Velma and Shaggy are debating on which cleaning solution to use when cleaning the Mystery Machine based on how strong the solution may be.

Velma recommends using a 0.25 M NaOH solution with a pH of 13.40.
Shaggy recommends using a 0.025 M NaOH solution with a pH of 12.50.

Who is recommending the stronger cleaning solution, Velma or Shaggy? Why is their recommendation correct?

The syringes' circle measures area 10.17 square inches.

The area of a circle is the area that a circle occupies on a two-dimensional plane. The region contained by the circle's radius or perimeter is another way to define the circle's area. The circle's radius, or r, is equal to its diameter in half.

We need to calculate the area of the circle

You may determine the circle's surface area via

Change the formula's value for r.

Area of circle =π[tex]r^{2}[/tex]

Area of circle =3.14[tex]\times[/tex]1.80[tex]\times[/tex]1.80

Area of circle =10.17 [tex]cm^{2}[/tex]

Hence the area of the Circle is 10.17[tex]cm^{2}[/tex]

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completely saturated with salt to freshwater. ... Salt marshes, estuaries, and mangrove forests are each unique ecosystems in ... These areas often serve as nursing grounds where young marine life is ... Several reptiles reside in the salt marsh habitat,

Answer:

La definición de un elemento es una parte o aspecto de algo abstracto, especialmente uno que es esencial o característico.

Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

En los reactivos hay 6 átomos de hidrógeno pero en los productos solo 2. No cumple la ley de conservación.

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

E 2C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos hay 4 átomos de carbono y en los productos solo dos. No cumple la ley de conservación.

Answer:

Chemical reaction, not physical

Explanation:

The concentration of the HCl solution is 0.816 M (or 816 mM).

To determine the concentration of the HCl solution, we can use the balanced equation for the neutralization reaction between HCl and NaOH:

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

This reaction is a neutralization reaction, which means that the number of moles of H+ ions (from the HCl) is equal to the number of moles of OH- ions (from the NaOH).

Given that 20.4 mL of a 1 M NaOH solution was needed to completely react with 25 ml of HCl, we can use the volume and molarity of the NaOH solution to determine the number of moles of OH- ions:

Molarity = moles of solute/litres of solution

Moles of OH- = (20.4 mL x 1 M) / 1000 mL/L = 0.0204 moles

Since the number of moles of H+ ions is equal to the number of moles of OH- ions, we can use the number of moles of OH- to determine the number of moles of H+ ions:

moles of H+ = moles of OH- = 0.0204 moles

We can then use the number of moles of H+ ions and the volume of the HCl solution to determine the concentration of the HCl solution:

Molarity = moles of solute/litres of solution

concentration of HCl = moles of H+ / (25 mL / 1000 mL/L) = 0.0204 moles / 0.025 L = 0.816 M (or 816 mM)

Therefore, the concentration of the HCl solution is 0.816 M (or 816 mM).

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There are a few reasons why the demand for ammonia has increased over time:

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Answer:you answer would be B

Explanation:and I'm bc I took the rest lol

Parellel Curcuit Explanation: I took the Test On k12

Answer:

b is your answer

Explanation:

Answer:

The solution that is least concentrated is the one containing 4 moles of solute dissolved in 6 liters of solution .

Explanation:

Concentration is defined as the amount of a substance in a given apquantitybof solvent or solution. The unit of concentration is usually given as mol/litre

Mathematically, concentration = Number of moles of solute/ volume of solution in litres.

To determine the solution that is least concentrated from the given solutions, their concentrations in mol/L is calculated.

Concentration of solution containing 4 moles of solute dissolved in 6 liters of solution = 4 mol/6 litres = 0.67 mol/L

Concentration of solution containing 1 mole of solute dissolved in 1 litre of solution = 1 mol/ 1 litre = 1 mol/L

Concentration of solution containing 1 mole of solute dissolved in 1 liter of solution = 1 mol/ 1 litre = 1 mol/L

Concentration of solution containing 8 moles of solute dissolved in 4 liters of solution = 8 moles / 4 litres = 2 mol/L

Concentration of solution containing 8 moles of solute dissolved in 4 liters of solution = 8 moles/ 4 litres = 2 mol/L

Concentration of solution containing 3 moles of solute dissolved in 2 liters of solution = 3 moles / 2 litres = 1.5 mol/L

Therefore, the solution that is least concentrated is the one containing 4 moles of solute dissolved in 6 liters of solution .

Among the following alkenes (D) IV cannot be converted into an alkyne by reacting it with bromine followed by an excess of sodium amide and then with water.

An alkene must first be brominated by an addition reaction that produces a vicinal dibromide in order to transform it into an alkyne. All alkenes that have at least one double bond double substituted render them unsuitable for this method due to the requirement of this vicinal dibromide. This is so that the alkane can undergo a double elimination and produce an alkene, which needs at least one C-H and C-X bond. This hinders the conversion of molecule IV into an alkyne.

The dibromo alkane would change into the provided alkene by losing one unit of HBr if it were to react with bromine. However, the second beta-elimination cannot take place since there isn't hydrogen that is physically linked to the alkene carbon. So (D) IV is the right option.

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A flask contains a mixture of N₂ and O₂ at STP. If the partial pressure of N₂ is 40 kPa, the partial pressure of O₂ is 61.325 kPa.

STP is the abbreviation which is used for a Standard Temperature and Pressure. The standard temperature is 273 K as well as the standard pressure is 1 atm pressure.

1 atm = 101.325 kPa

According to Dalton's law, state's that the sum of the individual pressures exerted by the gases in a mixture is the total pressure.

[tex]P_{total}[/tex]= [tex]P_{A}[/tex] + [tex]P_{B}[/tex]

Therefore, [tex]P_{total}[/tex]= [tex]p_{n2}[/tex] + [tex]P_{O2}[/tex]  

[tex]P_{N2}[/tex] = 40kPa

[tex]P_{total}[/tex] = 101.325kPa

101.325kPa = 40kpa + [tex]P_{O2}[/tex]    

[tex]P_{O2}[/tex] = 61.325kpa

--The given question is incorrect, the correct question is

--"A flask contains a mixture of N₂ and O₂ at STP. If the partial pressure exerted by the N₂ is 40.0 kPa, the partial pressure of O₂ is?"--

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The measurement of expired CO₂ that typically provides a numeric display of the partial pressure of CO₂ in torr or mmHg is the capnometry.

The capnometry measurement of the  CO₂ , carbon dioxide is the measurement in the expired air and it provides the clinician with the noninvasive measurement of systemic metabolism and the ventilation. it is used to determine the correlation in between the tidal CO₂  and the partial CO₂  in the non intubated breathless patents.

Thus, the measurement if the expired CO₂  that shows the partial pressure of the CO₂  is the capnometry.

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Answer:

pH= 0.8

pOH=  13.2

Explanation:

Number of moles = mass/molar mass

mass= 15 g

molar mass =36.5 g/mol

Number of moles = 15 g/36.5 g/mol = 0.4 moles

From;

n= CV

Where;

C= concentration of solution

V= volume of solution

n= Number of moles

C = n/V

n= 0.4 moles

V= 2500mL or 2.5 L

C= 0.4/2.5

C= 0.16 M

Hence [H^+] = 0.16 M

pH= - log [H^+]

pH= 0.8

pOH= 14 - pH

pOH= 14 - 0.8

pOH=  13.2

A 16. 81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21. 33 grams of CO₂ and 5. 822 grams of H₂O are produced. In a separate experiment, the molar mass is found to be 104. 1 g/mol.  The empirical formula is CH₃   and molecular formula is C₇H₇O₂₁

The empirical formula can be calculate as follows:

The reaction can be write

CxHyOz  → CO₂ + H₂O

As a result, we may state that there are two O-atoms for every one C-atom (12g) in CO2 (32g).

This indicates that the ratio is 12g C/32g O.

The molar mass of CO₂ is 44 g/mole.

(12/44) x 33 = 9 g

There are 9 grams of carbon in every 33 grams of CO₂

The same can be done for water:

In H₂O, each element is represented by two H atoms and one O atom. 2 g H and 16 g O.

[2 g H / 18 g H2O] are present in 5. 822 g of water

(2/18)x 5.822= 0.6468 g

The initial sample had 14.16 g of sample, 9 g of C, and 0.6468 g of H, which resulted in 34.3532g of oxygen.

Determine the amount of moles.

C: 9.0 g / 12.0 g/mol = 0.75 mol

H: 0.6468 g / 1.0 g/mol = 0.6468 mol

O: 34.3532g / 16.0 g/mol =  2.14 mol

Then we divide by the smallest number

C: 0.75 mol / 0.6468 mol = 1

H: 0.6468 mol / 0.6468 mol= 1

O:  2.14 mol/ 0.6468 mol =  3

so the empirical formula will be CH₃

Determine the molecular formula

mass molecular formula / mass of empirical formula = n

We have to multiply the empirical formula by n to get the molecular formula.

104.1 /15 = 7= n

This means the  molecular formula = C₇H₇O₂₁

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This double displacement reaction and the coefficients of all the reactants and products in this balanced chemical reaction is Bacl₂ + Na₂CO₃ = BaCO₃ + 2Nacl.

A double displacement reaction is a particular type of reaction in which two reactants swap ions to produce two new molecules. Water-soluble ionic compounds interact with one another in a number of double displacement processes.

Coefficients are the numbers or expressions put in front of a chemical symbol or formula to balance chemical equations. It provides information on the number of atoms or molecules of the drug or chemical that are a part of the reaction.

When two or more compounds come into touch with one another and create a new substance, the process is known as a chemical reaction (s). Reactants or reagents are the name(s) for the substance(s) or substances that are initially incorporated into the chemical process. Chemical reactions typically involve a chemical change and produce one or more products, which typically differ from the reactants in some ways.

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Answer:

no picture you need add it

The bowling ball pendulum didn’t hit Bill Nye in the face because the amount of kinetic energy can never be more than the amount of potential energy, some of the energy is transferred to heat. This statement is true.

The bowling ball pendulum did not hit Bill Nye in the face because potential energy will always be greater than kinetic energy. When a force (a push or a pull) acts on something over a long distance, this occurs.

For instance, if the object is positioned at a higher height, its kinetic energy will be higher. Potential energy is not transferable and varies with object mass, height, and distance.

Thus, The bowling ball pendulum didn’t hit Bill Nye in the face because the amount of kinetic energy can never be more than the amount of potential energy, some of the energy is transferred to heat.

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Answer:

[tex]T_2=238.57^{\circ} C[/tex]

Explanation:

Given that,

Initial volume, V₁ = 43 L

Initial temperature, T₁ = 225℃ = 498 K

Final volume, V₂ = 20.6 L

We need to find the final temperature. We know that, the relation between volume and temperature is given by :

[tex]V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}[/tex]

Put all the values,

[tex]T_2=\dfrac{498\times 20.6}{43}\\\\T_2=238.57^{\circ} C[/tex]

So, the final temperature is equal to [tex]238.57^{\circ} C[/tex].

Yes!

Explanation:

If density is greater, the object sinks. Saturn is mainly composed of the lightest two gases known, hydrogen and helium. It is the only planet in our solar system whose density is less than water.

Answer: Solid ammonium chloride can be separated from a solid mixture of ammonium chloride and anhydrous chloride through the process of sublimation.

Explanation:

A process in which solid substance converts directly into gas without undergoing liquid state is called sublimation.

For example, when solid ammonium chloride is heat in the apparatus then it will convert directly into vapors without undergoing liquid state. During this process it leaves behind anhydrous chloride into the mixture itself.

When these vapors are cooled down at the surface of funnel then it gives ammonium chloride in the solid state.

Thus, we can conclude that solid ammonium chloride can be separated from a solid mixture of ammonium chloride and anhydrous chloride through the process of sublimation.

Answer:

1.) The property by the virtue of which the metals can be beaten into sheets.

Malleability

Click it while asking question it allow u to paste image.

Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Explanation:

Given: Volume of solute = 120 mL

Volume of solvent = 350 mL

Now, total volume of the solution is as follows.

[tex]V_{total} = V_{solute} + V_{solvent}\\= 120 mL + 350 mL\\= 470 mL[/tex]

Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.

[tex]\frac{V_{solute}}{V_{total}} \times 100 mL\\\frac{120 mL}{470} \times 100 mL\\= 25.53 mL[/tex]

Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.

[tex]Percent (v/v) = \frac{25.53 mL}{100 mL}\\= 25.5%[/tex]

Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

To balance a chemical equation, you can only adjust the coefficients; you cannot change the subscripts. The ratios of the atoms in the molecule and the resulting chemical characteristics are altered by changing subscripts.

Changing the coefficients solely affects the quantity of molecules in that specific chemical. However, modifying the subscripts will change the substance itself, rendering your chemical equation incorrect.

You can determine the substance from the subscript. You can find out how much of each element is present in the molecule. The substance itself would change if it were altered. In contrast, simply altering the coefficient results in a change in the number of molecules.

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Answer:

c

c

Explanation:

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Answer: Memory B and memory T cells are types of lymphocytes.

Explanation:

Memory B cells forms the part of adaptive immune system. These cells develop inside the germinal centers of the secondary lymphoid organs. These cells circulate in the blood. These are produced by the bone marrow and can be found in tonsil and spleen. Memory B cells are responsible for recognizing previous infections with a foreign antigen and prepare antibody against the new infection. Memory T cells recognize the antigen lived in the body for longer and produce quick response against it on second exposure. These are one of the types of T lymphocytes.

The Lucas Test is used to detect the presence of a primary alcohol.

When the test is positive, the mixture of the primary alcohol with the Lucas reagent changes from a clear and colourless characteristic to a turbid, cloudy, and hazy characteristic. This visual change is due to the reaction of the primary alcohol with the Lucas reagent which is a mixture of concentrated hydrochloric acid and zinc chloride.

The Lucas Test is used to detect the presence of a primary alcohol, and when a positive result is obtained, the reaction of the primary alcohol with the Lucas reagent, a mixture of hydrochloric acid and zinc chloride, causes the visual change from a clear and colourless characteristic to a turbid, cloudy, and hazy one.

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Normal

BeI2 + SrSO4 → SrI2 + BeSO4

Complete ionic:

Be2+ + 2I- + Sr2+ + SO42- → Sr2+ + 2I- + Be2+ + SO42-

Net ionic:

Be2+ + 2I- → Sr2+ + 2I- + Be2+

The complete ionic equation for this reaction is the same as the normal equation, except that the reactants and products are written as their respective ions.

The net ionic equation is the same as the complete ionic equation, except that the spectator ions, which are ions that appear on both the reactant and product sides, are omitted.

In this reaction, strontium sulfate and beryllium iodide react to form strontium iodide and beryllium sulfate. The spectator ions are Sr2+ and 2I-, which appear on both sides of the equation and cancel out, leaving the net ionic equation.

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