what is the mass percent of carbon in decane c {10}h {22}? use two decimal places in atomic masses. only give the numeric value of your answer.

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Answer 1

The mass percent of carbon in decane, C{10}H{22}, is 12.11%.

This can be determined by using the atomic mass of each element. Carbon has an atomic mass of 12.01 and Hydrogen has an atomic mass of 1.008.

When calculating the mass percent, you must first determine the total molar mass of the compound.

The total molar mass of decane is calculated by multiplying the atomic mass of each element by the number of atoms of that element in the molecule.

For example, the total molar mass of decane is calculated by multiplying 12.01 (atomic mass of carbon) by 10 (the number of carbon atoms) and 1.008 (atomic mass of hydrogen) by 22 (the number of hydrogen atoms).

This yields a total molar mass of 142.256.

The mass percent of carbon can be determined by dividing the total molar mass of carbon by the total molar mass of decane and then multiplying by 100.

This is calculated by dividing 12.01 (atomic mass of carbon) by 142.256 (total molar mass of decane) and then multiplying by 100, which yields a mass percent of 12.11%.

The mass percent of carbon in decane, C{10}H{22}, is 12.11%.

This was determined by calculating the total molar mass of decane, which is 142.256, and then dividing the total molar mass of carbon by the total molar mass of decane and then multiplying by 100.

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Related Questions

2. select the system with the greatest amount of entropy. a. pure water b. 0.500 m nacl c. 0.500 m mgcl2 d. 0.500 m alcl3

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Answer: the answer is 15.009

Explanation:

What is the mass of 0.928 moles of Ti(SO3)2

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1) You know the number of moles, you can easily work out the molar mass of Ti(SO3)2 (titanium sulfite), but you don't know the actual mass

2) By adding the mass of the atoms that make up titanium sulfite, you should get something like 207.9934 g/mol

3) To find the actual mass, you times the molar mass and the moles together

Final Answer = 193g

What do these two changes have in common?
boiling sugar to make caramel
using a large magnet to remove pieces of iron from a junkyard

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Boiling sugar to make caramel and using a large magnet to remove pieces of iron from a junkyard are two very different processes, but they have one thing in common: they both involve a physical change.

A physical change is a change in a substance that does not result in the formation of a new substance with different chemical properties. In other words, the substance does not undergo a chemical reaction, but rather a change in its physical properties.

Boiling sugar to make caramel is a physical change because the sugar undergoes a change in its physical properties, such as color, texture, and taste, without undergoing a chemical reaction. The sugar molecules are heated to the point where they break down and re-form into a new substance with new properties, but the chemical composition of the sugar remains the same.

Using a large magnet to remove pieces of iron from a junkyard is also a physical change because the magnet is not altering the chemical properties of the iron, but only its physical location. The magnet is attracting and removing the iron from the junkyard, but the iron itself is not undergoing a chemical reaction.

In both cases, the substances are undergoing a physical change, but their chemical properties remain unchanged.

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if a 9.48g of hydrosulfuric acid is reacte with 6.35g of silver nitrate calculate the mass in g of solid silver sulifde formed

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Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

When 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate, the reaction forms solid silver sulfide. The equation for this reaction is:

H₂S + 2 AgNO₃ → Ag₂S + 2 HNO₃.

To calculate the mass of silver sulfide formed, we need to use the mole ratio of the two reactants. We know that the molecular weight of silver nitrate is 169.88 g/mol and the molecular weight of hydrosulfuric acid is 34.08 g/mol.

Using the mole ratio, we can find the moles of each reactant:

9.48 g/34.08 g/mol = 0.2786 moles of H₂S and 6.35 g/169.88 g/mol = 0.0373 moles of AgNO₃.

Since the reaction forms 1 mole of Ag₂S for every 2 moles of AgNO3, we can calculate the moles of Ag₂S formed: (0.0373 moles of AgNO₃ x 1 mole of Ag₂S)/2 moles of AgNO₃ = 0.01865 moles of AgS.

Now, using the molecular weight of silver sulfide (119.97 g/mol), we can calculate the mass of silver sulfide formed: 0.01865 moles of Ag₂S x 119.97 g/mol = 2.238 g of Ag₂S.

Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

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all atoms can be easily detected by atomic emission, this is advantageous compared with atomic absorption. group of answer choices true false

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The statement, "all atoms can be easily detected by atomic emission, this is advantageous compared with atomic absorption," is false.

Atomic absorption and atomic emission spectroscopy are two commonly employed techniques for the determination of elements present in a sample.

The advantage of atomic emission spectroscopy over atomic absorption spectroscopy, and vice versa, is dependent on the particular sample to be analyzed.

The principle of atomic absorption spectroscopy is that an atom in the gaseous state absorbs ultraviolet or visible radiation to move from the ground state to an excited state.

As a result, the intensity of the transmitted radiation decreases in proportion to the concentration of the absorbing species.

When a sample is analyzed, the sample is vaporized and the amount of absorption is measured at a specific wavelength.

The amount of radiation that is absorbed by the sample is directly proportional to the amount of the analyte present in the sample.

This information can then be used to estimate the analyte's concentration in the original sample.In atomic emission spectroscopy, the sample is excited by a high-energy source, causing the atoms to reach a higher energy state.

The atoms will eventually return to their ground state by releasing the excess energy, which is emitted as light.

The frequency and intensity of the light emitted is used to determine the concentration of the analyte present in the sample. This process is known as atomic emission spectroscopy.

Atomic absorption spectroscopy is superior in cases where the analyte concentration is low or the sample is a complex mixture,

whereas atomic emission spectroscopy is superior when high sensitivity is required or when the sample contains multiple elements.

Thus, it can be concluded that not all atoms can be easily detected by atomic emission, and that both methods have advantages and disadvantages.

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calculate grxn for the reaction at -73 c under the following standard conditions at equilibrium at ph2

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To calculate the Gibbs free energy change (ΔG_rxn) for the reaction at -73°C under the given standard conditions at equilibrium and pH 2, we would need the specific reaction equation, as well as the standard free energy change (ΔG°) and equilibrium constant (K) for that reaction.

Once we have those, we can use the equation ΔG_rxn = ΔG° + RTlnQ, where R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient. However, without the specific reaction details, we cannot calculate ΔG_rxn.

To further elaborate, the Gibbs free energy change (ΔG_rxn) is a measure of the spontaneity of a chemical reaction, and it can tell us whether a reaction will occur spontaneously or not.

The ΔG_rxn can be calculated using the equation ΔG_rxn = ΔG° + RTlnQ, where ΔG° is the standard free energy change of the reaction at standard conditions (usually 298 K and 1 atm), R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin, and Q is the reaction quotient.

The reaction quotient (Q) is the ratio of the concentrations of the products to the concentrations of the reactants at any given point in the reaction. Under standard conditions, the reaction is at equilibrium, and the reaction quotient (Q) equals the equilibrium constant (K).

If Q < K, then the reaction will proceed spontaneously in the forward direction to reach equilibrium, and ΔG_rxn will be negative.

If Q > K, then the reaction will proceed spontaneously in the reverse direction to reach equilibrium, and ΔG_rxn will be positive. If Q = K, then the reaction is at equilibrium, and ΔG_rxn will be zero.

However, to calculate the Gibbs free energy change (ΔG_rxn) for a specific reaction, we need to know the specific reaction equation, as well as the standard free energy change (ΔG°) and equilibrium constant (K) for that reaction.

These values can be experimentally determined or obtained from reference tables. Therefore, without the specific reaction details, we cannot calculate ΔG_rxn.

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calculate the molarity of the two solutions. the first solution contains 0.500 mol of naoh in 2.30 l of solution.

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The molarity of the first solution containing 0.500 mol of NaOH in 2.30 l of the solution is 0.217 M.

The molarity of a solution is defined as the number of moles of solute per liter of solution. In order to calculate the molarity of the given solution, we need to divide the number of moles of solute by the volume of the solution given in liters. Using the formula for molarity, we have;

Molarity = Number of moles of solute / Volume of solution in liters

Given, Number of moles of solute = 0.500 mol

Volume of solution = 2.30 L

Substitute the values of the given information into the molarity formula; Molarity = 0.500 mol / 2.30 L = 0.217 M

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after pipetting the solution to be diluted into the volumetric flask, how much water should be added before the first mixing?

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After pipetting the solution, the amount of water needed depends on the desired concentration and the amount of solution to be diluted.

When pipetting a solution to be diluted into a volumetric flask, the first step is to add the appropriate amount of water. The amount of water needed depends on the desired concentration and the amount of solution to be diluted. For example, if you are diluting 1 mL of a 5M solution to a 2M solution, you would need to add approximately 3 mL of water.

This can be calculated as follows:

C₁V₁ = C₂V₂

where, C₁ = initial concentration, C₂= final concentration, V₁= initial volume, V₂= final or desired volume.

Substituting the values, we can find the desired volume.

Once you have added the desired amount of water, you should mix the solution by swirling the flask or stirring the solution gently with a stirring rod. It is important to mix the solution thoroughly to ensure a uniform concentration of the solution.

Once the solution has been mixed, you should check the volume of the solution. You can do this by reading the volume at the bottom of the meniscus, which is the curved surface of the liquid. It is important to make sure that the volume is correct as this will affect the concentration of the solution.

Finally, you should adjust the volume of the solution as needed. If the volume is too high, you can remove a small amount of liquid using a pipette. If the volume is too low, you can add more water.

In summary, after pipetting the solution to be diluted into a volumetric flask, you should add the appropriate amount of water and mix the solution to get the desired concentration. You should then check the volume of the solution and adjust it as needed.

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49.2 ml of a 0.524 m solution of hno3 is titrated with fe(oh)3. it takes 85 ml of fe(oh)3 to reach the equivalence point. what is the concentration (molarity) of the fe(oh)3? answer to 2 decimal places

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The Fe(OH)₃ solution has a content of 0.304 M.

In this titration, HNO₃ is the acid and Fe(OH)₃ is the base. At the equivalence point, all the H+ ions from the HNO₃ react with all the OH- ions from the Fe(OH)₃ to form water and the salt, Fe(NO₃)₃. We can use the balanced chemical equation for the reaction to determine the stoichiometric ratio of HNO₃ to Fe(OH)₃ and calculate the molarity of Fe(OH)₃.

The balanced chemical equation for the reaction is:

HNO₃ + 3Fe(OH)₃ → Fe(NO₃)₃ + 3H₂O

From the equation, we see that 1 mole of HNO₃ reacts with 3 moles of Fe(OH)₃. Therefore, the number of moles of HNO₃ in the solution can be calculated as:

moles of HNO₃ = Molarity of HNO₃ x Volume of HNO₃ solution in liters

moles of HNO₃ = 0.524 M x (49.2 mL / 1000 mL/L)

moles of HNO₃ = 0.0258 mol

At the equivalence point, the number of moles of Fe(OH)₃ added is equal to the number of moles of HNO₃ in the solution. Therefore, we can calculate the molarity of Fe(OH)₃ as:

Molarity of Fe(OH)₃ = moles of Fe(OH)₃ added / Volume of Fe(OH)₃ solution in liters

Since the volume of the Fe(OH)₃ solution added is 85 mL, or 0.085 L, we can calculate the moles of Fe(OH)₃ as:

moles of Fe(OH)₃ = moles of HNO₃ = 0.0258 mol

Therefore, the molarity of Fe(OH)₃ is

Molarity of Fe(OH)₃ = 0.0258 mol / 0.085 L

Molarity of Fe(OH)₃ = 0.304 M

Thus, the concentration (molarity) of the Fe(OH)₃ solution is 0.304 M, rounded to two decimal places.

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the energy required to break one mole of iodine-iodine bonds in i2 is 151 kj/mol. what is the longest wavelength of light capable of breaking a single i-i bond?

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The longest wavelength of light capable of breaking a single I-I bond is approximately 787 nm (nanometers).

What is energy ?

Energy is considered a quantitative property that can be transferred from an object to perform work.

The energy required to break a mole of I2 molecules is 151 kJ/mol. We can use this information to calculate the energy required to break a single I-I bond:

Energy required to break a single I-I bond = Energy required to break one mole of I2 molecules / Avogadro's number

Energy required to break a single I-I bond = 151 kJ/mol / 6.022 x 10^23 molecules/mol

Energy required to break a single I-I bond = 2.51 x 10^-19 J/bond

To calculate the longest wavelength of light capable of breaking a single I-I bond, we can use the equation:

E = hc/λ

Where

E is the energy of a photon h is Planck's constant c is the speed of lightλ is the wavelength of light

We want to find the wavelength of light that has an energy of 2.51 x 10^-19 J, so we can rearrange the equation as follows:

λ = hc/E

λ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (2.51 x 10^-19 J)

λ = 7.87 x 10^-7 m

Therefore, the longest wavelength of light capable of breaking a single I-I bond is approximately 787 nm (nanometers).

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which is the best colored indicator to use in the titration of 0.1 m ch3cooh(aq) with naoh(aq)? why? look up ka values in the appendix. indicator pka bromocresol green 4.8 bromothymol blue 6.8 phenolphthalein 9.2 group of answer choices