The school band has d drummers and 5 violinists. There are 2 more violinists than drummers. Which of the following equations represents the situation?​

The School Band Has D Drummers And 5 Violinists. There Are 2 More Violinists Than Drummers. Which Of

Answers

Answer 1

Answer:

A    d = 5+2

Step-by-step explanation:

There are two more drummers than violinists

There are 5 violinists

5 + 2 = d

or in other words, d = 7

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K


Related Questions

The sum of a rational number and an irrational number is always rational,

A.True
B.False

Answers

Answer:

True

Step-by-step explanation:

The sum of any rational number and any irrational number will always be an irrational number

The area of a circle is 78.5 cm^2. What is the diameter of the circle?
-5 cm
-10 cm
-12.5 cm
-39.25 cm

Answers

Answer:

10cm

Step-by-step explanation:

78,5=pi.r^2

Answer5:

Step-by-step explanation:

Name the two input device​

Answers

Answer:

keyboard and mouse are two examples of input device

Answer:

keyboard and mouse

Step-by-step explanation:

If you like my answer than please mark me brainliest

Given that f(x) = 2x³-7x²+7ax+ 16 is divisible by x-a, find
(i) the value of the constant a
(ii) the remainder when f(x) is divided by 2x+1.

Answers

Answer:

a = - 2, remainder = 21

Step-by-step explanation:

The Remainder theorem states that if f(x) is divided by (x - a) the remainder is f(a)

Since f(x) is divisible by (x - a) then remainder is zero , then

f(a) = 2a³ - 7a² + 7a² + 16 = 0 , that is

2a³ + 16 = 0 ( subtract 16 from both sides )

2a³ = - 16 ( divide both sides by 2 )

a³ = - 8 ( take the cube root of both sides )

a = [tex]\sqrt[3]{-8}[/tex] = - 2

Then

f(x) = 2x³ - 7x² - 14x + 16

Evaluate f(- [tex]\frac{1}{2}[/tex] ) for remainder on division by (2x + 1)

f(- [tex]\frac{1}{2}[/tex] ) = 2(- [tex]\frac{1}{2}[/tex] )³ - 7(- [tex]\frac{1}{2}[/tex] )² - 14(- [tex]\frac{1}{2}[/tex] ) + 16

        = 2(- [tex]\frac{1}{8}[/tex] ) - 7([tex]\frac{1}{4}[/tex] ) + 7 + 16

        = - [tex]\frac{1}{4}[/tex] - [tex]\frac{7}{4}[/tex] + 23

        = - [tex]\frac{8}{4}[/tex] + 23

       = - 2 + 23

       = 21

Which statement describes the graph?

Answers

Answer:

the graph crosses the y-axis at -5 and x-axis at -6

y=3x+2y is it a function how do you do it

Answers

9514 1404 393

Answer:

  yes

Step-by-step explanation:

Solve for y. You can do this by subtracting 3x+y from both sides of the equation.

  y -(3x+y) = 3x +2y -(3x +y)

  -3x = y

Or ...

  y = -3x

Each value of x maps to a single value of y, so this relation is a function.

_____

This equation is a first-degree polynomial in x. Any polynomial relation y=p(x) is a function, so this is a function.

Calculate 20% of 3 3/4 years in months.​

Answers

Answer:

It is 9 months

Step-by-step explanation:

[tex] = 20\% \times 3 \frac{3}{4} \\ \\ = \frac{20}{100} \times \frac{15}{4} \\ \\ = \frac{300}{400} \\ \\ = \frac{3}{4} \: \: { \sf{years}}[/tex]

convert them to months by multiplying by 12:

[tex]{ \sf{ = \frac{3}{4} \times 12}} \\ \\ = { \sf{9 \: months}}[/tex]

express 3x-x^2 as m-(x-n)^2. Ill give brainliest to correct answer!
(Also please see the picture since you might mistake x having a square as a 2x)

Answers

This is simply done by Method of Completing the Square.

3x - x²

Add and subtract half the coefficient of x and square it.

( This is done so there'd be no alterations to the quadractic Expression)

So To start

We'd like x² to be positive...(So factor out a negative).

( - 3x )

Now In this case

You see there's a Negative Outside the the bracket

Instead of adding and Subtracting squared values of half the coefficient of X... We'd Add Twice and do not subtract.

Reason: If you add outside the bracket and subtract the other inside the bracket... This will be wrong because there's a negative patiently waiting outside the bracket to Interact with the negative you subtracted to make it Positive.

See what I mean.

Let's say you added 2² and subtracted 2² in this problem

( - 3x - 2²)

If you decide to open the bracket

You'll have

+ 3x + 2²

NOW THIS IS WRONG BECAUSE WE ALTERED THIS EXPRESSION. WHERE'D 2² + 2² COME FROM?

THIS IS WHY YOU'LL ADD THE SQUARED COEFFICIENT OF X TWICE IN CASES LIKE THESE.

SO GOING BACK TO THE ORIGINAL QUESTION.

(x² - 3x )

Adding the half the coefficient of x twice and squaring them...

Coefficient of x = 3

Half of 3 = 3/2

Squaring it gives (3/2)²

NOW PROCEEDING

(3/2)² [ - 3x + (3/2)²]

If you open this bracket... (3/2)² will cancel out with (3/2)²

Meaning that we haven't altered the expression in any way

Moving On...

Applying basic factorizing principle

9/4 ( x - 3/2)².

Answer = 9/4 ( x - 3/2)² Which is in the Form m ( x - n )²

Therefore m = 9/4 and n = 3/2.

Hope This Helps

What is the fraction or mixed number and write in its simplest form.
3.8416

3.8416=—- (type an integer,proper fraction, or mixed number.)

Answers

Answer:

38416/10000

plss mark me brainliestt

Step-by-step explanation:

3.8416=38416/10000

La chispa de un relámpago artificial de 10.0 MV libera una energia de 0.125 MW .s ¿Cuántos coulombs de
carga fluyen?

Answers

Answer:

nzbzbzZnzbznzbzbzhzhsbsjs

Solve for x
ax+bx=10

Answers

Answer:

[tex]ax + bx = 10 \\ \\ x(a + b) = 10 \\ \\ x = \frac{10}{a + b} [/tex]

I hope I helped you^_^

27 devided by 1234 chunking method

Answers

Answer:

45

Step-by-step explanation:

[tex]\lim_{n \to \0}(x/(tan⁡(x))^(cot⁡(x)^2 )[/tex]

Answers

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

Solve using substitution.


6x + y = 7

8x + 9y = 17

(_,_)


Please help me I really need it

Answers

You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1

Select the correct answer.
Based on these segment lengths, which group of segments cannot form a triangle?
OA 12,7,8
OB. 8, 7, 13
OC. 1,2,3
OD. 80,140, 70
Reset
Next
2021 EdimentumAll rights

Answers

Answer:

C

Step-by-step explanation:

If you add up the length of two sides, the sum must be greater than the third side of the triangle.

If you add 1 and 2, it equals 3

But that means it will be equal to the length of the third side, 3

It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.

It's sort of difficult to explain this without any visual

You can look up "triangle inequality" to find out more about this

1. Can the numbers 12, 6, 6 be used to form the sides of a triangle? Why or why not?

Answers

Answer: No, a triangle is not possible in this case

Why not? Because the two sides 6 and 6 add to 6+6 = 12, which does not exceed the remaining side.

Refer to the triangle inequality theorem. This theorem says that for a triangle to be possible, we need these three facts to be true

a+b > cb+c > aa+c > b

where a,b,c are the three sides of the triangle. In short: adding any two sides must be larger than the third side.

I recommend cutting out slips of paper to try making a triangle with sides 12,6, and 6. You'll find its not possible. The two smaller sides combine to perfectly line up with the larger side. The three sides form a line and not a triangle.

Determine the sum by suitable re arrangement .
a) 6254 + 1297 + 446 + 103 Ans:
b) 1983 + 647 + 217 + 353 2.​

Answers

Answer:

a.8100

b.3200

Step-by-step explanation:

hope you're okay

Need answers in 2 minutes ASAP

Answers

Step-by-step explanation:

f(10)=10

f(-2)=-2

f(a)=a

f(a+b)=a+b

g(10)=5×10-12=3

g(-2)=5×(-2)-12=-10-12=-22

g(a)=5×a-12=5a-12

g(a+b)=5×(a+b)-12=5a+5b-12

h(10)=(10)^2 +4(10)-7=100+40-7=133

h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11

h(a)=a^2 +4a -7

h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7

Anyone’s knows how do this and the answer?

Answers

Answer:

12 -16. 19

4. 8. 22

3. -9. -4

Step-by-step explanation:

13-1 = 12

-10-6= -16

12 - -7 = 12+7=19

6-2 = 4

Keep subtracting

GIVING BRAINLIEST PLS HELP

Answers

Hope it helpsssss !!!!! Don’t mind about “so x=8 and smt” dad

State the transformations of the following function in order: = − 3|6 − 2| + 1

Answers

Answer:

6

Step-by-step explanation:

-3 | 6 - 2| + 1

-3 + 6 + 2 + 1

-3 + 9 = 6

19. When the members of a high school club are
arranged in rows of 2, 3, or 4, there is one
person always left over. But when the club
members are arranged in rows of 5, no one is
left over. What is the least number of people
who could be in the club?
À 15 people
C 45 people
B 25 people D 85 people

Answers

9514 1404 393

Answer:

 B.  25 people

Step-by-step explanation:

The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.

The least number of people who could be in the club is 2·12+1 = 25.

derivative : y=[(1+x^2)arctgx-x]/2

Answers

Answer:

s,-8*2-`±_'682-¥´owhsi

divide write your answer in simplest form 2/3 divided by 1/4

Answers

Answer:

8/3 or 2.6667

Step-by-step explanation:

when you divide fractions you use a technique called KCF

K = keep

C = change

F = flip

You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]

you keep [tex]\frac{2}{3}[/tex]

you change the symbol, so from ÷ you change it to x

and flip the last fraction, so you would have  [tex]\frac{4}{1}[/tex]

then you solve it

[tex]\frac{2}{3}[/tex] x  [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]

The result of 2/3 divided by 1/4 in simplest form is 8/3 .

Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.

Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].

Division of fractional terms:

[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]

Apply, division process of fractional terms.

[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]

[tex]= \frac{8}{3}[/tex]

Know more about division,

https://brainly.com/question/29775887

#SPJ6

On solving equation 3*1/5b+5=50, the value of b will be?

Answers

Answer:

Step-by-step explanation:

14 1⁄16

QUESTION 1 11 How does the term quartile relate to how data values are grouped when using a five- number summory?​

Answers

Data from the Bureau of Labor Statistics has been put into order by placing data in the lower and upper quartiles. If data are placed in order, then the lower quartile is central to the lower half of the data and the upper quartile becomes central to its upper half.

Do you guys know this because I was trying to submit but it don’t let me I put 7/6 but it say I need different Way

Answers

Answer:

is 5

Step-by-step explanation:

Hope it is helful...

Answer:

5

Step-by-step explanation:

So first when dividing fractions you need to invert and multiply. Thus the fraction becomes:

1/4 * 20/1.

When simplified it becomes 20/4 which is 5.

HOPE THIS HELPED

The Earth scientist most likely to study volcanoes is a (n)

A. Meteorologist

B. Geologist

C. Oceanographer

D. Astronomer

Answers

The answer is B Geologist

Answer:

geologist

Step-by-step explanation:

they work with the earths surface and natural land that changes

which graph represents the following system of inequalities?
a
b
c
d

Answers

Answer:

A

Step-by-step explanation:

Mark me brainliest.

Both graphs need dashed lines, since they’re < and > and not ≤ or ≥.

You need to shade above y > -x - 4 and you need to shade below y < 2x - 3.

You want to only include the purple section on the right.

if image of a point (4,6) under enlargement with centre (0,0) and scale factor 'k' is (2,3) find value of k ​

Answers

Answer:

k = 2

Step-by-step explanation:

2 x 2 = 4

3 x 2 = 6

so (2,3) multiplied by 2 will be (4,6)

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