Answer:
Explanation:
Concentration of Hg⁺² = 7.36 x 10⁻⁴ M
Concentration of Al⁺³ = 1.05 M
2Al + 3Hg⁺² = 2Al⁺³ + 3Hg .
E = E₀ + RT / nF ln [ Al⁺³]² / [ Hg⁺² ]³
E₀ = reduction potential of Hg⁺² minus reduction potential of Al⁺³
= 0.92 V - ( - 1.66 V )
= 2.58 V
E = 2.58 + .059 /n log [ Al⁺³]² / [ Hg⁺² ]³
n = 6 , [Al⁺³] = 1.05 M ; [Hg⁺²] = 7.36 x 10⁻⁴ M
E = 2.58 + .059 /6 log [ 1.05]² / [ 7.36 x 10⁻⁴ ]³
= 2.58 + .059 /6 log 27.65 x 10⁸ .
= 2.58 + .059 /6 [8+ log 27.65 ].
= 2.58 + .059 /6 [8+ log 27.65 ].
= 2.58 + .09
= 2.67 V .
Explain how an anaerobic condition is formed. Indicate the consequence of an anaerobic condition
Question 6 of 10
Which of the following produces a physical change?
A. Leaving metal outside in the rain until rust forms on its surface
B. Turning wood into ash
C. Melting butter in a microwave
D. Combining carbon dioxide and water to make sugar
SUBMIT
Answer:
uhhh D .-.
Explanation:
Answer:C
Explanation:
Argue whether this chemical reaction supports or does not support the Law of Conservation of Matter.
Make sure to explain and justify your answer.
A researcher combines 28g of Magnesium and 15g of Oxygen.
The mass of the substances after the chemical reaction is 32g.
Explanation:
The reaction is as follows:
2Mg(s) + O2(g) ---> 2MgO(s)
and the researcher said that 32 g of MgO was produced.
Stoichiometry:
28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg
15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2
1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO
1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO
0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO
1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO
Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.
Clouds most likely form as a result of
Answer:
Some clouds form as air warms up near the Earth's surface and Rises heated by Sunshine the ground heats the air just above it that warm air starts to rise because when warm it is lighter and less dense than the air around it as it rises its pressure and temperature drop causing water vapor to condense.
When airborne water vapor condenses into observable water droplets or ice crystals, clouds are created.
Condensation is most likely the cause of cloud formation. The transformation of airborne water vapor into a liquid or solid state is known as condensation. When the air is cooled or the pressure of the water vapor is raised, this occurs.
Water vapor from the Earth's surface is constantly evaporating into the atmosphere. When this water vapor rises, it cools in the atmosphere. The pressure of water vapor rises as the air cools. Water vapor will condense on minute airborne particles like dust, pollen, or salt crystals when the water vapor pressure reaches a particular level.
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250 mL of water is collected during a combustion reaction. The temperature in the
room is 23 °C and the pressure is 105 kPa. How many moles of water was collected?
(please show work)
Answer:
10.67 moles is the answers.hope it helped
Bauxite is best used for making (1 point)
nails
wires
paints
drains
***missed it on test when answered wires****
To solve this we must be knowing each and every concept related to ore and bauxite. Therefore, Bauxite is best used for making wires. The correct option is option B.
What is bauxite?Aluminum's primary source of supply is bauxite. Due to its small weight and ease of molding into fine wire or sheets, aluminum is particularly useful.
All across the world, bauxite may be found. The greatest deposits of this ore are in Australia and Guinea, an African nation. Although bauxite was initially found in France, it may now be found all over the world, such as the Caribbean.
Therefore, Bauxite is best used for making wires. The correct option is option B.
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Calculate the % dissociation of 0.10 M solution of acetic acid (pKa = 4.75)
Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, [tex]pK_a = -log\ K_a[/tex]
Taking antilog both side, we get :
[tex]K_a = 1.78\times 10^{-5}[/tex]
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
[tex]\alpha = \sqrt{\dfrac{K_a}{C}}\\\\\alpha =\sqrt{ \dfrac{1.78\times 10^{-5}}{0.1}}\\\\\alpha = 0.0133\times 100 = 1.33 \%[/tex]
Hence, this is the required solution.
Which of the following 1.0 M solutions con-
tains the most particles?
1. glucose
2. ethylene glycol
3. magnesium sulfate
4. potassium chloride
5. sodium sulfate
The most soluble substances gives more number of particles in solution. 1.0 M of sodium sulphate contains most particles here.
What is solubility?Solubility of a solute is the fraction of its concentration which is dissolved in a solvent. When solutes dissolved in solvent the dissociates into ions.
Solubility of a substance depends on the temperature, pressure, bond type and molecular weight of the compound. The no.of particles produced by a molecule when dissolved vary from compound to compound.
Glucose and ethylene glycol partially dissolves in water and they give only one particle as such and does not form ions.
Potassium chloride gives one K⁺ ions and Cl⁻ ions and magnesium sulphate gives one Mg²⁺ and SO₄²⁻ ions. Whereas, sodium sulphate (Na₂SO₄) gives two sodium ions and one sulphate ion.
Hence, more particles are produced when sodium sulphate is dissolved in water. Therefore, 5th option is correct.
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What is the pH of a 4.5 x 10 M HI solution?
Answer:
ik ppl sy no links but https://courses.lumenlearning.com/cheminter/chapter/the-ph-scale/
Explanation: it should help you
Match the time frame listed on the left with the characteristic listed on the
right.
Mesozoic era
?
Age of the dinosaurs
End of the
Mesozoic era
?
Most of Earth a desert
End of the
Paleozoic era
?
2
A layer of iridium
deposited all over Earth
mesozoic era - age of the dinosaurs
end of the paleozoic era - most of earth a desert
end of the mesozoic era - a layer of iridium deposited all over earth
The time frame can be matched with characteristic as:
mesozoic era (age of the dinosaurs) paleozoic era (desert)end of the mesozoic era (layer of iridium)What is matching?Matching is the placing of terms with their meaning or their best fit.
From the question, we can see that mesozoic era was associated with age of the dinosaurs, and paleozoic era is associated with earth in desert.
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How many grams of NaOH are contained in 5.0*10ml of a0. 77 sodium hydroxide solution
Answer:
1.54grams
Explanation:
Molarity of a solution = n/V
Where;
n = number of moles (mol)
V = volume (L)
Based on the information given in this question;
Volume of NaOH solution = 5.0 × 10ml
= 50ml = 50/1000 = 0.050 L
Molarity = 0. 77 M
Using; Molarity = n/V
0.77 = n/0.05
n = 0.77 × 0.05
n = 0.0385mol
To find the mass (grams) of NaOH in the solution, we use the following formula:
mole (n) = mass/molar mass
Molar mass of NaOH = 23 + 1 + 16 = 40g/mol
0.0385 = mass/40
mass = 0.0385 × 40
mass = 1.54grams.
(NEED HELP ASAP)
Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). (3 points)
1.
Adding a catalyst
2.
Removing hydrogen gas
3.
Increasing the pressure
a.
Shift to the right
b.
Shift to the left
c.
No effect
For the given reaction, according to Le -Chatlier principle adding a catalyst will bring the reaction to the right. Removing the hydrogen gas shift the equilibrium to the left and increasing pressure also shift to right.
What is Le -Chatlier principle ?According to this principle, when some a disorder is affecting the equilibrium of the system. The system balanced the factors which created the disorder and make a new equilibrium.
A catalyst always helps to proceed the reaction in the forward direction. Thus adding a catalyst shift the equilibrium to the right.
If any reactant or produced is removed from the system, the system shifts to the equilibrium to that direction in which they are producing. Removing hydrogen gas will then shift the reaction to the right to produce more hydrogen.
Increasing pressure shift the equilibrium to those direction in which the number of number of moles of gases decreases. Hence, the reaction shifts to the right here.
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Plz help me : 4.lodine, (two iodine atoms bonded together) is made up of:
all metals
all nonmetals
metal and nonmetal
Answer:
all non metals
Explanation:
iodine is a non metal, and if a metal had bonded with it, it would he considered a metal and non metal. But since two iodine atoms are bonded together, they are both non metals ( I2)
12. What is the empirical formula for C10H30O5?
3. Which of the following chemical equations is balanced? *
N2+H2 → NH3
N2+3H2→ 3NH3
N2+3H2→ 2NH3
I need some help with this
Answer:
1: b
2: in the article it says that the benefits from the drug outweigh the costs, so it think it is effective.
In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is obtained for liquids when the resulting solution is ideal. For real solutions we introduced activities and activity coefficients. Derive the molar Gibbs energy of mixing and the molar excess Gibbs energy of mixing in terms of activity coefficients.
Answer:
Attached below
Explanation:
Free energy of mixing = ΔGmix = Gf - Gi
attached below is the required derivation of the
a) Molar Gibbs energy of mixing
ΔGmix = Gf - Gi
hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )
b) molar excess Gibbs energy of mixing
Ni = chemical potential of gas
fi = Fugacity
N°i = Chemical potential of gas when Fugacity = 1
ΔG = RT In ( a2 / a1 )
When air moves in small circular patterns, it moves within a
Answer:
Convection
Explanation:
Define the term valence electrons
Answer:
Valence electrons are the number of electrons in an outer shell of an atom that can participate in forming chemical bonds with other atoms.
What would be the pressure if a canister with a volume of 8.95 L holds 0.155 mol of N2 at 23C
The pressure of a container with a volume of 8.95 L holds 0.155 mol of N₂ at 23°C is 42.64 atm.
What is ideal gas law ?Ideal gas law is also called as perfect gas law. It is represent by the equation PV = nRT, where, 'P' is the pressure, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant.
By ideal gas equation,
PV = nRT
Where,
P = Pressure
V = Volume
n = Number of moles
R = gas constant
T = Temperature
First convert temperature into kelvin
23°C + 273 = 296.15K
By putting given value in ideal gas equation we can solve this problem
P × 8.95 = 0.155 × 8.314 × 296.15 ÷ 8.95
= 381.64 ÷ 8.95
= 42.64 atm
Thus, The pressure of a container with a volume of 8.95 L holds 0.155 mol of N₂ at 23°C is 42.64 atm.
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What is voltage? A. The pressure that pushes electrons to the anode; it is derived from the negative charge of electrons at the cathode. B. None of these C. The speed of the electrons flowing to the anode; it is determined by the type of metal the electrodes are made of. D. The pressure that pushes electrons to the cathode; it is derived from the negative charge of electrons at the anode.
Answer:
D
Explanation:
I think it's D but not 100% sure
The pressure that pushes electrons to the cathode is derived from the negative charge of electrons at the anode. Hence, option B is correct.
What is an electrolytic cell?An electrolytic cell is a type of electrochemical cell that undergoes non-spontaneous reactions by deriving the energy in the form of voltage from external sources.
A voltaic cell is a cell in which chemical reactions are used to produce electrical energy in form of current.
Such a cell is made up of two electrodes and their electrolytes. The electrodes are connected via a salt bridge. The salt bridge allows electrons to move between the electrodes.
In a voltaic cell, an oxidation reaction occurs in the anode. During oxidation, electrons are produced. Therefore, the Na electrode in the anode will lose an electron spontaneously. At the cathode, reduction occurs. The Iron electrode here will gain the electron produced by the oxidation reaction at the anode. The salt bridge moves the electrons from the anode to the cathode.
Hence, the pressure that pushes electrons to the cathode is derived from the negative charge of electrons at the anode.
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What is the formula for Iodine Pentafluride?
Answer:
It's IF5. ................
pls help
1. write the complete chemical symbol for the ion with 14 protons 15 neutrons and 18 electrons
2. write the complete chemical symbol for the ion with 27 protons 32 neutrons and 25 electrons
Answer:
Particle Symbol Mass
electron e- 0.0005486 amu
proton p+ 1.007276 amu
neutron no 1.008665
What is the mass percent of calcium chloride if 57 g of CaCl2 is
dissolved in 334 g of water?
Answer:
Solubility in water Anhydrous: 74.5 g/100 mL (20 °C) Hexahydrate: 49.4 g/100 mL (−25 °C) 59.5 g/100 mL (0 °C) 65 g/100 mL (10 °C) 81.1 g/100 mL (25 °C) 102.2 g/100 mL (30.2 °C) α-Tetrahydrate: 90.8 g/100 mL (20 °C) 114.4 g/100 mL (40 °C) Dihydrate: 134.5 g/100 mL (60 °C) 152.4 g/100 mL (100 °C)
What is an electrolyte?
a
A-Any type of substance
A salt
A substance that cannot conduct electricity in solution
A substance that can conduct electricity in solution
с
d
Answer:
A substance that can conduct electricity in solution
How many moles are in 3.555 g of c2h2?
Answer:
0.13653499904751903
Explanation:
Convert Units .com
BONUS QUESTION
you are stuck with a problem. You need to measure pH of a solution known to be made from a metal hydroxide, but you don't have a meter or any indicators. You do happen to have some lead(II) nitrate that is soluble, and you remember that lead (II) hydroxide is insoluble. You add some to 1 liter of your own unkown solution and a precipitate forms. You add more unttil the precipitate stops forming and then a bit more just in case. After you filter and dry the precipitate, you have 3.81 grams of it. What was the approximate pH of the original solution?
*This is just a bonus question but I'm very confused on it so any help would be appreciated*
Answer:
pH = 12.5
Explanation:
The reaction that takes place is
2OH⁻(aq) + Pb⁺²(aq) → Pb(OH)₂(s)The OH⁻ species come from the metal hydroxide of the solution, and Pb(OH)₂ is the precipitate.
Now we convert 3.81 grams of Pb(OH)₂ into moles, using its molar mass:
3.81 g ÷ 241.12 g/mol = 0.0158 mol Pb(OH)₂Now we convert 0.0158 Pb(OH)₂ moles into OH⁻ moles, using the stoichiometric coefficients of the reaction:
0.0158 mol Pb(OH)₂ * [tex]\frac{2molOH^-}{1molPb(OH)_2}[/tex] = 0.0316 mol OH⁻With the given concentration (1 L), we calculate [OH⁻]:
[OH⁻] = 0.0316 mol / 1 L = 0.0316 MThen we calculate the pOH of the solution:
pOH = - log[OH⁻] = 1.5And finally we calculate the pH:
pH = 14 - pOHpH = 12.5All rivers have deltas; explain the process that forms these common landmasses.
How does a river form a delta?
Deltas are wetlands that form as rivers empty their water and sediment into another body of water. ... Deltas are wetlands that form as rivers empty their water and sediment into another body of water, such as an ocean, lake, or another river. Although very uncommon, deltas can also empty into land.
A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur.
Solution A: 2.67 % (m/v) NaCl
Solution B: 1.13 % (m/v) glucose
Solution C: distilled H2O
Solution D: 8.69 % (m/v) glucose
Solution E: 5.0% (m/v) glucose and 0.9% (m/v) NaCl
Write each solution to the appropriate bin.
Crenation Hemolysis Neither
Answer:
Following are the responses to the given choices:
Explanation:
The RBC crenation is implied through NaCl by 2,67 percent(m/v) because that solution becomes hypertonic to RBC because of the water within the RBC that passes externally towards the outskirts. RBC thus shrinks.1.13% (m/v), because the low concentration or osmotic that all this solution shows is hypotonic regarding RBC because of the water which has reached the resulting swelling in RBC.Distilled H2 implies hemolytic distillation.Glucose is indicated by crenation at 8.69 percent (m/v).5.0% (m/v) glucose and 0.9% (m/v) (Crenation is indicated by NaCl.v)If the lungs of a child hold 0.11 mol of air in a volume of 2.8 L, then the lungs of an average female adult, with a volume is 4.6 L, can be expected to hold 0.18 mol of air.
show work
Answer:
Explanation:
A childs lung can hold .11mols/ per 2.8 L so that gives us a molarity of .039M
A adults lungs can hold .18 mols /per 4.6 so that gives us .039M aswell meaining that the lung capacity between the two is not different.