what is 2x-9=5x+12 with the step by step

Answer:

WHEN X =5 LHS = 32*3 => 96 IS EQUAL TO RHS. therefore five years ago their product of ages is equal to 96.

hope this helps!

Answer:

27 square are there in the given figure

Answer:

put n = 5

A(5)= 2700+(5-1)*0.015*2700=

Answer:

91,25

Step-by-step explanation:

the step by step is on the picture! :)

Answer:

6

Step-by-step explanation:

x = area to be painted

y = gallons of paint needed

we know already one point of that function/graph :

x = 800

y = 2

so, for a simple relationship between the 2 variables we can assume

y = ax

2 = a×800

a = 2/800 = 1/400

so, we get

y = (1/400) x

for 2400 ft²

y = 1/400 × 2400 = 1/4 × 24 = 24/4 = 6

she needs 6 gallons of paint for 2400 ft².

6 gallons of paint are required to cover 2400 ft² area.

Graph options aren't given ; however, we could still obtain the required solution using the information given :

2 gallons covers 800 ft²

Let the number of gallons to cover 2400 feets = x

Using cross multiplication :

2 gallons = 800 feets

x gallons = 2400 feets

Cross multiply :

800 × x = 2400 × 2

800x = 4800

Divide both sides by 800

x = 4800 / 8

x = 6

Hence, 6 gallons of paint are required to cover 2400 ft².

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Answer:

(m-n)

Step-by-step explanation:

1st expression=

[tex] = {m}^{2} - {n}^{2} \: \: \: \: \: \: \: \: \: \: [/tex]

=(m-n) (m+n)

2nd expression=

[tex] ({m - n})^{2} [/tex]

=(m-n)(m-n)

therefore H.C.F=(m-n)

taking common (m-n)

Step-by-step explanation:

Answer-

b) 1

Answer:

15

Step-by-step explanation:

AC is the entire line segment.

AB and BC together make AC.

⇒ AB + BC = AC

⇒ [tex](2x+2)+(3x+6)=23[/tex]

Open the parentheses

[tex]2x+2+3x+6=23[/tex]

Combine like terms

[tex]5x+8=23\\5x=15\\x=3[/tex]

Therefore, x=3. Plug this into 3x+6 to find BC:

[tex]3x+6\\= 3(3)+6\\=9+6\\=15[/tex]

Therefore, BC is 15.

I hope this helps!

Answer:

5

⋅

(

n

+

1

)

Explanation:

To write Five times the sum of a number and one you first make "a number" into a variable. In this case let's call it  

n

.

Next let's create the sum of a number and one. This would be:  

n

+

1

.

Then to get five times this number we need to multiple this expression by five to get:  

5

⋅

(

n

+

1

)

Step-by-step explanation:

Answer:

-21/22

Step-by-step explanation:

1.Apply fraction cross multiply

2. Simplify

3.Expand

4.Subtract 24 from both sides

5.simplify

6. Subtract 18x form both sides

7.Simpiify, then divide both sides by -22to get answer.

Answer : 1+1 = 11

22+22 = 2222

Answer:

Q1: 14

Q2:Yes

Step-by-step explanation:

Q1: 172.5-25.5=147

147/10.5=14

Q2: 22.50+10%=24.75

24.75-20%=19.8

Answer:

84528 birds

Step-by-step explanation:

number of birds in the 2nd flock = 5283 * 5 = 26415

number of birds in the 3rd flock = 26415 * 2 = 52830

total = 5283 + 26415 + 52830 = 84528

Answer:

166.25

Step-by-step explanation:

12 1 /4 + 154

166 1/4

665/4 , 166.25

Hey there!

12 1/4 + 11.14

= 49/4 + 11.14

= 12.25 + 11.14

= 23.39 or 23 39/100

Answer: 23.39 or 23 39/100

Good luck on your assignment and enjoy your enjoy your day!

~Amphitrite1040:)

For the nth week, the total points earned in the DVD rentals is [tex]p_n + 2[/tex]

Your question is not complete, it seems it is missing the following information below;

DVD rentals:         1    2    3    

Total DVD points:  3   5    7    

The number of points earned is a function of number of DVD rentals.

For the first DVD, the number of points earned;

[tex]n_1 = p_1 + c\\\\where;\\c \ is \ the \ constant \ point \ earned[/tex]

3 = 1 + c

3- 1 = c

2 = c

For nth week the total point earned is given as;

[tex]n_t_h = p_n + c\\\\n_t_h = p_n + 2[/tex]

Thus, for the nth week, the total points earned in the DVD rentals is [tex]p_n + 2[/tex]

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Here we have a problem with arithmetic sequences.

After a small online search, I've found that:

Fantastik Flicks gives: 3 points for the first rental, 5 points for the second rental, 7 points for the third rental

And so on.

We will find that the total of points in the n-th week is given by:

Wₙ = 15 + (n - 1)*18

Looking at the number of points given for each rental, we can see that we have an arithmetic sequence with an increase of 2, 3, 5, 7, 9, 11, 13, 15,...

We want to find the total of points earned in each week. For example, for the first week the total of points is: W₁ = (3 + 5 + 7) = 15

For the second week, the total of points is: W₂ = (9 + 11 + 13) = 33

For the third week, the total number of points is: W₃ = (15 + 17 + 19)  = 51

Now let's see if Wₙ also is arithmetic. To see this, we need to look at the difference between consecutive elements of Wₙ.

W₂ - W₁ = 33 - 15 = 18

W₃ - W₂ = 51 - 33 = 18

So in both cases we got the same difference, this makes a lot of sense, taking in account that we construct the Wₙ with an arithmetic sequence, so is logical that the sequence {Wₙ} is also arithmetical.

Now that we know this, we can see that in the n-th week, the total of points will be: Wₙ = W₁ + (n - 1)*18Wₙ = 15 + (n - 1)*18

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I dont even know anything about math

Answer:

[tex]thank \: you[/tex]

Answer:

5k 1/2

Step-by-step explanation:

here you go!!!!!!!!!!!!!!

Answer:

-2h =6-15

-2h =-9

h=-9/-2

h=4.5

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

1:-

[tex]\\ \sf\longmapsto m+15[/tex]

2:-

[tex]\\ \sf\longmapsto x+6[/tex]

3:-

[tex]\\ \sf\longmapsto r-8[/tex]

4:-

[tex]\\ \sf\longmapsto \dfrac{3}{4}x=\dfrac{3x}{4}[/tex]

5:-

[tex]\\ \sf\longmapsto n(n-1)(n-2)=n![/tex]

6:-

[tex]\\ \sf\longmapsto n+(n+2)=2n+2[/tex]

Step-by-step explanation:

I think this answer will be correct

Hi ;-)

[tex]\text{s}=-8 \ \text{and} \ \text{t}=\frac{3}{4}\\\\\text{s}^2\text{t}-10=(-8)^2\cdot\frac{3}{4}-10=\\\\=64\cdot\frac{3}{4}-10=16\cdot3-10=48-10=\boxed{38}[/tex]

A = {0, 1}

B = {2, 3, 4}

C = {3, 5}

Then we have

A × (B U C)

= {0, 1} × {2, 3, 4, 5}

= {{0, 2}, {0, 3}, {0, 4}, {0, 5}, {1, 2}, {1, 3}, {1, 4}, {1, 5}}

and

(A × B) U (A × C)

= {{0, 2}, {0, 3}, {0, 4}, {1, 2}, {1, 3}, {1, 4}} U {{0, 3}, {0, 5}, {1, 3}, {1, 5}}

(underlined pairs are duplicates and common to both A × B and A × C)

= {{0, 2}, {0, 3}, {0, 4}, {0, 5}, {1, 2}, {1, 3}, {1, 4}, {1, 5}}

and these two sets are clearly identical.

Step-by-step explanation:

3a(2a+6b)

3a×2a+3a×6b

6a²+18ab

[tex]\\ \rm\longmapsto ^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]

[tex]\\ \rm\longmapsto ^{12}C_3[/tex]

[tex]\\ \rm\longmapsto \dfrac{12!}{3!(12-3)!}[/tex]

[tex]\\ \rm\longmapsto \dfrac{12!}{3!(9!)}[/tex]

[tex]\\ \rm\longmapsto \dfrac{12(11)(10)(9!)}{3!(9!)}[/tex]

[tex]\\ \rm\longmapsto \dfrac{12(11)(10)}{3!}[/tex]

[tex]\\ \rm\longmapsto \dfrac{1320}{3(2)(1)}[/tex]

[tex]\\ \rm\longmapsto \dfrac{1320}{6}[/tex]

[tex]\\ \rm\longmapsto 220[/tex]

Answer:

3?

Step-by-step explanation:

im not sure tho

Answer:

mean 11.14

Median 10

mode 10.

Explanation

Mean is sum of data divide by number of data.

Mode is the most appearing number.

Answer:

it should -1 because you have to evaluate the number

Domain: [tex](-\infty,\infty)[/tex]

Range: [tex](0,\infty)[/tex]

==============================================================

Explanation:

I'm assuming the function is [tex]f(x) = 2(3)^x[/tex] which is an exponential function.

The domain of any exponential function is the set of real numbers. In interval notation, the domain is [tex](-\infty, \infty)[/tex] which says we can pick any number between negative infinity and positive infinity: aka any number we want. There are no restrictions to worry about such as division by zero errors.

The range of this exponential function is the set of y values such that y > 0. It often helps to see the graph of what is going on (see below). Note how as x heads to the left, and gets more negative, the curve approaches the x axis. It never actually touches it however. So it will never reach y = 0 itself but instead just get very close. The inequality y > 0 translates to the interval notation [tex](0,\infty)[/tex]

----------

Summary:

Domain: [tex](-\infty,\infty)[/tex];  Range: [tex](0,\infty)[/tex]

So that's why the answer is choice A

The domain and range of the function f(x)  are  (-∞, ∞) and  (-∞, ∞) respectively.

A relation is a function if it has only One y-value for each x-value.

The function f(x) = 2(3x) can be simplified to f(x) = 6x.

The domain of a function is the set of all possible input values for x, while the range is the set of all possible output values for f(x).

Since there are no restrictions on the value of x that can be plugged into the function, the domain of f(x) is all real numbers, or (-∞, ∞).

To find the range, we can look at the behavior of the function as x varies. As x increases or decreases, the value of f(x) also increases or decreases, respectively, at a rate of 6 times the rate of change of x.

Therefore, the range of f(x) is also all real numbers, or (-∞, ∞).

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