Two gears are connected by a chain. The larger gear has a linear velocity of 17π/6 inches per second. The angular velocity of the smaller gear is 34π/3 radians per minute.

What is the radius of the smaller gear?

1.25 feet

1.5 feet

15 feet

18 feet

Answers

Answer 1

So

[tex]\\ \rm\Rrightarrow v=r\omega[/tex]

v is linear velocityomega is angular velocity

[tex]\\ \rm\Rrightarrow r=\dfrac{v}{\omega}[/tex]

[tex]\\ \rm\Rrightarrow r=\dfrac{17\pi}{6}\div\dfrac{34\pi}{3}=\dfrac{17\pi}{6}\times \dfrac{3}{34\pi}[/tex]

[tex]\\ \rm\Rrightarrow r=\dfrac{1}{4}[/tex]

[tex]\\ \rm\Rrightarrow r=0.25ft[/tex]

Convert to ft

0.25(3)=0.75ft

1 min=60s

Hence

34π/3×60=34π×20=680π

So

[tex]\\ \rm\Rrightarrow r=\dfrac{17\pi}{6}\times \dfrac{1}{680\pi}[[/tex]

[tex]\\ \rm\Rrightarrow r=\dfrac{1}{40}[/tex]

[tex]\\ \rm\Rrightarrow r=0.025in[/tex]

Convert to ft

0.025(12)0.3ft

None of the above

Answer 2

The radius of the smaller gear is 15 feet, Option C is correct.

What is Velocity?

Velocity is defined as the rate of change of distance of a body with respect to time

We can use the relationship between linear velocity and angular velocity for gears to solve this problem:

v = rω

where v is the linear velocity, r is the radius of the gear, and ω is the angular velocity.

We are given the linear velocity of the larger gear, which is 17π/6 inches per second.

v = 17π/6 inches per second

ω = (34π/3) / 60 radians per second

the radius of the smaller gear is:

r = v / ω

= (17π/6) / ((34π/3) / 60)

= 17π/6×60/(34π/3)

=17π/6×60×3/34π

= 1/6 ×60× 3/2

= 180/12

=15 feet

Hence,  the radius of the smaller gear is 15 feet.

To learn more on Velocity click:

https://brainly.com/question/17127206

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Answers

Answer:

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Brainliest would be appreciated

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Answers

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Answers

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Answers

Hi :)

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Answers

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Answers

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