15 divided by 289 is approximately equal to 0.0519 or 519/10000. Fifteen divided by two hundred and eighty nine is a division problem that involves dividing 15 by 289. To solve this problem, we can use long division or a calculator.
Using long division, we start by dividing the first digit of the dividend (2) by the divisor (15). Since 2 is less than 15, we add a decimal point and a zero to the dividend and continue the process. We bring down the next digit (8) and divide 28 by 15, which gives us a quotient of 1 with a remainder of 13. We add a decimal point after the quotient and bring down the next digit (9) to get 139 as the new dividend. We divide 139 by 15, which gives us a quotient of 9 with a remainder of 4. We add a decimal point after the quotient and bring down the last digit (0) to get 40 as the new dividend. We divide 40 by 15, which gives us a quotient of 2 with a remainder of 10. Finally, we add a decimal point after the last quotient and write the remainder as a fraction over the divisor to get the final answer:
15 divided by 289 is approximately equal to 0.0519 or 519/10000.
In summary, fifteen divided by two hundred and eighty nine is a division problem that can be solved using long division or a calculator. The answer is a decimal or a fraction, depending on how the division is carried out.
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Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points in simplest radical form. ( − 3 , − 4 ) and ( − 5 , − 6 ) (−3,−4) and (−5,−6)
The length of the hypotenuse is 2 times the square root of 5. The Pythagorean theorem can be used to determine the length of the hypotenuse.
How to find distance between two points ?To graph the right triangle with the given points as the hypotenuse, we first plot the points on a coordinate plane . The two points form the endpoints of the hypotenuse, which is the line segment connecting them. We can find the length of this line segment using the distance formula:
distance = [[tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2]}[/tex]
In this case, we have:
distance = [[tex]\sqrt{(-5 - (-3))^2 + (-6 - (-4))^2}[/tex]]
distance = [tex]\sqrt{(-5 - (-3))^2 + (-6 - (-4))^2}[/tex]]
distance = [[tex]\sqrt{4 + 4}[/tex]]
distance = [[tex]\sqrt{8}[/tex]]
We can simplify [tex]\sqrt{8}[/tex] by factoring out the perfect square factor of 4:
distance = [[tex]\sqrt{4 * 2}[/tex]]
distance = [tex]\sqrt{4} *\sqrt{2}[/tex]
distance = 2 * [tex]\sqrt{2}[/tex]
Thus, the distance between the two points is 2 * [tex]\sqrt{2}[/tex] ] units.
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Please answer this question
The perimeter of parallelogram ABCD in which AM ,BN are angle bisector and DM = 4ft and MN = 3ft is: P = 2(AB + BN) = 2(2 + 2) = 8 ft.
What is perimeter?Perimeter is the total length of the boundary or the distance around the edge of a two-dimensional shape such as a polygon or a circle.
To find the perimeter of parallelogram ABCD, we need to find the length of each side of the parallelogram.
Since AM and BN are angle bisectors of parallelogram ABCD, we know that they intersect at the diagonals' midpoint. Therefore, we can say that DM = MB and MN = NA.
Using this information, we can label the sides of the parallelogram as follows:
AB = CD = x (opposite sides of a parallelogram are equal)
AM = MC = BM = MD = x/2 (diagonals of a parallelogram bisect each other)
BN = ND = NA = NC = y (angle bisectors of a parallelogram bisect opposite angles and sides)
DM = 4 ft and MN = 3 ft (given)
Since DM = MB, we can write:
x/2 + 4 = y + 3
x/2 - y = -1
Since BM = MC, we can write:
x/2 + y = x
y = x/2
by substituting-
x/2 + 4 = x/2 + 3
x = 2
Therefore, AB = CD = 2 ft and BN = ND = NA = NC = x/2 = 1 ft.
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Can someone explain this correctly to me?
Answer:
2.80
Step-by-step explanation:
It asks to find the shipping and handling price.
The first step is take that percentage, 20% and convert into decimal form. Then you need to multiply that by the original price. So it would be 0.2 x 14.
That gives you 2.80 which is the shipping and handling price. That's all you have to do.
Wendy throws a dart at this square-shaped target:
Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Explain your answer and show your work
Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer and show your work.
a) The probability of hitting the black circle inside the target is closer to zero.
b) The probability of hitting the white portion inside the target is closer to one.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
The total area of the region is given as follows:
10² = 100 units squared.
The black circle has a radius of one unit(as the diameter is of 2 units), hence it's area is given as follows:
A = 3.14 x 1²
A = 3.14 units squared.
Then the probability of hitting the black circle is of:
3.14/100 = 0.0314 -> closer to zero.
The probability of hitting the white circle is given as follows:
1 - 0.0314 = 0.9686 -> closer to one.
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the physician orders lanoxin elixir 0.175 mg po q.am for the patient. the pharmacy sends a bottle labeled: lanoxin elixir 0.05 mg/ml. how many milliliters will the nurse administer to the patient? write your answer as a decimal number.
The nurse should administer 3.5 mL of Lanoxin elixir 0.05 mg/mL to the patient to achieve the desired dose of 0.175 mg.
First, we need to convert the prescribed dose of 0.175 mg to milligrams per milliliter (mg/mL) using the concentration of the Lanoxin elixir, which is 0.05 mg/mL.
To determine how many milliliters of Lanoxin elixir 0.05 mg/mL the nurse should administer to the patient, we need to use a simple formula:
Dose = Desired dose / Stock strength
Where:
Desired dose is 0.175 mg
Stock strength is 0.05 mg/mL
So, substituting the values into the formula:
Dose = 0.175 mg / 0.05 mg/mL
Dose = 3.5 mL
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Two ballons, Balloon A and Balloon B, have a total volume of 3/5 gallon. Balloon A has a greater volume than Balloon B. The difference of their volumes is 1/5 gallon. Write and solve a system of equations using elimination to find the volume of each balloon.
PLEASE HELP
The volume of balloon A is [tex]\frac{2}{5}[/tex] gallon and the volume of balloon B is [tex]\frac{1}{5}[/tex] gallon.
What is volume?
Any three-dimensional solid's volume is simply the amount of space it takes up. A cube, cuboid, cone, cylinder, or sphere can be one of these solids.
We are given that two balloons have a total volume of [tex]\frac{3}{5}[/tex] gallon.
Let the volume of balloon A be x and the volume of balloon B be y.
So, we get
x + y = [tex]\frac{3}{5}[/tex]
Also, it is given that the difference of their volumes is [tex]\frac{1}{5}[/tex] gallon and Balloon A has a greater volume than Balloon B.
So, we get another equation as
x - y = [tex]\frac{1}{5}[/tex]
Now, on adding both the equations, we get
⇒ 2x = [tex]\frac{4}{5}[/tex]
Now, on solving we get
⇒ x = [tex]\frac{2}{5}[/tex]
Now, on substituting the value of x in the equation, we get
⇒ [tex]\frac{2}{5}[/tex] + y = [tex]\frac{3}{5}[/tex]
⇒ y = [tex]\frac{1}{5}[/tex]
Hence, the volume of balloon A is [tex]\frac{2}{5}[/tex] gallon and the volume of balloon B is [tex]\frac{1}{5}[/tex] gallon.
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Let alpha = phi/2008 . Find the smallest positive integer n such that 2 [cos(alpha) sin(alpha) + cos (4 alpha) sin (2 alpha) + cos (9 alpha) sin (3 alpha) +.....+ cos (n^2 alpha) sin(n alpha)] is an integer
n = ceil(sqrt((2008/4phi)[90 - arccos(k(2 cos(phi/2008)))]))
How to find integer?Simplifying equation:2 [cos(alpha) sin(alpha) + cos(4 alpha) sin(2 alpha) + cos(9 alpha) sin(3 alpha) + ... + cos(n^2 alpha) sin(n alpha)]
= [sin(2 alpha) + sin(8 alpha) + sin(18 alpha) + ... + sin(n^2 alpha)].
Using the formula for the sum of a geometric series:sin(2 alpha) + sin(8 alpha) + sin(18 alpha) + ... + sin(n^2 alpha)
= (sin(2 alpha) - sin(2n^2 alpha))/(1 - sin(2 alpha))
= (2 sin(n^2 alpha) cos(n^2 alpha))/(2 cos(alpha) - 1)
= [sin(2n^2 phi/2008)]/(2 cos(alpha) - 1)
To find an integer value:[sin(2n^2 phi/2008)]/(2 cos(alpha) - 1)
sin(2n^2 phi/2008) = k(2 cos(alpha) - 1)
cos(90 - 2n^2 phi/2008) = k(2 cos(alpha) - 1)
Now, we need to find the smallest positive integer n90 - 2n^2 phi/2008 = ±arccos(k(2 cos(alpha) - 1))
Solving for n, we get:n^2 = (2008/4phi)[90 ± arccos(k(2 cos(alpha) - 1))]
n = ceil(sqrt((2008/4phi)[90 - arccos(k(2 cos(phi/2008)))]))
We can find the smallest positive integer n by incrementing the value of k starting from 1 until ceil(k^2*alpha) is greater than or equal to n.
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GIVING BRAINLIEST FOR RIGHT ANSWER
Answer:
4
Step-by-step explanation:
Answer:
[tex]x\leq 6[/tex]
Step-by-step explanation:
I need the answer help pls
Answer:
Step-by-step explanation:
Triangle A: All sides have length 12 cm.
Triangle B: Two sides have length 10 cm, and the included angle measures 60°.
Triangle C: Base has length 15 cm, and base angles measure 40°.
Triangle D: All angles measure 60°.
Which triangle is not a unique triangle? (5 points)
a
Triangle A
b
Triangle B
c
Triangle C
d
Triangle D
triangle C
Step-by-step explanation:
If you draw it out, it looks unique
a cargo ship carries only 5-ton trucks and 12-ton trucks. for each shipment, the cargo ship must carry at least 750 trucks and the total weight of the trucks can be at most 5,000 tons. what is the maximum number of 12-ton trucks that the cargo ship can carry per trip?
The maximum number of 12-ton trucks that the cargo ship can carry per trip is 750. This is obtained by solving the linear programming problem subject to the given constraints.
Let's denote the number of 5-ton trucks and 12-ton trucks that the cargo ship carries by x and y, respectively. Then, we can write the following two constraints based on the requirements.
x + y ≥ 750 (constraint 1: the ship must carry at least 750 trucks)
5x + 12y ≤ 5000 (constraint 2: the total weight of the trucks can be at most 5,000 tons)
We want to maximize the number of 12-ton trucks y, subject to these two constraints.
To solve this problem, we can use linear programming techniques.
The feasible region is the set of all (x,y) pairs that satisfy the two constraints
The feasible region is bounded by the x-axis, the y-axis, and the two lines 5x + 12y = 5000 and x + y = 750.
We want to find the point in the feasible region where the number of 12-ton trucks y is maximized. This point will lie on one of the corners of the feasible region.
We can calculate the coordinates of the corners of the feasible region by solving the system of equations formed by the two constraint lines:
x + y = 750 (equation 1)
5x + 12y = 5000 (equation 2)
Multiplying equation 1 by 5, we get:
5x + 5y = 3750 (equation 3)
Subtracting equation 1 from equation 2, we get:
7y = 1250
y = 178.57 (rounded to 2 decimal places)
Substituting this value of y into equation 1, we get:
x = 571.43 (rounded to 2 decimal places)
The coordinates of this corner point are (571.43, 178.57).
Similarly, we can calculate the coordinates of the other corner points:
(750, 0), (500, 250), and (0, 750)
We can now evaluate the objective function (the number of 12-ton trucks y) at each of these corner points:
At (571.43, 178.57), y = 178.57
At (750, 0), y = 0
At (500, 250), y = 250
At (0, 750), y = 750
The maximum value of y is 750, which occurs at the point (0, 750).
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The sum of a number and 12 squared
Answer:
x = the unknown number. Its square is x2. The sum of a number and its square is 12:
x + x²= 12
Putting the quadratic into standard form:
x2 + x - 12 = 0
(x+4)(x-3) = 0
x = -4 and 3
Let's check x=-4:
x + x2 = 12
(-4) + (-4)2 = 12
-4 + 16 = 12
12 = 12
Now let's check x= 3:
x + x2 = 12
3 + 32 = 12
3 + 9 = 12
12 = 12
Yup, they both work. There are two answers, x = -4 and x = 3
if you have $11 and save $5 each week how much money you will have after 6 weeks
Answer: 41$
Step-by-step explanation:
This is because 5x6=30 (To find how much money is made)
then 11+30=41 (add both amounts)
The number of cases of a disease
increases by the same factor each year, as
shown in the table below.
Write an expression for the number of
cases of the disease after n years.
Start
End of year 1
End of year 2
End of year 3
Number of cases
1400
2100
3150
4725
Answer:
N*r^n
Step-by-step explanation:
Let the initial number of cases at the start of year 1 be represented by N.
From the given information, we know that the number of cases increases by the same factor each year. Let this factor be represented by r.
Then, at the end of year 1, the number of cases would be N*r, since it has increased by a factor of r.
Similarly, at the end of year 2, the number of cases would be Nrr, or N*r^2.
At the end of year 3, the number of cases would be Nrrr, or Nr^3.
We can use this pattern to write a general expression for the number of cases after n years:
N * r^n
where N is the initial number of cases, r is the common factor by which the number of cases increases each year, and n is the number of years elapsed.
6y^2+11y-7
Solve this pls show work
Step-by-step explanation:
hope this will help u
PLEASE HELP!!
Write a function that represents the situation: A population of 5 fruit flies increases by 12.5% each day.
P(t) = 5(1 + 0.125)^t
where P(t) is the population of fruit flies after t days.
simplify 4+5(3x - 2) - 3x
Answer:
12x - 6
Step-by-step explanation:
[tex] \rm \: 4 + 5(3x - 2) - 3x[/tex]
[tex] \rm \: = 4 + 15x - 10 - 3x \: \sf (distribute \: the \: 5)[/tex]
[tex] \rm= 12x - 6 \: \sf (combine \: like \: terms)[/tex]
[tex] \rm= 6(2x - 1) \: \sf (factor \: out \: a \: 6)[/tex]
[tex] \rm \: = 6(2x) - 6(1) \: \sf (distribute \: the \: 6)[/tex]
[tex] \rm \:= 12x - 6 \: \sf (simplify)[/tex]
a sample of test scores is normally distributed with a mean of 120 and a standard deviation of 10. what score is located 2 standard deviations below the mean? g
The score located 2 standard deviations below the mean is 100. This score can be found by subtracting 2 standard deviations (20) from the mean (120).
The normal distribution is a bell-shaped curve that is symmetrical around the mean. This means that if you calculate the number of standard deviations away from the mean, you can use the same number to calculate how many standard deviations away from the mean the score is.
For example, in this question, the mean is 120 and the standard deviation is 10. To find the score located 2 standard deviations below the mean, subtract 2 standard deviations from the mean. This means the score is 120 - 20 = 100.
In general, the formula for calculating the score located x standard deviations away from the mean is:
Score = Mean + (x * Standard Deviation)
For example, to find the score located 4 standard deviations away from the mean, the formula is:
Score = Mean + (4 * Standard Deviation)
In this example, the score is 120 + (4 * 10) = 160.
In summary, to find the score located x standard deviations away from the mean, use the formula:
Score = Mean + (x * Standard Deviation)
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0.5878. Find the measure of angle B, in degrees, for
Let cos 54° =
sin B = 0.5878.
Determine the domain of the following graph:
Answer:
domain is [-11 , -3]
Step-by-step explanation:
domain is x
range is y
x values are from -11 to -3
Which expression is equivalent to
-5
28p9q5
12pq
7 ? Assume P≠0,q≠0.
The expression -5 + 28p9q5 - 12pq + 7 is equivalent to 7. Since all the terms except the last one contain variables, we can use algebra to solve for the value of the expression.
What is algebra?Algebra is a branch of mathematics which deals with the manipulation of equations, inequalities, and other mathematical expressions. Algebra is used to solve equations, simplify expressions, and model real-world problems.
To begin, we can add -5 and 7 to obtain 2. This means that the expression is now equal to 2 + 28p9q5 - 12pq. We can then simplify this expression by combining like terms.
Since 28p9q5 and -12pq are both products of the same variables, we can add them together. When we do so, we obtain 16p9q5, which means that the expression is now equal to 2 + 16p9q5.
Finally, we can simplify the remaining term by breaking down the product. We can divide 16 by 8 to obtain 2, and then divide 9 by 3 to obtain 3. This means that the expression is now equal to 2 + 2p3q5. Since there are no more terms to simplify, we can conclude that the answer is 2.
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what is the value of the t score for a 99.8% confidence interval if we take a sample of size 5? group of answer choices
the t-score for a 99.8% confidence interval with a sample size of 5 is 4.604.
The t-score for a 99.8% confidence interval with a sample size of 5 can be found using a t-distribution table or calculator.
Since we have a sample size of 5, the degrees of freedom (df) will be n - 1 = 4.
From the t-distribution table or calculator, the t-score for a 99.8% confidence interval with 4 degrees of freedom is approximately 4.604.
Therefore, the t-score for a 99.8% confidence interval with a sample size of 5 is 4.604.
the complete question is :
what is the value of the t score for a 99.8% confidence interval if we take a sample of size 5?
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Solve for y
y-5.4=4.86
Answer: y - 10.26
Step-by-step explanation: Add 5.4 on both sides and that leaves you with y
if the number of samples were doubled, what would be the new confidence interval (keeping the same confidence level?)
If the number of samples is doubled, the new confidence interval would be 9.61, 10.39 or narrower (smaller) while keeping the same confidence level.
. When calculating the confidence interval, the standard error is used, along with the sample mean and the critical value from the distribution. If we have a larger sample size, we can be more confident in our estimate of the population parameter because the sample mean will more closely resemble the population mean. As a result, the confidence interval can be narrower, indicating a higher degree of precision. For Example:Suppose a sample of 50 was taken, and the mean weight of an object was 10 grams with a standard deviation of 2 grams.
At a 95 percent confidence level, the confidence interval for the mean weight would be 10 ± (1.96)(2/√50) = (9.15, 10.85)Now suppose that the sample size is doubled to 100. The standard error will be cut in half, i.e., 2/√100 = 0.2. As a result, the new confidence interval would be 10 ± (1.96)(0.2) = (9.61, 10.39). Notice that the new confidence interval is narrower, indicating a higher degree of precision while keeping the same confidence level.
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PLEASE HELP!!
Solve and explain
Answer:Tham I can’t even se the letters you should have posted each question one by one
Step-by-step explanation:
good luck
9 km
7 km
3 km
3 km
3 km
2 km
8 km
9 km
3 km
7 km
Answer: what do you mean? I need more info-
Step-by-step explanation:
I can answer it with more info :)
10 points question at position 1 samples of rejuvenated mitochondria are mutated (defective) with a probability 0.15. find the probability that at most one sample is mutated in 10 samples
The probability that at most one sample is mutated in 10 samples is 0.746.
To calculate this probability, we use the binomial distribution formula.
The binomial distribution formula is used to calculate the probability of a certain number of successes (in this case, samples that are mutated) in a certain number of trials (10 samples). We need to find the probability of 1 success or fewer in 10 trials.
This is equal to P(x<=1) = 1 - P(x>1), where x is the number of successes.
For this calculation, we need the following parameters: n = 10 (number of trials), p = 0.15 (probability of a single sample being mutated), and x = 1 (number of successes). So, P(x<=1) = 1 - P(x>1) = 1 - P(x = 2) - P(x = 3) - P(x = 4) - P(x = 5) - P(x = 6) - P(x = 7) - P(x = 8) - P(x = 9) - P(x = 10).
The probability of at most one sample being mutated in 10 samples is calculated by adding the individual probabilities of 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 samples being mutated, which equals 0.746.
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No notes. No Book. No Phone. No Ipad
Calculator allowed. Homework allowed
Quiz 6.1
1) Which expression is equivalent to 83
√834
5
√835
a.
b.
4
c. (√83) 5
d. (√83)*
2) Which expression is equivalent to V30'
a. 307
7
b. 305
c. 304
d. 3021
6) Write (b) as a radical expression.
Simplify completely.
Name:
Block:
3) Write x¹/5 in radical form.
Date:
Guinn
4) Write √45 in rational exponent form.
5) What is the value of n if va = a"?
7) Write √-64x as a rational exponent.
Simplify completely.
Part B:
How many times faster (round to the nearest tenth)?
8) The power function H(m) = 240m models an animal's approximate resting heard rate H
(in beats per minute) given its mass m (in kilograms). Consider a gorilla with a mass of 200
kilograms and a chimpanzee with a mass of 50 kilograms.
Part A:
Which animal has a faster heart rate when resting (Show all work)?
The gorilla has a heart rate that is four times faster than the chimpanzee's when they are resting.
What is expression in math?Expression in math is a combination of numbers, variables, operations and/or symbols that represent a value, quantity or an equation. It can either be a single term, or several terms connected by mathematical operations such as addition, subtraction, multiplication and division. Expressions are typically used in equations, formulas and problems to help solve them.
To calculate the heart rate of the gorilla, we use the power function given: H(m) = 240m. Substituting in m = 200, we get H(200) = 240(200) = 48,000 beats per minute.
To calculate the heart rate of the chimpanzee, we use the same power function: H(m) = 240m. Substituting in m = 50, we get H(50) = 240(50) = 12,000 beats per minute.
Therefore, the gorilla has a heart rate that is four times faster than the chimpanzees when they are resting.
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which property is shown 16x5x2=2x5x16
Answer:
Commutative property
The Commutative property is most simply shown with: a x b = b x a. In multiplication, the values can shift or "commute" in any order
g the probability that a patient recovers from a stomach disease is 0.8 exactly 14 recover? at least 10 recover?
A patient's probability of recovering is 0.8, so the likelihood that they won't is 0.2.
The probability that a patient will recover from a stomach disease is 0.8. Assume that 20 persons have reportedly got this illness.
Let X = # of recoveries out of 20 patients who caught the condition while PMF for X and resolve issues. Imagine that a 20-person sample was chosen at random.
Here, Bernoulli trials are applicable.
Recall that the chance of k successes in n trials using the Bernoulli approach is given by:
P(k)=( n/k )p (power k) * (q power n−k)
where q=1-p is the probability that an attempt would fail
where q=1-p is the probability that an attempt would fail
Here, let's make recovery a success. Hence, p = 0.8, q = 0.2, and n = 20
The probability that at least 10 recoveries will occur is
P(X10) = P(10) + P(11) + P(12) +... + P (20)
The complete question will be:
The probability that a patient recovers from a stomach disease is 0.8. Suppose twenty people are known to have contracted this disease. What is the probability that at least ten recover?
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