Suppose the quantum number rule for the angular momentum quantum number, I was
l = 0,1,2,...,l
Instead of
l = 0,1,2,...,l-1
Drag the text components into the boxes to create the Ar electron configuration for the new rule.

Answer:yes

Explanation:

I think so

There are more metals than nonmetals on the periodic table. The majority of elements on the periodic table are metals, which are found on the left and middle sections of the periodic table.

Metals typically have properties such as high electrical and thermal conductivity, luster, malleability, and ductility.

Nonmetals, on the other hand, are found on the right-hand side of the periodic table, along with the noble gases. Nonmetals generally have properties opposite to those of metals, such as poor electrical and thermal conductivity and a lack of metallic luster. There are fewer nonmetals compared to metals on the periodic table.

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Answer:

I hope this answer is correct

Explanation:

This is an oxidation-reduction (redox) reaction:

Zn0 - 2 e- → ZnII (oxidation)

2 HI + 2 e- → 2 H0 (reduction)

Zn is a reducing agent, H2SO4 is an oxidizing agent.

Reactants:

Zn

Names: Zinc source: wikidata, accessed: 2019-09-07, Zinc powder (pyrophoric) source: ICSC, accessed: 2019-09-04, Zn source: wikidata, accessed: 2019-09-07

Appearance: Grey-to-blue powder source: ICSC, accessed: 2019-09-04

H2SO4 – Sulfuric acid source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: NIOSH NPG, accessed: 2019-09-02

Other names: Oil of vitriol source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Sulfuric acid, concentrated (> 51% and < 100%) source: ICSC, accessed: 2019-09-04, H2SO4 source: wikidata, accessed: 2019-09-07

Appearance: Clear, colorless liquid source: wikipedia, accessed: 2019-09-27; Odourless colourless oily hygroscopic liquid source: ICSC, accessed: 2019-09-04; Colorless to dark-brown, oily, odorless liquid. [Note: Pure compound is a solid below 51°F. Often used in an aqueous solution.] source: NIOSH NPG, accessed: 2019-09-02

Products:

ZnSO4 – Zinc sulfate source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04

Other names: White vitriol source: wikipedia, accessed: 2019-09-27, Goslarite source: wikipedia, accessed: 2019-09-27, Zinc sulfate (1:1) source: wikidata, accessed: 2019-09-02

Appearance: White powder source: wikipedia, accessed: 2019-09-27; Colourless hygroscopic crystals source: ICSC, accessed: 2019-09-04

H2

Names: Dihydrogen source: wikidata, accessed: 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07

Answer:

2.98 moles of NaCl are produced.

Explanation:

Given data:

Moles of sodium = 2.98 mol

Amount of chlorine = excess

Moles of NaCl produced = ?

Solution:

Chemical equation:

2Na + Cl₂    →     2NaCl

Now we will compare the moles of sodium chloride with only sodium because sodium is limiting reactant and chlorine is in excess thus sodium limit the yield of product.

                    Na        :        NaCl

                    2          :            2

                 2.98        :          2.98

2.98 moles of NaCl are produced.

Answer:

Mass of liquid B = 271.2 gram

Explanation:

Given:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Assume:

Volume of liquid A = Va

Volume of liquid B = Vb

So,

Volume of mixture = Va + Vb

Mass of liquid A = 1000(Va)

Mass of liquid B = 600(Vb)

Mass of mixture = Mass of liquid A + Mass of liquid B

1 = 1000(Va) + 600(Vb)

Volume of mixture = 1 / 850

So,

(1/850) = Va + Vb

Vb = (1/850) - Va

1 = 1000(Va) + 600[(1/850) - Va]

Va = 7.25 × 10⁻⁴

Vb = (1/850) - Va

Vb = (1/850) - [7.25 × 10⁻⁴]

Vb = 4.25 × 10⁻⁴

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(4.25 × 10⁻⁴)

Mass of liquid B = 271.2 gram

The mass of liquid B in the 1 Kg mixture is 300 g

Let the volume of liquid A be Va

Let the volume of liquid B be Vb

From the question given above, the following data were obtained:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

For Liquid A:

Density of liquid A = 1000 kg/m³

Volume of liquid A = Va

Mass of Liquid A =?

Mass = Density × Volume

Mass of Liquid A = 1000 × Va

For Liquid B:

Density of liquid B = 600 kg/m³

Volume of liquid B= Va

Mass = Density × Volume

Mass of Liquid B = 600 × Va

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Volume = mass /density

Volume of mixture = 1 / 850

Mass of mixture = 1 Kg

Mass of mixture = Mass of liquid A + Mass of liquid B

Volume of mixture = Va + Vb

Volume of mixture = 0.0012 m³

Thus,

0.0012 = Va + Vb

Substitute Vb in equation 2 into equation (1)

1 = 1000(Va) + 600[0.0012 – Va]

1 = 1000Va + 0.72 – 600Va

Collect like terms

1 – 0.72 = 1000Va – 600Va

0.28 = 400Va

Divide both side by 400

Va = 0.28 / 400

Volume of mixture = 0.0012 m³

Volume of liquid A (Va) = 0.0007 m³

Vb = 0.0012 – Va

Vb = 0.0012 – 0.0007

Volume of liquid B (Vb) = 0.0005 m³

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(0.0005)

Mass of liquid B = 0.3 Kg

Multiply by 1000 to express in grams

Mass of liquid B = 0.3 × 1000

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Answer:

Rb = +1 , Sr = +2, In= +3,  Sn = +4, Sb= +5

Explanation:

Formula:

Zeff = Z - S

Z = atomic number

S = number of core shell or inner shell electrons

For Sn:

Electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Zeff = Z - S

Zeff = 50 - 46

Zeff = +4

For Rb:

Electronic configuration:

Rb₃₇ = [Kr] 5s¹

Zeff = Z - S

Zeff = 37 - 36

Zeff = +1

For Sb:

Electronic configuration:

Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³

Zeff = Z - S

Zeff = 51 - 46

Zeff = +5

For In:

Electronic configuration:

In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹

Zeff = Z - S

Zeff = 49 - 46

Zeff = +3

For Sr:

Electronic configuration:

Sr₃₈= [Kr]  5s²

Zeff = Z - S

Zeff = 38 - 36

Zeff = +2

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

[tex]a=\frac{v-u}{t}[/tex]

thus,

[tex]t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds[/tex]

Answer:B

Explanation: an object in motion will stay in motion until acted on by another force and an object in rest will stay in test until acted on by another force

Answer:

D. all of the answers are correct

Explanation:

edge 2020

Rainforests are defined by the evergreen and canopy trees. The tropical and temperate rainforests differ in the locations, type of plantation, and temperature. Thus, option d is correct.

Tropical and temperate rainforests are rainforests that differ from each other based on various factors. The tropical rainforest is located at the latitude near the equator, between the Tropic of Cancer and Capricorn. They are covered with canopied trees and average warm temperature conditions.

On the other hand, the temperate rainforests are found away from the Equator near the north side of the tropics and are marked by the presence of coniferous or broadleaf trees. They have a cooler climate and two seasons.

Therefore, option d. the tropical and temperate rainforests have different temperatures, locations, and trees.

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Answer:Three mutual conversions of energy forms occur at nuclear power plants: nuclear energy is converted into thermal energy, thermal energy is converted into mechanical energy, and mechanical energy is converted into electric energy.

Explanation:

Answer:

protons and neutrons so A and C

Answer:

it is nanometers the third one

Explanation:

hope this helps

The correct answer is:

(D) Micrometers

Hope this helps!

Answer:

yes

Explanation:

everything will change

Answer: below -45

Explanation:

Given :

Mass of given magnesium chloride, m = 256 g.

To Find :

How many grams of chloride are there in 256 g of magnesium chloride.

Solution :

Molecular formula of magnesium chloride is [tex]MgCl_2[/tex].

Molecular formula of [tex]MgCl_2[/tex] is, M = 95.211 g/mol .

Mass of chlorine in 1 mol of [tex]MgCl_2[/tex]  is , m = 35.5 × 2 = 71 g.

So, amount of chlorine in 256 gram [tex]MgCl_2[/tex] :

[tex]m =\dfrac{71\times 256}{95.211}\\\\m = 190.90\ g[/tex]

Hence, this is the required solution.

Answer:i believe 9-?

Explanation:

boron-10

boron-11

carbon-12

carbon-13

oxygen-16

oxygen-17

oxygen-18

chlorine-35

chlorine-37

A brother is bragging about doing a bench press of 4000 grams at the gym. 4000 grams is equal to 8.818 pounds.

The bench press or chest press is training or weight training to strengthen your arm and chest muscles. It is done by laying down on a bench and pushing and pulling up the bars with weight.

It is a common weight-lifting exercise in gyms. Trainers use accordingly weight on the basis of the trainee's weight and strength that is doing the bench press, and the weight is measured differently in different countries. Eight-pound is not a very big amount.

In America, weight is measured in pounds, one kg is 1000 grams and

1 gram is 0.00220462

4000 x 0.00220462

4000 grams will be 8.818 pounds.

Thus, 4000 grams is equal to 8.818 pounds.

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Answer:

A. color change

Explanation:

changing the color of a metal does not change its physical properties.

hope it helps.

Answer:

Liquid: water

Solid: Rocks

Gas: Air

Explanation:

Answer:

11 g/mL

Explanation:

From the question given above, the following data were obtained:

Mass of metal = 102.06 g

Volume of water = 38 mL

Volume of water + metal = 47 mL

Density of metal =.?

Next, we shall determine the volume of the metal. This can be obtained as shown below:

Volume of water = 38 mL

Volume of water + metal = 47 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water)

Volume of metal = 47 – 38

Volume of metal = 9 mL

Finally, we shall determine the density of the metal as follow:

Mass of metal = 102.06 g

Volume of metal = 9 mL

Density of metal =.?

Density = mass /volume

Density of metal = 102.06 / 9

Density of metal = 11.34 ≈ 11 g/mL

Therefore, the density of the metal is 11 g/mL

Answer:

Mintu should chosen a material with a lower specific heat

Explanation:

I got the answer right on the test trust me it is correct

Answer:

The glass cup falling from the counter

Explanation:

the glass isn't changing in any chemical way. it's still made of the same material, just broken apart.

Answer:

106.7 degrees f

Explanation:

Answer:

3.83%

Explanation:

First, find the average of the measured value.  You should get 286.

291 + 287 + 295 + 281 = 1154

1154/4 = 288.5

Subtract the accepted value (300) from the average measured value (286).  Take the absolute value of your answer.  You should get 14.

288.5 - 300 = -11.5 = 11.5

Divide the difference from the above problem (14) by the accepted value (300).  You should get 0.0467.

11.5/300 = 0.0383

Multiply by 100%.

0.0383 × 100% = 3.83%

The percent error is 3.83%.

Answer:

3.83 percent

Explanation:

Accepted Value = 300 degrees celsius

So since we are given the formula for percentage error,

we know that we have to find the average measured value since the accepted value is already provided

Average Measured Value:

Sum of all measured values / number of measured values

(291 + 287 + 295 + 281) / 4

1154 / 4

288.5 degrees celsius

Now, plugging the values in the given formula:

(average measured value - accepted value) *100 / accepted value

(288.5 - 300) * 100 / 300

-1150 / 300

-3.83 percent

Taking Absolute Value:

3.83 percent

Hence, the average value of the temperature is 3.83 percent less than the accepted value

Answer:

Test variable (independent variable): Predators, Pollution, Food.Outcome variable (dependent variable): Cricket Frogs.Control group: Beginning Frog Count

Explanation:

If pollution isincreased, then the cricket frog population will (stay the same) over the span offive years.If the amount of food available isincreased, then the cricket frog population will (increase) overthe span of five years.Procedure:The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sureto identify the test variable (independent variable), outcome variable (dependent variable), andcontrol group for this experiment.