The correct answers are (a) Angular frequency of motion = 3.98 rad/s; rounded off to two decimal places = 4.00 rad/s. (C)(b) Total Mechanical Energy of Pendulum = 0.1124 J (B)(c) Bob's speed as it passes the lowest point of the swing = 0.556 m/s (C).
Simple pendulum length (L) = 0.79m
Mass of the bob (m) = 0.24kg
Angle pulled = 8.50
Now we need to find some values to solve the problem
Answer: 0.132m
Using the formula of displacement of simple harmonic motion
x = Acosωt .............(i)
where
A = amplitude
ω = angular frequency
t = time
To get the angular frequency, let’s consider the initial condition: at t = 0, x = A and v = 0
∴ x = Acos0
∴ A = x
Let’s differentiate equation (i) with respect to time to get the velocity
v = -Aωsinωt .............(ii)
At x = 0, v = Aω
∴ Aω = mghmax
∴ Aω = mg
∴ ω = g/L
= 3.98 rad/s
Total Mechanical Energy of Pendulum at its Lowest Point
The potential energy of the bob when it is at the lowest point is zero.
E = K.E + P.E
where
E = Total energy = K.E + P.E
K.E = Kinetic energy = 1/2 mv²
P.E = Potential energy
At the highest point, P.E = mghmax; at the lowest point, P.E = 0
Therefore, E = 1/2 mv² + mghmax
⇒ E = 1/2 × 0.24 × v² + 0.24 × 9.8 × 0.132...
∴ E = 0.1124 J
Speed of the bob as it passes the lowest point of the swing
Consider the equation for velocity (ii)
v = -Aωsinωt
Let’s plug in t = T/4, where T is the time period
v = -Aωsinω(T/4)
∴ v = -Asinπ/2 = -A
∴ v = -ωA= -3.98 × 0.132...
∴ v = 0.556 m/s
Therefore, the correct answers are:(a) Angular frequency of motion = 3.98 rad/s; rounded off to two decimal places = 4.00 rad/s. (C)(b) Total Mechanical Energy of Pendulum = 0.1124 J (B)(c) Bob's speed as it passes the lowest point of the swing = 0.556 m/s (C).
To know more about frequency visit:
https://brainly.com/question/30677308
#SPJ11
A sinusoidal voltage V(t) = (170.) sin(1884 t) is applied to a series LCR circuit with L= 100. mH, C =5.00. uF, and R= 200.0 12. Find the rms voltage and the frequency of the source.
The rms voltage represents the effective voltage of an AC waveform. It is calculated by dividing the peak voltage (Vm) by the square root of 2 (√2). In this case, the given peak voltage is 170 V.
Vrms = Vm/√2 = 170/√2 ≈ 120.2 V
The frequency of an AC waveform indicates the number of complete cycles it completes in one second. For an LC circuit, the frequency can be determined using the formula: f = 1/(2π√(LC)). Here, L represents the inductance and C represents the capacitance of the circuit.
f = 1/(2π√(0.1 × 5.00 × 10⁻⁶)) ≈ 1017.83 Hz
Therefore, the rms voltage of the source is approximately 120.2 V, and the frequency of the source is approximately 1017.83 Hz.
It's worth noting that these calculations assume an ideal scenario without considering factors like resistance, losses, or deviations from the theoretical model. However, they provide a good estimation for understanding the behavior of the given AC circuit.
know more about Waveform here : brainly.com/question/24224027
#SPJ11
An electronic device puts out 3.57 mA at 13.6kV. What is its power output in watts?
An electronic device puts out 3.57 mA at 13.6kV.The power output of the given electronic device is 48.552 W
Power output of the given electronic device is calculated by the formula: Power = Voltage × CurrentP = V × IWhere, P = Power in Watts, V = Voltage in volts and I = Current in Amperes. Power in Watts is calculated by multiplying voltage in Volts times current in Amps: 10 Amps of current at 240 Volts generates 2,400 Watts of power. This means that the same current can deliver twice as much power if the voltage is doubled.
Substituting the given values in the above formula: P = 13.6 kV × 3.57 mAP = 13.6 × 10³ V × 3.57 × 10⁻³ AP = (13.6 × 3.57) × 10⁰ WP = 48.552 W
The power output of the given electronic device is 48.552 W.
Learn more about power at
https://brainly.com/question/29575208
#SPJ11
An airplane propeller of total length L rotates around its center with angular speed w in a magnetic field B that is perpendicular to the plane of rotation. If the field is the earth's field of 0.50 G and the propeller turns at 200 rpm and is 2.8 m long, what is the potential difference between the middle and either end? Express your answer using two significant figures.
The potential difference between the middle and either end of the propeller is 1.72 V. Expressing this in two significant figures, we get 1.7 V.
The potential difference between the middle and either end of the propeller can be calculated using the following formula:
V = BL
where:
* V is the potential difference in volts
* B is the magnetic field strength in teslas
* L is the length of the propeller in meters
* ω is the angular velocity in radians per second
We know that the magnetic field strength is 0.50 G, which is equal to 0.0050 T. The length of the propeller is 2.8 m. The angular velocity can be calculated from the rotational speed using the following formula:
ω = 2πf
where:
* ω is the angular velocity in radians per second
* f is the rotational speed in revolutions per minute (rpm)
The rotational speed is 200 rpm. Substituting this into the formula for ω, we get:
ω = 2π(200 rpm) = 125.66 rad/s
Now we have all the information we need to calculate the potential difference. Substituting the values for B, L, and ω into the formula for V, we get:
V = (0.0050 T)(2.8 m)(125.66 rad/s) = 1.72 V
Therefore, the potential difference between the middle and either end of the propeller is 1.72 V. Expressing this in two significant figures, we get 1.7 V.
Learn more about potential difference with the given link,
https://brainly.com/question/24142403
#SPJ11
Task 1. V(2) at 470 nm equals 0,10. Calculate the luminous flux of 90 W monochromatic lamp radiating at 470 nm. Task 2. There are 20 luminaires in a room and 2 lamps in each luminaire. Luminous flux of each lamp is equal 2000 Im. Power installed of lighting installation equals 1000 W. Calculate luminous efficacy of a luminaire. Task 3. Compare incandescent lamps and fluorescent lamps
They are more expensive than incandescent lamps and have a cooler color temperature.
Task 1:
The luminous flux of a 90 W monochromatic lamp radiating at 470 nm can be calculated using the formula:
φ_v= P_v / V(λ)
Where, φ_v is the luminous flux in lumens, P_v is the radiant flux in watts, and V(λ) is the luminous efficacy for a given wavelength λ.
Here, V(λ) = 0.05 lumens/watt (at 470 nm).Thus,φ_v = 90 W / (0.05 lm/W) = 1800 lm
Therefore, the luminous flux of a 90 W monochromatic lamp radiating at 470 nm is 1800 lumens.
Task 2:
Luminous efficacy is defined as the ratio of luminous flux to power consumed. The luminous efficacy of a luminaire can be calculated using the formula:
η = φ_v / P
Where, η is the luminous efficacy in lumens/watt, φ_v is the luminous flux in lumens, and P is the power consumed in watts.
Here, the total luminous flux of the installation is:
φ_v = 20 × 2 × 2000
= 80,000 lm
And the total power consumed is:
P = 1000 W
Therefore, the luminous efficacy of a luminaire is:
η = 80,000 lm / 1000 W
= 80 lm/W
Task 3:
Incandescent lamps are lamps that produce light by heating a filament until it glows. They are relatively inexpensive, have a warm color temperature, and can be dimmed easily.
However, they are highly inefficient, converting only about 5% of the energy they consume into visible light.
The remaining 95% of the energy is released as heat, making them hot to the touch and wasteful to operate.
Fluorescent lamps, on the other hand, produce light by passing an electric current through a gas that contains mercury vapor.
The mercury vapor emits ultraviolet light, which is absorbed by a phosphorescent coating on the inside of the lamp, causing it to glow.
Fluorescent lamps are much more efficient than incandescent lamps, converting about 25% of the energy they consume into visible light.
They also last much longer than incandescent lamps and come in a wide range of sizes and shapes.
However, they are more expensive than incandescent lamps and have a cooler color temperature.
Learn more about expensive from the given link
https://brainly.com/question/31453515
#SPJ11
heat of vaporization =2257 J/g. (1) how much heat is required to warm the solid sample to its meitng point? (2) how much heat is required to meit the sample?
(1) The amount of heat required to heat the solid sample to its melting point can be calculated using the following formula:
Q = m × C × ΔT
where
Q is the amount of heat energy, m is the mass of the substance, C is the specific heat capacity, and ΔT is the temperature change.
Since we only want to know how much heat is required to warm the solid to its melting point, ΔT will be the difference between the initial temperature and the melting point temperature.
In this case, the information given is the heat of vaporization. To answer the question, we need to know the specific heat capacity of the substance. Let's assume that it is 1 J/g°C. The melting point of the substance is not given in the problem, so we'll also assume it is 0°C. Therefore:
Q = m × C × ΔTQ
= m × 1 J/g°C × (0°C - T)Q
= -mT J/g
where T is the melting point temperature in Celsius.
To find the value of T, we need to set the heat required to equal the heat of fusion, since that's the point at which the substance will start to melt. Therefore:-mT = -2257 J/gT = 2257 / m
The value of m is not given in the problem, so we cannot calculate T.
(2) How much heat is required to melt the sample?The amount of heat required to melt the sample can be calculated using the following formula:
Q = mL
where Q is the amount of heat energy, m is the mass of the substance, and L is the heat of fusion. In this case, we're given the heat of vaporization, which is not the same as the heat of fusion.
To calculate the heat of fusion, we can use the following formula:
L = Q / m
where Q is the heat of vaporization and m is the mass of the substance. Therefore:
L = 2257 J/g / m
Since the mass of the substance is not given in the problem, we cannot calculate the heat of fusion.
Learn more about heat of fusion: https://brainly.com/question/30403515
#SPJ11
(a) Write down the Klein-Gordon (KG) equation in configuration of space-time representation ? (b) What kind of particles does the equation describe? (4) Write down the quark content of the following particle und (a) proton (P) (b) Delta ∆++ c) Pion π- (d) Lambda ∆° (strangeness number = ad
e) Kaon K+ (strangeness number = +1)
(a) The Klein-Gordon equation in configuration space-time representation is:
∂²ψ/∂t² - ∇²ψ + (m₀c²/ħ²)ψ = 0.
(b) The Klein-Gordon equation describes scalar particles with spin 0.
(c) The quark content of the mentioned particles is as follows:
(a) Proton (P): uud.
(b) Delta ∆++: uuu.
(c) Pion π-: dū.
(d) Lambda ∆°: uds.
(e) Kaon K+: us.
(a) The Klein-Gordon (KG) equation in configuration space-time representation is given by:
∂²ψ/∂t² - ∇²ψ + (m₀c²/ħ²)ψ = 0,
where ψ represents the wave function of the particle, t represents time, ∇² is the Laplacian operator for spatial derivatives, m₀ is the rest mass of the particle, c is the speed of light, and ħ is the reduced Planck constant.
(b) The Klein-Gordon equation describes scalar particles, which have spin 0. These particles include mesons (pions, kaons) and hypothetical particles like the Higgs boson.
(c) The quark content of the particles mentioned is as follows:
(a) Proton (P): uud (two up quarks and one down quark)
(b) Delta ∆++: uuu (three up quarks)
(c) Pion π-: dū (one down antiquark and one up quark)
(d) Lambda ∆°: uds (one up quark, one down quark, and one strange quark)
(e) Kaon K+: us (one up quark and one strange quark)
In the quark content notation, u represents an up quark, d represents a down quark, s represents a strange quark, and ū represents an up antiquark. The number of subscripts indicates the electric charge of the quark.
Learn more about mesons:
https://brainly.com/question/13274788
#SPJ11
An astronomer observed the motions of some galaxies. Based on his observations, he made the following
statements. Which one of them is most likely to be false?
Take Hubble's constant to be 67 km/s/Mpc.
A. A galaxy observed to be movine away from us at a speed of 70
km/s is at a distance of about 1 Moc from us
B. A galaxy observed to be movine away from us at a speed of /000
km/s is at a distance of about 100 Mpc from Us
C. A galaxy observed to be movine away from us at a speed of /00
Xmas is at a distance of ahout O inc from us D.A galaxy observed to be movine away from us at a speed of
70000 km/s is at a distance of about 1 Gpc from Us.
An astronomer observed the motions of some galaxies. Based on his observations, the statement that is most likely to be false is D.
A galaxy observed to be moving away from us at a speed of 70,000 km/s is at a distance of about 1 Gpc from us.
Given Hubble's constant as 67 km/s/Mpc. We know that Hubble's law states that the speed of a galaxy is directly proportional to its distance from us. That is, v = H₀d,
where H₀ is the Hubble's constant.
A galaxy observed to be moving away from us at a speed of 70 km/s is at a distance of about 1 Mpc from us. So, statement A is true.
A galaxy observed to be moving away from us at a speed of 1000 km/s is at a distance of about 100 Mpc from us. So, statement B is true.
A galaxy observed to be moving away from us at a speed of 10000 km/s is at a distance of about 1500 Mpc from us. So, statement C is true.
However, a galaxy observed to be moving away from us at a speed of 70000 km/s would have a distance of about 1040 Mpc, not 1 Gpc (1 billion parsecs) as stated in option D. Therefore, statement D is most likely to be false.
Learn more about "Hubble's constant" refer to the link : https://brainly.com/question/14316817
#SPJ11
3. Define or describe each of the following terms. Include a diagram for each. (3 marks each) I. Reflection II. Refraction III. Diffraction IV. Doppler Effect
We can describe the 1.Reflection II. Refraction III. Diffraction IV. Doppler Effect
I. Reflection:
Reflection is the process by which a wave encounters a boundary or surface and bounces back, changing its direction. It occurs when waves, such as light or sound waves, strike a surface and are redirected without being absorbed or transmitted through the material.
The angle of incidence, which is the angle between the incident wave and the normal (perpendicular) to the surface, is equal to the angle of reflection, the angle between the reflected wave and the normal.
A diagram illustrating reflection would show an incident wave approaching a surface and being reflected back in a different direction, with the angles of incidence and reflection marked.
II. Refraction:
Refraction is the bending or change in direction that occurs when a wave passes from one medium to another, such as light passing from air to water.
It happens because the wave changes speed when it enters a different medium, causing it to change direction. The amount of bending depends on the change in the wave's speed and the angle at which it enters the new medium.
A diagram illustrating refraction would show a wave entering a medium at an angle, bending as it crosses the boundary between the two media, and continuing to propagate in the new medium at a different angle.
III. Diffraction:
Diffraction is the spreading out or bending of waves around obstacles or through openings. It occurs when waves encounter an edge or aperture that is similar in size to their wavelength. As the waves encounter the obstacle or aperture, they diffract or change direction, resulting in a spreading out of the wavefronts.
This phenomenon is most noticeable with waves like light, sound, or water waves.
A diagram illustrating diffraction would show waves approaching an obstacle or passing through an opening and bending or spreading out as they encounter the obstacle or aperture.
IV. Doppler Effect:
The Doppler Effect refers to the change in frequency and perceived pitch or frequency of a wave when the source of the wave and the observer are in relative motion.
It is commonly observed with sound waves but also applies to other types of waves, such as light. When the source and observer move closer together, the perceived frequency increases (higher pitch), and when they move apart, the perceived frequency decreases (lower pitch). This effect is experienced in daily life when, for example, the pitch of a siren seems to change as an emergency vehicle approaches and then passes by.
A diagram illustrating the Doppler Effect would show a source emitting waves, an observer, and the relative motion between them, with wavefronts compressed or expanded depending on the direction of motion.
Learn more about Reflection from the given link
https://brainly.com/question/4070544
#SPJ11
A gun fires a 8 gm bullet at 599 m/s. As a result, the gun gets a recoil speed of 17 m/s backwars. Considering that momentum is conserved for the system, what is the mass of the gun in kg? Write your answer in one decimal point.
The mass of the gun is approximately 0.3 kg (rounded to one decimal point). To solve this problem, we can apply the principle of conservation of momentum.
To solve this problem, we can apply the principle of conservation of momentum.
According to the conservation of momentum, the total momentum before the bullet is fired is equal to the total momentum after the bullet is fired.
Let's denote the mass of the gun as "M" and the mass of the bullet as "m". The initial velocity of the gun is 0 m/s, and the initial velocity of the bullet is 599 m/s. The final velocity of the gun-bullet system (considering both the gun and the bullet together) is 17 m/s.
Using the conservation of momentum, we can write the equation:
0 + m * 599 m/s = (M + m) * 17 m/s
Simplifying the equation:
599m = 17(M + m)
Now we need to solve for the mass of the gun (M). We can rearrange the equation as follows:
599m = 17M + 17m
582m = 17M
M = (582m) / 17
Substituting the mass of the bullet as 8 grams (0.008 kg), we can calculate the mass of the gun:
M = (582 * 0.008) / 17
M ≈ 0.2735 kg
Therefore, the mass of the gun is approximately 0.3 kg (rounded to one decimal point).
To learn more about conservation of momentum click here
https://brainly.com/question/30483812
#SPJ11
A tennis ball on Mars, where the acceleration due to gravity is 0.379 of a g and air resistance is negligible, is hit directly upward and returns to the same level 9.50 s later.
How high above its original point did the ball go?
The maximum height reached by the tennis ball above its original point is 168.8605 meters.
Here, we are going to find out how high a tennis ball would go above its original point if it's hit directly upward and returns to the same level 9.50 seconds later. The acceleration due to gravity on Mars is 0.379 of a g. To solve this problem, we need to use the kinematic equations of motion and the equation to calculate the maximum height reached by an object that is launched vertically upwards using the acceleration due to gravity.
Using kinematic equation, we have:
s = ut + (1/2)at²
Where:
s = height or displacement
u = initial velocity = 0 (the ball was hit directly upward)
a = acceleration due to gravity on Mars = 0.379 x 9.81 m/s² = 3.73259 m/s²t = time taken by the ball to reach the maximum height or displacement = 9.50 s
Substituting the given values, we have:s = (0 × 9.50) + (1/2) (3.73259) (9.50)²s = 168.8605 m
To know more about original point:
https://brainly.com/question/11524720
#SPJ11
A satellite in Earth orbit has a mass of 100 kg and is at an altitude of 2.00 × 10⁶m.(b) What is the magnitude of the gravitational force exerted by the Earth on the satellite?
The magnitude of the gravitational force exerted by the Earth on the satellite is approximately 1.32 × 10⁴ N.
The gravitational force between two objects can be calculated using the formula:
F = G * (m1 * m2) / r²
where F is the gravitational force, G is the gravitational constant (approximately 6.674 × 10⁻¹¹ N m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
In this case, the mass of the satellite (m1) is 100 kg, and the distance between the satellite and the center of the Earth (r) is the sum of the Earth's radius (6.37 × 10⁶ m) and the altitude of the satellite (2.00 × 10⁶ m), which equals 8.37 × 10⁶ m.
Plugging these values into the formula, we get:
F = (6.674 × 10⁻¹¹ N m²/kg²) * (100 kg * 5.97 × 10²⁴ kg) / (8.37 × 10⁶ m)²
≈ 1.32 × 10⁴ N
The magnitude of the gravitational force exerted by the Earth on the satellite is approximately 1.32 × 10⁴ N. This force keeps the satellite in orbit around the Earth.
To learn more about gravitational force, visit
https://brainly.com/question/14874038
#SPJ11
Three forces acting on an object are given by F,- (-2.35i + 5.503) N., (5.501 -2.41) N, and F,- (-461) N. The object experiences an acceleration of magnitude 3.60 m/s². . (a) What is the direction of the acceleration? ________________ (counterclockwise from the +x-axis) (b) What is the mass of the object? ________________kg (c) If the object is initially at rest, what is its speed after 15.0 ? m/s _______________ m/s
(d) What are the velocity components of the object after 15.0 s? (Let the velocity be denoted by V.) v = (______ i + __________ j )m/s
The direction of the acceleration is counterclockwise from the +x-axis. The mass of the object is 6.34 kg. If the object is initially at rest, its speed after 15.0 s is 54.0 m/s. The velocity components of the object after 15.0 s are (-8.14i + 43.9j) m/s.
The object experiences an acceleration of magnitude 3.60 m/s². The net force on the object is obtained by summing the given forces, resulting in a counterclockwise direction from the +x-axis. Using Newton's second law of motion, the mass of the object is determined to be 6.34 kg. If the object is initially at rest, its speed after 15.0 s is calculated to be 54.0 m/s. The velocity components of the object after 15.0 s are found to be (-8.14i + 43.9j) m/s, indicating a negative x-direction velocity and positive y-direction velocity.
Learn more about acceleration:
https://brainly.com/question/17314399
#SPJ11
At gas is compressed slowly from 8m2 to 2m under a pressure of 6Pa. During the process 100J of heat was removed. What is the work done on the gas? What is the change in internal energy of the gas?
The work done on the gas is -36 J and the change in internal energy of the gas is -64 J.
To determine the work done on the gas and the change in internal energy, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
Q = -100 J (negative since heat is removed)
P = 6 Pa
A₁ = 8 m²
A₂ = 2 m²
First, we need to calculate the change in volume (ΔV) using the formula for the change in volume of a gas undergoing a process with constant pressure:
ΔV = A₂ - A₁
ΔV = 2 m² - 8 m² = -6 m² (negative since the gas is being compressed)
Now, let's calculate the work done on the gas (W) using the formula:
W = PΔV
W = 6 Pa * (-6 m²) = -36 J (negative since work is done on the gas)
Next, we can determine the change in internal energy (ΔU) using the first law of thermodynamics:
ΔU = Q - W
ΔU = -100 J - (-36 J) = -100 J + 36 J = -64 J (negative since the internal energy decreases)
To know more about work done refer to-
https://brainly.com/question/32263955
#SPJ11
standing wave on a 2-m stretched string is described by: y(x,t) = 0.1 sin(3rıx) cos(50nt), where x and y are in meters and t is in seconds. Determine the shortest distance between a node and an antinode
Standing wave on a 2-m stretched string is described by: y(x,t) = 0.1 sin(3rıx) cos(50nt), where x and y are in meters and t is in seconds.The shortest distance between a node and an antinode is approximately 16.67 cm.
To determine the shortest distance between a node and an antinode in the given standing wave, we need to analyze the properties of nodes and antinodes.
In a standing wave on a string, nodes are points where the displacement is always zero, while antinodes are points where the displacement reaches its maximum value.
The equation for the given standing wave is y(x, t) = 0.1 sin(3πx) cos(50πt).
To find the distance between a node and an antinode, we can consider the wave pattern along the string.
The general equation for a standing wave on a string is y(x, t) = A sin(kx) cos(ωt), where A is the amplitude, k is the wave number, x is the position along the string, and ω is the angular frequency.
Comparing this with the given equation, we can see that the wave number (k) is 3π and the angular frequency (ω) is 50π
In a standing wave, the distance between a node and an adjacent antinode is equal to λ/4, where λ is the wavelength of the wave.
The wavelength (λ) can be calculated using the formula λ = 2π/k.
Substituting the given value of k = 3π, we can find λ:
λ = 2π/(3π) = 2/3 meters.
Therefore, the shortest distance between a node and an antinode is equal to λ/4:
λ/4 = (2/3) / 4 = 2/12 = 1/6 meters.
To convert this into centimeters, we multiply by 100:
(1/6) ×100 = 100/6 cm ≈ 16.67 cm.
Therefore, the shortest distance between a node and an antinode is approximately 16.67 cm.
To learn more about antinode visit: https://brainly.com/question/11735759
#SPJ11
Q|C An unpolarized beam of light is incident on a stack of ideal polarizing filters. The axis of the first filter is perpendicular to the axis of the last filter in the stack. Find the fraction by which the transmitted beam's intensity is reduced in the three following cases. (b) Four filters are in the stack, each with its transmission axis at 30.0⁰ relative to the preceding filter.
The transmitted beam's intensity is reduced by a fraction of 93.75% in this scenario.
In this scenario, an unpolarized beam of light passes through a stack of four ideal polarizing filters. Each filter has its transmission axis at a 30.0⁰ angle relative to the preceding filter. We need to find the fraction by which the transmitted beam's intensity is reduced.
When an unpolarized light beam passes through a polarizing filter, it becomes linearly polarized along the transmission axis of the filter. Subsequent filters can only transmit light that is polarized in the same direction as their transmission axis.
In this case, the first filter will polarize the light in a specific direction, let's say vertically. As the light passes through the subsequent filters, which are at 30.0⁰ angles, the intensity of the transmitted beam will decrease.
Each filter will transmit 50% of the light that reaches it. So, after passing through the first filter, the intensity is reduced by 50%. The second filter will further reduce the intensity by 50% of the remaining light, resulting in a total reduction of 75%.
The third filter will reduce the intensity by an additional 50% of the remaining light, resulting in a total reduction of 87.5%. Finally, the fourth filter will reduce the intensity by another 50% of the remaining light, resulting in a total reduction of 93.75%.
Therefore, the transmitted beam's intensity is reduced by a fraction of 93.75% in this scenario.
Note: The specific angles and number of filters in the stack may vary, but the principle of each filter transmitting 50% of the polarized light and reducing the intensity remains the same.
to learn more about intensity
https://brainly.com/question/17583145
#SPJ11
fasttt
The value of standard resistor in ohm is 0000 005 500 100 QUESTION The value of standard resistor in ohm is NIDO 0000 200 000 080000 QUESTION 4
The value of the standard resistor is 5,500 ohms.
The value of the standard resistor is 200,000 ohms.
The value of the standard resistor is given as "5,500 ohms." This means that the resistor has a resistance of 5,500 ohms, which is a standard value commonly used in electronic circuits. The value of the standard resistor is given as "200,000 ohms."
This implies that the resistor has a resistance of 200,000 ohms, which is also a standard value in the field of electronics. The values provided are written in a format that separates the digits using spaces or zeroes. This format is sometimes used to make the numbers easier to read, particularly for values that involve multiple zeros.
Learn more about ohms here:
https://brainly.com/question/30266391
#SPJ11
What is the total charge of the protons that must be fired at the tumor to deposit the required energy
In order to calculate the total charge of the protons that must be fired at the tumor to deposit the required energy, we need to use the formula: Q = E/Dwhere Q is the total charge of the protons, E is the required energy, and D is the energy deposited per unit charge.
The energy required to treat a tumor is typically given in gray (Gy), which is a unit of absorbed dose. The energy deposited per unit charge is given in gray per coulomb (Gy/C).Therefore, the formula can be written as:Q = E/(D/C)Where C is the coulomb.Since the energy deposited by protons is 1.6 x 10-13 J/C, and the energy required to treat a tumor is typically between 50 Gy and 80 Gy, the total charge of the protons needed to deposit this energy will depend on the specific requirements of the tumor being treated.
Assuming that the tumor requires 60 Gy of energy, the total charge of the protons that must be fired at the tumor to deposit this energy would be:Q = 60 Gy / (1.6 x 10-13 J/C) = 3.75 x 10^14 C.
To know more about protons visit:-
https://brainly.com/question/12535409
#SPJ11
Estimate the maximum magnetic force that Earth's magnetic field could exert on a 8.3 long current-carrying wire in a 12A circuit in your house. Bearth =0.45×10−4T. Calculate your answer with 4 significant figures or 4 digits after the decimal point. F=IL×B=ILBsinθ
The estimated maximum magnetic force that Earth's magnetic field could exert on the 8.3-meter long current-carrying wire in the 12A circuit is approximately 4.224 × 10⁻² Newtons.
The formula for the magnetic force on a current-carrying wire in a magnetic field is given by
F = ILBsinθ, where
F is the force,
I is the current,
L is the length of the wire,
B is the magnetic field strength, and
θ is the angle between the wire and the magnetic field.
Given:
L = 8.3 meters
I = 12A
B = 0.45 × 10⁻⁴ T
θ = 90 degrees (maximum interaction)
Substituting the given values, we can calculate the maximum magnetic force:
F = (8.3 meters) * (12A) * (0.45 × 10⁻⁴ T) * sin(90 degrees)
Since sin(90 degrees) = 1, we have:
F = (8.3 meters) * (12A) * (0.45 × 10⁻⁴ T) * 1
Simplifying the expression, we find:
F ≈ 4.224 × 10⁻² Newtons
Therefore, the estimated maximum magnetic force that Earth's magnetic field could exert on the 8.3-meter long current-carrying wire in the 12A circuit is approximately 4.224 × 10⁻² Newtons.
To know more about force, click here-
brainly.com/question/30507236
#SPJ11
PIP 0255 INTRODUCTION TO PHYSICS Figure 4.3 (a): Rocket Launch? Maximum Altitude ↑ Altitude = 1200 m Fuel runs out a = g (downwards) Figure 4.3 (b): Rocket Drop! Maximum Altitude 10 a = + 3.2 m/s² a = g (downwards) 21 MAY 2022 ↑ (c) Refer to Figure 4.3 (a): During the launching of a rocket, a rocket rises vertically, from rest, with an acceleration of 3.2 m/s² until it runs out of fuel at an "altitude" (fancier, technical term for height) of 1200 m. After this point (1200 m), the rocket's acceleration is that of gravity (downwards). Even so, the rocket will still reach a maximum altitude. Refer to Figure 4.3 (b): Once the rocket has reached maximum altitude, it will then drop back down to earth, till it hits the ground (where the altitude is considered zero). Take g = 9.8 m/s². Based on this, answer the following (Show your calculation): (i) Determine the velocity (v) of the rocket at the altitude of 1200 m. (2 x ½ mark) (ii) Find the time (t) it takes the rocket to reach this altitude of 1200 m. (2 x 1 mark) (iii) Find the maximum altitude that the rocket can reach even when its fuel has run out (Note: at that point when the fuel is used up, acceleration, a, is no longer 3.2 m/s²). (2 x ½ mark) (iv) Find the velocity that the rocket will hit the ground on earth (on impact, altitude = 0) when it drops back down to earth from the maximum altitude. (2 × ½ mark)
The velocity (v) of the rocket at the altitude of 1200 m is 87.8 m/s. The time (t) it takes the rocket to reach this altitude of 1200 m is 20.7 s. The maximum altitude that the rocket can reach even when its fuel has run out is 8.86 km. The velocity that the rocket will hit the ground on earth is 417.96 m/s.
Determine the velocity (v) of the rocket at the altitude of 1200 m.The initial velocity (u) of the rocket = 0,Acceleration (a) of the rocket until it runs out of fuel = 3.2 m/s²,Height (s) of the rocket = 1200 m,
Using the formula;v² - u² = 2asv² - 0² 2as,
v² - 0² = 2(3.2)(1200),
v² = 7680,
v = 87.8 m/s.
Find the time (t) it takes the rocket to reach this altitude of 1200 m.The initial velocity (u) of the rocket = 0,Acceleration (a) of the rocket until it runs out of fuel = 3.2 m/s²,Height (s) of the rocket = 1200 m,
Using the formula;s = ut + 1/2 at²1200,
0 + 1/2 (3.2) t²t = 20.7 s.
Find the maximum altitude that the rocket can reach even when its fuel has run out.When the fuel runs out, the acceleration, a, is no longer 3.2 m/s², it is 9.8 m/s².The final velocity of the rocket (v) at this point can be obtained using the formula;v = u + at,
87.8 + (9.8)(20.7) = 287.66 m/s.
Using the formula;v² - u² = 2as,where v = 287.66 m/s, u = 87.8 m/s and a = -9.8 m/s² (negative because it is against the upward direction), we can find the maximum altitude that the rocket can reach;287.66² - 87.8² = 2(-9.8)sshould be substituted with the height of the maximum altitude.s = 8859.12 m or 8.86 km.
Find the velocity that the rocket will hit the ground on earth (on impact, altitude = 0) when it drops back down to earth from the maximum altitude.Using the formula;v² - u² = 2as,where u = 287.66 m/s (since it is the initial velocity when the rocket starts falling), a = 9.8 m/s² (negative because it is against the upward direction) and s = 8859.12 m (height of the maximum altitude), we can find the velocity that the rocket will hit the ground;v² - (287.66)² = 2(-9.8)(-8859.12)v = 417.96 m/s
The velocity (v) of the rocket at the altitude of 1200 m is 87.8 m/s.
The time (t) it takes the rocket to reach this altitude of 1200 m is 20.7 s.
The maximum altitude that the rocket can reach even when its fuel has run out is 8.86 km
The velocity that the rocket will hit the ground on earth (on impact, altitude = 0) when it drops back down to earth from the maximum altitude is 417.96 m/s.
The velocity (v) of the rocket at the altitude of 1200 m is 87.8 m/s. The time (t) it takes the rocket to reach this altitude of 1200 m is 20.7 s. The maximum altitude that the rocket can reach even when its fuel has run out is 8.86 km. The velocity that the rocket will hit the ground on earth (on impact, altitude = 0) when it drops back down to earth from the maximum altitude is 417.96 m/s.
To know more about Acceleration visit:
brainly.com/question/12550364
#SPJ11
The magnetic flux through a coil containing 10 loops changes from 20Wb to-20Wb in 0.038. Find the induced voltage e.
The magnetic flux through a coil containing 10 loops changes from 20Wb to-20Wb in 0.038.Then the induced voltage is 1052.63 V.
When the magnetic flux through a coil changes, it induces an electromotive force (EMF) or voltage. According to Faraday's law of electromagnetic induction, the magnitude of the induced voltage is directly proportional to the rate of change of magnetic flux. The formula to calculate the induced voltage is:
e = -N * (ΔΦ / Δt)
Where:
e is the induced voltage,
N is the number of loops in the coil,
ΔΦ is the change in magnetic flux, and
Δt is the time taken for the change in magnetic flux.
In this case, the coil contains 10 loops, and the magnetic flux changes from 20 Wb to -20 Wb. The change in magnetic flux (ΔΦ) is equal to the final flux minus the initial flux:
ΔΦ = (-20 Wb) - (20 Wb) = -40 Wb
The time taken for this change in magnetic flux (Δt) is given as 0.038 seconds.
Substituting these values into the formula, we get:
e = -10 * (-40 Wb / 0.038 s)
e = 1052.63 V
Therefore, the induced voltage is 1052.63 V.
Learn more about Induced voltage
brainly.com/question/4517873
#SPJ11
What is the magnitude of the output gear angular velocity (in units of rad/sec)?
The magnitude of the output gear angular velocity is 50 rad/sec. The actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.
The magnitude of the output gear angular velocity is determined by the gear ratio between the input and output gears. The gear ratio is the ratio of the number of teeth on the output gear to the number of teeth on the input gear.
To find the magnitude of the output gear angular velocity in units of rad/sec, you can use the formula:
Output gear angular velocity = Input gear angular velocity * (Number of teeth on input gear / Number of teeth on output gear)
Let's say the input gear has 20 teeth and the output gear has 40 teeth. If the input gear is rotating at 100 rad/sec, we
can calculate the output gear angular velocity as follows:
Output gear angular velocity = 100 rad/sec * (20 / 40) = 50 rad/sec
In this case, the magnitude of the output gear angular velocity is 50 rad/sec.
Remember to check the units and the gear ratio to ensure the correctness of your calculation. Also, note that the actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.
Learn more about: magnitude
https://brainly.com/question/31022175
#SPJ11
If a star has a maximum intensity at 644 nm, what is its
temperature?
4500K
5000K
2000K
3000K
2500K
The wavelength at which the maximum intensity of light is produced by a star is known as its Wien's displacement law. The temperature of a star can be determined using this law.
The maximum intensity of a star is observed at 644 nm. The temperature of the star can be determined as follows. The formula for Wien's displacement law is given by:
[tex]$$\lambda_{max} = \frac{b}{T}$$[/tex]
where λmax is the wavelength of the maximum intensity of light, b is Wien's constant, and T is the temperature of the star in Kelvin (K).
The constant value of b is 2.898 × 10⁻³ mK.
When we substitute the given values into the above equation, we get:[tex]$$\lambda_{max} = \frac{2.898\times10^{-3}mK}{T}$$[/tex]
[tex]$$T = \frac{2.898\times10^{-3}mK}{\lambda_{max}}$$[/tex]
Since the wavelength of maximum intensity of light from the star is given to be 644 nm, we need to convert this to meters before substituting it into the above equation:
[tex]$$\lambda_{max} = 644 nm = 6.44\times10^{-7} m$$[/tex]
Now substituting into the equation, we get:
[tex]$$T = \frac{2.898\times10^{-3}mK}{6.44\times10^{-7}m} = 4500K$$[/tex]
Therefore, the temperature of the star is 4500K.
To learn more about temperature visit;
https://brainly.com/question/7510619
#SPJ11
Show that the first Covarient derivative of metric tensor th
The first covariant derivative of the metric tensor is a mathematical operation that describes the change of the metric tensor along a given direction. It is denoted as ∇μgνρ and can be calculated using the Christoffel symbols and the partial derivatives of the metric tensor.
The metric tensor in general relativity describes the geometry of spacetime. The first covariant derivative of the metric tensor, denoted as ∇μgνρ, represents the change of the metric tensor components along a particular direction specified by the index μ. It is used in various calculations involving curvature and geodesic equations.
To calculate the first covariant derivative, we can use the Christoffel symbols, which are related to the metric tensor and its partial derivatives. The Christoffel symbols can be expressed as:
Γλμν = (1/2) gλσ (∂μgσν + ∂νgμσ - ∂σgμν)
Then, the first covariant derivative of the metric tensor is given by:
∇μgνρ = ∂μgνρ - Γλμν gλρ - Γλμρ gνλ
By substituting the appropriate Christoffel symbols and metric tensor components into the equation, we can calculate the first covariant derivative. This operation is essential in understanding the curvature of spacetime and solving field equations in general relativity.
To learn more about tensor click here brainly.com/question/31184754
#SPJ11
A 1000μF capacitor has a voltage of 5.50V across its plates. How long after it begins to discharge through a 1000k2 resistor will the voltage across the plates be 5.00V?
Approximately 0.0953 seconds after the capacitor begins to discharge through the 1000k2 resistor, the voltage across its plates will be 5.00V.
To determine the time it takes for the voltage across the capacitor to decrease from 5.50V to 5.00V while discharging through a 1000k2 (1000 kilohm) resistor, we can use the formula for the discharge of a capacitor through a resistor:
t = R * C * ln(V₀ / V)
Where:
t is the time (in seconds)
R is the resistance (in ohms)
C is the capacitance (in farads)
ln is the natural logarithm function
V₀ is the initial voltage across the capacitor (5.50V)
V is the final voltage across the capacitor (5.00V)
R = 1000k2 = 1000 * 10^3 ohms
C = 1000μF = 1000 * 10^(-6) farads
V₀ = 5.50V
V = 5.00V
Substituting the values into the formula:
t = (1000 * 10^3 ohms) * (1000 * 10^(-6) farads) * ln(5.50V / 5.00V)
Calculating the time:
t ≈ (1000 * 10^3) * (1000 * 10^(-6)) * ln(1.10)
t ≈ 1000 * 10^(-3) * ln(1.10)
t ≈ 1000 * 10^(-3) * 0.0953
t ≈ 0.0953 seconds
Learn more about capacitors at https://brainly.com/question/30696136
#SPJ11
Part A Jack underwent radiation therapy using a beam of neutrons to treat a skin cancer on his hand He received a dose equivalent of 30 mSv that was absorbed in 24 g of tissue The relative biological effectiveness (RBE) of these neutrons is 12 What absorbed dose of radiation did Jack receive? Express your answer in grays to two significant figures. ► View Available Hint(s) vo ΑΣφ ? Gy Submit Part B What was the total energy of the absorbed radiation Express your answer in joules to two significant figures ► View Available Hint(s) VO ΑΣ) O ! 75°F Sul ΑΣφ ? Jack underwent radiation therapy using a beam of neutrons to treat a skin cancer on his hand. He received a dose equivalent of 30 mSv that was absorbed in 24 g of tissue. The relative biological effectiveness (RBE) of these neutrons is 12 Submit Part 6 Suppose till also being treated for slan cancer received the same absorbed dose but from an electron beam (beta particles) with an RBE of 12 What dose equivalent did she receive? Express your answer in sieverts to two significant figures ► View Available Hints) 195 t PE ΑΣΦ ? ? Sv Submit
Jack received a dose equivalent of 30 mSv during his radiation therapy using a beam of neutrons to treat his skin cancer on his hand.
Part A:
To calculate the absorbed dose, we can use the formula:
Absorbed Dose (Gy) = Dose Equivalent (Sv) / RBE
Dose Equivalent = 30 mSv
RBE = 12
Absorbed Dose = 30 mSv / 12 = 2.5 mGy = 2.5 × 10^-3 Gy
Therefore, the absorbed dose of radiation that Jack received is 2.5 ×
10^-3 Gy.
Part B:
To calculate the total energy of the absorbed radiation, we can use the formula:
Total Energy (Joules) = Absorbed Dose (Gy) × Mass (kg) × Specific Heat Capacity (J/kg·°C) × Temperature Change (°C)
Since no temperature change is mentioned, we assume no change in temperature, resulting in zero energy.
Therefore, the total energy of the absorbed radiation is 0 Joules.
Learn more about absorbed dose here : brainly.com/question/30512352
#SPJ11
Question 5 Somewhere in deep space, two small, spherical pieces of rock went into circular orbits around a large, spherical asteroid. Satellite Rock A had an orbital radius of R₁ = 280.0 km and a period of TA. Determine the radius RB of Satellite Rock B's orbit, given that it takes the rock a time TB 3.78TA to orbit the asteroid once.
Previous question
Next q
The radius of Satellite Rock B's orbit (RB) is approximately 522.47 km.
To determine the radius of Satellite Rock B's orbit (RB), we can use Kepler's Third Law of Planetary Motion, which relates the orbital period and orbital radius of celestial bodies. Kepler's Third Law states that the square of the period (T) of an object in an orbit is proportional to the cube of its orbital radius (R).
Mathematically, it can be expressed as: T² ∝ R³
Given that Satellite Rock A has an orbital radius of R₁ = 280.0 km and a period of TA, we can write the following equation: TA² = R₁³
Now, let's consider Satellite Rock B. We are given that it takes Rock B a time TB = 3.78TA to orbit the asteroid once. Using the same equation, we can write: TB² = RB³
Since we want to find RB, we can rearrange the equation:
RB = (TB²)^(1/3)
Substituting the value of TB = 3.78TA, we get:
RB = (3.78TA²)^(1/3)
Since we know that TA² = R₁³, we can substitute this into the equation:RB = (3.78 * R₁³)^(1/3)
Now we can calculate the value of RB using the given radius of Satellite Rock A: RB = (3.78 * (280.0 km)³)^(1/3)
RB ≈ 522.47 km
Therefore, the radius of Satellite Rock B's orbit (RB) is approximately 522.47 km.
To learn more about radius:
https://brainly.com/question/24051825
#SPJ11
15 16 22 QUESTION 8 decibel-part During takeoff, the sound intensity level of a jet engine is 110 dB at a distance of 40 m What is the Intensity of sound in units of Wim 27 QUESTION 9 decibel-part what is the power of the ſet entine mentioned in part A in units of Watts? QUESTION 10 decibel-part For the ſet mention in part A what is the sound intensity at a distance of 500 m from tho jet? Enter your answer in scientific notation with 2 decimals Scientific notation supports the following forms 45.60-6 or 456E-6 (using capital or lowercase E) The field doesn't support units (eg 25 cm 4504 KHZ aren't supported). • Constants such as "pl" and "e" (Euler constant) aren't supported, thus, numbers such as 67e or pl will be invalid QUESTION 11 Decibel Part What is the sound intensity level (in units of dB) of the jet engine mentioned in part A at this new distance of 500m? Enter your answer in scientific notati with 4 significant figures (3 decimals) do not use any intermediate rounded values in your calculation)
To solve these questions, we need to use the formulas and relationships related to sound intensity and sound level.
Question 8: The intensity of sound is 0.1 W/m².
Question 9: The power of the jet engine is approximately 201.06 W.
Question 10: The sound intensity at a distance of 500 m from the jet is approximately 0.0016 W/m².
Question 11: The sound intensity level of the jet engine at the new distance of 500 m is approximately 86.02 dB.
Question 8:
To find the intensity of sound in units of W/m², we need to convert the sound intensity level (given in dB) to intensity using the formula:
Intensity (W/m²) = 10^((dB - 120) / 10)
Substituting the given values, we get:
Intensity = 10^((110 - 120) / 10) = 10^(-1) = 0.1 W/m²
Question 9:
To find the power of the jet engine in units of Watts, we need to use the formula:
Power (W) = 4πr²I
Where r is the distance from the source and I is the sound intensity. In this case, r = 40 m and I = 0.1 W/m².
Substituting the values, we get:
Power = 4π(40²)(0.1) = 64π W ≈ 201.06 W
Question 10:
To find the sound intensity at a distance of 500 m from the jet, we can use the inverse square law for sound propagation:
I2 = I1 * (r1 / r2)²
Where I1 is the initial sound intensity at a given distance r1, and I2 is the sound intensity at the new distance r2.
In this case, I1 = 0.1 W/m², r1 = 40 m, and r2 = 500 m.
Substituting the values, we get:
I2 = 0.1 * (40 / 500)² ≈ 0.0016 W/m²
Question 11:
To find the sound intensity level at the new distance of 500 m, we can use the formula:
dB2 = dB1 + 10 log10(I2 / I1)
Where dB1 is the initial sound intensity level and I1 is the initial sound intensity, and dB2 is the sound intensity level at the new distance and I2 is the sound intensity at the new distance.
In this case, dB1 = 110 dB and I2 = 0.0016 W/m² (from the previous question).
Substituting the values, we get:
dB2 = 110 + 10 log10(0.0016 / 0.1) ≈ 86.02 dB
Learn more about sound intensity:
https://brainly.com/question/14349601
#SPJ11
Four resistors R 1 =78Ω,R 2 =35Ω,R 3 =60Ω and R 4 =42Ω are connected with a battery of voltage 6 V. How much is the total current in the circuit? Express your answer in amperes (A).
The total current in the circuit is 0.028 (A).
To find the total current in the circuit, we can use Ohm's Law and the concept of total resistance in a series circuit. In a series circuit, the total resistance (R_total) is the sum of the individual resistances.
Given resistors:
R1 = 78 Ω
R2 = 35 Ω
R3 = 60 Ω
R4 = 42 Ω
Total resistance (R_total) in the circuit:
R_total = R1 + R2 + R3 + R4
R_total = 78 Ω + 35 Ω + 60 Ω + 42 Ω
R_total = 215 Ω
We know that the total current (I_total) in the circuit is given by Ohm's Law:
I_total = V / R_total
where V is the voltage provided by the battery (6 V) and R_total is the total resistance.
Substituting the given values:
I_total = 6 V / 215 Ω
I_total ≈ 0.028 A
Therefore, the total current in the circuit is approximately 0.028 amperes (A).
To know more about ohm's law refer here: https://brainly.com/question/1247379#
#SPJ11
Let’s visualize a parallel plate capacitor with a paper dielectric in-between the plates. Now, a second identical capacitor, but this one has a glass sheet in-between now. Will the glass sheet have the same dependence on area and plate separation as the paper?
Swapping the paper for glass has what effect? This is the precise idea of dielectric: given the same capacitor, the material makes a difference. Comparing the paper and glass dielectrics, which would have the higher dielectric and hence the higher total capacitance? Why?
Dielectric materials, such as paper and glass, affect the capacitance of a capacitor by their dielectric constant. The dielectric constant is a measure of how effectively a material can store electrical energy in an electric field. It determines the extent to which the electric field is reduced inside the dielectric material.
The glass sheet will not have the same dependence on area and plate separation as the paper dielectric. The effect of swapping the paper for glass is that the glass will have a different dielectric constant (also known as relative permittivity) compared to paper.
In general, the higher the dielectric constant of a material, the higher the total capacitance of the capacitor. This is because a higher dielectric constant indicates that the material has a greater ability to store electrical energy, resulting in a larger capacitance.
Glass typically has a higher dielectric constant compared to paper. For example, the dielectric constant of paper is around 3-4, while the dielectric constant of glass is typically around 7-10. Therefore, the glass dielectric would have a higher dielectric constant and hence a higher total capacitance compared to the paper dielectric, assuming all other factors (such as plate area and separation) remain constant.
In summary, swapping the paper for glass as the dielectric material in the capacitor would increase the capacitance of the capacitor due to the higher dielectric constant of glass.
To know more about dielectric constant click this link -
brainly.com/question/13265076
#SPJ11
In a Young's double-slit interference apparatus, what happens to the pattern when the slits are moved closer together? The pattern A) narrows B) stays the same C) widens D) turns to dots
Young's double-slit interference apparatus is a famous experiment that demonstrates the wave nature of light. When light passes through two parallel slits, it produces an interference pattern on a screen behind it. The pattern consists of alternating bright and dark fringes. The answer to this question is option C) widens.
The interference pattern generated by the two slits is a function of the distance between them. The distance between the slits affects the path length difference of the light waves that pass through each slit. When the distance between the slits is reduced, the distance traveled by each beam of light through the slits is also reduced. This causes the fringes in the interference pattern to spread out further apart, increasing the width of the interference pattern.
Hence, the answer to this question is option C) widens.
The width of the pattern can be calculated using the formula w = λL/d, where w is the width of the fringe pattern, λ is the wavelength of light, L is the distance from the slits to the screen, and d is the distance between the slits. As the distance between the slits decreases, the width of the pattern will increase.
To learn more about interference visit;
https://brainly.com/question/31857527
#SPJ11