Answer:
16.18 mph
Explanation:
the speed of elevators =
(783×3600)/(33×5280) =
2,818,800/174,240 = 16.18 mph
a 4,000 kilogram rocket has accelerates at a rate of 35 m/s2. How much force is required to do this?
[tex]\Large{\underline{\sf Given:-}}[/tex]
Mass=4000kgAcceleration=35m/s^2[tex]\Large{\underline{\sf To\:Find:-}}[/tex]
Force[tex]\Large{\underline{\sf Formula:-}}[/tex]
[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]
[tex]\Large{\underline{\sf Solution:-}}[/tex]
[tex]\\ \sf\longmapsto Force=4000(35)[/tex]
[tex]\\ \sf\longmapsto Force=14000N[/tex]
PLEASE HELP DUE IN ALMOST AN HOUR PLEASE
Answer:
Below
Explanation:
4. You can use this formula to calculate the acceleration of an object
acceleration = velocity / elapsed time
Plugging our values in....
acceleration = 1700 m/s / 25 s
= 68 m/s^2
5. You can use this formula to calculate the final velocity of an object
finalvelocity = initialvelocity + (acceleration) (time)
Plugging our values in....
finalvelocity = 1.5 m/s + (2.4 m/s^2) ( 3 seconds)
= 8.7 m/s
Hope this helps! Best of luck <3
Forgot how to do this please help
Answer:
213K = 100. 56
189K = 87. 22
113K = 45
201K = 93. 88
Explanation:
The formula for F to C = ( 1. 8*C) + 32
So, C = (F - 32) ÷ C
A car starting from rest accelerated at a rate of 0 .5 m/s up to 2 km what would be the final velocity of the car and how much time would it take to cover 1.6
Using third equation of kinematics
[tex]\\ \rm\longmapsto v^2=u^2+2as[/tex]
[tex]\\ \rm\longmapsto v^2=0^2+2(0.5)(1.6)[/tex]
[tex]\\ \rm\longmapsto v^2=1.6[/tex]
[tex]\\ \rm\longmapsto v=\sqrt{1.6}[/tex]
[tex]\\ \rm\longmapsto v=0.4m/s[/tex]
Now using 1st equation of motion
[tex]\\ \rm\longmapsto v=u+at[/tex]
[tex]\\ \rm\longmapsto t=v-u/a[/tex]
[tex]\\ \rm\longmapsto t=\dfrac{0.4-0}{0.5}[/tex]
[tex]\\ \rm\longmapsto t=\dfrac{4}{5}[/tex]
[tex]\\ \rm\longmapsto t=0.8s[/tex]
Answer:
Using third equation of kinematics
[tex]\begin{gathered}\\ \rm\longmapsto v^2=u^2+2as\end{gathered}[/tex]
⟼v
2
=u
2
+2as
[tex]\begin{gathered}\\ \rm\longmapsto v^2=0^2+2(0.5)(1.6)\end{gathered}[/tex]
⟼v
2
=0
2
+2(0.5)(1.6)
5 sentences about the importance of investigatory project
Answer:
Student science investigatory projects provide students practical experience in using the scientific method and help stimulate their interest in scientific inquiry. Given the benefits society can realise from professional scientific inquiry, such goals in themselves have importance.
Hope it helps you.PLEASE HELP
A 2.80 kg mass is dropped from a
height of 4.50 m. Find its kinetic
energy (KE) when it is 3.00 m
above the ground.
Answer:
41.16J
Explanation:
m =2.8 kg
h1 = 4.5 m
h2 = 3 m
PE at top = mgh1= 4.5mg
PE at 3 m = mgh2= 3mg
energy is conserved los in PE = gain in KE
KE at 3 m above the ground
= mg(4.5 - 3) J
= 2.8 kg*9.8m/s^2*1.5 m
= 41.16 joules
Answer: 42 m/s
Explanation:
m=2.8 kg , V1=0 m/s , h1=4.5 m , h2=3 m , V2=? m/s
E1 = E2 >>> K1 + U1 = K2 + U2
Kinetic Energy (KE) = K = [tex]\frac{1}{2}[/tex] m [tex]V^{2}[/tex] Potential Energy (PE) = U = mgh
[tex]\frac{1}{2}[/tex] m [tex]V1^{2}[/tex] + mg[tex]h_{1}[/tex] = K2 + mg[tex]h_{2}[/tex] >>> V1=0 >> K1=0 >>> K2 = -mgΔh
K2 = 2.8 kg × 10 m/s2 × 1.5 m = 42 m/s
A carver begins work on a block of granite that has volume of 1000 cm3 and a density of 5 g/cm3. What is the mass of the block of granite?
Answer:
D (density) = M (mass) / V (volume)
M = D * V = 5 g / cm^3 * 1000 cm^3 = 5000 g
The mass of the block of granite is 5000 grams.
We know that density is defined as mass divided by volume. So, we can write the following equation:
Density = Mass / Volume
We are given that the density of the granite is 5 g/cm³ and the volume is 1000 cm³.
We can plug these values into the equation to solve for the mass:
5 g/cm³ = Mass / 1000 cm³
Mass = (5 g/cm³)(1000 cm³)
Mass = 5000 grams
1 cm³ of granite has a mass of 5 grams. So, a block of granite with a volume of 1000 cm³ will have a mass of 5000 grams.
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If a person walks forwards five meters but then moves back one meter,
what is their displacement?
Answer:
4
Explanation:
because when u have 5 then take 1 away u have 4
If a taxi cab travels 45.8 m/s for 146 s, how far did it travel?
Your Answer:
Answer:
6.68 km
Explanation:
distance = speedxtime
45.8 x 146
6686.6 m
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Explanation:
I hope it helped U
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Compare and contrast scientific inquiry "skill and process".
Answer:
The inquiry process takes advantage of the natural human desire to make sense of the world... This attitude of curiosity permeates the inquiry process and is the fuel that allows it to continue. Process skills are not used for their own sake.
What is the acceleration of the car in initial 2 seconds [ans:20m/s^2
Answer:
[tex]accelaration = \frac{v}{t} \\ = in \: intial2sec \: v = 40 \\ a = \frac{40}{2} = 20 \frac{m}{ {se}^{2} } \\ thank \: you[/tex]
Answer:
20 m/s^2
Explanation:
v = u + at
Velocity:-
u = 0
v2 = 40
v = v2 - u = 40 - 0 = 40
Time:-
t2 = 2
t1 = 0
t = t2 - t1 = 2 - 0 = 2
Substituting v and t in formula,
v = u + at
40 = 0 + (a)(2)
2a = 40
=> a = 40/2
=> a = 20
You have 50L of water, it froze. So find its new volume. Density of water is 1000kg/m^3 or 1kg/L, density of ice is 920kg/m^3 or 0.92kg/L.
Answer:
D (density) = Mass / Volume
V (ice) = Mass / Density = 50000 g / .92 kg / L
V = 50 kg / .92 kg / L
1 Liter of water weighs 1 kilogram = 50 L weighs 50000 g
V = 54.3 L the mass does not change upon the change of phase (freezing)
write the value of g on the moon and Jupiter
Answer:
The value of g on the moon is 1.625 m/s2 and the value of the g on the jupiter is 2.528g.
Jupiter's surface gravity is 24.79/s or 2.528 g .
The acceleration due to gravity on the surface of the moon is approximately 1.625m/s .
hope this helps you
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Name the component that the resistance decreases as the current increases.
Answer:
LDRs and thermistors
Light dependent resistors or LDRs are made of semiconductor material. Their resistance decreases as the light intensity increases. ... Their resistance decreases as the temperature increases.
science (Friction/Forces)
which option is correct?
Answer:
A
Explanation:
At constant speed, acceleration=0
From the formula, Fnet=ma (Resultant force= mass x acceleration), sub a=0
Fnet=0
Since the resultant force=0, the pushing force is equal to the frictional force
The same 200 N force acts on an area greater than 2m2.
What happens to the pressure?
the pressure is (200 N)/(10 cm2)×(100 cm/M)2=200,000 pa
What will be the gravitational force between the bodies if the mass of each is doubled and the distance between them is halved?
Explanation:
if the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on.
What happens to the weight of an object when it is taken from Earth to the Moon? why ?
Answer:
So, if a body is taken to moon, the moon attracts the body with a force less as compared to the attraction force by the earth. Hence the weight decreases.
Explanation:
Hopefully it is helpful...how do you calculate the numerical value of physical quantity
The value of a physical quantity is normally expressed as an implied product of a numeric value and a unit of measurement.
There are three categories to consider:
There is no explicit unit of measurement included. Examples of this would include index of refraction of a medium and the specific gravity of a substance (which is ratio of the density of the material divided by the density of some reference material, usually water at some specified temperature). In this category, there is an implied measurement unit of 1 . It is usually not written because 1 times any number is that same number, so it is pointless to write the “times 1”. The value of an index of refraction is simply a number, and that number is all you write for the quantity value. That number is the numerical value of the physical quantity. It is only slightly more complicated for specific gravity, because you are dividing one density by another, and both values should be expressed in the same units of measurement, and the division of one by the other cancels out those units, leaving you with 1 as the overall measurement unit.
For plane angles, there is a relationship between the length s of the arc of a circle, the radius r of that circle, and the angle a subtended by the arc at the circle center:
a = s/r
with the angle a being measured in the unit of radians. (To write the formula for some other angular unit requires incorporating a numeric factor, which is basically a conversion factor from radians to degrees,) Thus, if you have a circle of radius 3 m and an arc of 6 m on that circle, the the angle subtended or formed is:
(6 m)/(3 m) = 2, but we said this is the number of radians, so it is 2 rad.
Notice, we are dividing a length by a length (both the arc length and the radius being lengths), so if we use the same measurement unit for both lengths (regardless that unit being meters, feet, parsecs, or anything else), the two units cancel each other out upon division. This means that the unit we are calling radian is like with specific gravity in #1—it has the value 1. Indeed, we see the formula gives us 2 and we know that it is 2 rad, and the only way we can have them be the same, 2 rad = 2, is if the unit radian is actually just a funny, special name for the number 1. Why do we give the number 1 a special name here, unlike in category #1? That is because some inexperienced people find the concept of radian to be strange and inconvenient. They would rather use degrees, or arcminutes, or arcseconds, or semicircles, or some other such unit, and they all have different sizes. For example, a full circle is 2π rad and it is also 360°. Therefore, since both equal one circle of rotation, they must be equal to each other:
360° = 2π rad. Divide both sides by 360 to get:
1° = (2π/360) rad = (π/180) rad. Now, we saw above that rad = 1, so:
1° = (π/180) rad = (π/180) × 1 = π/180.
Thus, like the radian, the degree is also a number—not 1 though, but rather π/180, which cannot be “thrown away” because π/180 times a number does not yield back the original number.
Thus, 30° = 30 × π/180 = π/6 = π/6 × 1 = π/6 rad.
This is the explanation as to when we express an angle in degrees, we must write the ° symbol or spell out degrees, whereas when we express the angle in radians, we may either explicitly write rad or we may leave it off. Unfortunately secondary school geometry textbooks do not seem to understand this point and typically leave off the mandatory ° symbol. That usually gets straightened out when radians are presented—typically later in the second year of algebra or in trigonometry, but it becomes something necessary for students to unlearn the incorrect and learn the correct. Thus, if an angular unit is included, you can convert that angular unit into a real number and multiply by the numeric part of the physical quantity value to the the numeric value of the physical quantity. (And absence of angular unit implies radians, which have numeric value 1, so the numeric value of the quantity is just the numeric value that is present.
Solid angles work similarly, involving area divided by area. The steradian (sr) is the unit that has value 1.
Circle the letter of each sentence that is a scientific question
a. At what temperature does water boil?
b. When does the sun rise on April 3?
c. How can my team work better together?
d. Why does she like science more than he does?
Answer:
a - temperature
b sun ( how things work science)
Answer:
(A)
Explanation:
because they are asking at temperature does water boil they can do experaments to find or they can use science
on the way to school the bus speeds from 20 m/s to 36 m/s in 4 seconds. what distance does the bus cover in this time frame
Answer:
d=s
t
d=36
4
d=10m/s
Explanation:
distance is equal to speed over t therefore 36 divide by 4 is 10
A girl walks 150 m from home to school in an easterly direction. She then turns and walks away 25 m to a shop what distance did the girl walk?
Answer:
175 miles
Explanation:
because when the girl walked from point A to B which is 150 miles and walks away 25 miles to a shop.
The force of gravity on the moon is only 16.6% the force of gravity on Earth. For each item listed in the table below, fill in what its weight would be on the moon?
==> Take an Earth weight. Don't forget the unit.
==> Multiply it by 0.166 .
==> The product is its Moon weight. Don't forget the unit.
Example:
If I weigh 1,000 lbs on Earth.
Multiply 1,000 lbs by 0.166 .
I weigh 166 lbs on the Moon
The complete table is as follows -
ITEM W(E) W(M)
Apple 150 g 25 g
Hammer 1.5 lbs 0.25 lbs
Person 180 lbs 30 lbs
Blue whale 200 tons 33.3 tons
We have the force of gravity on the moon is only 16.6% the force of gravity on Earth.
We have to fill the table given in the question.
Define Gravity in Physics.In physics, gravity is a fundamental interaction which causes mutual attraction between all things with mass or energy. The gravitational force between two bodies of mass 'm' and 'M' separated by a distance 'r' apart is given by -
[tex]$F = \frac{GMm}{r^{2} }[/tex]
According to the question, we have -
Force of gravity on the moon is only 16.6% the force of gravity on Earth.
This means that for an object of mass 'm' -
F(M) = 16.6% of F(E)
This means that a person would weigh six times less on the moon than they do on Earth -
W(moon) = [tex]\frac{1}{6}[/tex] W(earth)
Let's complete the table -
ITEM W(E) W(M)
Apple 150 g 1/6 x 150 = 25 g
Hammer 1.5 lbs 1/6 x 1.5 = 0.25 lbs
Person 180 lbs 1/6 x 180 = 30 lbs
Blue whale 200 tons 1/6 x 200 = 33.3 tons
Hence, the complete table is given above.
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a body is moving with uniform velocity of 15 m/s calculate its velocity after it travels 100m in 20 second
Since the body is moving with uniform velocity, its velocity after it travels 100 m in 20 s is 15 m/s.
Hope it helps! Please do comment
How many significant figures are in each number?
.0054
78.0
09002
.993
Answer:
0.0054 » two significant figures.
78.0 » three significant figures.
0.09002 » four significant figures.
0.993 » three significant figures.
Explanation:
[tex].[/tex]
the density of silver at 0°C is 10310 kg/m^3 and the coefficient of linear expansion is 0.000019/°C . calculate its density at 100°C ?
Explanation:
The relative change in length of the edges of a cube are the coef times the change in temperature.
One meter expands to (1 + coef x 100C) = 1.0019 meter
Divide the mass by this number cubed to correct for volume expansion.
10310 kg / 1.00571 = 10251 kg/m3
1) Calculate average speed (in meters/sec) if a golf cart runs 140 meters in 10 seconds
2) Calculate the average speed in km/hr of Charlie who runs to the store 4km away in 30 mins
3)calculate the distance in km that Charlie runs if he maintains the average speed from question 2 for 1 hour
4) a bicycle rider travels 50.0km in 2.5 hours. What is the cyclists average speed?
5)what is the average speed ( in mph) of the car that traveled a total of 200 miles in 5.5 hours
Answer:
Your father has just built a new house for the family. Write a letter to your either brother who lives abroad describing the new house and the prestige has accorded your family
5) Two knights are jousting on horseback. It takes 2.2 seconds for the knights to meet in the middle
of the course and collide. If one knights horse ran at 6m/s and the other's horse at 9m/s, then
how far apart must they have been begin with?
Answer:
33m
Explanation:
Step 1: Whats going on?
We know that since they meet in the middle, and dont stop, that both knights take the same time to travel to the middle. This means that if they are traveling at a constant speed we can easily calculate the distance each travels
Step 2: Model it with Equations
General equation: V = D/t [m/s]
T = D1 + D2 = V1*t + V2*t = t * (v1 + v2)
Step 3: Sub in knowns
T = 2.2 s* (6m/s + 9m/s)
T = 33m
0.054x2.33x90............
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