Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem.

A cube-shaped box has an edge length of 45 meter.

What is the volume of the container?



Enter your answer, as a fraction in simplest form, in the box.

The horizontal distance between the base of the ladder and the wall is 29.34 feet.

What is trigonometry?

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It involves the study of the properties and functions of angles, as well as the relationships between these angles and the lengths of the sides of triangles. Trigonometry has many practical applications in fields such as engineering, physics, astronomy, and surveying, among others. Some common concepts in trigonometry include the sine, cosine, and tangent functions, as well as the Pythagorean theorem and the unit circle.

We can use trigonometry to solve this problem. Let x be the horizontal distance between the base of the ladder and the wall.

We know that the ladder is 30 feet long and forms an angle of 78° with the ground. Let's call the angle between the ladder and the wall θ.

Using trigonometry, we can write,

cos θ = x/30

We want to find x, so we can rearrange this equation to solve for x,

x = 30 cos θ

Now we just need to substitute the value of θ into this equation. We know that the ladder forms an angle of 78° with the ground, so the angle between the ladder and the wall is θ = 90° - 78° = 12°

Substituting this value into the equation, we get,

x = 30 cos 12°

Using a calculator, we can evaluate cos 12° to be approximately 0.9781. Multiplying this by 30, we get:

x ≈ 29.34

So the horizontal distance between the base of the ladder and the wall is approximately 29.34 feet. Rounded to the nearest hundredth of a foot, the answer is x ≈ 29.34 feet.

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You would have $2,450 to buy to cover the cost of the membership.

An online buying club offers a membership for $245, for which you will receive a discount of 10 percent on all brand-name items you purchase.

We have to determine how much you would have to buy to cover the cost of the membership.

You have to buy to cover the cost of the membership = An online buying club offers a membership/Receive a discount

You have to buy to cover the cost of the membership = $245/10%

You have to buy to cover the cost of the membership = $245/0.10

You have to buy to cover the cost of the membership = $2,450

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Answer:

C

Step-by-step explanation:

Since the number in the parenthesis is treated as "x", for f(2), replace "x" with 2. So the equation will be f(2) = 3(2) + 2. Then multiply. f(2) = 6 + 2. Lastly add them up. f(2) = 8. The answer is 8.

Answer: Let x be the man's income.

He spent 58% of his income, which is 0.58x.

The amount of money left is the remaining 42% of his income, which is 0.42x.

According to the problem, 0.42x = GH210.00.

Solving for x, we get:

x = GH210.00 / 0.42

x = GH500.00

Therefore, the man's income is GH500.00.

Step-by-step explanation:

The given values are inserted in the point-slope form which formed the equation 140 = -14x + 10 and has been graphed.

When you know the slope of the line to be investigated and the given point is also the y-intercept, you can utilize the slope-intercept formula, y = mx + b. (0, b).

The y value of the y-intercept point is denoted by the symbol b in the formula.

The general form of a linear equation is y-y1=m(x-x1).

It draws attention to the line's slope and one of the line's points (that is not the y-intercept).

So, in the given situation:
The point-slope form is: y = mx + b

Then y is y and b is the x value and m is the slope.

Now, insert values as follows:

y = mx + b

140 = -14x + 10

Graph the equation as follows:

(Refer to the graph attached below)

Therefore, the given values are inserted in the point-slope form which formed the equation 140 = -14x + 10 and has been graphed.

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The fractions a. 5/7 b. 30/42 e. 45/84 are equivalent to 15/21.

       When it comes to fractions, equivalent means that both fractions show the same part of a whole. The numerator and denominator of equivalent fractions may be multiplied or divided by the same number or the number multiplied by the numerator and denominator should be the same.

 The following are steps to simplify fractions:

 First, find the greatest common factor (GCF) of both numbers.

And then divide both numbers by the GCF. The result is the simplified fraction.

            The greatest common factor of 15 and 21 is 3. By dividing both 15 and 21 by 3, the simplified fraction will be found.

                   15/21 = 5/7

 By dividing both 30 and 42 by 6, the simplified fraction will be found.

                     30/42 = 5/7

 By dividing both 45 and 84 by 3, the simplified fraction will be found.

       45/84 = (5/12)21/15 and 25/31 are not equivalent to 15/21.

     Therefore, the correct options are a. 5/7 b. 30/42 e. 45/84

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The length is therefore shrinking at a rate of -541/3, or around -180.33 square inches per hour.

A rectangle is a flat, four-sided shape with parallel, equal-length opposite sides on each side. There are four right angles (90-degree angles). The distance between the two longer sides, also known as the longer sides or the longer edges, is the rectangle's length. The distance between the two shorter sides, also known as the shorter sides or the shorter edges, determines the rectangle's width. The perimeter of a rectangle is equal to the total of the lengths of all of its sides, and the area of a rectangle is equal to the product of its length and width.

given

Let A represent the rectangle's area, l its length, and w its width. So, we are aware of:

A = lw

By applying the derivative to time t, we obtain:

(d/dt) = dA/dt (lw)

l(dw/dt) + w(dl/dt) = dA/dt

dw/dt = 0 since the width is kept constant, which results in:

w(dl/dt) = dA/dt

We are informed that w = 3 in and that dA/dt = –541 in2/hour. By replacing these values, we obtain:

-541 = 3(dl/dt)

By calculating dl/dt, we obtain:

dl/dt = -541/3

The length is therefore shrinking at a rate of -541/3, or around -180.33 square inches per hour.

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1. It will take about 8 years for the tithe to double in value if invested at 7.75% APR compounded monthly.

2. An annual interest rate of 4.84% compounded semi-annually would be required for $22,500 to accumulate to $50,000 in 14 years.

3 A principal of $26,512.18 invested in a GIC at 4% APR compounded quarterly would return $40,000 in 9 years.

a. Using the TVM Solver function in Excel, we can input the following information:

Present value (PV): -$35,000 (since it's an outgoing cash flow)

Future value (FV): $70,000 (since we want the tithe to double in value)

Interest rate per period (Rate): 7.75%/12 (since the APR is compounded monthly)

Number of periods (Nper): unknown (what we're solving for)

Payment (Pmt): 0 (since there are no recurring payments)

Solving for Nper, we get 96.16 months, or approximately 8 years.

Therefore, it will take about 8 years for the tithe to double in value if invested at 7.75% APR compounded monthly.

b. Present value (PV): -$22,500 (since it's an outgoing cash flow)

Future value (FV): $50,000

Interest rate per period (Rate): unknown (what we're solving for)

Number of periods (Nper): 14*2=28 (since the interest is compounded semi-annually, we need to double the number of years)

Payment (Pmt): 0

Solving for Rate, we get 4.84% APR.

Therefore, an annual interest rate of 4.84% compounded semi-annually would be required for $22,500 to accumulate to $50,000 in 14 years.

c. Using the TVM Solver function in Excel, we can input the following information:

Present value (PV): unknown (what we're solving for)

Future value (FV): $40,000

Interest rate per period (Rate): 4%/4 (since the APR is compounded quarterly)

Number of periods (Nper): 9*4=36 (since the interest is compounded quarterly, we need to multiply the number of years by 4)

Payment (Pmt): 0

Solving for PV, we get $26,512.18.

Therefore, a principal of $26,512.18 invested in a GIC at 4% APR compounded quarterly would return $40,000 in 9 years.

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In option C, we can see that the equation is in vertex form.

What is parabola ?

A parabola is a symmetrical U-shaped curve formed by the graph of a quadratic function. It is a type of conic section that results from the intersection of a cone and a plane that is parallel to one of the sides of the cone. A parabola can also be defined as the set of points in a plane that are equidistant from a fixed point called the focus and a fixed line called the directrix. Parabolas have many applications in physics, engineering, and mathematics, including projectile motion, antenna design, and optimization problems.

According to the question:
The equation that reveals the minimum or maximum value of f(x) without changing the form of the equation is C f(x)=(x-2)²-16.

This equation is in vertex form, which is f(x) = a(x-h)² + k. In this form, the vertex of the parabola is at the point (h, k), and the value of "a" determines whether the parabola opens upwards or downwards.

In option C, we can see that the equation is in vertex form, where the vertex is (2, -16). Therefore, the minimum value of f(x) is -16, which occurs at x=2.

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Step-by-step explanation:

Let the John age be x

Clark is 8 years older than John will be written as :

x+8 = x

In 5 years, Clark will be twice as old as John will be written as :

(x+8)+5 = 2(x+8)

Simplify it

x+13 = 2x+16

x-2x = 16-13

-x = 3

x = -3

Their current age :

= x+8

= -3+8 ( x = -3)

= 5

=2(x+8)

=2(-3+8)

=-6+16

=10

Present age John and Clark are 3 and 11 years respectively .

Let the John present age be J and Clark present age be C

Clark is 8 years older than John will be written as :

C= J + 8

In 5 years, Clark will be twice as old as John will be written as :

C+ 5 = 2(J + 5)

Substitute,

C = J + 8

Simplify it

J + 8 + 5 = 2J + 10

J = 3

C = J + 8

C =11

Thus their present ages are :

Clark = 11 years

John = 3 years

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Answer:3/7

Step-by-step explanation:

Answer: 1287

Step-by-step explanation:

1. The perimeter of triangle JKL is the sum of the three sides of the triangle, which is JK + KL + LJ is 37.

2. The measure of arc ZWX is 136.

3. Length of AB is 48

4. The value of x is 30π.

It states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

1. The perimeter of triangle JKL is the sum of the three sides of the triangle, which is JK + KL + LJ.

As JA = 14, AL = 17, and

CK = 6,

then the perimeter of JKL is 14 + 17 + 6 = 37.

2. To find the measure of arc ZWX, we can use the formula for the circumference of a circle, which is 2πr, where r is the radius.

As WZ and AR are diameters of the circle, they each have a length of 2r. The measure of arc ZWX is the same as the measure of angle WCX plus the measure of angle YCZ, which is

42 + 94 = 136.

Therefore, the measure of arc ZWX is 136.

3. To find the length of AB, we can use the Pythagorean Theorem.

OC is given as 12. and Radius is given as 30.

So, length of OC=30-12

=18

As OB is also the radius of the circle, its length is 30.

By using the Pythagorean Theorem,

OB²=BC²+OC²

BC²=OB²-OC²

BC=√30²-12²

BC=24

As we know a perpendicular divides a line into 2 equal parts, thus, AB=BC+AC

AB=48

4. To find the value of x, we can use the formula for the measure of an arc, which is

2πr × (angle/360).

As the measure of arc AB is 60 degrees and the measure of arc CD is 20 degrees, then x can be calculated as

2πr × (60/360) + 2πr × (20/360) = 30π.

Therefore, the value of x is 30π.

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The ages of Paige, Quiana, and Ryan, given their relationship to each other's ages are:

The amount of each type of coin that Uncle Ralph has are:

The equations we have are:

Paige is half as old as Quiana: P = 0.5 x Q

Quiana is three years younger than Ryan: Q = R - 3

Ryan is nine years older than Paige: R = P + 9

Now we can substitute for R from the second equation into the new equation: Q - 3 = (0.5 x Q) + 9

Now, let's solve for Q: 0.5 x Q = Q - 12 => 0.5 x Q = 12

Now we can find Q: Q = 24

Now that we have Quiana's age, we can find Paige's and Ryan's ages:

P = 0.5 x Q = 0.5 x 24 = 12

R = P + 9 = 12 + 9 = 21

Uncle Ralph has 18 coins in total: Q + D + N = 18

The number of quarters and dimes combined is the same as the number of nickels: Q + D = N

He has $2.10 worth of coins: 0.25 x Q + 0.10 x D + 0.05 x N = 2.10

Now we have two equations:

Q + D = 9

0.25 x Q + 0.10 x D + 0.05 x (Q + D) = 2.10

We can solve the system of linear equations. Multiply the first equation by 0.15 and subtract it from the second equation:

0.30 x Q + 0.15 x D - (0.15 x Q + 0.15 x D) = 2.10 - 1.35 => 0.15 x Q = 0.75

Substitute the value of Q back into the first equation to find the number of dimes: 5 + D = 9 => D = 4

Now we can find the number of nickels using the second equation: N = Q + D = 5 + 4 = 9

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Answer:

9/14

Step-by-step explanation:

add them

Answer:9%

Step-by-step explanation:

Sorry for taking so long i didn't understand it at first

the correct equation to find x, the measure of angle M in AAMP is: [tex]x = 149[/tex]. Thus, option C is correct.

To find the value of x, we need to know the angles of triangle AMP.

Assuming that AAMP is a quadrilateral, we know that the sum of its angles is   [tex]360[/tex] degrees.

Thus, we can write:

Angle AMP + Angle M + Angle A [tex]= 360[/tex]

We know that Angle AMP is  [tex]180 - 95 - 54 = 31[/tex]  degrees (since the sum of the angles in triangle AMB is 180 degrees, and we are given that Angle BAM = 95 degrees and Angle ABM = 54 degrees).

Substituting this value and the given value of Angle A (which is 180 degrees) into the equation above, we can solve for Angle M:

[tex]31 + Angle M + 180 = 360[/tex]

Angle   [tex]M = 149[/tex] degrees

Therefore, the correct equation to find x, the measure of angle M in AAMP is: [tex]x = 149[/tex]

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If i have four boxes arranged in a [tex]2 \times 2[/tex] grid, in 6 distinct ways can i place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit

If a student has four boxes arranged in a 2 × 2 grid, the distinct ways to place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit are six in number.

There are two possibilities for which box is left blank, so let's consider them separately:

Case 1: The top left box is left blank. In this case, the other three boxes must contain the digits 1, 2, and 3. There are three choices for what digit goes in the top right box, and then two choices for what digit goes in the bottom left box, and then one choice for what digit goes in the bottom right box.

This gives a total of 3·2·1 = 6 ways to place the digits in the boxes when the top left box is left blank.

Case 2: A different box is left blank. In this case, one of the digits must be left out. There are three choices for which digit is left out, and then three choices for which box is left blank. Once the digit and the blank box have been chosen, the remaining two digits can be placed in the other two boxes in any order, giving 2 ways.

This gives a total of 3·3·2 = 18 ways to place the digits in the boxes when a different box is left blank.

Therefore, the distinct ways to place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit are six in number.

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As per the expression, the cost of 444 burgers and 666 hot dogs from Eric's Hot Ham food truck would be $2773.

In this case, Eric's expression is 3.25b + 2h, where b represents the number of burgers and h represents the number of hot dogs. The expression tells us how much it costs to buy a certain number of burgers and hot dogs from Eric's truck.

To find the cost of 444 burgers and 666 hot dogs, we can substitute b = 444 and h = 666 into the expression. So the cost would be:

3.25(444) + 2(666)

Now we just need to simplify this expression by using the order of operations.

First, we multiply 3.25 by 444 to get 1441. Then, we multiply 2 by 666 to get 1332.

Next, we add these two values together:

1441 + 1332 = 2773

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Answer:

Step-by-step explanation:

1/5(-25) + 16/8

-5 + 2 = -3

Option A

The length of the missing side of the geometric system of right triangles is equal to 2√29 units.

In this problem we find a geometric system formed by two right triangles, in which we must determine the length of a missing side. The length can be found by means of Pythagorean theorem, whose formula is now introduced:

r² = x² + y²

Where:

r = 30, x = 28

30² = 28² + y²

y = √(30² - 28²)

y = 2√29

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The LCM of  x² - x and 3 - 3x is given by the  expression 6x² −3x³  −3x.

Equatiοns are statements in mathematics that have twο algebraic expressiοns οn either side οf the equals (=) sign.

It shοws that the expressiοns printed οn the left and right sides have an equal relatiοnship.

In any mathematical equatiοn, we have LHS = RHS (left hand side = right hand side).

Equatiοns can be sοlved tο find the value οf an unknοwn variable that represents an unknοwn quantity.

LCM of unkone terms are given by their product:

(x² - x) × (3 - 3x)

= (3x² -  3x³) - (3x -3x²)

= 3x² -  3x³ - 3x + 3x²

= 6x² −3x³  −3x

Thus, the LCM of  x² - x and 3 - 3x is given by the  expression 6x² −3x³  −3x.

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The sum of the first $20$ terms of the arithmetic sequence is $420$.

In an arithmetic sequence, the sum of the second and eighth terms is $5$, and the product of the fourth and fifth terms is also $5$. The sum of the first $20$ terms of this sequence can be calculated using the following formula:

Sum of the first $20$ terms = $20$/2($a_1 + a_{20})$, where $a_1$ is the first term of the sequence and $a_{20}$ is the twentieth term of the sequence.

Therefore, we need to find the first term of the sequence and the twentieth term of the sequence. To find the first term, we use the following equation:

$5 = a_2 + a_8$, where $a_2$ is the second term and $a_8$ is the eighth term.

To find the twentieth term, we use the following equation:

$5 = a_4 \times a_5$, where $a_4$ is the fourth term and $a_5$ is the fifth term.

Solving both equations, we get $a_2 = 1$ and $a_{20} = 40$. Then, we can calculate the sum of the first $20$ terms of the sequence:

Sum of the first $20$ terms = $20$/2($1 + 40$) = $420$.

Therefore, the sum of the first $20$ terms of the arithmetic sequence is $420$.

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Answer:

Area: 81*pi

Circumference: 18*pi

Step-by-step explanation:

Area: 9^2= 81

So it would be 81*pi

Circumference: 9*2= 18

So it would be 18*pi

If you want the full area then it's 81*pi= 254.34

If you want the full circumference it's 18*pi= 56.55

Therefore , the solution of the given problem of unitary method comes out to be  the composite shape's overall size is 30  square units.

Utilizing previously well-known variables, this uniform convenience, or all crucial elements from a prior flexible study that followed a particular methodology event can all be used to achieve the goal. It will be possible to contact the entity again if the anticipated assertion outcome actually happens; if it doesn't, both important systems will surely miss the statement.

Here,

We must divide the composite shape into smaller shapes and sum up their areas in order to determine the area of the composite shape.

We can see that the composite form is made up of a triangle with a base of four and a height of three, and a rectangle with dimensions of six by four.

=> length times breadth equals six by four, or 24 square units, for a rectangle.

Triangle's area is equal to

=>  (1/2) x base times height, or (1/2) x 4 times 3, or 6 square units.

As a result, the composite shape's overall size is:

=> 24 + 6 = 30  square units.

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Answer:

................

Step-by-step explanation:

.................

Answer:

Step-by-step explanation:

1)   [tex]6x^4 \times 6x^4 = 36x^8[/tex]                (needs to be [tex]36x^{16}[/tex] )

2)   [tex](4y^2) \times (4y^2) =16y^4[/tex]    (needs to be [tex]25y^4[/tex] )

1)   Change both [tex]6x^4 \text{ terms to } 6x^8.[/tex]

2)  Change both [tex]4x^2 \text{ terms to } 5y^2.[/tex]

Bonus:

Need to change a minus to a plus,

     [tex]36x^{16}-25y^4=(6x^8+5y^2)(6x^8-5y^2)[/tex]

Answer:

Step-by-step explanation:

nothing makes it true

The correct option is E. BC and AD, are the two parallel sides of the quadrilateral ABCD.

quadrilateral on  coordinate plane had points:

A(-3, 1) B(1, 4) C(5, 1) D(1, -2).

Find distance between points using distance formulae:

d = √(x2 - x1)²  + (y2 - y1)²

AB = √(1 + 3)²  + (4 - 1)²

AB = √(4)²  + (-3)²

AB = √16 + 9

AB = √25

AB = 5

CD = √(5 - 1)²  + (1 + 2)²

CD = √(4)²  + (3)²

CD = √16 + 9

CD = √25

CD = 5

As, sides Ab and CD are both equal of 5 units each, , then the sides in between them BC and AD will be parallel.

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