The brakes on a 15,680 N car exert a stopping force of 640 N.
The car's velocity changes from 20.0 m/s to 0 m/s. What is the
mass of the car? (Estimate 10 N/kg for g.)

Answer: The light beam will not diffract out of the prism.

Explanation: The angle the light is entering the prism is greater than the critical angle therefore total internal reflection will occur. Hope this helps :)

Answer:

v=11.8m/s

Explanation:

speed of the ball

Force=mass*centripetal acceleration

Centripetal acceleration= V2/r

F=M*V2/r

Data

F=310N

M=2.0kg

r=0.90m

v=?

310N=(2.0kg)*V2/0.90m

cross multiply

279Nm=(2.0kg)V2

V2= 279Nm/2.0kg

V2=139.5Nm/kg

apply square root both sides

√V2=√139.5

V=11.8m/s

Let r be the distance between the man and point Q. He applies a torque of

(r i ) × ((-800 N) j ) = ((-800 N) r ) k

pointing "into the page" with magnitude (800 N) r.

Meanwhile, the rope applies a torque of

((3.0 m) i ) × ((500 N) j ) = (1500 N•m) k

pointing out of the "page" with mag. 1500 N•m

The beam is held in place in a horizontal position, so the torques cancel and

(800 N) r = 1500 N•m

r = (1500 N•m)/(800 N) = 1.875 m ≈ 1.9 m

Answer:

Please find attached the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel

Explanation:

The given parameters are;

The initial velocity with which the boy throws the rock, u = 12 m/s

The direction in which he throws the rock = Down

The height from which the rock was thrown, h = 20 m

The height at which the river is located = 0 m

The kinematic equation of motion, of the rock can be given as follows;

h = u·t + 1/2·g·t²

Where;

t = The time of motion of the rock

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the rock is thrown = 20 m

Substituting the known values into given equation, we get;

20 = 12·t + 1/2·9.8·t² = 12·t + 4.9·t²

4.9·t² + 12·t - 20 = 0

t = (-12 ± √(12² - 4×4.9×(-20)))/(2 × 4.9) = (-12 ± √(242))/(9.8)

t ≈ -3.587 seconds or t ≈ 1.138 seconds

Attached please find the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel.

Explanation:

The theory which is linked to person and climate is more concerned with Mother Nature and human's position within it. It is a misconception that humans are the most important species on this planet and they are relying on other species for their life. Conservation ethics also revolve around making human societies and habitats healthier, preserving vital resources for the present and future. This philosophical approach values the human/nonhuman interaction of nature, understanding how humans and the world have a continuing causal association with one another.

Answer:

The answer is below

Explanation:

Volt in physics is a term that is used to describe the unit of both electrical potential difference and electromotive force. In other words, it is a unit of measuring the voltage between two points. It is represented as "V".

The formula for Voltage is V=IR

Where V= Voltage, I = Current and R = Resistance.

Answer:

biking

Explanation:

To make the Bike move you peddle with your legs.

Answer:

Organizational clothing.

Explanation:

An organizational clothing can be defined as the standard field uniform of the U.S Navy that is being loaned to a person (officer) by a naval activity and as such must be returned to the naval activity as soon as the person is transferred.

Basically, an organizational clothing is generally considered to be the property of the U.S Navy and should be sent to the regional or area naval coordinator.

Hence, when required to be returned to the issuing activity upon the individual's transfer, clothing loaned to an individual by a navy activity is referred to as organizational clothing.

Correct value of kinetic energy is 704 × 10³ J

Answer:

v = 147.18 m/s

Explanation:

At any point/moment during the fall, the sky diver will possess kinetic energy with the formula;

KE = ½mv²

Where;

m is mass

v is velocity

We are given;

m = 65 kg

KE = 704 × 10³ J

Thus;

704 × 10³ = ½ × 65 × v²

v² = (2 × 704 × 10³)/65

v² = 21661.53846153846

v = √21661.53846

v = 147.18 m/s

Answer:

D: The hydrogen bonds between water molecules are more cohesive in the liquid state than in the solid state.

Explanation:

If we assume that there is no phase change due to heating, we know that the temperature change will be proportional to the mass heated, being the proportionality constant that is a quantity which depends on the material, and also represents the resistance of the material to cause a change in the temperature and is called specific heat.

Now, if we are to assume that the mass is the same for the three phases, and that the amount of heat supplied is also the same, the phase with the highest specific heat will therefore possess the lowest temperature change.

At a lower temperature, the hydrogen bonds will be more cohesive than at higher temperatures.

We are told that in it's solid state, it has a specific heat capacity of 2.093 J/g°C while in its liquid state, it has a specific heat capacity of 4.186 J/g°C.

Thus, the hydrogen bonds between water molecules in the liquid state will be less cohesive than in its solid state.

Answer: D

Explanation:

Answer:

The displacement of Sudhir is 0.781 km.

Explanation:

Given;

initial distance, d₁ = 0.4 km = 400 m, N60.0°W

final distance, d₂ = 0.5 km

Make a sketch of Sudhir motion to form a right angled triangle;

(Check image uploaded).

Apply cosine rule to determine d "displacement"

d² = 500² + 400² - (2 x 500 x 400 x cos 120)

d² = 410,000 - (400,000 x -0.5)

d² = 410,000 - (-200,000)

d² = 410,000  + 200,000

d² = 610,000

d = √610000

d = 781.03 m

d = 0.781 km

Therefore, the displacement of Sudhir is 0.781 km.

Answer:

40×（9.8+2）＝432n

Explanation:

9.8m/s^2 is acceleration of gravity

Once the object is moving, the force of friction opposes the force exerted on the object. The wheel and axle makes this easier by reducing the friction involved in moving an object.

Hope it helps!

Answer:

The wheel and axle work by reducing the effect of friction on an object, thereby creating a mechanical advantage.

Answer:

[tex]-500\ \text{mph}[/tex]

Explanation:

h = Height at which the plane is flying = 6 miles

S = Distance between plane and radar = 10 miles

[tex]\dfrac{dS}{dt}[/tex] = Rate at which S is decreasing = -400 mph

Distance between S and and the elevation of the plane

[tex]b=\sqrt{S^2-h^2}=\sqrt{10^2-6^2}\\\Rightarrow b=8[/tex]

From Pythagoras theorem we get

[tex]S^2=b^2+h^2[/tex]

Differentiating with respect to time we get

[tex]2S\dfrac{dS}{dt}=2b\dfrac{db}{dt}+2h\dfrac{dh}{dt}\\\Rightarrow S\dfrac{dS}{dt}=b\dfrac{db}{dt}+h\dfrac{dh}{dt}\\\Rightarrow 10\times -400=8\times \dfrac{db}{dt}+0\\\Rightarrow \dfrac{db}{dt}=\dfrac{10\times -400}{8}\\\Rightarrow \dfrac{db}{dt}=-500\ \text{mph}[/tex]

Velocity of the plane is [tex]-500\ \text{mph}[/tex].

If the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph

Given the data in the question;

As illustrated in the diagram below, we determine the value of "y"

Using Pythagorean theorem:

[tex]S^2 = x^2 + y^2[/tex]------------Let this be Equation 1

We substitute in our value

[tex]y = \sqrt{(10miles)^2- (6miles)^2} \\\\y = \sqrt{100mi^2- 36mi^2}\\\\y = \sqrt{64mi^2}\\\\y = 8miles[/tex]

Now, we determine velocity of the plane i.e the change in distance in horizontal direction ([tex]\frac{dy}{dt}[/tex])

Lets differentiate Equation 1 with respect to time t

[tex]2S\frac{ds}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]------ Let this be Equation 2

Since, the plane is not landing, [tex]\frac{dx}{dt} =0[/tex]

We substitute our values into Equation 2 and find [tex]\frac{dy}{dt}[/tex]

[tex][2*10mi*(-400mph) ] = [2*6mi*0] + [2*8mi * \frac{dy}{dt}]\\\\-8000m^2ph = 0 + 16miles * \frac{dy}{dt}\\\\\frac{dy}{dt} = \frac{-8000m^2ph}{16miles}\\\\\frac{dy}{dt} = -500mph[/tex]

Therefore, if the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph

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Answer:

(a) the height of the diving board is 22.896 m

(b) the horizontal distance traveled by the girl is 7.02 m

(c) if she had just drop off the board, her time to drop to the water would have been longer.

Explanation:

Given;

initial speed of the girl, u = 3.9 m/s

time to hit the water, t = 1.8 s

(a) the height of the diving board is calculated as;

h = ut + ¹/₂gt²

h = (3.9 x 1.8)  +  ¹/₂ x 9.8 x 1.8²

h = 7.02 + 15.876

h =  22.896 m

(b) the horizontal distance traveled by the girl is calculated as;

X = ut

X = 3.9 x 1.8

X = 7.02 m

(c) if she just drop off the board, then the initial speed will be zero;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

2h = gt²

[tex]t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \ \times\ 22.896 }{9.8} }\\\\t = 2.16 \ s[/tex]

Thus, if she had just dropped off the board, her time to drop to the water would have been longer.

Answer:

10.90km

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

d = 10.90km

Hence the magnitude of the bicyclist's total displacement is 10.90km

The bicyclist magnitude of displacement is equal to 9.62m

To find the resultant magnitude of the bicyclist total displacement, we have to find the x and y component.

For the first direction, the components are

[tex]x_1 = -4.5i[/tex]

sine we don't have any vertical displacement, the y-component is equal to zero.

for the second direction,

[tex]x_2 = -6.7sin27i\\y_2= 6.7cos27j[/tex]

The resultant x and y component are;

Let's find the magnitude of displacement

[tex]R = \sqrt{R_x^2 + R_x^2}\\R = \sqrt{(-7.54)^2 + (5.97)^2 }\\\\R = 9.62m[/tex]

The bicyclist magnitude of displacement is equal to 9.62m

Learn more on resolution of vectors here;

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Answer:

I tried...

Explanation:

Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:

• 1 pound (lb) = 16 ounces (oz)

• 2,000 pounds (lbs) = 1 ton (T)

I think that's everything?

In the English system, mass is measured in pounds and weight is also measured in pounds. However, it is important to understand the difference between mass and weight.

Mass is a measure of the amount of matter in an object and is a scalar quantity. It does not change with location or gravitational force. In the English system, mass is typically measured using a scale or balance, which compares the object's mass to a standard mass. The pound (lb.) is the unit of mass in the English system.

Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is a vector quantity. It depends on the object's mass and the gravitational force acting on it. In the English system, weight is typically measured using a spring scale or a balance that incorporates a spring. The pound (lb.) is also used as the unit of weight in the English system.

Weight = Mass x Acceleration due to gravity

Mass is measured in pounds (lb.) and weight is also measured in pounds (lb.).It is important to note that weight can vary depending on the gravitational force acting on an object.

Learn more about weight here:

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Answer:

Final speed of security car v = 65 m/s

Explanation:

Given:

Speed of race car u1 = 35m/s

Speed of security car u2 = 5 m/s

Acceleration = 5 m/s²

Find:

Final speed of security car v

Computation:

Assume, they chase S meter

So

S = u1t + [1/2]at²

S = 35t

S = u2t + [1/2]at²

so,

35t = 5t +  [1/2](5)t²

t = 12 s

So

v = u + at

v = 5 + 5(12)

Final speed of security car v = 65 m/s

Answer: 12.56 m/s

Explanation:

The velocity of something that is doing a circular motion can be written as:

v = R*w

Where:

v is the velocity.

R is the radius, in this case, we know that it is 8m.

w is the angular velocity, we know that:

w = 2*pi*f

where:

pi = 3.14

f = frequency, this is equal to the inverse of the period, and we know that the period is 4 seconds.

then:

f = 1/4s

w = 2*3.14*(1/4s)

Then the velocity will be:

v = 8m*2*3.14*(1/4s) = 12.56 m/s

The velocity is 12.56 meters per second, and the mass of the passenger does not mater for this particular calculation.

Answer:

a) The initial speed of the projectile is approximately 42.410 meters per second.

b) The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) The horizontal range of the projectile is 169.64 meters.

d) The maximum height of the projectile is 68.775 meters.

e) The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

Explanation:

According to the statement, the projects shows a parabolic motion, which consists in the combination of horizontal uniform motion and vertical uniformly accelerated motion due to gravity. This motion is represented by the following equations of motion:

[tex]x = x_{o} + v_{o}\cdot t\cdot \cos \theta[/tex] (1)

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \theta + \frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)

Where:

[tex]x_{o}[/tex], [tex]x[/tex] - Initial and current horizontal position, measured in meters.

[tex]y_{o}[/tex], [tex]y[/tex] - Initial and current vertical position, measured in meters.

[tex]\theta[/tex] - Launch angle, measured in sexagesimal angle.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]t[/tex] - Time, measured in second.

a) By using (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]y = 0\,m[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then initial speed of the projectile is:

[tex]v_{o}\cdot t \cdot \sin \theta = y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]v_{o} = \frac{y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2} }{t\cdot \sin \theta}[/tex]

[tex]v_{o} = \frac{0\,m-20\,m-\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)^{2} }{(8\,s)\cdot \sin 60^{\circ}}[/tex]

[tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex]

The initial speed of the projectile is approximately 42.410 meters per second.

b) The vertical component of the velocity of the projectile is determine by differentiating (2) in time and substitute all known values:

[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (3)

([tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 4\,s[/tex])

[tex]v_{y} = -2.5\,\frac{m}{s}[/tex]

The horizontal component of the velocity of the projectile is:

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-2.5\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 21.352\,\frac{m}{s}[/tex]

The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) By (1) we find the horizontal range of the projectile:

([tex]x_{o} = 0\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 8\,s[/tex])

[tex]x = 0\,m + \left(42.410\,\frac{m}{s} \right)\cdot (8\,s)\cdot \cos 60^{\circ}[/tex]

[tex]x = 169.64\,m[/tex]

The horizontal range of the projectile is 169.64 meters.

d) The projectile reaches its maximum height when velocity is zero. By (3) and knowing that [tex]v_{y} = 0\,\frac{m}{s}[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the time associated with maximum height is:

[tex]0\,\frac{m}{s} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot t[/tex]

[tex]t = 3.745\,s[/tex]

And by (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 3.745\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the maximum height reached by the projectile is:

[tex]y = 20\,m + \left(42.410\,\frac{m}{s} \right)\cdot (3.745\,s)\cdot \sin 60^{\circ}+\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.745\,s)^{2}[/tex]

[tex]y = 68.775\,m[/tex]

The maximum height of the projectile is 68.775 meters.

e) If we know that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the components of the speed are, respectively:

[tex]v_{y} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)[/tex]

[tex]v_{y} = -41.728\,\frac{m}{s}[/tex]

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-41.728\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 46.807\,\frac{m}{s}[/tex]

The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

Answer:

Fossil fuels are non-renewable . They took a very long time to form and we are using them up faster than they can be replaced - once they have all been used up, they cannot be replaced.

Answer:

The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”

Explanation:

I did the practice.

Answer:

C.) Ralph: "I'm not sure about bananas. I'd have to think about it."

Explanation:

Just took the practice

Answer:

your pretty no matter what others say

Explanation:

Answer:

two bros chillin in a hot tub five feet apart cuz there not gay

Explanation:

do you remember this vine

Explanation:

Fnet = ma = (3kg)(8m/s²) = 24N.

50N - 24N = 26N.

Hence the frictional force is 26N.

Answer:

True

Explanation:

This heat energy allows the change of state to happen, and the temperature remains constant during the process. The amount of energy required to change the state of a substance depends upon the mass and characteristics of that substance. The energy required to change the state of a material is known as the latent heat. During a change of phase the temperature does not change, but the internal energy does. The internal energy is the sum of the kinetic energy of the molecules and the chemical potential energy of the molecules.

Answer:

O Intense rain or an earthquake

Explanation:

Landslides can be initiated in slopes already on the verge of movement by rainfall, snowmelt, changes in water level, stream erosion, changes in ground water, earthquakes, volcanic activity, disturbance by human activities, or any combination of these factors.

Intense rain or an earthquake can trigger a landslide.

In conclusion, intense rain or an earthquake can trigger a landslide.

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Answer:

Topographic maps give the user the ability to view a three-dimensional landscape on a two-dimensional map. One who is able to read a topo map can identify the elevation and location of valleys, peaks, ridges, and other land features.

Explanation:hope this helps

Answer:

Explanation:

V = I*R

V/R = I