The depth of the water at the end of a pier changes periodically along with the movement of tides. on a particular day, low tides occur at 12:00 a.m. and 3:30 p.m., with a depth of 3.25 meters, while high tides occur at 7:45 a.m. and 11:15 p.m., with a depth of 8.75 meters. which of the following equations models d, the depth of the water in meters, as a function of time, t, in hours? let t = 0 be 12:00 a.m. d = negative 3.75 cosine (startfraction 4 pi over 31 endfraction t) 5 d = negative 3.75 cosine (startfraction 4 pi over 29 endfraction t) 5 d = negative 2.75 cosine (startfraction 4 pi over 31 endfraction t) 6 d = negative 2.75 cosine (startfraction 4 pi over 29 endfraction t) 6

Answer:

2, 4, 8

Step-by-step explanation:

Well, it says Max put $1 on the first day(which is already entered for you), then it says that he put in $2 on the second day. Then it says that he doubles how much he puts in each day after, which just means to multiply the last entered amount by 2. So, he put in 2 x 2 = $4 on the third day, and lastly, 4 x 2 = $8 on the fourth day.

Hope this helps :)

Answer:

$3.31 for each

Step-by-step explanation:

$6.62 divided by 2 = $3.31

Answer:

$6.62 divided by 2= $3.31

Step-by-step explanation:

What your going to do is divide 6 by 2 = 3

Next divided 62 by 2 = 32

Easy =)

Have a great day/night

Answer:

7

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

Use PEDMAS

P - Parenthesis ; E - exponents ; D -division ; M - mulitplication ;

A - Addition ;  S- subtraction.

First do the operation in the inner most parenthesis.

100 - [ 5 *(3 + 4)] = 100 - [ 5* 7 ]   {Now the outer parenthesis}

                             = 100 - 35

                             =  65

Answer:

(-6,8)

Step-by-step explanation:

Answer:

1.4 grams of medison for thr whole week combinded

Answer:

1.4 g

Step-by-step explanation:

0.2 gram per day x 7 days = 1.4 g total consumed in a week

Answer:

[tex]D : y = \frac{-1}{4}x + \frac{1}{2}[/tex]

Step-by-step explanation:

let D be the line that passes through the points (6, -1) and (-6, 2)

Then D has an equation of the form D: y = ax + b

Now we need to find a and b in order to be able to write the equation of the line D:

[tex]a = \frac{-1-2}{6-(-6)}= \frac{-3}{12}= \frac{-1}{4}[/tex]

Since the point (6 , -1) lies on the line D then :

-1 = (-1/4) × (6) + b

then

-1 = (-6/4) + b

then 

b = -1 - (-6/4) = -1 + 6/4 = -4/6 + 6/4 = (-4+6)/4 = 2/4 = 1/2

then

b = 1/2

Conclusion:

Since a = -1/4 and b = 1/2 then

[tex]D : y = \frac{-1}{4}x + \frac{1}{2}[/tex]

Step-by-step explanation:

-0.7n = -1/2

-0.7n = -0.5

n = 0.5/0.7

n = 0.715

Answer:

0 < t ≤ 8  (in hours)

Up to (and including) 8 hours

Step-by-step explanation:

Let t = number of hours the room is rented

Given:

Create an equation using the given information and solve for t:

⇒ 39 + 9.8t ≤ 117.4

Subtract 39 from both sides:

⇒ 9.8t ≤ 78.4

Divide both sides by 9.8

⇒ t ≤ 8

Therefore, the possible amounts of time for which they could rent the meeting room is 0 < t ≤ 8  (in hours)

Answer:

8 is the very maximum number of hours the room can be rented. As long as 8 is not exceeded, the room is rentable for what money the math club has.

Step-by-step explanation:

Givens

Formula

payment ≥ 39 + 9.80*t                where t is in hours.

Solution

117.40 ≥ 39 + 9.80*t                      Subtract 39 from both sides.

117.40 - 39 ≥9.80*t

78.40 ≥ 9.80*t                               Divide by 9.8

78.40/9.80 ≥ 9.80*t/9.80

8 ≥ t    

Answer t≥ 8

B is 5.625

A=2x

C=8x

5.625x2(x)*8(x)=90

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The proposed design of the atrium (V < V') is possible since its volume is less than the maximum possible atrium.

The atrium with the maximum allowable radius (R), in feet, is represented in the image attached. The real atrium is possible if and only if the real radius (r) is less than the maximum allowable radius and therefore, the real volume (V), in cubic feet, must be less than than maximum possible volume (V'), in cubic feet.

First, we calculate the volume occupied by the maximum allowable radius:

V' = (8 · π / 3) · (45 ft)³

V' ≈ 763407.015 ft³

The proposed design of the atrium (V < V') is possible since its volume is less than the maximum possible atrium. [tex]\blacksquare[/tex]

To learn more on volumes, we kindly invite to check this verified question: https://brainly.com/question/13338592

Answer:

x = 2.5

Step-by-step explanation:

Answer:

x = -3

Step-by-step explanation:

9(3+x) = 4(3+x)

9(3+x) - 4(3+x) = 0

(9-4)(3+x) = 0

5(3+x) = 0

15+5x = 0

-15 = 5x

x = -3

20.5 yeah :)

"HABANG BUHAY SONG"

Answer: 3/5

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of each other.

Answer:

container for catching bugs because posters have nothing to do with volume

Answer:

I think Madden should go for the poster because poster have more angles as well as width length and height.

Step-by-step explanation:

Brainliest??????

Answer:

multiply base area by 2 , and add the base perimiter and height

Step-by-step explanation:

hope this helped

The time period of the given function will be π.

We have the following expression -

y = (-1/3)sin(2x)

We have -

y = (-1/3)sin(2x)

We can write -

ωx = 2x

Now -

ω = 2π/T

(2π/T)x = 2x

2π/T = 2

T = 2π/2

T = π

Therefore, the time period of the given function will be π.

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Answer:

0.03

Step-by-step explanation:

[tex] \frac{0.21}{7} [/tex]

==>

[tex] \frac{0.21 \times 100}{7 \times 100} [/tex]

===>

[tex] \frac{21}{7} \times \frac{1}{100} [/tex]

==>

[tex]3 \times \frac{1}{100} [/tex]

==>

[tex] \frac{3}{100} [/tex]

==>

[tex]0.03[/tex]

Answer:

I dont know pls ask you parents...

Step-by-step explanation:

I dont know

Answer:

(x - 4)

Step-by-step explanation:

x² - x - 12

to factor consider the factors of the constant term (- 12) which sum to give the coefficient of the x- term (- 1)

the factors are + 3 and - 4 , since

3 × - 4 = - 12 and + 3 - 4 = - 1 , then

x² - x - 12 = (x + 3)(x - 4) ← in factored form

The simplest form of a^2-ab is given by 3x^3 + x^2 + 6x - 9.

We have given that,

a = x^2,

b = 3x + 2,

c = x – 3

We have to determine ab- c^2.

A fraction is in its simplest form when the numerator and the denominator have no common factors besides one.

ab- c^2

[tex]=x^2(3x+2) - (x-3)^2\\ =3x^3 + 2x^2 - (x^2 - 6x + 9) \\=3x^3 + 2x^2 - x^2 + 6x - 9 \\=3x^3 + x^2 + 6x - 9\\[/tex]

The simplest form of a^2-ab is given by 3x^3 + x^2 + 6x - 9.

To learn more about the simplest form visit:

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In other words, it shows when the ball hits the ground.

Answer:

-2,4

Step-by-step explanation:

to do a reflection across the y axis, apply -x,y to your coordinates

Answer:

  A. horizontal velocity is constant at 25 m/s in every interval

  B. downward velocity increases by 9.8 m/s each second, to 19.6 m/s, 29.4 m/s, 39.2 m/s, 49.0 m/s

Step-by-step explanation:

Since the ball is not rocket-powered, it has no acceleration in the horizontal direction. (We ignore slowing due to air friction.) The horizontal velocity remains constant at 25 m/s.

__

The vertical acceleration is given as 9.8 m/s² in the downward direction. That is, each second the ball is in motion, its velocity downward increases by 9.8 m/s. The table can be filled with ...

  t = 2 s, v = -19.6 m/s

  t = 3 s, v = -29.4 m/s

  t = 4 s, v = -39.2 m/s

  t = 5 s, v = -49.0 m/s

__

The sign is negative because the direction is downward. Positive is up.

Answer:

3^2=9 5^3=125 9^2=81

Step-by-step explanation:

exponent is just multiplying the base by itself however we many times the exponent's (the small number on the top right of the base) value is

base-->5^3<--exponent

3^2=3×3=9

5^3=5×5×5=125

9^2=9×9=81

example

6^4=6×6×6×6=1296

[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &28000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years\dotfill &5\\ \end{cases} \\\\\\ A=28000(1 - 0.09)^{5}\implies A=28000(0.91)^5\implies A\approx 17472.90[/tex]

Answer:

845 miles

Step-by-step explanation:

Hope this helps!

By solving a quadratic equation, we will see that the width of the walkway is 3ft.

Remember that for a rectangle of length L and width W, the area is:

A = W*L

Now, we know that for our garden we have:

W = 8ft

L = 12ft

If we add a walkway of width x around the garden, then the new measures are:

W' = 8ft + 2x

L' = 12ft + 2x

So the area is:

A' = ( 8ft + 2x)*( 12ft + 2x)

And we know that it is equal to 192 ft^2, then:

192 ft^2 = ( 8ft + 2x)*( 12ft + 2x)

Now we can solve this for x.

192ft^2 = 96ft^2 + 4x^2 + 20ft*x

0 = 96ft^2 - 192ft^2 + 20ft*x + 4x^2

0 = -96ft^2 + 20ft*x + 4x^2

This is a quadratic equation, and the solutions are given by the Bhaskara's formula:

[tex]x = \frac{-20ft \pm \sqrt{(20ft)^2 - 4*4*(-96ft^2)} }{2*4} \\\\x = \frac{-20ft \pm 44ft}{8}[/tex]

We only take the positive solution, so we get:

x = (-20ft + 44ft)/8 = 3ft

So the width of the walkway is 3ft.

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