There are ‘n’ arithmetic means between 33 and – 3. If second last mean: second mean = 1: 5, find the value of n.

Answer:

[tex] \frac{ - 4 + 4i}{ - 3 - 6i} \\ multiply \: and \: divide \: by \: - 3 + 6i \\ \frac{ - 4 + 4i}{ - 3 - 6i} \times \frac{ - 3 + 6i}{ - 3 + 6i} \\ = \frac{ ( - 4 + 4i)( - 3 + 6i)}{ ( - 3 - 6i)( - 3 + 6i)} \\ = \frac{12 - 24i - 12i + 24 {i}^{2} }{ {( - 3)}^{2} - {(6i)}^{2} } \\ = \frac{12 - 24 - 36i}{9 + 36} \\ = \frac{ - 12 - 36i}{45} \\ \frac{ - 36i}{45} + \frac{ - 12}{45} \\ thank \: you[/tex]

Answer:

B

Step-by-step explanation:

22/7 X 14 squared

--------------------------------  =308

           2

406-308= 98cm ^2

Answer: 8 inches

Step-by-step explanation:

224/3.5 = 64

8*8=64

8in * 8in * 3.5In = 224 cubic inches

Step-by-step explanation:

square cube 214

I think this was your answer

Answer:

the value of X is 3 and y is 6 .

Answer:

not proportional

Step-by-step explanation:

We can check using cross products

18/73  = 4/16

18*16 = 73*4

288=292

Since this is not equal, this is not proportional

Answer:

25°

Step-by-step explanation:

20°--5°=

20°+5°=

25°

Answer: fell 25 degrees

Step-by-step explanation: 20-25= -5

//Give thanks(and or Brainliest) if helpful (≧▽≦)//

Answer: false

Step-by-step explanation:

Since it is a circle, when you draw the line it will meet at two points which fails the vertical line test. In order to pass the vertical line test it must only meet at one point.

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Answer:

B

Step-by-step explanation:

look at where the line reaches on the y-axis

Answer:

(3x2-7x)-(4x2+6x)= −x^2−13x

Step-by-step explanation:

(3x2-7x)-(4x2+6x)

Distribute the Negative Sign:

=3x^2−7x+−1(4x^2+6x)

=3x^2+−7x+−1(4x^2)+−1(6x)

=3x^2+−7x+−4x^2+−6x

Combine Like Terms:

=3x^2+−7x+−4x^2+−6x

=(3x^2+−4x^2)+(−7x+−6x)

=−x^2+−13x

Not sure if this is what you wanted. Sorry if this is what you weren't looking for.

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 5y = - 10 ( subtract 2x from both sides )

5y = - 2x - 10 ( divide the terms by 5 )

y = - [tex]\frac{2}{5}[/tex] x - 2 ← in slope- intercept form

with slope m = - [tex]\frac{2}{5}[/tex] and y- intercept c = - 2

Answer:

"How many times does 81 divide into 547?"

Answer:

a point

Step-by-step explanation:

because it really seems like a point I dunno

Answer:

119.93

Step-by-step explanation:

I will assume the total of the cost of the movies will be the total.

the total  = 4*14.99 + 3*19.99

total = 119.93

Answer:

[tex]y = - 2x - 4[/tex]

Step-by-step explanation:

Slope intercept eqn:

[tex]y - y1 = m(x - x1)[/tex]

P = (-4,4) and Q = (-3,2)

Let (x1, y1) = (-4,4) and (x2, y2) = (-3,2).

[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{ 2 - 4}{ - 3 - ( - 4)} = \frac{ - 2}{1} = - 2[/tex]

Therefore the equation of the line in slope-intercept form :

[tex]y - 4 = - 2(x - ( - 4)) \\ y - 4 = - 2(x + 4) \\ y - 4 = - 2x - 8 \\ y = - 2x - 8 + 4 \\ y = - 2x - 4[/tex]

Answer:

Sorry I don't really understand your question, but 28-19 is 9 therefore 9 is more than 0

9 >0

The range of the function  g(x) = |x + 2|– 1 is (-1,∞) and domain of the function is (-∞,∞).

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

For example f(x) = x²

Now if we put x = 1 then it is called as domain variable while the value of function at x = 1 its that f(1) = 1 called range variable.

Given the function  g(x) = |x + 2|– 1

The minimum value of the function

At x = -2 ⇒ |-2+ 2|– 1 = -1

The maximum value of the function

At x = ∞ ⇒ |∞+ 2|– 1 = ∞

So,

The range will be (-1, ∞)

Now,

We can put x as -∞ and ∞ so the domain will be (-∞,∞).

Hence "The range of the function  g(x) = |x + 2|– 1 is (-1,∞) and domain of the function is (-∞,∞)".

For more details about the range and domain of the function,

brainly.com/question/28135761

#SPJ2

Answer:

A radius is a line segment with one endpoint at the center of the circle and the ... is called the midpoint, and arc PQ ≅ arc PR if and only if PQ ≅ PR.

Step-by-step explanation:

brainliest please

Answer:

A radius is a line segment with

Let numbers be x and 2x

ATQ

[tex]\\ \rm\longmapsto \dfrac{x+7}{2x+7}=\dfrac{3}{5}[/tex]

[tex]\\ \rm\longmapsto 5(x+7)=3(2x+7)[/tex]

[tex]\\ \rm\longmapsto 5x+35=6x+21[/tex]

[tex]\\ \rm\longmapsto 6x-5x=35-21[/tex]

[tex]\\ \rm\longmapsto x=14[/tex]

Answer:

brainliest is appreciated

Answer:

Step-by-step explanation:

I take it that what you are asking is which one of the three choices gives f(5) = 2.

It is not the table. When you try adding 5 in the x column, you get a much larger result than 2 for y.

And it is not the scattered points of the graph. x = 5 gives 5 on the y axis, not 2.

It is the first choice on the left.

f(5) = x - 3

f(5) = 5 - 3

f(5) = 2

Expression represent the area of the sandbox is a² + 3a

GIven that;

Length of sandbox is three feet longer than its width

Find:

Expression represent the area of the sandbox

Computation:

Assume;

Width of sandbox = a feet

So,

Length of sandbox = (a + 3) feet

[tex]Area\ of\ rectangle = Length \times Width[/tex]

So,

Area of the sandbox = Length of sandbox × Width of sandbox

Area of the sandbox = (a + 3) × a

Area of the sandbox = a² + 3a

Learn more:

https://brainly.com/question/23649629?referrer=searchResults

We have

v = (-7, 9) - (4, 3) = (-7 - 4, 9 - 3) = (-11, 6)

which as a linear combination of the i and j unit vectors is

v = -11i + 6j

Answer:

Step-by-step explanation:

Answer:

Fifteen feet is the closest to the side length of the frame, have a good day