balloon
Answer:
0.5kg
Explanation:
Mass = Weight / Gravitational field strength
Mass = 4.9 / 9.8
Mass = 0.5
What is the efficiency of a machine that lifts a load of 12.0 kg a vertical distance of 5.00
m in 30.0 s after being supplied with 70.0 W of power? Explain the steps you take to get the answer.
Answer:
Efficency = 28%
Explanation:
We have the load has a weight of:
[tex]w =m*g\\w =12*9.81\\w = 117.72 [N][/tex]
Work in physics is defined as the product of force (weight) by distance.
[tex]W=w*d[/tex]
where:
W = work [J]
w = weight = 117.72[N]
d = distance = 5 [m]
[tex]W=117.72*5\\W=588.6[J][/tex]
Now power is defined as the relationship of work at a certain time.
[tex]P=W/t\\[/tex]
where:
P = power [W]
W = work = 588.6[J]
t = time = 30[s]
[tex]P=588.6/30\\P=19.62[W][/tex]
Now the efficiency of a machine is defined as the power output over the power input to the machine. The power input should always be greater than the power output.
[tex]efficency = \frac{Power_{out}}{Power_{in}}\\Efficeny = \frac{19.62}{70} \\Efficency = 0.28\\Efficency = 28%[/tex]
box
Complete the concept map on ATP production. Choose your answer from the
Key Words
Electron Transport Chain
Krebs Cycle
Pyruvate
Glycolysis
Glucose
ADP
C
ATP
Acetyl COA
ADP
IC
ATP
CO2
High energy electrons and H*
ADP
IC
ATP
02
H2O
Answer:
Glycolysis
Pyruvate
Krebs Cycle
Electron Transport Chain
Explanation:
The concept map on ATP production shows the process of cellular respiration in living organisms.
Cellular respiration begins with glucose which is broken down in the process of glycolysis that occur in cytoplasm and gives 2 ATP. Glycolysis gives pyruvate as end product that enter in the process of Krebs Cycle or citric acid cycle as a aerobic process, that occur in mitochondria and produces 2 ATP. This energy is then used in Electron Transport Chain to pump high energy electrons and H+ that produces 36 ATP.
Dos personas aplican sendas fuerzas de 50N sobre una mesa, en direcciones horizontales perpendiculares entre sí. ¿Cuanto vale el módulo e la resultante de estas dos fuerzas? Ilustra tu respuesta con un dibujo.
Answer:
|Fr| = 50*√2 [N]
Explanation: (See Annex )
En el diagrama de cuerpo libre ( mostrado en el anexo) se ve que, al ser las dos fuerzas iguales (50 N) el paralelogramo formado para encontrar la resultante de las fuerzas (Fr) es un cuadrado, y la diagonal de ese cuadrado ( que es al mismo tiempo la hipotenusa del triangulo recto OPA ) es igual a:
Hipotenusa = |Fr| = √ (50)² + (50)²
|Fr| = √2* (50)²
|Fr| = 50*√2 [N]
A crate is pushed up a ramp at an angle of 30 degree by a 300 N force. How much power is spent in raising the crate to a height of 0.98 m 15s ? Assume that the coefficient of friction between the surfaces of the crate and ramp is 0.30 and the crate moves up the ramp at a constant speed.
Answer:
You use a force of 150 N to push a 30 kg crate across the floor for a distance of 10 m. If the crate is moving at a speed of 5 m/s…
A car accident my rolls off a cliff as it leaves the cliff it has a horizontal velocity of 13 ms it hiys the ground 60 m from the shoreline calculate the height of the cliff
Answer:
104.59 m
Explanation:
The following data were obtained from the question:
Horizontal velocity (u) = 13 ms¯¹
Horizontal distance (s) = 60 m
Height (h) =?
Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:
Horizontal velocity (u) = 13 ms¯¹
Horizontal distance (s) = 60 m
Time (t) =?
s = ut
60 = 13 × t
Divide both side by 13
t = 60 / 13
t = 4.62 s
Finally, we shall determine the height cliff. This can be obtained as follow:
Time (t) = 4.62 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
h = ½gt²
h = ½ × 9.8 × 4.62²
h = 4.9 × 21.3444
h = 104.59 m
Thus, the height of the cliff is 104.59 m
Kyle is flying a helicopter at 125 m/s on a heading of 325 o . If a wind is blowing at 25 m/s toward a direction of 240.0 o , what is the craft's resultant velocity?
Answer:
The resultant velocity of the helicopter is [tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex].
Explanation:
Physically speaking, the resulting velocity of the helicopter ([tex]\vec v_{H}[/tex]), measured in meters per second, is equal to the absolute velocity of the wind ([tex]\vec v_{W}[/tex]), measured in meters per second, plus the velocity of the helicopter relative to wind ([tex]\vec v_{H/W}[/tex]), also call velocity at still air, measured in meters per second. That is:
[tex]\vec v_{H} = \vec v_{W}+\vec v_{H/W}[/tex] (1)
In addition, vectors in rectangular form are defined by the following expression:
[tex]\vec v = \|\vec v\| \cdot (\cos \alpha, \sin \alpha)[/tex] (2)
Where:
[tex]\|\vec v\|[/tex] - Magnitude, measured in meters per second.
[tex]\alpha[/tex] - Direction angle, measured in sexagesimal degrees.
Then, (1) is expanded by applying (2):
[tex]\vec v_{H} = \|\vec v_{W}\| \cdot (\cos \alpha_{W},\sin \alpha_{W}) +\|\vec v_{H/W}\| \cdot (\cos \alpha_{H/W},\sin \alpha_{H/W})[/tex] (3)
[tex]\vec v_{H} = \left(\|\vec v_{W}\|\cdot \cos \alpha_{W}+\|\vec v_{H/W}\|\cdot \cos \alpha_{H/W}, \|\vec v_{W}\|\cdot \sin \alpha_{W}+\|\vec v_{H/W}\|\cdot \sin \alpha_{H/W} \right)[/tex]
If we know that [tex]\|\vec v_{W}\| = 25\,\frac{m}{s}[/tex], [tex]\|\vec v_{H/W}\| = 125\,\frac{m}{s}[/tex], [tex]\alpha_{W} = 240^{\circ}[/tex] and [tex]\alpha_{H/W} = 325^{\circ}[/tex], then the resulting velocity of the helicopter is:
[tex]\vec v_{H} = \left(\left(25\,\frac{m}{s} \right)\cdot \cos 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \cos 325^{\circ}, \left(25\,\frac{m}{s} \right)\cdot \sin 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \sin 325^{\circ}\right)[/tex][tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex]
The resultant velocity of the helicopter is [tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex].
B4-WWT03: OBJECT CHANGING VELOCITY-WORK
A 2-kg object accelerates as a net force acts on it.
During the 5 seconds this force acts, the object
changes its velocity from 3 m/s east to 7 m/s west.
A student states:
"The initial kinetic energy of the object was 9 Joules, and the final kinetic energy was 49 Joules. Thus the change in
kinetic energy of this object during these 5 seconds was 40 J, and thus the work done on this object by the net force
during this period was also 40 J.
What if anything, is wrong with this statement? If something is wrong, identify it and explain how to correct
it. If this statement is correct, explain why.
Answer:
Part A;
he mass of the object, m = 2 kg
The initial speed of the object, u = 3 m/s east
The final speed of the object, v = 7 m/s west
The initial kinetic energy of the object = 1/2 × m × u² = 1/2 × 2 × 3² = 9 Joules
The final kinetic energy of the object = 1/2 × m × v² = 1/2 × 2 × 7² = 49 Joules
Based on the change in the momentum produced by the force which changes the direction of the object, we add the two energy quantities to get the total change in energy as follows;
The change in kinetic energy = 9 J + 49 J = 58 J
The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period
Part B;
The kinetic energy, K. E. = 1/2 × m × v²
The kinetic energy of the car A = 1/2 × 1000 × 6² = 18,000 J
The kinetic energy of the car B = 1/2 × 1600 × 8² = 51,200 J
The kinetic energy of the car C = 1/2 × 1200 × 8² = 38,400 J
The kinetic energy of the car D = 1/2 × 1600 × 4² = 12,800 J
Given that work required = Force × Distance, and the distance, is constant, we have;
The force required is directly proportional to the energy kinetic energy of the car that is to be stopped
Therefore, we have;
B = 1, C = 2, A = 3, and D = 4
The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d
∴ W ∝ F.
Explanation:
Part A;
The mass of the object, m = 2 kg
The initial velocity of the object, u = 3 m/s east
The final velocity of the object, v = 7 m/s west
The initial kinetic energy of the object = [tex]1/2 * m * u^2 = 1/2 * 2 *3^2 = 9 \text{ Joules}[/tex]
The final kinetic energy of the object = [tex]1/2 * m * v^2 = 1/2 * 2 * 7^2 = 49 \text{ Joules}[/tex]
Based on the change in the momentum produced by the force which changes the direction of the object, we add the two energy quantities to get the total change in energy as follows;
The change in kinetic energy = [tex]9 J + 49 J = 58 J[/tex]
The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period.
Part B;
The kinetic energy, K. E. = 1/2 × m × v²
The kinetic energy of the car A = [tex]1/2 * 1000 *6^2 = 18,000 J[/tex]
The kinetic energy of the car B = [tex]1/2 * 1600 * 8^2 = 51,200 J[/tex]
The kinetic energy of the car C = [tex]1/2 * 1200 * 8^2 = 38,400 J[/tex]
The kinetic energy of the car D =[tex]1/2 * 1600 * 4^2 = 12,800 J[/tex]
Given that work required = Force × Distance, and the distance, is constant, we have;
The force required is directly proportional to the energy kinetic energy of the car that is to be stopped
Therefore, we have;
B = 1, C = 2, A = 3, and D = 4
The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d.
Learn more:
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Which statement best describes the adiabatic process?
Answer:
diaetes
Explanation:
Answer:
A: In an adiabatic process, no heat enters or leaves the system
A car travelled a distance of 5km due East, then 5km due North and then 5km due East. Calculate the total distance and displacement travelled by car also sketch the path.
Answer:
Total displacement
The displacement of the car is 10 kilometers due East and 5 kilometers due North.
The magnitude of the displacement of the car is approximately 11.180 kilometers.
Total distance
The total distance of the car is 15 kilometers.
Explanation:
According to the statement the car shows the following path, whose displacement is represented by the following formula: (All distances are measured in kilometers)
[tex]\vec r = \vec r_{1} + \vec r_{2}+\vec r_{3}[/tex] (1)
Where:
[tex]\vec r_{1}[/tex] - First displacement to the east.
[tex]\vec r_{2}[/tex] - Displacement to the north.
[tex]\vec r_{3}[/tex] - Second displacement to the east.
If we know that [tex]\vec r_{1} = (5,0)[/tex], [tex]r_{2} = (0,5)[/tex] and [tex]r_{3} = (5,0)[/tex], then the displacement of the car is:
[tex]\vec r = (10, 5)[/tex]
The displacement of the car is 10 kilometers due East and 5 kilometers due North.
The magnitude of the displacement represents the distance of the car from point of departure in a straight line and is determined by the Pythagorean Theorem:
[tex]\|\vec r\| = \sqrt{10^{2}+5^{2}}[/tex]
[tex]\|\vec r\| \approx 11.180\,km[/tex]
The magnitude of the displacement of the car is approximately 11.180 kilometers.
The distance travelled of the car is the sum of magnitudes of the displacement of the car, each of them are calculated by Pyhtagorean Theorem:
[tex]d = \|\vec r_{1}\| + \|\vec r_{2}\| + \|\vec r_{3}\|[/tex] (2)
[tex]d = 5\,km + 5\,km + 5\,km[/tex]
[tex]d = 15\,km[/tex]
The total distance of the car is 15 kilometers.
A pitcher threw a baseball straight up at 35.8 meters per second. What was the ball's velocity after 2.50 seconds? (Note that, although the baseball is still climbing, gravity is accelerating it downward.)
Answer:
The velocity after 2.5 seconds is 11.3 m/s
Explanation:
Given;
u = 35.8 m/s
t = 2.50s
g = 9.8 m/s^2
Mathematically;
V = U-gt
Substituting these values;
V = 35.8-2.5(9.8)
V = 35.8-24.5
V = 11.3 m/s
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 1.200 kg of the substance increases in temperature from 10.0°C to 70.0°C?
Answer:
0.035 J/g°C
Explanation:
From the question given above, the following data were obtained:
Heat (Q) absorbed = 2500 J
Mass (M) = 1.2 Kg
Initial Temperature (T₁) = 10 °C
Final Temperature (T₂) = 70 °C
Specific heat capacity (C) =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial Temperature (T₁) = 10 °C
Final Temperature (T₂) = 70 °C
Change in temperature (ΔT) =
ΔT = T₂ – T₁
ΔT = 70 – 10
ΔT = 60 °C
Thus, the change in the temperature of the substance is 60 °C
Next, we shall convert 1.2 Kg to grams (g). This can be obtained as follow:
1 Kg = 1000 g
Therefore,
1.2 Kg = 1.2 Kg × 1000 g / 1 Kg
1.2 Kg = 1200 g
Thus, 1.2 Kg is equivalent to 1200 g.
Finally, we shall determine the specific heat capacity of substance. This can be obtained as follow:
Heat (Q) absorbed = 2500 J
Mass (M) = 1200 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) =?
Q = MCΔT
2500 = 1200 × C × 60
2500 = 72000 × C
Divide both side by 72000
C = 2500 / 72000
C = 0.035 J/g°C
Therefore, the specific heat capacity of the substance is 0.035 J/g°C
A) About 9.1
B) about 14.1
C) about 17.2
D) about 18.1
Please help me
D. 18.1
K^+H^+G^=180° (sum of int angles of triangle)
K^+30+62=180
K^=88°
GH/sinK=KG/sinH
X/sin88=16/sin62
X*sin62/sin62=16*sin88/sin62
X=18.1
Review the vocabulary associated with nuclear and wave therapies
Answer:
Sonography- using sound waves to image internal structures
Brachytherapy- Therapy where radiatio is placed inside or next to the diseased area
lithiotripsy- The physical breakage of stones by the application of pulsed ulrasound
radiopharmaceuticals- internally delivered and targeted ionizing radiation
Explanation:
Answer:
Here are the answers :D
Explanation:
I just did it right now on Edg22 and I got it correct :D
Edwin Hubble used a telescope and observed fuzzy blobs of light off in the distance. He realized that these lights were: O Stars O Galaxies O Universes O Planets
Answer:Galaxies
Explanation:
I know about this stuff, I hope it helped!
Answer:
B-galaxies
Explanation:
e2020
Describe how the motion and arrangement of particles in a substance change as the substance freezes.
Answer:
As a substance freezes, its particles lose some of their freedom of motion and become more orderly.
Explanation:
Answer:
They get closer and slow down
Explanation:
How are the components of a heterogeneous mixture distributed?
Answer:
heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.
Read the question, and then use the drop-down menus to complete the paragraph.
What is Earth’s atmosphere made of?
The most abundant gas in Earth’s atmosphere is
, followed by
, which is needed to burn wood and fuel. The third-most abundant gas is
. The amount of
in the atmosphere is very small, making up just 0.033% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around
in the atmosphere to form clouds and then rain.
Answer:
The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon. The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.
Explanation:
The atmospere of the earth is made up of different types of gases like Nitrogen, oxygen, Carbon di oxide etc.
What is atmosphere?Atmosphere is defined as the envelope of the gases covered the whole planet of earth and is responsible to save us from ultravoilet rays and entrape the radiation to maintain the ideal temperature on the surface of earth by green house effect.
The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon.
The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars.
Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.
To know more about Atmosphere follow
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PLEASE HELP!!
What does the electromagnet in an electric motor do?
A. It transforms mechanical energy into electrical energy.
B. It transforms magnetic force into electrical energy.
C. It transforms electrical energy into mechanical energy.
D. It transforms electrical energy into magnetic force.
Answer:
C. It transforms electrical energy into mechanical energy
Answer: C
Explanation:
the most useful property of metalloids is their
Answer:
their ability to conduct electricity
Explain what happens as an object moves through each phase of matter.
ASAP PLEASE ????????
Explanation:
gas vibrate and moves freely at high speeds, liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place
hope it helps you
Which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams
Explanation:
The mass of a cylinder made of barium with a height of 2 inches depends on the radius of the cylinder as defined by the
function m(r) = 7.18872.
which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams?
round to the nearest hundredth of an inch.
En un lago helado se lanza un trozo de hielo de 500 g a la velocidad de 20 m/s. Si el coeficiente de rozamiento es de 0.04, calcula: a) La fuerza de rozamiento. b) La aceleración del trozo de hielo. c) El espacio recorrido por el trozo de hielo hasta detenerse.
Answer:
Sabemos que:
La masa del trozo de hielo es 500g
la velocidad inicial es 20 m/s
el coeficiente de fricción es 0.04
a) La fuerza de rozamiento de un objeto de masa M es escrita como:
F = M*g*μ
Y es en dirección opuesta al movimiento del objeto, entonces la rescribimos como:
F = -M*g*μ
Donde M es la masa del objeto, 500g, es útil escribirla en kilogramos, entonces podemos escribir M = 500g = 0.5 kg
g es la aceleración de la gravedad:
g = 9.8m/s^2
y μ es el coeficiente de fricción, en este caso es 0.04
Entonces la fuerza de fricción es:
F = -0.5kg*9.8m/s^2*0.04 = -0.196 N
b) Ahora queremos la aceleración, tenemos la segunda ley de Newton que dice:
F = M*a
-0.196 N = 0.5kg*a
(-0.196 N)/0.5kg = a = -0.392 m/s^2
c) Primero debemos escribir la ecuación de movimiento.
La aceleración es:
a = -0.392 m/s^2
Para obtener la velocidad, debemos integrar sobre el tiempo para obtener.
v(t) = (-0.392 m/s^2)*t + v0
Donde v0 es la velocidad inicial, en este caso 20m/s
Entonces la ecuación es:
v(t) = (-0.392 m/s^2)*t + 20m/s
Recordemos que esta fuerza solo actua mientras el objeto se mueva, esto significa que cuando la velocidad sea igual a cero, la fuerza desaparece, por lo tanto el objeto se detiene.
Entonces podemos obtener el valor de t para el cual la velocidad es igual a cero.
v(t) = 0 = (-0.392 m/s^2)*t + 20m/s
(0.392 m/s^2)*t = 20m/s
t = 20m/s/(0.392 m/s^2) = 51.02 s
Esto significa que el objeto se va a mover por 51.02 segundos antes de detenerse totalmente.
Ahora, la ecuación de la posición puede obtenerse si integramos la ecuación de la velocidad, así obtenemos:
p(t) = (1/2)*(-0.392 m/s^2)*t^2 + 20m/s*t + p0
donde p0 es la posición inicial del objeto.
Ahora, el espacio total recorrido por el trozo de hielo va a ser igual a la diferencia entre la posición final y la posición inicial, esto es:
D = p(51.02s) - p(0s)
D = ((1/2)*(-0.392 m/s^2)*(51.02s)^2 + 20m/s*51.02s + p0) - ((1/2)*(-0.392 m/s^2)*(0s)^2 + 20m/s*(0s) + p0)
D = (1/2)*(-0.392 m/s^2)*(51.02s)^2 + 20m/s*51.02s = 510.20 m
El trozo de hielo se mueve por 510.20 metros.
3. Explain why the planets orbit the Sun and why the orbits are slower the further
away a planet is from the Sun.
Answer:
The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.