The molar solubility of CoS is 5.0 x 10-22 mol l-1 in pure water. Calculate the Ksp for Cos.
A-1.6 × 10-35
B-2.5x 10-43
C-4.7 x 10-6
D-5.0 x 10-22
E-2.2 x 10-11

Answer:

the answer is (A). .A nuclear reaction releases more energy per gram and appears to violate the law of conservation of mass.

Explanation:

Most mass is converted into energy so it violates the law.

When the two vehicles collide, then vehicle with slow speed will pushes back.

Speed of any moving body is define as the distance travelled by that body in per unit of time.

As it is mentioned that one car has a speed of 30 mph and another one has a speed of 60mph, if both of these cars get collide then the car with high speed pushed back the car with low speed.

Hence the car with slow speed pushed back.

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One of the most significant characteristics of the Dead Sea is its salinity level. The images show the rock salt deposits on the shore.

The dead dea is the most salty landlocked lake on the Earth surface. It is located in the middle East, between Israel and Jordania. Its nort-south length is about 80 km and its east-west wide varies between 7 and 20 km.

The Jordan river is the most significan afluent on the Dead Sea, from which it receives most of its water.

The Dead Sea is the deepest and lowest water body on the Earth, being its surface level 400 mt below the sea level.

Due to different reasons, during the last decades, there was a sharp and continuous drop in the water level. For this reason the lake surface is decreasing year after year.

Among its many characteristics, one of them -and probably the most notorious one- is the salinity.  The percentage of dissolved salts in the lake is much higher than the one recorded in the oceans, seas or lakes of the globe. Its value is between 8 and 10 times higher the salt level of oceans.

The salts present in the lake are chlorine, magnesium, sodium, calcium, potassium, bromine and sulfur. Their concentration vary according to the strate and deph, but it tends to increase toward the lake’s bottom. The high salinity level provides an oily aspect, bleach taste, and extreme density.

Several rock salt deposits can be seen on the shore and near it. Salt columns can also be seen in deepest areas. These structures are becomming more common with time, as water evaporates, water provision from afluent sources decreases, and salinity near the surface increases.

Mainly due to the extreme salt level, which turns to be lethal, almost no forms of life inhabit these waters. Only some bacteria species and one algae species can be found in the water, and some plant species near the coasts.

What we can observe in these images are the rock salt deposits on the shore.

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Answer:

b

Explanation:

cause it stops at 8 and it starts going up until it hits 14

Explanation:

Cytoplasm is a semi-solid substances inside cells.

Answer:

It commonly ranges between 0 and 14, but can go beyond these values if sufficiently acidic/basic. pH is logarithmically and inversely related to the concentration of hydrogen ions in a solution. The pH to H + formula that represents this relation is: The solution is acidic if its pH is less than 7.

Explanation:

Answer:

4.3 %

Explanation:

Trust me.

Answer:

456 K

Explanation:

PV = nRT

PV/ T = nR       since nR is constant for this scenario

P1 V1 /T1   =  P2 V2 / T2

500 * 1 / 200 =  (760*.75)  *2 /T2    Solve for T2 =456 K

(Note that .750 atm =   760 mmHg * .75 )

Answer:

4 Molecules

Explanation:

Because the coefficient is 4.

Taking into account the reaction stoichiometry, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

In first place, the balanced reaction of the decomposition of mercury oxide is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles ×216.59 g/mole= 433.18 grams

Hg: 2 moles ×200.59 g/mole= 401.18 grams

O₂: 1 mole ×32 g/mole= 32 grams

The following rule of three can be applied: if by reaction stoichiometry 433.18 grams of HgO form 32 grams of O₂, 12 grams of HgO form how much mass of O₂?

[tex]mass of O_{2} =\frac{12 grams of HgOx 32 grams of O_{2}}{433.18 grams of HgO}[/tex]

mass of O₂= 0.886 grams

Then, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

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Answer:

An alcohol is an organic compound with a hydroxyl (OH) functional group on an aliphatic carbon atom. Because OH is the functional group of all alcohols, we often represent alcohols by the general formula ROH, where R is an alkyl group. Alcohols are common in nature.

Explanation:

[tex]12 \times 2 + 2 \times 2 + 16 \times 2[/tex]

[tex] = 24 + 2 + 32 [/tex]

[tex] = 58 \: gram \: per \: mole[/tex]

[tex]58 = 100\% \\ 24 = x\%[/tex]

[tex]x = \frac{24 \times 100}{58} = 41.38\%[/tex]

Answer:

"The Circuit" by author Francisco Jimenez, tells the story of Panchito and his experiences on a new country, having to deal with learning a second language and adapting to a new culture and environment. Even if you had not been in a similar situation as Panchito, you could connect his stories to your personal experiences at school in many ways. Maybe, the first classes of spanish or french were difficult to you as you could not understand all the words the teacher was saying, but as you were learning things were easier for you. Or you can connect Panchito's experiences by writing about that time in school you were not afraid of asking for help when you had to deal with a difficult situation 

Antifreeze is the coolant used in car engines that regulates the temperature. The cooling system turns over around 40 times to regulate the temperature.

Heat is the product of the mass, temperature change, and the specific heat of the substance.

Given,

The heat of surroundings = 44000 kJ

Mass of the substance = 8719 gm

Specific heat = 8.37 J/g degrees celsius

Change in temperature = 15 degrees celsius

Q system is calculated as:

8719 × 8.37 × 15

= 1095 kJ

The number of antifreeze is calculated as:

Δ H ÷ Q system = 44000 ÷ 1095

= 40

Therefore, 40 times the cooling system was turned over.

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Answer:

[tex]\boxed{O_2 \: ^{2-} (\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^4}[/tex]

[tex]\boxed{O_2 \: ^{1-}(\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4{ (π∗2py)}^{2} {(π∗2px)}^{1}}[/tex]

Explanation:

[tex]\sf \: Electronic \: configuration \: of \: O_2 \: ^{2-} and \: O_2 \: ^{1-}[/tex]

Electronic configuration of any diatomic molecule can be determined using MOT(molecular orbital theory).

To know the electronic configuration of above two molecules, draw the MOT of O2 molecule.(refer the diagram)

There are 16 electrons in O2 molecule out of which Four electrons are in non bonded state. Remaining 12 electrons of 16 will be filled according to MOT, since O2 is not a S-P mixing case, in without S-P mixing case the sigma orbital(σ2pz) lies below the Pi orbital(π2px,π2py) in bonding state as you can see in the diagram, on other hand the other diatomic molecules like B2, C2 & N2 are S-P mixing case where Pi orbital lies below and sigma orbital lies above.

Now, the electronic configuration of O2 molecule is

[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^2 [/tex]

There are two electrons unpaired electrons in MOT hence the O2 molecule is paramagnetic which contradicts VBT, Thats why MOT dominant VBT.

in case of O2^2-(peroxide linkage) the two electrons enters in the Anti Bonding of pi orbital. hence the electronic configuration of O2^2- is

[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4(π∗2py,π∗2px)^4[/tex]

since the HOMO (highest occupied molecular orbital) is paired the O2^2- is diamagnetic in nature.

Coming to O2^1- (superoxide linkage) the one electron enters in the Anti Bonding of pi orbital hence the electronic configuration comes out,

[tex](\sigma2s)^2(\sigma∗2s)^2(\sigma2pz)^2(π2py,π2px)^4{ (π∗2py)}^{2} {(π∗2px)}^{1} [/tex]

The HOMO of O2^1- is unpaired hence it is Paramagnetic in nature.

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When 6.1 moles of Cu is reacted with excess S 3.05 number of mole of Cu2S are produced.

The balance equation of the above reaction is:

2Cu +S --> Cu2S

This means that 2 moles of Cu = 1 mole of Cu2S

Therefore 6.1 moles of Cu = X mole of Cu2S

Make X the subject of formula,

X = 6.1 ×1/2

X = 3.05 moles

Therefore, when 6.1 moles of Cu is reacted with excess S 3.05 number of mole of Cu2S are produced.

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Explanation:

density= mass × volume

3.35×5

=. 16 .75

For a carbonate containing a kind of cation, we have that Option 1 is the correct answer: ammonium.

Generally, Any of two families of chemical substances generated from carbonic acid or carbon dioxide is referred to as carbonate.

In conclusion, Sodium, potassium, and ammonium are the three carbonates that are soluble.

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Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K

Gay-Lussac's law states that "the pressure exerted by a given mass of gas at constant volume varies directly with its absolute temperature".

It is expressed as;

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

Given the data in the question;

Initial pressure of gas; [tex]P_1 = 0.5atm[/tex]

Final pressure of gas; [tex]p_2 = 2.5atm[/tex]

Final temperature; [tex]T_2 = 900K[/tex]

Initial temperature before pressure change; [tex]T_1 = \ ?[/tex]

We substitute our given values into the expression above.

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\\frac{0.5atm}{T_1} = \frac{2.5atm}{900K}\\\\T_1 = \frac{0.5atm\ *\ 900K}{2.5atm}\\ \\T_1 = \frac{450K}{2.5}\\\\T_1 = 180K[/tex]

Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K.

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Answer:

Because the non-metal comes from the right hand side of the Periodic Table as we face it, its nuclear charge is very poorly shielded by its INCOMPLETE valence electronic shell, and this results in the well-known contraction of atomic radii across the Table from left to right.

Explanation:

Non metals usually gain electrons so they have more electron in the shells than protons in nucleus and hence they form negative ions. However, metals usually lose electron so they have more protons in nucleus than electrons in shells and hence they form positive ions.

Answer:

S.........................................

Mechanical Energy to Thermal Energy

hope it helps...!!!

Water has a high specific heat capacity hence, water can keep the  large bodies of water cooler in the summer months and warmer in the winter months.

The specific heat capacity of a substance refers to the heat that must be added to the substance in order to increase the temperature of the substance by 1K.

It must be noted that water has a high specific heat capacity hence, water can keep the  large bodies of water cooler in the summer months and warmer in the winter months. Hence, the statement is false

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Answer:

False

Explanation:

I took the Chemistry exam

Answer:

Insulators

Explanation:

They could work as Insulators

Hope it Helps

Answer: Heyo Kenji Here! Here's your answer- In a fat molecule, the fatty acids are attached to each of the three carbons of the glycerol molecule with an ester bond through the oxygen atom. During the ester bond formation, three molecules are released. Since fats consist of three fatty acids and a glycerol, they are also called triacylglycerols or triglycerides.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

Answer:

HEBW EISJS A A RID RO J KNE SINS DMO C EIS

The new volume of the balloon assuming the temperature remains constant is 0.5 L.

To calculate the new volume of the balloon, we apply Boyle's law

Boyle's law state that the volume of a fixed mass gas is inversly proportional to its pressure at constant temperature.

Formula:

Where:

Make V' the subject of the equation

From the question,

Given:

Substitute these values into equaion 2

Hence, The new volume of the balloon assuming the temperature remains constant is 0.5 L.

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Answer:

1= anode, 2=cathode and 3=oxidation potential

Explanation:

Anode is the electrode within an electrochemical cell where oxidation occurs.

Cathode is the electrode within an electrochemical cell where reduction occurs.

Oxidation is the voltage associated with the electron trances within an electrochemical cell.

the sun cooks the clouds the clouds pee on the earth and all the water falls to earth, pushing all the wind down that's why we have earthquakes

Following the quantic theory, the energy of a photon equals the radiation frequency multiplied by the universal constant. ν = 2.923x10¹⁵ Hz. E = 3.09x10¹⁵Hz.

It is the branch of physics that studies objects and forces at a very low scale, at atoms, subatoms, and particles levels.

Quantum mechanics states that the elemental particles that constitute matter -electrons, neutrons, protons- have the properties of a wave and a particle.

It emerges from the quantic theory exposed by Max Planck (1922), in which he affirmed that light propagates in energy packages or photons.

He discovered the Universal Planck constant, h, used to calculate the energy of a photon.

He stated that the energy of a photon (E) equals the radiation frequency (ν) multiplied by the universal constant (h).

E = νh

In the exposed example, we need to calculate the energy required to change from the 3rd shell to the first shell.

To do it, we should know that the energy in a level (Eₙ) equals the energy associated to an electron in the most inferior energy level (E₁) divided by the square of the shell number (n²).

Eₙ = E₁ / n²

E₁ is a constant. We can express it in Joules or electroVolts

So, let us calculate the energy at level 1 and 3

Eₙ = E₁ / n²

        E₁ =  -13.6 eV / 1² =  -13.6 eV

        E₃ =  -13.6 eV / 3² =  -13.6 eV / 9 = - 1.51 eV

The change of energy can be calculated in two ways,

Option 1

ΔE = E₁ - E₃ = 2.18x10⁻¹⁸ - 2.42x10⁻¹⁹ = 1.93x10⁻¹⁸J

ΔE = E₁ - E₃ = 13.6 - 1.51 = 12.09 eV

Option 2

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE =-13.6 eV (1/nf² - 1/ni²)

Where nf is the final level and ni is the initial level. When the electron passes from its initial level to its final level it is called electronic transition.

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE = -2.18x10⁻¹⁸ J (1/1² - 1/3²)

ΔE = -2.18x10⁻¹⁸ J (1 - 0.111)

ΔE = -2.18x10⁻¹⁸ J (0.888)

ΔE = - 1.937x10⁻¹⁸ J

or

ΔE = -13.6 eV  (1/nf² - 1/ni²)

ΔE = -13.6 eV  (1/1² - 1/3²)

ΔE = -13.6 eV  (1 - 0.111)

ΔE = -13.6 eV  (0.888)

ΔE = -12.08 eV

This is the energy required for the electron to go from n= 3 to n = 1. The negative sign (-) means energy (as light or photons) released or emitted.

If we want to express the result in Hz, we just need to make a conversion.

1Hz ⇔ 6.626x10⁻³⁴J ⇔ 4.136x10¹⁵ eV.

The energy required for the electron to go from n= 3 to n = 1 is 3.09x10¹⁵ Hz.

Now, we need to calculate the frequency, ν. This is, how many times the wave oscillates back and foward per second.

To do it, we will use the universal Planck constant, h, and the absolute value of the energy, E.

ν = E/h = 1.937x10⁻¹⁸ J / 6.626x10⁻³⁴ Js = 2.923x10¹⁵ 1/s =  2.923x10¹⁵ Hz.

Answer:

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