What force is required to stop a 1800-kg car in a distance of 0.20 m if it is initially moving at 2.2 m/s? What if the car is moving at 4.5 m/s

Answers

Answer 1

The formula for the force required to stop the automobile is F = m x a, where m = 1200 kg and F = 1200 x (-12.5) N = - 15000 N.

What force does an automobile need to stop?

As a car brakes, the rotating wheels create friction inside the wheel assemblies, bringing the vehicle to a stop. The kinetic energy of the automobile is lost as heat in the braking components due to this friction force, which slows the spinning of the wheels.

The automobile can come to a stop with any force higher than zero. The only difference is that it will take longer and cover a bigger distance before stopping.

Unless a force acts on a body, it stays at rest or moves in a straight path at a constant speed.

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Related Questions

Urgent help!

Two pure tones Cs and Gs, with frequencies from the Pythagorean diatonic scale, are sounded simultaneously. Find
a) the frequencies of the three combination tones and
b) the notes on the Pythagorean scale to which these tones belong.

Answers

The sum tone has a frequency of (Cs+Gs) and the difference tones have frequencies of (Cs-Gs) and (Gs-Cs).

How are combination tones made and what are they?

Combination tones are tones that are produced by the interaction of two or more pure tones in the ear or in a resonant system. They are produced by the sum and difference of the frequencies of the pure tones.

What is the Pythagorean diatonic scale and how is it related to music?

The Pythagorean diatonic scale is a tuning system in which the frequency ratios between adjacent notes are based on the ratios of small whole numbers. This scale was used in ancient Greek music and later became the basis for Western music theory.

The Pythagorean tuning system is related to music because it provides a mathematical foundation for the intervals and relationships between musical notes, and has influenced the development of Western music for centuries.

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This string is 5 meters long. What is the measurement of one wavelength?​

Answers

For sound waves in air, a wave 5 meters in length has a frequency around 68 Hz.
That's roughly 2 octaves below "middle C".

For electromagnetic waves in vacuum or air, a wave 5 meters in length has a frequency
around 60 MHz. That's the boundary line between the old analog TV channels 2 and 3 .

Which harmonic is this? * ​

Answers

The wave given in the diagram is a third harmonic wave

What type of harmonic is given?

A harmonic wave is a type of wave that is characterized by its frequency, which is a multiple of the fundamental frequency. In other words, a harmonic wave has a frequency that is an integer multiple of the fundamental frequency, such as twice, three times, four times, etc. the fundamental frequency.

A third harmonic wave specifically has a frequency that is three times the fundamental frequency. It is important to note that a third harmonic wave is just one type of harmonic wave, and there can be other harmonic waves with different frequencies that are also multiples of the fundamental frequency.

Third harmonic waves can be observed in various physical systems, including musical instruments, electrical circuits, and mechanical systems. In musical instruments, for example, a third harmonic wave can produce a higher-pitched sound than the fundamental frequency, while in electrical circuits, it can result in a distortion of the signal. In mechanical systems, a third harmonic wave can cause resonance, which can lead to damaging vibrations.

NB: This wave is known as a standing wave

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EARTH AND SPACE SCIENCE!
If we are in the path of totality of an eclipse then which is true?
a.) We are in the shadow of the Penumbra
b.) We may not be experiencing the solar eclipse right at that exact moment but we will be in the shadow of the Umbra at some point.

Answers

Answer:

b

Explanation:

Long answers are always the correct answer. FAXS

a number of sources indicate that writng assignments in lower level college courses are typically pages in length

Answers

According to a variety of sources, writing assignments in college courses at the entry level are typically 5-7 pages long, while those in courses at the main layer can be as long as 15-20 pages.

How often pages should a task have?

The vast majority of the times, the project will give precise instructions on how many words or pages that must produce. This is frequently a range instead of a precise figure   Always check to your teacher if you're unsure.

What is the duration of the assignment?

Length of Assignment refers to the number of days between the initial Operational Phase just at Incident or report site on the originating Resource Order and the beginning of returning travel to the Authorized Dispatch Place upon completion or completion of the assignment.

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A massless spring hangs from the ceiling with a small object of 100 g attached to its lower end. The object is initially held at rest at a position such that the spring is at its rest length. The object is then released and oscillates up and down, with its lowest position being 5.0 cm below the initial position. The object's speed at 2 cm below the initial position is:
Group of answer choices

2.23 m/s

14 m/s

0.21 m/s

0.45 m/s

Answers

The speed of the object at 2 cm below the initial position is 0.45 m/s when a small object of 100 g attached to its lower end.

Given the mass of small object (m1) = 100g

The distance of object from top of spring (x) = 5cm

The point of length of object (l) = 2cm

the speed of object at 2cm below the initial position is = v

We know that F = Kx where F = mg such that:

mg = kx then [tex]100 * 10^{-3} * 9.8 = k * 5 * 10^{-2[/tex]

k = 19.6

We know that from the conservation of energy,

initial potential energy (Ui) + kinetic energy (K.E) = final PE + KE such that:

[tex]1/2kx^2 - mgx + 1/2mv^2 = 0[/tex]

[tex]1/2 * 19.6 * (0.02)^2 - 0.1 * 9.8 * 0.02 + 1/2 * 0.1 * v^2 = 0[/tex]

[tex]0.00392 - 0.0196 = -0.05v^2[/tex]

[tex]0.3136 = v^2[/tex]

v = 0.45m/s

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Imagine, you are elected as a prefect in charge of laboratory in your school. The senior 1 class is about to report for first time. Many of the students have never heard about a laboratory. Prepare a short speech about a laboratory for the new admitted students. The speech should last not more 20 minutes?

Answers

I am very pleased to be here today to welcome all of you to the laboratory.

As a prefect, I am in charge of this laboratory and I would like to take this opportunity to tell you a bit about what a laboratory is and why it is important.A laboratory is a place where scientific experiments are conducted and new knowledge is gained. The laboratory provides a safe and controlled environment for students to explore, analyze, and test out new ideas and concepts. In addition to providing a space for experimentation, the laboratory also provides access to specialized equipment and materials that can be used for research purposes.In the laboratory, you will learn how to use the scientific method to answer questions and solve problems. You will also learn how to properly use the equipment and materials found in the laboratory.This is an important skill that will help you to become a successful scientist.

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Today, which measures are not helping people survive or protect property from earthquakes?
A. building codes that set standards for earthquake-resistant construction
B. long-term predictions about where earthquakes will strike
C. short-term predictions about when earthquakes will strike
D. safety procedures to follow when earthquakes strike

Answers

The practices don't assist people survive earthquakes or safeguard property safety precautions to take when an earthquake occurs.

What are the basic plans for buildings that can withstand earthquakes?

The ability of something like a building to bend, wobble, and deform again without collapsing is referred to as ductility, and it is frequently incorporated into earthquake-resistant designs. When subjected to the either vertical or horizontal shear stresses of an earthquake, a ductile structure can bend and flex.

Do structures withstand earthquakes?

Based just on seismic dangers in the area, buildings are made to endure a particular amount of shaking. For instance, a structure in Los Angeles would be constructed to withstand a stronger earthquakes than one in Nyc. But, seismologists do not often know the precise size.

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5. [6.67/10 Points] DETAILS
MY NOTES
ASK YOUR TEACHER
N/C
(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the
magnitude of the electric field only.)
6.00 μC
1.50 μC -2.00 μC
3.00 cm
Submit Answer
PREVIOUS ANSWERS
---Select---
Need Help? Read It
(b) If a charge of -6.13 µC is placed at this point, what are the magnitude and direction of the force on it?
magnitude
N
direction
SERCP11 15.3.P.018. 2/5 Submissions Used
2.00 cm →

Answers

As the charge is negative, the force, which has a magnitude of 33.05 N, is directed to the left, against the electric field.

What is the electric field's intensity at a specific distance from the point charge E?

E is a symbol for the magnitude of the electric field at a specific distance from a point charge. At twice the distance from the point charge, what is the electric field's strength? The field's strength is E/2 at twice the distance. The field's strength is still equal to E at a distance that is twice as great.

E = k*q/r²

r1 = 2.00 cm

r2 = 1.00 cm + 3.00 cm = 4.00 cm

r3 = 1.00 cm

Using these distances, we can calculate the electric field due to each charge:

E1 = kq1/r1² = (9.0 x 10⁹ Nm²/C²) * (1.50 x 10⁻⁶ C) / (0.02 m)² = 168.75 N/C (to the right)

E2 = kq2/r2² = (9.0 x 10⁹ Nm²/C²) * (-2.00 x 10^⁻⁶ C) / (0.04 m)² = -112.50 N/C (to the left)

E3 = kq3/r3² = (9.0 x 10⁹ Nm²/C²) * (6.00 x 10⁻⁶ C) / (0.01 m)² = 5.40 x 10⁶ N/C (to the right)

E = E1 + E2 + E3 = 168.75 N/C - 112.50 N/C + 5.40 x 10⁶ N/C = 5.39 x 10⁶ N/C (to the right)

F = q*E

F = (-6.13 x 10 C) * (5.39 x 10⁶ N/C) = -33.05 N

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A-65.1 μC charge is in a 23648 N/C electric field. What is the magnitude of the force (in N) on this
charge?

Answers

first of all you need to transform the value of the charge to the SI system which means

-65.1μC = -65.1 × 10^-6 C

then you calculate the force using this formula

F = E / |q|

F = 23648 / 65.1 × 10^-6 N

What is the linear diameter in meters of an object that has an angular diameter of 10 arcs ends and a distance of 50,000 meters?

Answers

the linear diameter of the object is approximately 77.28 meters for an object that has an angular diameter of 10 arcs ends and a distance of 50,000 meters

The angular diameter of an object is the angle it subtends at the observer's eye, while the linear diameter is the physical size of the object. We can use trigonometry to relate the angular diameter, the distance to the object, and the linear diameter.

If an object has an angular diameter of 10 arc seconds (10"), it subtends an angle of:

θ = 10" / 3600 = 0.0027778 radians

The linear diameter, D, is related to the distance, d, and the angle, θ, by the formula:

tan(θ/2) = D/2d

Rearranging this formula gives:

D = 2d * tan(θ/2)

Substituting the given values, we get:

D = 2 * 50,000 m * tan(0.0027778/2)

D = 2 * 50,000 m * tan(0.0013889)

D = 2 * 50,000 m * 0.0007728

D = 77.28 m

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What is an electrical circuit?
A. It is a closed path through which current can flow.
B. It is a loop that provides no resistance at room temperature.
C. It is an open loop that does not permit current flow.
OD. It is a region of accumulation of excess charge.

Answers

Answer:

A

Explanation:

It can be a circuit if it's not closed

A Carnot engine is operated as an air conditioner to cool a house in the summer. The air conditioner
removes 14 kJ of heat per second from the house, and maintains the inside temperature at 293 K, while
the outside temperature is 369 K. The power required for the air conditioner under these operating
conditions, in SI units, is closest to:

Answers

In SI units, the needed power for the air conditioner under these operating circumstances is most closely 69.3 kW.

The power required for a Carnot engine operating as an air conditioner is given by the formula

[tex]P = \frac{Q_H}{\eta },[/tex]

where [tex]Q_H[/tex] is the rate of heat removed from the house, and η is the Carnot efficiency. The Carnot efficiency is given by the formula,

[tex]\eta =\frac{ 1 - T_C}{T_H}[/tex]

where [tex]T_C[/tex] is the cold reservoir temperature (293 K) and [tex]T_H[/tex]is the hot reservoir temperature (369 K).

Thus, the power required for the air conditioner is given by:

[tex]P = \frac{14 kJ/s }{(\frac{1 - 293 K}{369 K}) }\\=\frac{ 14 kJ/s }{ (1 - 0.798) }\\[/tex]

[tex]= \frac{14 kJ/s }{ 0.202 }\\P= 69.3 kW.[/tex]

Therefore, the power required for the air conditioner under these operating conditions, in SI units, is closest to 69.3 kW.

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A 1200 kg wrecking ball hangs from a 14-m-long cable. The ball is pulled back until the cable makes an angle of 19.0 ∘ with the vertical. By how much has the gravitational potential energy of the ball changed?

Answers

Explanation:

Seems like there might be an easier way than all of this trig work.....let me know if it is incorrect:  ( due to rounding the answer may be 8979 J )

The acceleration of a particle is a constant. At t=0, the velocity of the particle is (15.8i+ 18.4j) m/s. At t= 5.1 s the velocity is 14.0j m/s.
(a) What is the particle's acceleration (in m/s^2)?
a=

(b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin.
r(t)=
v(t)=

Answers

Answer:

(a) To find the particle's acceleration, we can use the formula: a = (v2 - v1)/t where v1 is the initial velocity, v2 is the velocity at time t, and t is the time interval. Substituting the given values, we get: a = (14.0j - (15.8i + 18.4j))/5.1 s a = (-15.8i - 4.4j)/5.1 s a = (-3.1i - 0.9j) m/s^2 Therefore, the particle's acceleration is (-3.1i - 0.9j) m/s^2. (b) To find the position function, we can integrate the velocity function with respect to time: r(t) = ∫v(t) dt Integrating

what is diffraction grating​

Answers

Answer:

Diffraction Grating: Definition and Applications

A diffraction grating is a device that is used to separate light into its component wavelengths. It consists of a flat surface that has a large number of parallel grooves or lines etched into it. When light is shone onto the grating, it is diffracted into its individual wavelengths, producing a spectrum of colors. Diffraction gratings are commonly used in various applications, such as spectroscopy, astronomy, and telecommunications.

The science behind diffraction gratings is based on the principles of wave interference and diffraction. When light passes through a narrow slit or a small opening, it diffracts, or spreads out, into a series of bright and dark fringes. When a beam of light passes through a grating, the light is diffracted by each of the parallel lines on the surface of the grating, resulting in a series of bright and dark fringes that are spaced apart at regular intervals. The spacing between the lines on the grating determines the amount of diffraction, and therefore the angle at which the diffracted light is scattered.

Diffraction gratings are commonly used in spectroscopy, which is the study of the interaction between light and matter. Spectroscopy is used in various applications, such as identifying the chemical composition of materials, analyzing the spectra of stars and galaxies, and studying the properties of molecules and atoms.

In astronomy, diffraction gratings are used in telescopes and spectrometers to study the spectra of stars and galaxies. By analyzing the spectra, astronomers can determine the chemical composition, temperature, and other properties of celestial objects.

In telecommunications, diffraction gratings are used in fiber-optic communication systems to separate different wavelengths of light. This allows for the transmission of multiple signals over a single optical fiber, increasing the capacity and speed of the communication system.

In conclusion, a diffraction grating is a device that is used to separate light into its component wavelengths. It consists of a flat surface with parallel lines etched into it, which diffract the light and produce a spectrum of colors. Diffraction gratings are commonly used in spectroscopy, astronomy, and telecommunications, and they play an important role in our understanding of the interaction between light and matter.

Explanation:

Answer:

diffraction grating is an optical component with a periodic structure that diffracts light into several beams travelling in different directions.

Explanation:

"People say that what we're all seeking is a meaning for life. I don't think that's what we're really seeking. I think that what we're seeking is an experience of being alive, so that our life experiences on the purely physical plane will have resonances within our own innermost being and reality, so that we actually feel the rapture of being alive."

Explain the meaning of this excerpt. How can you connect this to The Metamorphosis? Use specific examples from the novella, especially chapter 3, to support your discussion.

Answers

According to this passage, the ultimate aim of existence is to completely experience and appreciate the state of being alive rather than merely to discover a particular purpose or significance.

What purpose does life serve? John Campbell?

"I don't think [the purpose of life] is what we're seeking," said Joseph Campbell. I believe it is an experience of life, allowing our experiences on the strictly physical plane to resonate with our innermost selves and realities, allowing us to truly feel the joy of existence.

What are Joseph Campbell's Journey quotations?

The bravery to probe the depths, the idea of creative rebirth, and the never-ending cycle of transformation within ourselves are all fundamental themes of the hero's journey.

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state two difference between mains electcity and that supplied by 1.5 cell

Answers

The  two differences between mains electricity and that supplied by a 1.5V cell:

Voltage:Power output

What is power output?

Power Output means the average rate of electric energy delivery during one Metering Interval.

Power output: Compared to a 1.5V cell, mains electricity has a much greater power output. This is so that more power can be delivered to devices and appliances by mains electricity, which is provided at a higher voltage and current.

Compared to a 1.5V cell, the voltage provided by mains electricity is usually much higher. A 1.5V cell produces DC (direct current) voltage, whereas the mains electricity in the majority of nations is typically supplied at a voltage of 110–120V or 22–240V AC (alternating current). The kinds of devices and appliances that can be powered by mains electricity versus those that can be powered by a 1.5V cell are affected by this difference in voltage levels.

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A uniform sphere with mass 28.0 kg and radius 0.380 m is rotating at constant angular velocity about a stationary axis that lies along a diameter of the sphere. If the kinetic energy of the sphere is 236 J, what is the tangential velocity of a point on the rim of the sphere?

Answers

The tangential speed of a point on the sphere's rim is 2.31 m/s.

Where does a cycle wheel with a radius of 0.5 metres rotate at a constant angular speed of 10 metres per second?

An area of 0.1 T magnetic field lies perpendicular to the plane of a cycle wheel with a radius of 0.5 m, rotating at a constant rate of 10 rad/s. Between its centre and rim, there is a 0.5 V. zero EMF created.

I = (2/5) * m * r²

where m is the mass of the sphere and r is the radius.

Substituting the given values, we get:

I = (2/5) * 28.0 kg * (0.380 m)² = 1.35 kg m²

K = (1/2) * I * ω²

Substituting the given value of K and the calculated value of I, we get:

236 J = (1/2) * 1.35 kg m² * ω²

Solving for ω, we get:

ω = √(2 * 236 J / (1.35 kg m²)) = 6.62 rad/s

v = r * ω

Substituting the given value of r and the calculated value of ω, we get:

v = 0.380 m * 6.62 rad/s = 2.31 m/s.

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**NEED ANSWER ASAP, DUE TOMORROW**
Why do astronomers believe the disk formed after the stellar halo? (HINT: What observations do we have to support that?)

Answers

Astronomers believe that the disk of the Milky Way galaxy formed after the stellar halo based on several lines of evidence, including observations of the ages and motions of stars in different regions of the galaxy.

What is the evidence of the stars?

One key piece of evidence is that the stars in the halo of the Milky Way are generally much older than the stars in the disk. This suggests that the halo formed first, likely through the merging of smaller galaxies or the accretion of gas and stars from the surrounding environment.

Additionally, the stars in the halo of the Milky Way have very different motions than those in the disk. Halo stars tend to move in random, elliptical orbits, while disk stars follow more circular orbits around the center of the galaxy. This difference in motion also supports the idea that the two structures formed at different times and through different processes.

Finally, studies of the chemical composition of stars in the Milky Way also support the idea that the disk formed after the halo. The disk contains a higher proportion of heavy elements than the halo, which suggests that the disk formed from gas that had already been enriched by earlier generations of stars in the halo.

Taken together, these lines of evidence support the idea that the disk of the Milky Way formed after the stellar halo.

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A person goes down a skate ramp at a height of 10 m and reaches a maximum height of 8 m on the other side. Explain what happens to the energy.

Answers

When a person goes down a skate ramp from a height of 10 m and reaches a maximum height of 8 m on the other side, there is a transfer of energy happening.

What is energy transfer?

Initially, the person has gravitational potential energy due to their position at a height of 10 m. As the person goes down the ramp, this gravitational potential energy is converted into kinetic energy, which is the energy of motion. This is because the person is accelerating as they move down the ramp due to the force of gravity.

As the person reaches the bottom of the ramp, all of their gravitational potential energy has been converted into kinetic energy. At this point, the person's kinetic energy is at its maximum. However, the person's kinetic energy starts to decrease as they move up the other side of the ramp. This is because the person is now moving against the force of gravity and must use their kinetic energy to overcome this force and move upward.

As the person moves up the other side of the ramp, their kinetic energy is gradually converted back into gravitational potential energy. At the maximum height of 8 m on the other side of the ramp, the person's kinetic energy has been fully converted back into gravitational potential energy, and they are once again at their maximum height.

Therefore, the energy of the person is constantly being converted between kinetic energy and gravitational potential energy as they go down the ramp and up the other side. This conversion of energy is due to the force of gravity acting on the person and the changes in their height as they move along the ramp. No energy is lost during this process; it is simply converted from one form to another.

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Complete question is: A person goes down a skate ramp from a height of 10 m and reaches a maximum height of 8 m on the other side, there is a transfer of energy happening.

We perform an experiment with a 28 cm rod with a mass of .07 kg swinging from its endpoint. The pendulum is allowed to move freely. The pendulum system is then placed on a cart. From rest of both the cart and the pendulum, the cart is push and the acceleration (a) of the cart and the angle of the pendulum is measured. (1): Justify based on theory the maximum displacement angle observed. (2): Do the same, but what if the rod is hung 8 cm from its endpoint?

Answers

The rod is hung 8 cm from its endpoint instead of 28 cm, the maximum potential energy and thus the maximum angle of displacement will be smaller.

What is Potential Energy?

Potential energy is the energy possessed by an object due to its position or state. It is the energy that can be stored in an object as a result of its position or configuration. The amount of potential energy an object has depends on its position or configuration relative to other objects or systems, as well as the forces acting on it. Potential energy can be converted into other forms of energy, such as kinetic energy or thermal energy, depending on the situation.

The maximum displacement angle observed in a simple pendulum system is directly related to the initial potential energy and the gravitational potential energy of the system. As the pendulum is pulled away from its resting position, it gains potential energy, which is then converted to kinetic energy as it swings back towards the center.

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CPO Science. what is the net force on the refrigerator shown to the right?

Answers

The magnitude of the net force is 50N, directed to the right. Since there is no friction, the only horizontal force is due to the applied force. The normal force (directed upward) and the force of gravity (directed downward) exactly cancel out.

Applying pressure to a box will cause it to shift. In physical science, the concept of force is essential. Force is expressed in newtons in the metric system. (N). A tiny measure of energy is a newton. 500–1,000 newtons of energy are needed to lift the average person.

A joule is a unit of energy.

With regard to power and distance, the unit of energy is connected. In order to move something one metre with one newton of power, one joule (J) of energy is required. To drag a small book across a table, a joule of energy is roughly equivalent to that required. You can pull harder or for a longer distance if you have more stamina.

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What is the net force on the refrigerator shown to the right?

200 N

1,000 N

50 N

= Fg

1,000 N = F.

b) Calculate the mass of the refrigerator.

c) What is the refrigerator's acceleration?

Some solar panels have a total area of 12 m2 . Each 1.0 m2 of the panels receives 0.85 kJ of energy from the Sun in 1.0 s. The efficiency of the panels is 16%. How much power do they produce?

Answers

The solar panels produce 1.632 kW of power.

The first step is to calculate the total energy received by the solar panels per second. To do this, we need to multiply the total area of the solar panels by the energy received per unit area and the efficiency of the panels. The efficiency takes into account any losses due to conversion of the energy into electrical power.

We are given that each 1.0 m2 of the panels receives 0.85 kJ of energy from the Sun in 1.0 s. Therefore, we can calculate the energy received by the 12 m2 of panels as:

energy received = area x energy per unit area

energy received = 12 m2 x 0.85 kJ/m2

energy received = 10.2 kJ

If the efficiency of the panels is 16%, then the power they produce is:

Power = (Efficiency × Energy) / Time

Power = (0.16 × 10.2 kJ) / 1.0 s

Power = 1.632 kW

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In the scientific method, which of the following should a researcher do after gathering raw data? Perform the experiment to test the hypothesis Analyze the data collected and check to see if they support the hypothesis Propose new directions for further research Report the results obtained through the experiment and list the methodology used

Answers

Answer:

Analyze the data collected and check to see if they support the hypothesis

Explanation: A. if they already have the raw data thaat means they have already conducted the experiment so it can not be the first option

B. once you collect the raw data you need to check if it corresponds to the data so it would have to be the 2 option.

Hopes this helps.

Mica is investigating the speed of waves. She hypothesizes that waves travel at different speeds depending on the media. She sets up an experiment where she sends two different waves through air, water, and glass. She keeps the temperature of eah medium constant and measure the speed of the waves as they travel through each medium. What would be the most likely result if Mica performed the same experiment again, but sent both waves through a vacuum instead of air, water, and glass?

Answers

Answer:

If Mica sends both waves through a vacuum instead of air, water, and glass, then she would find that the waves travel at the same speed. This is because a vacuum is a completely empty space with no matter or medium to interact with, and the speed of light is constant in a vacuum. Therefore, any electromagnetic waves, including light waves, radio waves, and microwaves, would travel at the same speed in a vacuum.

Point charge A is on the x-axis at x = -3.00 cm. At x= 1.00 cm on the x-axis its electric field is 2800 N/C. Point charge B is also on the x-axis, at x= 5.00 cm. The absolute magnitude of charge B is twice that of A.
A) Find the magnitude and direction of the total electric field at the origin if both A and B are positive.
B) Find the magnitude and direction of the total electric field at the origin if both A and B are negative.
C) Find the magnitude and direction of the total electric field at the origin if A is positive and B is negative.
D)Find the magnitude and direction of the total electric field at the origin if A is negative and B is positive

Answers

Answer:

We can use the electric field equation to find the electric field at the origin due to each point charge, and then add them vectorially to find the total electric field. The electric field due to a point charge is given by:

Explanation:

E = k * q / r^2

where k is Coulomb's constant, q is the magnitude of the point charge, and r is the distance from the charge to the point where we want to find the electric field.

A) Both charges are positive. The electric field at the origin due to charge A is:

E_A = k * q_A / r_A^2

where q_A is the magnitude of charge A, r_A is the distance from A to the origin, and we have:

q_A > 0

r_A = 3.00 cm = 0.03 m

The electric field at the origin due to charge B is:

E_B = k * q_B / r_B^2

where q_B = 2 * q_A is the magnitude of charge B, r_B is the distance from B to the origin, and we have:

q_B > 0

r_B = 5.00 cm = 0.05 m

Using Coulomb's constant k = 9.00 x 10^9 N*m^2/C^2, we get:

E_A = (9.00 x 10^9 Nm^2/C^2) * q_A / r_A^2

E_A = (9.00 x 10^9 Nm^2/C^2) * q_A / (0.03 m)^2

E_A = 1.00 x 10^12 q_A N/C

E_B = (9.00 x 10^9 Nm^2/C^2) * q_B / r_B^2

E_B = (9.00 x 10^9 Nm^2/C^2) * 2q_A / (0.05 m)^2

E_B = 7.20 x 10^11 q_A N/C

The total electric field at the origin is the vector sum of E_A and E_B. Since the charges are on the x-axis and the origin is also on the x-axis, the total electric field will be along the x-axis. Therefore, we only need to add the magnitudes of E_A and E_B to get the total electric field:

E_total = |E_A| + |E_B|

E_total = 1.00 x 10^12 q_A N/C + 7.20 x 10^11 q_A N/C

E_total = 1.72 x 10^12 q_A N/C

Substituting q_A = 2800 N/C * (0.01 m)^2 / (9.00 x 10^9 N*m^2/C^2) = 3.11 x 10^-6 C, we get:

E_total = 5.39 N/C

Therefore, the magnitude of the total electric field at the origin is 5.39 N/C, and it is directed along the positive x-axis.

B) Both charges are negative. The only difference from part A is that the charges now have negative signs, so we have:

q_A < 0

q_B = -2 * |q_A| = -2q_A < 0

Substituting these signs into the equations for E_A and E_B, we get:

E_A = -1.00 x 10^12 |q_A| N/C

E_B = -7.20 x 10^11 |q_A| N/C

The total electric field at

not sure if this solves your answer but hope it somewhat helps.

Answer:

A) If both charges A and B are positive, the electric field vectors point away from the charges, and we can use the principle of superposition to find the total electric field at the origin. The electric field at the origin due to charge A is:

E_A = k*q_A/r_A^2

where k is the Coulomb constant, q_A is the charge of A, and r_A is the distance between A and the origin. Since A is on the x-axis, r_A is simply the distance between A and the origin:

r_A = |-3.00 cm| = 3.00 cm = 0.03 m

Using the given electric field at x=1.00 cm, we can solve for the charge of A:

2800 N/C = k*q_A/(0.01 m)^2

q_A = (2800 N/C)(0.01 m)^2/k = 2.5210^-8 C

The electric field at the origin due to charge B is:

E_B = k*q_B/r_B^2

where q_B is the charge of B, and r_B is the distance between B and the origin:

r_B = |5.00 cm| = 5.00 cm = 0.05 m

Since the absolute magnitude of charge B is twice that of A, q_B = 2q_A = 5.0410^-8 C. Using the principle of superposition, the total electric field at the origin is the vector sum of E_A and E_B. Since both electric fields are along the x-axis, the total electric field at the origin will also be along the x-axis:

E_total = E_A + E_B = kq_A/r_A^2 + kq_B/r_B^2

E_total = (910^9 Nm^2/C^2)(2.5210^-8 C)/(0.03 m)^2 + (910^9 Nm^2/C^2)(5.0410^-8 C)/(0.05 m)^2

E_total = 1.87*10^6 N/C

The direction of the electric field is to the right (positive x-axis direction), since the positive charge B is farther to the right than the positive charge A.

Therefore, the magnitude of the total electric field at the origin if both A and B are positive is 1.87*10^6 N/C to the right.

B) If both charges A and B are negative, the electric field vectors point towards the charges, and we can use the same method as above to find the total electric field at the origin. The electric field at the origin due to charge A is:

E_A = -k*q_A/r_A^2

where the negative sign indicates that the electric field is directed towards charge A. The electric field at the origin due to charge B is:

E_B = -k*q_B/r_B^2

Using the same values for q_A and q_B as in part A, we get:

E_total = E_A + E_B = -kq_A/r_A^2 - kq_B/r_B^2

E_total = -(910^9 Nm^2/C^2)(2.5210^-8 C)/(0.03 m)^2 - (910^9 Nm^2/C^2)(5.0410^-8 C)/(0.05 m)^2

E_total = -2.23*10^6 N/C

The magnitude of the total electric field at the origin is 2.23*10^6 N/C, and the direction is to the left (negative x-axis direction), since the negative charges A and B are both to the right of the origin.

Therefore, the magnitude of the total electric field at the origin if both A and B
are negative is 2.23*10^6 N/C to the left.

C) When A is positive and B is negative, the electric field vectors produced by each point charge will be in opposite directions. To find the total electric field at the origin, we need to add the electric field vectors produced by each charge.

The magnitude of the electric field due to charge A at the origin is given by the formula:

E = k * Q / r^2

where k is the Coulomb constant (9.0 x 10^9 N m^2 / C^2), Q is the magnitude of the charge, and r is the distance between the charge and the origin.

Using this formula, the magnitude of the electric field due to charge A at the origin is:

E_A = k * Q_A / r_A^2
= (9.0 x 10^9 N m^2 / C^2) * Q_A / (0.03 m)^2
= (9.0 x 10^9 N m^2 / C^2) * (|Q_A|) / (0.03 m)^2
= (3.2 x 10^6) * |Q_A| N/C

where |Q_A| is the absolute magnitude of charge A.

Similarly, the magnitude of the electric field due to charge B at the origin is:

E_B = k * Q_B / r_B^2
= (9.0 x 10^9 N m^2 / C^2) * (-2|Q_A|) / (0.05 m)^2
= - (1.4 x 10^6) * |Q_A| N/C

where |Q_B| is the absolute magnitude of charge B.

The total electric field at the origin is the vector sum of E_A and E_B:

E_total = E_A + E_B

Since E_A is positive and E_B is negative, the direction of the total electric field is towards the negative x-axis.

The magnitude of the total electric field is:

|E_total| = |E_A + E_B|
= |E_A| - |E_B|
= (3.2 x 10^6) * |Q_A| - (1.4 x 10^6) * |Q_A|
= (1.8 x 10^6) * |Q_A| N/C

Therefore, the magnitude of the total electric field at the origin is (1.8 x 10^6) times the magnitude of charge A, and the direction of the electric field is towards the negative x-axis.

Thunder was heard 2second after the lightening .if the velocity of sound is 350m/s,how far is the lightening

Answers

Thunder was heard 2second after the lightening .if the velocity of sound is 350m/s, the lightening is about 700 meters far.

The meter's definition, please.

In international agreement in 1983, the meter was redefined as the distance that light would travel in a vacuum within 1/299,792,458 of both a second, building on these and other advancements. In a vacuum, this definition also fixed the light's speed at 299,792,458 meters a second.

In terms of measurement, what does the word "meter" mean?

A typical metric unit called a meter is equivalent to around 3 feet, 3 inches. This indicates that metric measurement system includes the meter. Objects about one meter long include guitars, baseball bats, & yard poles. In athletic competitions like running and swimming, distances are also measured in meters.

The distance between the viewer and the lightning is about 700 meters.

To know more about meters visit:

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A gas burner transfers 9.40 ✕ 105 J into a block of ice with a mass of 2.23 kg and an initial temperature of 0°C.
(a)
How much of the energy (in J) supplied by the burner goes into melting all the ice into liquid water? (Enter your answer to at least three significant figures.)
J
(b)
How much of the energy (in J) supplied by the burner goes into raising the temperature of the liquid water? (Enter your answer to at least three significant figures.)
J
(c)
What is the final temperature of the liquid water in degrees Celsius?

Answers

Answer:

HOPE IT HELPS..........

What is the amplitude of this graph? *
A.1
B.2
C.3
D.4​

Answers

The amplitude of the graph is 4. Option D.

What is amplitude?

Amplitude refers to the maximum displacement or distance from the rest position of a vibrating object or wave. In other words, it measures the strength or intensity of the vibration or wave.

For sound waves, it determines the loudness of the sound, while for light waves, it affects the brightness of the light.

In the graph, the maximum amount of displacement of the wave is 4.

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