Answer:
[tex]\displaystyle \text{min} = \frac{\sqrt{3+2\sqrt{3}}}{2} - \frac{2\sqrt[4]{3}}{\sqrt{2}} \text{ at } x = \frac{\sqrt{3}}{2}\text{ and } \\ \\ \text{max} = 2\sqrt{5} -4 \text{ at } x = 4[/tex]
Step-by-step explanation:
We want to find the maximum and minimum values of the function:
[tex]\displaystyle f(x) = \sqrt{x + x^2} - 2\sqrt{x}[/tex]
On the interval [0, 4].
First, evaluate its endpoints:
[tex]\displaystyle \begin{aligned} f(0) &= \sqrt{(0)+(0)^2} - 2\sqrt{0} \\ &= 0 \\ \\ f(4) &= \sqrt{(4)+(4)^2} - 2\sqrt{(4)} \\ &= 2\sqrt{5} -4 \end{aligned}[/tex]
Recall that the extrema of a function occurs at its critical points; that is, where its derivative equals zero (or is undefined).
Take the derivative of both sides:
[tex]\displaystyle f'(x) = \frac{d}{dx}\left[ \sqrt{x + x^2} - 2\sqrt{x}\right][/tex]
Differentiate:
[tex]\displaystyle \begin{aligned} f'(x) &= \frac{1}{2\sqrt{x + x^2}} \cdot (1 + 2x) - 2\left(\frac{1}{2\sqrt{x}}\right) \\ \\ &= \frac{2x+1}{2\sqrt{x+x^2}} - \frac{1}{\sqrt{x}} \\ \\\end{aligned}[/tex]
Note that the derivative is undefined at x = 0. Hence, x = 0 is a critical point.
Solve for the zeros of the derivative:
[tex]\displaystyle\begin{aligned} \frac{2x+1}{2\sqrt{x + x^2}} - \frac{1}{\sqrt{x}} &= 0\\ \\ \frac{2x+1}{2\sqrt{x}\sqrt{1 + x }} - \frac{1}{\sqrt{x}} &= 0 \\ \\ \frac{2x+1}{2\sqrt{1+x}} - 1 &= 0\\ \\ 2x + 1 &= 2\sqrt{1+x} \\ \\ 4x^2 + 4x + 1 &= 4 + 4x \\ \\ x^2 &= \frac{3}{4} \\ \\ x= \frac{\sqrt{3}}{2} \end{aligned}[/tex]
Therefore, our only two critical points are at x = 0 and x = √3/2:
Evaluate the function at x = √3/2:
[tex]\displaystyle \begin{aligned} f\left(\frac{\sqrt{3}}{2}\right) &= \sqrt{\left(\frac{\sqrt{3}}{2} \right)+ \left(\frac{\sqrt{3}}{2}\right)^2} - 2 \sqrt{\left(\frac{\sqrt{3}}{2}\right)} \\ \\ &= \frac{\sqrt{3+2\sqrt{3}}}{2}- \frac{2\sqrt[4]{3}}{\sqrt{2}} \\ \\ &\approx -0.5900\end{aligned}[/tex]
In conclusion: the exact maximum and minimum values of f on the interval [0, 4] is:
[tex]\displaystyle \text{min} = \frac{\sqrt{3+2\sqrt{3}}}{2} - \frac{2\sqrt[4]{3}}{\sqrt{2}} \text{ at } x = \frac{\sqrt{3}}{2}\text{ and } \\ \\ \text{max} = 2\sqrt{5} -4 \text{ at } x = 4[/tex]
look at the image bellow<3
Answer:
1770000, 1800000
Step-by-step explanation:
1770000
Answer:
1,770,000 & 1,780,000
Step-by-step explanation:
Rounding, I suppose
The graph represents a function.
Which ordered pair can be plotted together with these four points, so that the resulting graph still represents a function?
O (0,0)
0 (-3,1)
0 (1,3)
O (31)
If we consider the ordered pair (0,0) then only the graph still represents a function.
How to define a graph represent a function?
In a function, there can not be two different values of x corresponding to the same value of y.
Here, the points on the graph are (0,0), (-3,1), (1,3) and (3, 1).
If we consider point (-3,1) then there will be two points corresponding to the same y value i.e. (-3,1) and (3, 1).
The values of x for a single value of y.
i.e. y = 1.
So, if we consider the ordered pair (0,0) then only the graph still represents a function. Therefore, the correct answer is option (a) (0,0).
To learn more about the graph
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YA'LL ARE SMART!! PLEASE HELP!!
Answer:
Its C
Step-by-step explanation:
Substitute in 3 for x and check. The equation doesn't work.
Substitute 2 in for y. The equation still doesn't work.
So its right.
lol are u using edguenity
rip
4/10 divided by 5/8
Answer:
16/25
Step-by-step explanation:
keep the first fraction the same, make the second fraction 8/5, and then multiply the two fractions across.
Power Function:
Exercise: Recognize and analyze the graph of the power function as the exponent "n" and the coefficient "a" vary
1. Consider a positive exponent power function
A) Describe the graph of the function when n is even, for this you must attach an image of the graph of the function that meets these conditions.
B) Describe the graph of the function when n is odd, for this you must attach an image of the graph of the function that meets these conditions.
C) Describe what happened when the coefficient a is positive and also when it is negative. Is there any change in the graph?
D) Describe what happened when the coefficient a increases or decreases. What happens to the graph of the function?
2. Consider a negative exponent power function
A) Describe the graph of the function when n is even, for this you must attach an image of the graph of the function that meets these conditions.
B) Describe the graph of the function when n is odd, for this you must attach an image of the graph of the function that meets these conditions.
C) Describe what happened when the coefficient a is positive and also when it is negative. Is there any change in the graph?
D) Describe what happened when the coefficient a increases or decreases. What happens to the graph of the function?
Problem 1
Part A
If n is even, then we have a "parabolic" shape going on. I put that in quotes because if n = 2, then we have a true parabola; however, if n is even and larger than 2, then we have a curve that looks like a parabola, but it's not exactly a perfect parabola. All of these curves have in common that the end behavior is the same for the left and right sides.
Consider the example where a = 1 and n = 2. This means
y = a*x^n
turns into
y = 1*x^2
which is the same as
y = x^2
This produces the parent parabola curve. This curve opens upward.
I recommend using Desmos to graph y = a*x^n, where the 'a' and n are parameters set up. Check out the screenshot below.
---------------------
Part B
If n is odd, then we'll get something that looks like a cubic curve. If n = 3, then we get a cubic curve. If n is odd and n > 3, then we get something that looks like a cubic curve, but it's not exactly this perfect cubic.
If we let a = 2 and n = 3, then y = a*x^n becomes y = 2x^3. The graph of which is below.
---------------------
Part C
If a > 0 then the curve is like the previous examples shown earlier.
If a < 0, then we will reflect those given earlier curves over the horizontal x axis. An example is shown below using y = -x^2. This time we have a = -1 and n = 2. In other words, I reflected the example in part A over the x axis.
---------------------
Part D
As 'a' increases, then the graph gets more narrow. It also gets vertically stretched. Consider the example of going from y = 1x^2 to y = 3x^2 as shown below.
As 'a' decreases, then the process is done in reverse: the curve gets more flatter and wider horizontally. We consider the curve to be vertically compressed or squished. So we'd go from y = 3x^2 to y = 1x^2 as an example.
============================================================
Problem 2
Part A
For all of problem 2, we'll only consider negative values of n. We want n to be even, so let's say n = -2. Furthermore, let's say a = 2.
This means y = ax^n becomes y = 2x^(-2) which is the same as y = 2/(x^2)
The curve we get is really two separate pieces. There's a gap or disconnect at x = 0 because of a division by zero error. One piece of the curve is always increasing, while the other piece is always decreasing.
---------------------
Part B
Since we want n to be odd and negative, let's say n = -1. We'll keep a = 2 the same as before.
That means y = ax^n becomes y = 2x^(-1) as shown in the diagram below. What we have is a hyperbola. This is a disconnected set of two curves that collectively entirely define this function in a visual sense. Note the gap when x = 0 due to the division by zero error.
Recall that y = 2x^(-1) is the same as y = 2/x
Again, I'm using Desmos to generate each of these graphs.
Similar to part A, the two pieces are disconnected. This curve is known as hyperbola. It's always increasing if a < 0, and it's always decreasing when a > 0.
---------------------
Part C
If 'a' is positive, then the graph of y = 2/(x^2) is entirely above the x axis (aka everything is positive). On the flip side, if 'a' is negative, then everything swaps to being negative. That will reflect the curve over the x axis to get what you see in the example below. We have a = -2 and n = 2.
---------------------
Part D
As 'a' increases, this means the graph spreads out. If 'a' decreases, then it gets more compressed.
An example is shown below going from y = 1/x to y = 3/x which shows expansion going on (reverse it to get a compression).
============================================================
Once again, the screenshots are shown below as examples.
PLEASE HELP!!! MATH IS HORRIBLE! URGENT!!
What is the algebraic expression for the word phrase "the quotient of 24 and 6 less than m"?
A. m-6/24
B. 24/m-6
C. 6-m/24
D. 24/6-m
Answer:
A. m-6/24
Step-by-step explanation:
This is the required expression because,
1. Quotient of 24 and 6 less than m.
2. It means quotient of 24 and 6 subtracted from m.
3. Representing it mathematically, m-6/24.
The mathematical expression for "the quotient of 24 and 6 less than m" is m - 6/24 option (A) is correct.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
It is given that:
The expression in the word is: "the quotient of 24 and 6 less than m"
Here m is the number.
The quotient of 24 and 6 is 6/24
Linear expression can be defined as the relation between two variables, if we plot the graph of the linear expression we will get a straight line.
If in the linear expression, one variable is present, then the expression is known as the linear expression in one variable.
The quotient of 24 and 6 is less than m which means 6/24 should be subtracted from m.
= m - 6/24
Thus, the mathematical expression for "the quotient of 24 and 6 less than m" is m - 6/24 option (A) is correct.
Learn more about the expression here:
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HELP BRAINIEST TO WHOEVER RIGHT
Answer:
180 degrees
Step-by-step explanation:
Two angles are called supplementary when their measures add up to 180 degrees.
Another name for plane 2
Answer: https://www.lmtsd.org/cms/lib/PA01000427/Centricity/Domain/187/1.1%20Answer%20Key.pdf
Step-by-step explanation:
that sould work
What’s the answer ASAP
Answer:
none
Step-by-step explanation:
38×2=76
43×2=86
45×2=90
Use the similar shape concept of geometry to find the missing value (x). Round your answer to the nearest tenth if necessary.
7 in
3 in
x in
4 in
Step-by-step explanation:
7:3
4:x
-cross multiply
7x = 12
x = 12÷7
x = 1.7
Define terminating and non terminating decimals.
Answer:
terminating decimals has an end digit and has a finite number of digits.
Non-terminating has no end term and has an infinite number of terms.
Select the conic section that represents the equation.
x² + y²=8
circle
ellipse
parabola
hyperbola
Answer:
hyperbola!!!
Step-by-step explanation:
What does this symbol mean ~=
Answer:
It means that it is approximately equal to or about/around.
Help plz due in 20 min
Answer:
its either the 3rd one or the 5th one
sorry hope this helps a little bit
Step-by-step explanation:
Answer:
49½+5½
Step-by-step explanation:
Because here, we have 7√5, which we can place the two numbers in index form, 7 is equal to√49 which is 49½ and √5 is equal to 5½. So the answer is 49½•5½
what is the y intercept of the quadratic function f(x)=x^2+x-6
Answer:
[tex](0,\, -6)[/tex].
Step-by-step explanation:
On a cartesian plane, the [tex]y[/tex]-intercept of a function is the point where the graph of that function intersects with the [tex]y\![/tex]-axis.
The [tex]y[/tex]-axis of a cartesian plane is the same as the equation [tex]x = 0[/tex] (that is, the collection of all points with an [tex]x[/tex]-coordinate of [tex]0[/tex].)
Construct a system of two equations, with one equation representing [tex]y[/tex]-axis and [tex]y = f(x)[/tex] to represent the graph of this function:
[tex]\begin{aligned}\begin{cases} y = x^{2} + x - 6 & \text{for the quadratic function} \\ x = 0 & \text{for the $y$-axis}\end{cases}\end{aligned}[/tex].
Solve this system for [tex]x[/tex] and for [tex]y[/tex]. If a solution exists, then the [tex]y\![/tex]-axis and the graph of [tex]y = f(x)[/tex] would indeed intersect. The point [tex](x,\, y)[/tex] would be the intersection of the [tex]y\!\![/tex]-axis and the graph of [tex]y = f(x)\![/tex].
Substitute the second equation of the system into the first.
[tex]\begin{aligned}\begin{cases} x = 0 \\ y = -6\end{cases}\end{aligned}[/tex].
Hence, the intersection of the [tex]y[/tex]-axis and the graph of [tex]y = f(x)[/tex] would be [tex](0,\, -6)[/tex]. By definition, this point would be the [tex]y\![/tex]-intercept of [tex]y = f(x)\![/tex].
Answer: (0, -6)
Step-by-step explanation:
got it right on my test
Helppp me pleaseee!!!!!!!!!!
Answer:
A
Step-by-step explanation:
-4.5+4.4= -0.1
-0.1 + x = 0
So the answer needs to be equal to 0.1.
-6.7+6.8= 0.1
-4.5+4.4 -6.7+6.8 =0
I don’t understand this
Answer:
Yes
Step-by-step explanation:
Statement 1: If JK and LM bisect each other then, they divide each other in 2 equal parts.
So,
JP = PK [Because of statement 1]
MP = PL [Because of statement 1]
∠JPM = ∠LPK [Because they are vertically opposite angles]
So, ΔJPM ≅ to ΔKPL [By SAS congruence criteria of triangle]
The surface area of a cone with radius r units and slant height s units is shown below: Surface area = 3.14(rs + 2) Part A: Ifr= 6 units and s = 4 units, write an expression that can be used to calculate the surface area of the cone. (4 points) Part B: What is the surface area of the cone? Show your work. (6 points)
Answer:
188.4 units²
Step-by-step explanation:
Hi there!
Part A
Surface area of a cone = [tex]3.14(rs+r^2)[/tex] where r is the radius of the base and s is the slant height
⇒ r = 6
Replace r with 6
[tex]3.14(6s+6^2)[/tex]
⇒ s = 4
Replace s with 4
[tex]3.14(6*4+6^2)[/tex]
Part B
Evaluate the expression found in Part A:
[tex]3.14(6*4+6^2)[/tex]
Find 6²:
[tex]=3.14(6*4+36)[/tex]
Find 6*4:
[tex]=3.14(24+36)[/tex]
Find 24+36:
[tex]=3.14(60)\\=188.4[/tex]
Therefore, the surface area of the cone is 188.4 units².
I hope this helps!
What is the slope of the line represented by the equation f(x) = -3x + 7?
Answer:
m=-3
Step-by-step explanation:
HELPPPP FAST PLEASEEEE
Answer:
135, 9, 15
Step-by-step explanation:
Beads per necklace=(Total beads used)/(Total number of necklace made) = 135/9 = 15
What is an equation of the line that passes through the point (-1, 4) and is perpendicular to the line x-6у = 12?
Answer:
y=-6x-2
Step-by-step explanation:
x-6y=12
y=x/6-2
y=mx+c
since theyre perpendicular, 1/6 * m = - 1
m = -6
y=-6x+c
sub x=-1,y=4
4=-6(-1)+c
c = -2
y=-6x-2
4743 in ^2 = ___ ft^2
9514 1404 393
Answer:
32 15/16 ft^2
Step-by-step explanation:
There are 144 square inches in a square foot, so the number of square feet is ...
(4743 in²) × (1 ft²)/(144 in²) = (4743/144) ft² = 32 15/16 ft² = 32.9375 ft²
twice a number added to the product of 14 and 2 is 30. find the number
Answer:
1
Step-by-step explanation:
2x + (14 • 2) = 30
2x + 28 = 30
2x = 30 - 28
2x = 2
x = 2/2
x = 1
Hope this helps you. Do mark me as brainliest.
Simplify this algebraic expression with the steps
help me to solve this question
9514 1404 393
Answer:
see attached
Step-by-step explanation:
Addition, subtraction, and multiplication by a scalar all work on a term-by-term basis. For example the upper left term of A+2B is (2) +2[2] = 6, where (2) is the upper left term of A, and [2] is the upper left term of B.
It is convenient to let your graphing calculator or a spreadsheet do the repetitive arithmetic for you. Attached is the result of using the free Go.ogle Sheets spreadsheet.
Help!! Truth Table
Thank you!!
Answer:
Step-by-step explanation:
[tex]\begin{array}{c|c|c|c|c}p&q&r&p \vee q&(p \vee q)\ =>\ r\\---&---&---&---&------\\T&T&T&T&T\\T&T&F&T&F\\T&F&T&T&T\\T&F&F&T&F\\F&T&T&T&T\\F&T&F&T&F\\F&F&T&F&T\\F&F&F&F&T\\---&---&---&---&------\\\end{array}[/tex]
what is the length of an arc subtended by an angle of 1.25 radians in a circle with a diameter of 24 cm?
Answer:
15 cm.
Step-by-step explanation:
Recall that the arc-length of a circle is given by the formula:
[tex]\displaystyle s = r\theta[/tex]
Where r is the radius and θ is the measure of the central angle in radians.
The circle has a diameter of 24 cm, so its radius is 12 cm.
And its central angle is 1.25 radians. Hence, the arc-length will be:
[tex]\displaystyle s = \left(12\right)\left(1.25\right) = 15\text{ cm}[/tex]
In conclusion, the arc-length for a circle with a diameter of 24 cm subtended by a central angle of 1.25 radians is 15 cm.
Rony earns 17 dollars less than half of what John earns. If John earns p dollars, how much does Rony earn in dollars?
a. p - 1/2
b. 1/2 + p
c. (p/2) - 17
d. 17 + (p/2)
Answer:
The correct choice is option c. (p/2) - 17
The following table gives a partial set of values of a polynomial function.
x | -2 | -1 | 0 | 1 | 2 | 3
g(x) |-14| -2 | 0 |-4| -6| 2
Between which two values would a relative minimum most likely occur?
-2 and 0
-1 and 1
0 and 2
1 and 3
(-2 and 0 is incorrect btw)
Using the concepts of relative minimum and relative maximum, it is found that a relative minimum is most likely to occur between 1 and 3.
--------------------------------------------
A relative minimum occurs when the function is decreasing, then it starts to increase.A relative maximum occurs when the function is increasing, then it starts to decrease.--------------------------------------------
Over the interval -2 and 0, the function is increasing the whole time, which means that a relative minimum is not likely to occur.Over the interval -1 and 1, the function is increasing, then it starts to decrease, which means that a relative maximum is likely to occur.Over the interval 0 and 2, the function is decreasing the whole time, which means that a relative minimum is not likely to occur.Over the interval 1 and 3, the function is decreasing, then it starts to increase, which means that a relative minimum is likely to occur. This is the correct option.A similar problem is given at https://brainly.com/question/9839310
Answer:
x | -2 | -1 | 0 | 1 | 2 | 3
g(x) |-14| -2 | 0 |-4| -6| 2
Between which two values would a relative minimum most likely occur?
-2 and 0
-1 and 1
0 and 2
1 and 3
the correct answer is 1 and 3
What is ³√64? Please help!
The answer you are looking for is 4.
To prove your answer, just test it.
Solution/Explanation:
³√64=4.
Does 4³=64?
Yes, it does. So, what does this mean?
It means that the answer is correct.
So, therefore, the final answer is 4.
I hope this helped you find the answer to your question.
So, the answer that you are looking for is 4.