This year, the number of raffle tickets sold for a school's extracurricular activities fundraiser is 848. It is estimated that the number of raffle tickets sold will increase by 5% each year. Find the total number of raffle tickets sold at the end of 9 years.

Select the correct answer below:

9,158
9,351
9,818
10,666

HI Your answer is 42

I have calculated it you can trust me

Well you have marked right in the pic

PLEASE MARK AS BRAINLIEST

(i) Correcting the figures to 3 decimal places:

-0.005627 ≈ -0.006

0.0056 ≈ 0.006

-0.0049327 ≈ -0.005

0.0049 ≈ 0.005

-0.001342 ≈ -0.001

(ii) Correcting the figures to 3 significant figures:

-0.005627 ≈ -0.00563

0.0056 ≈ 0.00560

-0.0049327 ≈ -0.00493

0.0049 ≈ 0.00490

-0.001342 ≈ -0.00134

(i) When rounding to 3 decimal places, we look at the fourth decimal place and round the figure accordingly. If the fourth decimal place is 5 or above, we round up the preceding third decimal place. If the fourth decimal place is less than 5, we simply drop it.

(ii) When rounding to 3 significant figures, we consider the digit in the third significant figure. If the digit in the fourth significant figure is 5 or above, we round up the preceding third significant figure. If the digit in the fourth significant figure is less than 5, we simply drop it.

Rounding to the correct number of decimal places or significant figures is important to maintain precision and accuracy in calculations and measurements. It helps to ensure that the reported values are appropriate for the level of precision required in a given context.

For more such questions on significant figures

https://brainly.com/question/30169

#SPJ8

Answer:

1. 01= 234, 03= 255 (since the data is

already sorted)

2. I0R = 255 - 234= 21

3. Lower limit = 234- 1.5 * 21= 203.5

Upper limit = 255+ 1.5 * 21= 285.5

4. Outliers: 110, 120, 178 (below the

lower limit), and 273 (above the upper

limit)

The boundaries of the 99% confidence interval are

From the question, we have the following parameters that can be used in our computation:

Selected, x = 28021

Sample, n = 38433

This means that the proportion, p is

p = 28021/38433

p = 0.729

The 99% confidence interval is then calculated as

CI = p ± z * √(p * (1 - p)/n)

Where

z = 2.576 i.e. the z-score at 99% confidence interval

So, we have

CI = 0.729 ± 2.576  * √(0.729 * (1 - 0.729)/38433)

Evaluate

CI = 0.729 ± 0.0058

Evaluate

CI = (0.7232, 0.7348)

Hence, the confidence interval is (0.7232, 0.7348)

Read more about confidence interval at

https://brainly.com/question/32801070

#SPJ1

Answer:

height = 10 ft

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )

given A = 70 and b = 14 , then

[tex]\frac{1}{2}[/tex] × 14 × h = 70

7h = 70 ( divide both sides by 7 )

h = 10 ft

Answer: Nope

Step-by-step explanation:

No, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.

To understand why, let's consider an example with an item priced at $100.

If there is a 20% discount applied initially, the price of the item would be reduced by 20%, which is $100 * 0.20 = $20. So the new price after the first discount would be $100 - $20 = $80.

Now, if there is an additional 30% discount applied to the $80 price, the discount would be calculated based on the new price. The 30% discount would be $80 * 0.30 = $24. So the final price after both discounts would be $80 - $24 = $56.

Comparing the final price of $56 to the original price of $100, we can see that the total discount is $100 - $56 = $44.

Therefore, the total discount received is $44 out of the original price of $100, which is a discount of 44%, not 50%.

Hence, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.

Answer:

-33x√2

Step-by-step explanation:

[tex]-5x\sqrt{98}+2\sqrt{2x^2}\\\\= -5x\sqrt{2*7^{2} } + 2(x\sqrt{2} )\\\\= -5x(7)(\sqrt{2} ) + 2x\sqrt{2} \\\\= -35x\sqrt{2} +2x\sqrt{2} \\\\= (-35+2)x\sqrt{2}\\ \\=-33x\sqrt{2}[/tex]

Answer: [tex](-\infty, 0) \cup (0, \infty)[/tex]

Step-by-step explanation:

The graph of [tex]\frac{\sin x}{x}[/tex] is continuous for all real [tex]x[/tex] except [tex]x=0[/tex], and multiplying this by [tex]1/3[/tex] does not change this.

The mean of the scores to the nearest tenth is 83.7.

Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers.

Given the question above, we need to find the mean of the scores to the nearest tenth.

We can find the mean by using the formula below:

[tex]\text{Mean} = \dfrac{\text{Sum of all the observations}}{\text{Total number of observations}}[/tex]

Now,

[tex]\text{Mean} = \dfrac{70(6)+75(3)+80(9)+85(5)+90(7)+95(8)}{6+3+9+5+7+8}[/tex]

[tex]\text{Mean} = \dfrac{420+225+720+425+630+760}{38}[/tex]

[tex]\text{Mean} = \dfrac{3180}{38}[/tex]

[tex]\text{Mean} = 83.7[/tex]

Therefore, the mean of the scores to the nearest tenth is 83.7.

Read more about the mean at:

https://brainly.com/question/32056327

Answer:   there are 20 people who claimed to be neither CDO partisans nor ANC partisans.

Step-by-step explanation:

To determine the number of people who are none of these two parties, we need to subtract the total number of people who claimed to be CDO partisans, ANC partisans, and those who claimed to be both from the total number of people surveyed.

Total surveyed people = 130

Number claiming to be CDO partisans = 80

Number claiming to be ANC partisans = 60

Number claiming to be both ANC and CDO = 30

To find the number of people who are none of these two parties, we can calculate it as follows:

None of these two parties = Total surveyed people - (CDO partisans + ANC partisans - Both ANC and CDO)

None of these two parties = 130 - (80 + 60 - 30)

None of these two parties = 130 - 110

None of these two parties = 20

Answer:

8/15

Step-by-step explanation:

1/15(4 + 1/20(4)

4/15 + 4/20  I can reduce 4/20 to 1/5

4/15 + 1/5

4/15 + 3/15 = 7/15

Together they can get 7/15 of the job done.  15/15 - 7/15 is 8/15.

That means that they have 8/15 left to do.

Helping in the name of Jesus.

The correct Option is A. The measure of angle HGF is 20°.

Quadrilateral EFGH is an isosceles trapezoid with bases EH and FG.

The measure of angle HGF is (9y + 3)°, and the measure of angle EFG is (By + 5)°.

To find the measure of angle HGF, we need to solve for the value of y.

Since EFGH is an isosceles trapezoid, the opposite angles are congruent.

Therefore, the measure of angle EFG is also (9y + 3)°.

To find the value of y, we can set the two expressions equal to each other: (9y + 3)° = (By + 5)°.

Next, we can solve for y by isolating it.

We subtract 3° from both sides: 9y = By + 2.

To get y by itself, we subtract By from both sides: 9y - By = 2.

Finally, we can factor out y: y(9 - B) = 2.

To solve for y, we divide both sides by (9 - B): y = 2 / (9 - B).

Now that we have the value of y, we can substitute it back into the expression for angle HGF: (9y + 3)°.

Thus, the measure of angle HGF is (9(2 / (9 - B)) + 3)°.

Therefore, The correct Option is A.

For more questions on angle

https://brainly.com/question/25770607

#SPJ8

Answer:

A: the probability that a 1 is received is 0.56.

B:  the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).

Step-by-step explanation:

To solve this problem, we can use conditional probabilities and the concept of Bayes' theorem.

a. To find the probability that a 1 is received, we need to consider the two possibilities: either a 1 was sent and remained unchanged, or a 0 was sent and got flipped to a 1 by the random error.

Let's denote:

P(1 sent) = 0.6 (probability a 1 is sent)

P(0→1) = 0.2 (probability a 0 is flipped to 1)

P(1 received) = ?

P(1 received) = P(1 sent and unchanged) + P(0 sent and flipped to 1)

= P(1 sent) * (1 - P(0→1)) + P(0 sent) * P(0→1)

= 0.6 * (1 - 0.2) + 0.4 * 0.2

= 0.6 * 0.8 + 0.4 * 0.2

= 0.48 + 0.08

= 0.56

Therefore, the probability that a 1 is received is 0.56.

b. If a 1 is received, we want to find the probability that a 0 was sent. We can use Bayes' theorem to calculate this.

Let's denote:

P(0 sent) = ?

P(1 received) = 0.56

We know that P(0 sent) + P(1 sent) = 1 (since either a 0 or a 1 is sent).

Using Bayes' theorem:

P(0 sent | 1 received) = (P(1 received | 0 sent) * P(0 sent)) / P(1 received)

P(1 received | 0 sent) = P(0 sent and flipped to 1) = 0.4 * 0.2 = 0.08

P(0 sent | 1 received) = (0.08 * P(0 sent)) / 0.56

Since P(0 sent) + P(1 sent) = 1, we can substitute 1 - P(0 sent) for P(1 sent):

P(0 sent | 1 received) = (0.08 * (1 - P(0 sent))) / 0.56

Simplifying:

P(0 sent | 1 received) = 0.08 * (1 - P(0 sent)) / 0.56

= 0.08 * (1 - P(0 sent)) * (1 / 0.56)

= 0.08 * (1 - P(0 sent)) * (25/14)

= (2/25) * (1 - P(0 sent))

Therefore, the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).

A message is coded into the binary symbols 0 and 1 and the message is sent over a communication channel. The probability a 0 is sent is 0.4 and the probability a 1 is sent is 0.6. The channel, however, has a random error that changes a 1 to a 0 with probability 0.2 and changes a 0 to a 1 with probability 0.1. (a) What is the probability a 0 is received? (b) If a 1 is received, what is the probability a 0 was sent?

To calculate the probabilities, we can use the following information:

Total number of student athletes = 204

Number of students who play soccer = 52

Number of students who play volleyball = 31

Probability of a student playing both soccer and volleyball = 5/204

1.  Probability that a student plays both soccer and volleyball:

Let's denote the probability of playing both soccer and volleyball as P(Soccer and Volleyball). From the given information, we know that the number of students who play both soccer and volleyball is 5.

P(Soccer and Volleyball) = Number of students who play both soccer and volleyball / Total number of student athletes

P(Soccer and Volleyball) = 5 / 204

2.  Probability that a student plays volleyball:

We want to find the probability of a student playing volleyball, denoted as P(Volleyball).

P(Volleyball) = Number of students who play volleyball / Total number of student athletes

P(Volleyball) = 31 / 204

Therefore, the probability that a randomly selected student athlete in this school plays both soccer and volleyball is 5/204, and the probability that they play volleyball is 31/204.

for similar questions on  probabilities.

https://brainly.com/question/251701

#SPJ8

Answer:A' = (15, -15), B' = (9, -9), and C' = (15, -9)

Step-by-step explanation:

To dilate triangle ABC with a center of dilation at the origin (0,0) and a scale factor of 3, you need to multiply the coordinates of each vertex by the scale factor.

Let's calculate the coordinates of triangle A'B'C':

For point A:

x-coordinate of A' = scale factor * x-coordinate of A = 3 * 5 = 15

y-coordinate of A' = scale factor * y-coordinate of A = 3 * (-5) = -15

Therefore, A' = (15, -15)

For point B:

x-coordinate of B' = scale factor * x-coordinate of B = 3 * 3 = 9

y-coordinate of B' = scale factor * y-coordinate of B = 3 * (-3) = -9

Therefore, B' = (9, -9)

For point C:

x-coordinate of C' = scale factor * x-coordinate of C = 3 * 5 = 15

y-coordinate of C' = scale factor * y-coordinate of C = 3 * (-3) = -9

Therefore, C' = (15, -9)

Hence, the correct coordinates of triangle A'B'C' are A' = (15, -15), B' = (9, -9), and C' = (15, -9).