The Henry's law constant for H2 is 8.1×10−4 Matm at 25∘C. What pressure of hydrogen is needed to maintain a H2 concentration of 0.42 M?

When a reaction vessel initially containing 68.0 kg [tex]CH_4[/tex] and excess steam yields 16.9 kg [tex]H_2[/tex], the percent yield would be 49.8%

Recall that: percent yield = yield/theoretical yield x 100%

From the equation of the reaction:

[tex]CH_4 + 2H_2O --- > CO_2 + 4H_2[/tex]

The mole ratio of methane to steam is 1:4.

Mole of 68.0 kg methane = 68000/16.0 = 44239.4 moles

Equivalent mole of  [tex]H_2[/tex]= 16,957.6 moles

Mass of 16,957.6 moles  [tex]H_2[/tex] = 16,957.6 x 2 = 33,915.2 grams or 33.92 kg

Percent yield = 16.9/33.92 x 100% = 49.8%

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The percentage yield of the reaction that yields 16.9 kilograms of Hydrogen gas, H₂ is 66.3%

CH₄ + H₂O —> CO + 3H₂

Molar mass of CH₄ = 16 g/mol

Mass of CH₄ from the balanced equation = 1 × 16 = 16 g = 0.016 Kg

Molar mass of H₂ = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g = 0.006 Kg

SUMMARY

From the balanced equation above,

0.016 Kg of CH₄ reacted to produce 0.006 Kg of H₂

From the balanced equation above,

0.016 Kg of CH₄ reacted to produce 0.006 Kg of H₂

Therefore,

68 Kg of CH₄ will react to produce = (68 × 0.006) / 0.016 = 25.5 Kg of H₂

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (16.9 / 25.5) ×100

Percentage yield = 66.3%

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Answer:

Explanation:

Universal indicator. The universal indicator turns orange in acidic solutions with a pH of  

Answer:

57.6g

Explanation:

In the balanced equation H2O and Mg(OH)2 have the same coefficient (1) so we know that 3.2 moles of H2O react to form 3.2 moles of Mg(OH)2. Now we just have to calculate the mass of the H2O which we can do by finding the molar mass from the periodic table. For this just add the molar masses of the consituent atoms. (2(1)+1(16))=18g/mol H2O. Now that we know the molar mass we just have to multiply it by the amount of moles. 18*3.2=57.6g H2O

Answer:

It depends

(plum will spoil more quickly at warm temperatures)

Explanation:

Answer:

Sorry I'm late man, but I bombed this quiz and here's the actual answers

1. functional group (top row); uses (bottom row)

2. Uses of Functional Groups Involving Oxygen

3. carbonyl

4. N is single bonded to R, and single bonded twice to H. (Or B)

5. RCOOH

6. a carboxylic acid and an amine

7. ethylamine

8. alchohol

9. alkyl halide

10. A central carbon is double bonded to O above, and single bonded to R below left and to O R prime below right. (Or B again)

Explanation:

Keep grinding. I know I will. I'm going to have to pull some all nighters in order to catch up before I work this summer. I'm so ahead on my classes and it still looks like I'll be doing school til the middle of June. You're not alone (If you're in the same situation as me that is). Good luck!

Answer:

I think it is alkyl halide

Explanation:

Edg 2022

Hazardous materials are grouped into classes identifying their similarities in composition and structure.

The hazardous materials are grouped into classes in order to tell us about the severity of hazard and it is done on the basis of similarity in composition.

So we can conclude that hazardous materials are grouped into classes identifying their similarities in composition and structure.

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Answer:

See answers below

Explanation:

-44.3 kj/mole   *   x moles =  -  18.7 kj

solve for x = .422 mole  dissolved

Mole weight of  NaOH is

                     Na = 22.989     O = 15.999   H = 1.008    gm/mole

                            = ~~ 40 gm/mole   for NaOH

40 gm / mole   *  .422 mole = 16.88 gm  of NaOH

Answer:This reaction will be followed by TLC to monitor the progress of the oxidation. The camphor is then reduced by sodium borohydride to give the isomeric alcohol,

Explanation:

hopes this helps<33

The collision and decomposition of 2 ammonium nitrate molecules results in the formation of 2 molecules of [tex]N_2O[/tex] and 4 molecules of [tex]H_2O[/tex]

Ammonium nitrate decomposes to produce nitrous oxide and water according to the following equation:

[tex]NH_4NO_3 --- > N_2O + 2H_2O[/tex]

In the above, a mole of ammonium nitrate decomposes to form a mole of nitrous oxide and 2 moles of water.

If moles of ammonium nitrate decomposes, the equation becomes:

[tex]2NH_4NO_3 ---- > 2N_2O + 4H_2O[/tex]

Thus, 2 moles of nitrous oxide and 4 moles of water would be formed.

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Answer:

It has two isomers; n-butane and isobutane. Here n-butane is a straight-chain compound with four carbon atoms bonded with single covalent bonds. Explanation: Butane is an alkane with four carbon atoms so molecular formula is C4H10.

Explanation:

Phosphorus has a larger atomic mass is your answer. :)

Explanation:

Normal saline contains Na+ and Cl-. Extracellularly,there is more Na+ and Cl- than intracellularly and most often during loss of bodily fluid,it is extracellular fluid that is lost and so the Na+ and Cl- ions in saline replenish these. Even if the loss of fluid is intracellular,it can still be replenished (passively )from the extracellular fluid into the intracellular fluid. Conversely, distilled water is just water which lacks any special electrolytes to carry out these functions as the normal saline

2NOCI(9) + 2NO(g) + Cl2(9) shows decrease in entropy.

Entropy in thermodynamic refers to the degrees that represent the absence of system's thermal energy that is not available to perform mechanical work, which is the degree of disorder or randomness in the system.

Therefore, 2NOCI(9) + 2NO(g) + Cl2(9) shows ddecrease in entropy because it shows degree of disorderliness is low

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Answer:

1.5 moles

Explanation:

O   mole weight = 15.999

O2 mole weight = 2 * 15.999 = 31.998 gm

48 / 31. 998  = ~ 1.5 moles

Answer:

v2 = 9.69L

Explanation:

p1 v1/t1 = p2 v2/t2

P = Pressure

V = Volume

T = Temperature

T = 273k

P = 1 atm

1.23 x 7.75/273k = 1xv2/273

The slashes I used represent as fractions. (:

72 g of Copper(i) oxide will be produced by 40 g of CuO base on the law of conservation of mass.

The law of conservation of mass states that mass remains constant at the end of every reaction.

The equation of the reaction is given below:

[tex]4CuO → 2Cu_2O + O_2[/tex]

Based on the equation of reaction, 4 moles of copper (ii) oxide produces 2 moles of copper (i) oxide.

Mass of 4 moles of CuO = 4 × 80 = 160 g

Mass of 2 moles of copper (i) oxide = 2 × 144 g = 288 g

Mass of Copper(i) oxide produced by 40 g of CuO will be: 40 × 288/160 = 72 g

Therefore, 72 g of Copper(i) oxide will be produced by 40 g of CuO.

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Answer:

The parts of the system is the mouth, throat or the pharynx if you want the scientific term, esophagus, stomach, small intestine, large intestine, rectum.

if you want just say intestine for those answers best if you say small and large though

Answer:

Answer:

As the plates travel horizontally past one other, no crust is formed nor destroyed.

Explanation: tectonic plates

Answer:

neutron number

Explanation:

^

In the titration of sodium oxalate with potassium permanganate the pink color change is due to shift in equilibrium position of the reaction

Chemical equilibrium is the equilibrium that exists between chemical species in which the rate of forward reaction is equal to the rate of backward reaction.

The pink color change in the that occurs in the titration of sodium oxalate with potassium permanganate is due to shift in equilibrium position of the reaction.

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Answer:

25.91 L

Explanation:

P1V1= P2V2

748 (26.5) =  765 ( V2)      V2 = 25.91 LITERS  

Answer:

35°C would have the highest velocity because it's temperature is lesser hence the inter molecular forces between it molecules will be stronger and the velocity of the molecules will be lower than the rest.

the 75°C one would have the highest flow rate because its molecules will have a higher velocity and the inter molecular force between them will be less stronger

Answer:

After 30 minutes have passed, the solution inside the dialysis tubing and the solution in the beaker will be tested for glucose and starch

-The presence of glucose will be tested with Benedict's solution, Testape®, or Clinistix

Answer:

C.) They act as catalysts.

The name of the compound which is formed by the combination of nitrogen, carbon and hydrogen atoms is ethylamine.

Compounds are the substances which are prepared by the mixture of different elements.

In the question it is described that first nitrogen atom is attached with 2 hydrogen atoms and one lone pair of electrons as [tex]\ddot{NH_{2}}\\[/tex]. Now with this molecule one carbon atom with two hydrogen atoms are attached (CH₂) and with this carbon atom another carbon atom with three hydrogen atoms are attached as (CH₃).

So obtained compound is NH₂-CH₂-CH₃ named as ethyl amine.

Hence name of the given compound is ethylamine.

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Answer:

The mass of SO₃ formed is 120 g

Explanation:

The balanced equation for the reaction is given below:

2SO₂ + O₂ —> 2SO₃

Next, we shall determine the mass of SO₂ that reacted and the mass of SO₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of SO₂ = 32 + (16×2)

= 32 + 32

= 64 g /mol

Mass of SO₂ from the balanced equation = 2 × 64 = 128 g

Molar mass of SO₃ = 32 + (16×3)

= 32 + 48

= 80 g /mol

Mass of SO₃ from the balanced equation = 2 × 80 = 160 g

Thus,

From the balanced equation above,

128 g of SO₂ reacted to produce 160 g of SO₃.

Now, we will get the mass of SO₃ by the reaction of 96 g of SO₂. This can be obtained as follow:

From the balanced equation above,

128 g of SO₂ reacted to produce 160 g of SO₃.

Therefore, 96 g of SO₂ will react to produce = = 120 g of SO₃.

With this, the mass of SO₃ formed is 120g

Answer:

false

Explanation:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. Its pH changes very little when a small amount of strong acid or base is added to it. A buffer protects from ph increasing.

Chemical buffers are substances that are necessary to preserve the constancy of pH in various biological and chemical systems. Therefore, the given statement is True.

They are composed of either a weak base and its conjugate acid, or vice versa. The weak base component of the buffer reacts with the acid upon addition, reducing the pH rise. Similarly, when a base is added, the weak acid component of the buffer reacts with it to prevent the pH from falling significantly.

This ability to withstand pH variations is essential for preserving the proper operation of biological systems, such as blood pH in the human body, as well as in other laboratory and industrial operations where it is necessary to preserve a stable pH for best results.

Therefore, the given statement is True.

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