Answer:
I'm not sure but I think it's 7
Step-by-step explanation:
28×2= 8x
8÷56=8x÷8
7=x
To show that NMQ ≈ QPN by SAS, what must be the value or x?
I need help with this please help me
Answer:
x = 3
Step-by-step explanation:
You want to know the value of x, given that NM = 5x-1 and QP = 3x+5 in congruent triangles NMQ and QPN.
CPCTCCorresponding parts of congruent triangles are congruent, so we have ...
NM = QP
5x -1 = 3x +5
2x = 6 . . . . . . . . . . add 1-3x
x = 3 . . . . . . . . . . divide by 2
Question 5, Please Answer and Explain
The trigonometric ratios for the angle x in the triangle are given as follows:
tan(x) = f/e.cos(x) = e/d.sin(x) = f/d.What are the trigonometric ratios?The three trigonometric ratios are defined as follows:
Sine of angle = length of opposite side divided by the length of the hypotenuse.Cosine of angle = length of adjacent side divided by the length of the hypotenuse.Tangent of angle = length of opposite side divided by the length of the opposite side.In the right triangle in this problem, we have that d represents the hypotenuse, while the sides relative to angle x are given as follows:
Adjacent side: length of e.Opposite side: length of f.These sides are used along with the definitions of each ratio to give the three trigonometric ratios of angle x.
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Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $80. Use the following random numbers to generate the size of 10 orders. .41 .99 .07 .05 .38 .77 .19 .12 .58 .60 What is the value for the first order size generated randomly based on random number 0.41? What is the value for the last order size generated randomly based on random number 0.60? What is the average order size?
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
a) Determine the value for the first order size generated based on 0.41
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
b) Value of the last order generated based on random number (0.6)
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
c) Average order size
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
The mail order seed follows a uniform distribution
(a) The value of the first order size generated by 0.41
The given parameters are:
[tex]a = 25[/tex] -- the lower bound
[tex]b = 80[/tex] -- the upper bound
To calculate the required value, we make use of the following order formula
[tex]Value = a + r(b - a)[/tex]
Where r represents the random number.
So, we have:
[tex]Value= 25 + 0.41 \times ( 80 - 25 )[/tex]
Open bracket
[tex]Value= 25 + 0.41 \times 55[/tex]
Evaluate the product
[tex]Value= 25 + 22.55[/tex]
Add the terms
[tex]Value= 47.55[/tex]
Hence, the value for the first order size generated randomly based on random number 0.41 is 47.55
(b) The value of the last order size generated by 0.60
In (a), we have:
[tex]Value = a + r(b - a)[/tex]
So, we have:
[tex]Value= 25 + 0.60 \times ( 80 - 25 )[/tex]
Open bracket
[tex]Value= 25 + 0.60 \times 55[/tex]
Evaluate the product
[tex]Value= 25 + 33[/tex]
Add the terms
[tex]Value= 58[/tex]
Hence, the value for the last order size generated randomly based on random number 0.61 is 58
(c) The average order size
To do this, we calculate the order size from 1 to 10, and then calculate the average value of the 10 orders.
Using a calculator, the sum of the 10 orders is:
[tex]\sum x= 478.8[/tex]
The average order size is then calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
This gives
[tex]\sum x= \frac{478.8}{10}[/tex]
[tex]\sum x= 47.88[/tex]
Hence, the average order size is 47.88
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The shaded numbers show a pattern in the multiplication table. Which
expression can find the number that comes next in the pattern?
5
X 0 1 2 3 4
0 0 0 0 0 0
1 0 1 23 4
0
5
0
2.
46
8
10
AWN
O
3
12 15
0
4
Lololo
12 16 20
5
0
5
10 15 20 25
25 + 11
25 x 6
25 X 4
25 + 1
Using pi 3 what is the answer
Answer:
12mm
Step-by-step explanation:
circumference (distance around) is equal to πd.
here, if π is 3, we do 3 x the diameter, which is 4. 3 x 4 = 12mm
If a copy machine can copy 34 sheets of paper in one minute. How many sheets can it copy in 2 hours?
Answer:
Step-by-step explanation:
34x60
60 minutes in a hour
34x60=204
204+204= 408
408 copies in 2 hours
Answer:
4080
Step-by-step explanation:
First you would multiply 34 by 120. After you multiply those numbers you should get 4080 as your answer.
Lillian is wrapping a gift box that has the size shown below. What is the volume of the box?
Enter your answer in the box.
Cube with height of 9 cm and area of base as 36 square cm.
cubic centimeters
[tex] \huge \mathrm{Answer࿐ }[/tex]
[tex] \boxed{\mathrm{volume = area \times height}}[/tex]
[tex]36 \times 9[/tex][tex]\mathrm{324 \: cm {}^{3} }[/tex]_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
Answer:
324
Step-by-step explanation:
if you do 36 times 9 you get 324
make x the subject of the formula in R = ax-p/q+bx
R = (ax - p)/(q + bx)
(ax - p) = R(q + bx)
ax - p = Rq + Rbx
ax - Rbx = Rq + p
x(a - Rb) = Rq + p
x = (Rq + p)/(a - Rb)
Given f(x) and g(x) are polynomials, is the product always a polynomial? Justify your argument.
The product of f(x) and g(x) is , .
select choice(sometimes never always)
a polynomial. By the definition of polynomials the product of polynomials is ,
Select Choice(sometimes never always)
a polynomial because the ,
Select Choice(exponents coefficients variables)
are real numbers and the ,
Select Choice(exponents coefficients variables)
are whole numbers. Real numbers and whole numbers are ,
Select Choice(closed not closed
under addition and subtraction.
The complete statement about the product of the polynomials is that:
The product of f(x) and g(x) is always a polynomial because the coefficients are real numbers and the exponents are whole numbers. Real numbers and whole numbers are closed under addition
How to complete the statementsFrom the question, we have the following parameters that can be used in our computation:
Polynomials f(x) and g(x)
When these polynomials are multiplied;
We get another polynomial
This is because, when you multiply two polynomials you get a sum of monomials.
A sum of monomials is always a polynomial
The sum of monomials stated above implies that the whole exponents and the real coefficients are closed under addition
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Rewrite the radical expression as an expression with a rational exponent.
the seventh root of x to the thrid power
x to the three sevenths power
x to the seven thirds power
x^21
x^4
Answer:
To rewrite the radical expression "the seventh root of x to the thrid power" as an expression with a rational exponent, we need to use the property that allows us to rewrite a root of a power as a power with a rational exponent. This property states that "the nth root of x to the mth power" is equal to "x to the m/nth power".
Using this property, we can rewrite "the seventh root of x to the thrid power" as "x to the 3/7th power". Therefore, the correct answer is "x to the 3/7th power".
The other answer choices are not equivalent to the original expression. "x to the seven thirds power" is not a valid expression because "thirds" is not a unit of measurement. "x^21" is not equivalent to the original expression because the base and exponent are not related in the same way as in the original expression. "x^4" is not equivalent to the original expression because the base is the same but the exponent is not.
Answer: x to the 3/7th power
Step-by-step explanation:
so you dont have to read a essay to get the answer lol
A conservative investor has $100,000 to invest. The investor has decided to use three vehicles for generating income: Municipal bonds, a certificate of deposit (CD), and a money market account. After reading a financial newsletter, the investor also has identified several additional restrictions on the investments:
a. No more than 40 percent of investment should be in bonds
b. The proportion allocated to the money market account will be at least double the amount in the CD
c. The annual return will be 8% for bonds, 9% for the CD and 7% for the money market account. Assume that the investor wants to maximize the total annual return
Then, formulate the LP model for this problem, ignoring any transaction costs and the potential for different investment
Answer: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested
Step-by-step explanation: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested
Consider the set {1, 2, 3, 4}.
a. Make a list of all samples of size 2 that can be drawn from this set of integers.
b. Construct the sampling distribution of sample means for samples of size 2 selected from this set.
c. Provide the distribution both in the form of a table and histogram.
Answer:
(a)
[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]
(b) Sampling Distribution (Table)
[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]
(b) Sampling Distribution (Histogram)
See attachment
Step-by-step explanation:
Given
[tex]Set = \{1,2,3,4\}[/tex]
[tex]n =4[/tex]
Solving (a): A list of sample size 2
We have:
[tex]n =4[/tex]
[tex]r = 2[/tex] --- the sample size
First, we calculate the number of list using permutation (orders matter)
[tex]n(List) = n^r[/tex]
So, we have:
[tex]n(List) = 4^2[/tex]
[tex]n(List) = 16[/tex]
And the list is:
[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]
Solving (b): Sample distribution of sample means of (a)
First, calculate the mean of each set using:
[tex]Mean = \frac{Sum}{2}[/tex]
So, we have:
[tex](1,1) \to \frac{1+1}{2} \to 1[/tex] [tex](1,2) \to \frac{1+2}{2} \to 1.5[/tex] [tex](1,3) \to \frac{1+3}{2} \to 2[/tex] [tex](1,4) \to \frac{1+4}{2} \to 2.5[/tex]
[tex](2,1) \to \frac{2+1}{2} \to 1.5[/tex] [tex](2,2) \to \frac{2+2}{2} \to 2[/tex] [tex](2,3) \to \frac{2+3}{2} \to 2.5[/tex] [tex](2,4) \to \frac{2+4}{2} \to 3[/tex]
[tex](3,1) \to \frac{3+1}{2} \to 2[/tex] [tex](3,2) \to \frac{3+2}{2} \to 2.5[/tex] [tex](3,3) \to \frac{3+3}{2} \to 3[/tex] [tex](3,4) \to \frac{3+4}{2} \to 3.5[/tex]
[tex](4,1) \to \frac{4+1}{2} \to 2.5[/tex] [tex](4,2) \to \frac{4+2}{2} \to 3[/tex] [tex](4,3) \to \frac{4+3}{2} \to 3.5[/tex] [tex](4,4) \to \frac{4+4}{2} \to 4[/tex]
Write out the sample means (sorted)
[tex]\bar x =\{1,1.5,1.5,2,2,2,2.5,2.5,2.5,2.5,3,3,3,3.5,3.5,4\}[/tex]
Construct a frequency table
[tex]\begin{array}{cc}{\bar x} & {f} & {1} & {1} & {1.5} & {2} & {2} & {3} & {2.5} & {4} & {3} & {3} & {3.5} &{2} & {4} & {1} & Total & 16\ \end{array}[/tex]
Construct the sampling distribution where the probability is calculated using: [tex]\frac{f}{Total}[/tex]
So, we have:
[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]
I need help understanding area with combined shapes
Answer:
Step-by-step explanation:
You can start by splitting one whole complex shape into multiple shapes. Then find the areas of the shapes and add them together. Check the image I attached.
Determine the greatest common factor of the following numbers 8 and 12
NO LINKS PLEASE!!!!
50 POINTS !!
PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Answer:
8.2
Step-by-step explanation:
(4.5)^2+(6.9)^2=c^2
20.25+47.61=67.86
sqrt of 67.86= 8.2 (rounded already) :)
please help me with this thank you.
Someone please help me. I will give you hella points I need this answer to like graduate type
Answer:
$9 and $7Step-by-step explanation:
The first equation:
x + 2y = 23The second equation:
2x + 3y = 39Convert to slope-intercept form:
x + 2y = 23 ⇒ 2y = -x + 23 ⇒ y = -1/2x + 11.52x + 3y = 39 ⇒ 3y = -2x + 39 ⇒ y = -2/3x + 13The graph is attached
Intersection point is (9, 7)
Adult tickets cost $9Child tickets cost $7What is the perimeter of the figure?
320 ft is the perimeter
Use the decimals 2.49, 9.19, and 6.7 to write two different addition facts and two different subtraction facts.
The solution to the equations is
Addition : 2.49 + 6.7 = 9.19 ; 6.7 + 2.49 = 9.19
Subtraction : 9.19 - 6.7 = 2.49 ; 9.19 - 2.49 = 6.7
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the equation be represented as A
Now , the value of A is
Let the three decimals be represented as set x = { 2.49 , 6.7 , 9.19 }
Now , the addition facts are given by equations ,
2.49 + 6.7 = 9.19 be equation (1)
6.7 + 2.49 = 9.19 be equation (2)
And , the subtraction facts are given by the equations ,
9.19 - 6.7 = 2.49 be equation (3)
9.19 - 2.49 = 6.7 be equation (4)
Hence , the equations are solved
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PLS BELP I DONT HAVE MUCH TIME!!!
Answer:
I'd say A or D but I have a feeling it's A
Zachary purchased a computer for $1,800 on a payment plan. Three months after he purchased the computer, his balance was 1,350. Five months after he purchased the computer , his balance was 1,050. What is an equation that models the balance B after m Months
Answer: y = -150x + 1800
Step-by-step explanation:
1. Find the linear slope of the line between two points.
(Change in Y)/(Change in X)
2. Write out an equation in point slope form.
(y-y1) = m(x-x1)
y-1800 = -150(x-0)
3. Simplify the equation and turn it into slope-intercept form.
y = -150x + 1800
Can y’all help me on question 13?!
Answer:
C
Step-by-step explanation:
20 - 13 = 7
Answer:
C)
Step-by-step explanation:
7 + 13 = 20
The answer is C
Help me please...... I dknt understand math I’m du.mb
Answer:
281/100
the mixed number would be 2 81/100
Step-by-step explanation:
Times 2.81 by 100
Hope it helps :)
Find each marked side or angle show the step by step
Answer:
taking b as reference angle
using cos rule
cos b=b/h
cos b=1.3/2.8
cos b=0.46
cos 62 =0.46
Step-by-step explanation:
therefore the value of b is 62 degree
I need help ASAP...please please someone help
Answer:
x = 26
Step-by-step explanation:
180=(4x+10)+(x+40)
180 = 4x + x +10 + 40
180 - 50 = 5x
130 = 5x
130 / 5 = x
26 = x
d= c/n solve for n, I've been trying to solve this by multiplying by n but i want to solve for n so that's wrong thank you guys :D
Answer:
You started correctly....
Step-by-step explanation:
d = c/n Multiply both sides by 'n'
dn = c now divide both sides of the equation by 'd'
n = c/d Done.
Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dAR, where R is the region in the first quadrant between the circles with center the origin and radii 3 and 4
Answer:
The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]
Step-by-step explanation:
Polar coordinates:
In polar coordinates, we have that:
[tex]x^2 + y^2 = r^2[/tex]
And
[tex]\int \int_{dA} f(x,y) da = \int \int f(r) r dr d\theta[/tex]
In this question:
[tex]\int \int_{dA} \sin{(x^2+y^2)} dA = \int \int_{dR} = \sin{r^2}r dr d\theta[/tex]
Region in the first quadrant between the circles with center the origin and radii 3 and 4
First quadrant means that [tex]\theta[/tex] ranges between [tex]0[/tex] and [tex]\frac{\pi}{2}[/tex]
Between these circles means that r ranges between 3 and 4. So
[tex]\int \int_{dR} = \sin{r^2}r dr d\theta = \int_{0}^{\frac{\pi}{2}} \int_{3}^{4} \sin{r^2} r dr d\theta[/tex]
Applying the inner integral:
[tex]\int_{3}^{4} \sin{r^2} r dr[/tex]
Using substitution, with [tex]u = r^2, du = 2rdr, dr = \frac{du}{2r}[/tex], and considering that the integral of the sine is minus cosine, we have:
[tex]-\frac{\cos{r^2}}{2}|_{3}{4} = \frac{1}{2}(-\cos{16} + \frac{9})[/tex]
Applying the outer integral:
[tex] \int_{0}^{\frac{\pi}{2}} \frac{1}{2}(-\cos{16} + \frac{9}) d\theta[/tex]
Has no factors of [tex]\theta[/tex], so the result is the constant multiplied by [tex]\theta[/tex], and then we apply the fundamental theorem.
[tex]\frac{\theta}{2}(-\cos{16} + \frac{9}) = \frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]
The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]
Find the range of values of x for which
|2x+1|-x-3<0, where x € R.
By analyzing the inequality and solving, the range of values of x for which the inequality is true is x € (-4/3, 4)
What is domain?Domain is the input to the function.
What is range?Range is the output of the function.
First, we'll consider the case where |2x+1|-x-3<0.
|2x+1|-x-3<0
|2x+1|<x+3
Now we need to take the absolute value of 2x+1, we have two cases to consider:
Case 1:
2x + 1 > 0
2x + 1 < x + 3
2x - x < 3 + 1
x < 4
Case 2:
2x + 1 < 0
-2x - 1 < x + 3
-2x - 1 -x - 3 < 0
-3x - 4 < 0
x > -4/3
Now we must find the intersection between the two cases:
x € (-4/3, 4)
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Tara is painting her room she brought paint that takes 3 gallons to cover an area of 75 square feet how many gallons of paint will tara need to paint 375 square feet of her room
Which equation justifies why ten to the one third power equals the cube root of ten?
ten to the one third power all raised to the third power equals ten to the one third plus three power equals ten
ten to the one third power all raised to the third power equals ten to the one third times three power equals ten
ten to the one third power all raised to the third power equals ten to the three minus one third power equals ten
ten to the one third power all raised to the third power equals ten to the one third minus three power equals ten
The equation that justifies ten to the one third power equals the cube root of ten is ten to the one third power all raised to the third power equals ten to the one third times three power equals ten. Option B
How to justify the powerwe are to find [tex]10^{\frac{1}{3} } = \sqrt[3]{10}[/tex]
The justification has to be done with the use of the properties of powers as well as roots.
[tex]a^\frac{m}{n} = \sqrt[n]{a^m}[/tex]
then we would have:
[tex]\sqrt[3]{10} = \sqrt[3]{10^1} =10^\frac{1}{3}[/tex]
then we would have
[tex](10^\frac{1}{3} )^3\\\\= 10^\frac{3}{3}[/tex]
= 10
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