What is the relationship between mass and kinetic energy evidence?

Answers

Answer 1

The equation for Kinetic Energy is: KE = 1/2 mv2. Kinetic energy has a direct relationship with mass, meaning that as mass increases so does the Kinetic Energy of an object.

In physics, an object's kinetic energy is the energy it has as a result of its motion.  It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.

The body retains its kinetic energy after gaining it during acceleration until its speed changes. The body does the same amount of work while slowing down from its current pace to rest. Formally, kinetic energy is any term in a system's Lagrangian that contains a time derivative.

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Related Questions

a typical gps satellites orbit at an altitude of 2.0 x10^7 m. find (a) the orbital period, and (b) the orbital speed of such a satellite

Answers

the orbital period is  7200sec or 2hours and orbital speed is 7,27m/s

(a) The orbital period of a satellite is the time it takes for the satellite to make one full orbit around the Earth. To calculate the orbital period, we can use the equation: T = 2 * pi * (a^3/GM)^(1/2) where T is the orbital period, a is the semi-major axis of the orbit (which is equal to the altitude of the satellite), pi is approximately 3.14, G is the gravitational constant (approximately 6.67 x 10^-11 m^3/kgs^2), and M is the mass of the Earth (approximately 5.98 x 10^24 kg).Plugging in the given altitude of 2.0 x 10^7 m for a and the known values for pi, G, and M, we get:

T = 2 * pi * (2.0 x 10^7 m)^3/ (6.67 x 10^-11 m^3/kgs^2 * 5.98 x 10^24 kg)^(1/2)

Simplifying, we get:

T = 2 * pi * (8.0 x 10^21 m^3/ (4.03 x 10^34 kg*m^3/s^2))^(1/2)

T = 2 * pi * (1.98 x 10^13 s^2/kg)^(1/2)

T = 7200 sec (or 2 hours)

(b) The orbital speed is the distance traveled by the satellite in one hour. We can calculate the orbital speed using the equation v = 2πa/T

Plugging in the values of a and T we get :

v = 2π (2.0 x 10^7 m) / 7200 sec

v = 7,27 m/s

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If the refractive index from air to water, nw = 1.3 and the velocity of light in the air is
3 x 108 m/s, what is the velocity of light in water?

Answers

Answer:

[tex]n _{w} = \frac{c}{v} \\ 1.3 = \frac{3 \times {10}^{8} }{v} \\ v = \frac{3 \times {10}^{8} }{1.3} \\ v = 2 \times {10}^{8} \: m {s}^{ - 1} [/tex]

The direction of the velocity of the planet is _______________________ (alwaysThe direction of the velocity of the planet is _______________________ (always, seldom, never) perpendicular to the net force acting upon the planet., seldom, never) perpendicular to the net force acting upon the planet.

Answers

According to the satellites' orbits and the speed at which they move, it either happens frequently or always.

As we begin to examine satellite orbits, we find that a circular orbit places the satellite always perpendicular to the object's net force and speed.

The orbit is stretched, just like in elliptical orbits. This informs us that the orbit has four points. As a result, the satellite rarely faces the satellite's net force in a perpendicular direction.

Rarely and always for elliptical orbits. According to the satellites' orbits and the speed at which they move, it either happens frequently or always.

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Because of the Doppler effect, a light- or sound-emitting object moving toward you has a ________ compared to a stationary object.

Answers

Because of the Doppler effect, a light- or sound-emitting object moving toward you has a lower amplitude compared to a stationary object.

The Doppler effect is generally defined as the shift in wave frequency (whether it be sound or light) caused by relative motion between the wave source and the observer. Every time a source wave moves in reference to the observer, this effect can be seen.

The Doppler effect allows astronomers to determine the frequency of light waves as an object moves in relation to the observer. As it approaches you, the frequency decreases and the item exhibits a blueshift. A redshift indicates that an item is travelling away from us.

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How do you find the acceleration of a ball rolling down a slope?

Answers

The ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.

Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.

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How do scientists collect evidence about Earth's climate?

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"Scientific evidence for warming of the climate system is unequivocal."

What evidence can be used to study the Earth's past climate?

Organisms such as diatoms, forams, and coral) can obey useful climate proxies. Other proxies involve ice cores climate, tree rings, and sediment cores. Chemical deputy records include isotope ratios, elemental examination, biomarkers, and biogenic silica.

Climate analyzers use every possible direct and indirect compilation to study the full history of Earth's climate, ice cores drawn from Greenland, Antarctica, and tropical mountain glaciers appear that Earth's climate greets to changes in greenhouse gas levels.

So we can conclude that Climate change is most usually measured using the average surface temperature of the planet.

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A 663 g ball strikes a wall at 12.2 m/s and rebounds at 10.4 m/s. The ball is in contact with the wall for 0.046 s. What is the magnitude of the average force acting on the ball during the collision

Answers

The Force acting on the ball during collision is 25.9 N.

To calculate the magnitude of the average force, we use the formula below.

F = m(v-u)/t..........Equation 1

Where:

F = Average force acting on the ball

m = mass of the ball

v = Final velocity

u = Initial velocity

t = time.

From the question,

Given:

m = 663  g = 0.663 kgv = 12.2  m/su = 10.4 m/st = 0.046  s

Substitute these given values into equation 1

F =  0.663 (12.2  -10.4 )/0.046

F = 25.9 N

Hence, The Force acting on the ball during collision is 25.9 N

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CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!

1.) Compare reflection and refraction. How are they similar and how are they different?

2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.

3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.

4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.

Answers

Answer:

1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.

2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.

3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.

Laws of reflection:

(i) The angle of reflection is always equal to the angle of incidence.

(ii) The incident rays, reflected rays and the normal, all lie in the same plane.

4.)Snell’s law formula is expressed as: μ= sin i/sin r

, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.

How much of the world's energy is hydroelectric?

Answers

According to the United Nations Environment Programme, hydropower accounted for 16.6% of global electricity generation in 2018.

This is equivalent to a total installed capacity of 706 GW, making it the second largest energy source after thermal sources.

Hydropower is a renewable energy source and is often seen as a more sustainable alternative to thermal sources, as it does not release any greenhouse gases into the atmosphere. Additionally, hydropower is a reliable source of energy, and can be used to meet peak energy demand.

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What are some benefits of dynamic exercises prior to playing volleyball how it will prepare your body leading to the game?

Answers

The benefits of dynamic exercises before playing volleyball and how they will prepare your body for the match are:

Increased Muscle Strength and PowerImproved Mobility and FlexibilityImproved Agility and Reaction TimeImproved Balance and CoordinationImproved Cardiovascular Endurance

Explanation of each of the benefits of dynamic exercises before playing volleyball and its preparation

Increased Muscle Strength and Power: Dynamic exercises help to increase muscle strength and power, which is essential for performing explosive movements required in volleyball.Improved Mobility and Flexibility: Dynamic exercises help to improve mobility and flexibility, which can help to reduce the risk of injury.Improved Agility and Reaction Time: Dynamic exercises help to improve agility and reaction time, which can help you to react quickly and effectively to the game.Improved Balance and Coordination: Dynamic exercises also help to improve balance and coordination, which can help you to perform better and avoid unnecessary injuries.Improved Cardiovascular Endurance: Dynamic exercises help to increase your cardiovascular endurance, which can help you to last longer during the game and maintain high intensity throughout.

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Classify the phase-change scenarios according to the direction of the heat flow in each case. No net transfer of heat occurs Heat is transferred from the water to the surroundings Heat is transferred to the water from the surroundings

Answers

When working through these problems, think about the heat in terms of movement of the molecules of water.

Heat is transferred from the water to the surroundings --- water molecules slowing down.

Heat is transferred to the water from the surroundings --- water molecules heating up.

a cloud of steam condenses into liquid water - Heat is transferred from the water to the surroundings. Steam has more molecules moving around than liquid water. Therefore the molecules had to slow down, thereby transferring heat to the surroundings.a block of ice sublimates into water vapor - Heat is transferred to the water from the surroundings --- water molecules are heating upa block of ice melts - Heat is transferred to the water from the surroundings. The water molecules are basically not moving. Therefore heat has to be introduced to the molecules, which causes the melting.a puddle of water evaporates - Heat is transferred to the water from the surroundings. The water molecules are moving in the liquid state. However, when more heat is introduced to the liquid, the molecules move more rapidly and evaporate.a puddle of water freezes into ice - Heat is transferred from the water to the surroundings --- water molecules slowing down as they go from a liquid state to a solid state.

ABOUT HEAT TRANSFER

Heat transfer is the transfer of energy due to the difference of temperature between two different places. The main discussion in heat transfer is how the energy in heat can move places and the rate of transfer under certain conditions. Heat transfer includes the processes of inflow and outflow of heat. In industrial processes, heat transfer is used to achieve the required temperature in the industrial process and maintain the required temperature throughout the process.

Heat transfer from one object to another can occur by conduction, convection, and radiation. The determinant of heat transfer is the temperature difference. The direction of heat transfer starts from a medium with a high temperature to a medium with a lower temperature. Heat transfer can occur with a single process or multiple processes.

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A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 34.5 m/s. With what maximum speed can it go around a curve having a radius of 60.0 m

Answers

With 20.23 ms⁻¹,  maximum speed can it go around a curve having a radius of 60.0 m

What's the maximum speed?

The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.

ac max = V² max / R   ....(1)

Inserting given values we get

ac, max  =  (34.5)² / 150 = 7.935 ms⁻²

For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes

Unew, max= √ac, max R new

Unew, max = √6.826 x 60

Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.

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You can tell from reading this passage that -
the narrator will definitely find a diamond at the Crater of Diamonds State Park.
diamonds are rare, valuable gems.
garnet is as valuable as a diamond.
semi-precious stones are ugly.

Answers

Answer: B or "diamonds are rare,valuable gems".

Explanation:

since the link does not show very much, I don't know if A is correct or not. D is incorrect because that  is an opinion. C is incorrect.

13. Shadrach, a form one student performed an experiment to investigate surface tension. he poured some water on a trough and allowed it to settle he then took a razor blade and gently placed it on the surface of the water in an attempt to make it float but failed give two possible reasons why the experiment failed​

Answers

Answer:

this because the surface tension was lowered by using an impurity or rising the temp of the water

Which of the following is the law of action-reaction?
OA. Newton's first law
B. Newton's second lav
OC. Newton's third law
OD. Newton's fourth law

Answers

Answer:

OC.Newton's third law of motion which states that,"every action has equal and opposite reaction."

*mark me brainliest

What is momentum Mcq?

Answers

L=rp Angular Momentum the linear momentum p. Moment of momentum is another name for angular momentum.

How do you gain traction?

List the object's mass and speed in step one. Convert any values into SI units in step two (kg, m, s). Step 3: To calculate an object's momentum, multiply the object's mass and velocity.

Can there be negative momentum?

Momentum can go wrong. As a vector quantity with both magnitude and direction, momentum has both. The sign, positive or negative, in physics serves as a cue as to the direction. Positive amounts normally signify a forward or upward motion, whereas negative quantities typically indicate a backward or downward motion.

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What is momentum?

Trends are easier to detect when the signal-to-noise ratio is low.
a True
b False

Answers

Answer:

I think it's b. False

Explanation:

Y’all which ones is incorrect (if there wrong plz tell me what to circle right then) thanks :3

WILL MARK BRAINLIEST FOR THIS :D

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Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that of the bones of other animals. Suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 47.0 g47.0 g and its apparent mass when submerged is 3.60 g3.60 g (the bone is watertight). What mass of water is displaced

Answers

The mass of water displaced when the mass of bird bone in water and air is given, is calculated to be 43.4 g.

Given that,

Weight of bird bone in air = True weight = 47 g

Apparent weight of the bird bone when submerged = 3.6 g

The equation for apparent weight is known to be,

Apparent weight = True weight - Buoyant force

Making Buoyant force as subject, we have,

Buoyant force = 47 g - 3.6 g = 43.4 g

F b = mw × g = (m wat - m air)× g

mw = m wat - m air = 47 g - 3.6 g = 43.4 g

Thus, the mass of the water displaced is 43.4 g.

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A point particle of charge -5.40 nC is located at the origin of a Cartesian coordinate system. Determine the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge.

Answers

The magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is 918.7 N/C.

Given that,

Charge on point particle Q = -5.4 nC = -5.4 × 10⁻⁹ C

Distance from the charge r = 23 cm = 23 × 10⁻² m

The relation between distance charge and electric field is known to be,

E = 1/4πε₀ × Q/r² = 9 × 10⁹ × (-5.4 × 10⁻⁹)/(23 × 10⁻²)² = (9 × 5.4)× 10⁴/(23)² = 918.7 N/C

Thus, the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is calculated to be 918.7 N/C.

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At an outdoor physies demonstration, a delay of 0.50 second was observed between the time sound waves left a loudspeaker and the time these sound waves reached a student through the air. If the air is at STP, how far was the student from the speaker? (1) 1.5 × 10-m (91.7 × 102 m (3) 6.6 × 10? m (4) 1.5 × 108 m

Answers

The distance that is covered by the sound is  1.66 * 10^2 m.

What is the distance?

We know that sound is a mechanical wave. The implication of this is that sound woulod need to have a medium through which the sound can be able to travel. The speed of sound in the various media through which the sound travels is not the same.

We know that the speed of sound in air is 331 m/s and we have to use this in our calculations.

Distance = speed * time

Distance =  331 m/s * 0.5 s

= 1.66 * 10^2 m

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After seeing the fur rubbed with the rod attract the neutral paper, imagine you had an instrument that lets you zoom in enough to see what the paper and rod are made of. Draw a model that shows what happens to the neutral paper to cause it to move towards the charged rod. Make sure to label everything in your model

Answers

Seeing the fur rubbed with the rod attracts neutral paper, this happens because the friction of the rod with the rubbed can produce a static electric force. It is this static electric force that causes the pieces of paper to be attracted and rod up.

If the rod or ruler has been rubbed into the hair, then brought closer to the paper, then the paper will lift and stick. Indeed, this can happen due to the presence of an electric charge. When you rub a plastic ruler over your hair, it becomes electrically charged, causing the paper to pull and stick.

The electric charge consists of two types of charge, namely negative charge, and positive charge. However, some objects have an equal amount of negative charge and positive charge. Objects that have the same amount of positive and negative charges are called neutral objects. Initially, a plastic ruler is also an electrically neutral object.

When you rub the ruler against dry hair, it gets an electric charge, because of that electric charge the plastic ruler can exert a force on the paper and pull it closer.

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Halp i'm so confused I want to cry....
Three children are throwing a disc in the park. The first child throws the disc 32 m [W 14° S] to the second child, who then throws the disc 15 m [E 62° S]. What is the net displacement of the disc?

*the answer is 32m (W 41 S) Please explain how to do this....
NO LINKS I WILL REPORT U

Answers

Answer:

Evidently W 14 S means West and to the South by 14 deg

If you draw the X-Y coordinates and enter this value

Tx1 = - 32 * cos 14 = -31     (along the negative x-axis)

Ty1 = -32 * sin 14 = -7.4     (along the negative y-axis)

Likewise

Tx2 = 15 * cos 62 = 7.04

Ty2 = -15 * sin 62 = -13.2

Tx = -31 + 7.04 = -24

Ty = -7.4 - 13.2 = -20.6

Final distance = (24^2 + 20.6^2)^1/2 = 31.6 m

Direction will be South of West

tan -20.6 / -24 = 41 deg

Runner A is initially 2.0 mi west of a flagpole and is running with a constant velocity of 8.0 mi/h due east. Runner B is initially 9.0 mi east of the flagpole and is running with a constant velocity of 4.0 mi/h due west. How far are the runners from the flagpole when they meet?

Answers

The definition of constant velocity is the speed of a moving object that doesn't change over time. The system travelling at a constant speed is subject to zero net acceleration.

What distinguishes instantaneous velocity from average velocity?

In contrast to instantaneous velocity, which is determined by slope of tangent line, average speed is defined as the shift in location (or displacement) during the course of transit.

Which of the four main claims about how a body can accelerate even when it has no velocity is untrue?

Speed is the measure of velocity in magnitude. As a result, it is impossible to have two objects moving at the same velocity. The right response is therefore option A.

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An atom with 29 protons and 36 neutrons is an isotope of
(A) Si
(B) Cu
(C) Kr
(D) CI

Answers

Answer:

(B) Cu

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Isotopes can be defined as the atom of an element that has the same number of protons but different number of neutrons. This ultimately implies that, the isotopes of an element have the same atomic number (number of protons) but different atomic mass (number of nucleons).

The isotope of an element is denoted by [tex] X_{Z}^{A} [/tex]

Where; X is the symbol of the element.

A is the atomic mass or number of nucleons.

Z is the atomic number or number of protons.

Hence, an atom with 29 protons and 36 neutrons is an isotope of copper because it has an atomic mass of 65, which corresponds with that of the chemical element known as copper with the symbol, Cu.

Roller Coaster Physics Gizmo


With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another. K= U

1/2mv^2 = mhm


a. Use algebra to solver for the speed. V=


b. With the no friction, does the final speed depend on the mass of the car?


c. With no friction, does the final speed depend on the steepness of the hill?


d. What is the final speed of the car if the height of the hill is 55 cm (. 55m)?

Answers

A) Using algebra, the required speed V=(2gh)1/2

B)  With the no friction, the final speed does not  depend on the mass of the car.

C) With no friction, the final speed does depend on the steepness of the hill.

D) The final speed of the car if the height of the hill is 55 cm is 3.569 m/s.

Given that there is no friction considered. Thus, the total energy of the system can be considered as conserved.

Thus, sum of kinetic and potential energy will be constant.

K = U

mu 2   = mgh ......................................(1)

m = mass of object

v = speed of object

g = acceleration due to gravity = 9.8 m/s2

h = height of object with respect to a reference position

Thus for an object at a height from ground, will have its potential energy converted to kinetic energy during it's descent.

(A) from (1)

mv2 = 2mgh

Thus,   v2 = 2gh

            v = (2gh)1/2

this, is the velocity of an object from conservation of energy.

(B) with no friction, the enrgy is taken to be conserved. from the answer of (A), we know,

v = (2gh)1/2.

clearly this equation doesn't depend on mass.

thus, final speed doesn't depend on the mass.

(C) Given height of hill , h = 65cm = 0.65 m

from (1),    v = (2gh)1/2.

the potential energy of car at the hill top = mgh

this potential energy gets entirely converted to kinetic energy at the bottom of hill due to conservation of energy. Thus

v = (2 x 9.8 x 0.65)1/2

   =  3.569 m/s

Thus, the final velocity of the car is 3.569 m/s

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X-rays with wavelengths of 0.95 nm are detected at a scattering angle of straight theta in a Compton-scattering experiment, as shown in the drawing. What is the scattering angle straight theta if the energy of the scattered photon is 5.111 keV. (For accuracy, use h = 6.626 x 10-34 J·s and c = 2.998 x 108 m/s.)

Answers

Answer:

The scattering angle is 0.80

Explanation:

As we know  

Wave length = h/mc (1-cos α) --1

W = mc^2

m = E/c^2

Substituting this in equation 1 we get  

Wavelength = hc/E (1-cos α)

Substituting the given values, we get -  

0.95*10^-9 = [(6.626 *10^-34 * 2.998 *10^8)/5.111*1000*1.6*10^-19} (1-cos α)

(1-cos α) = 1.14 *10^-10

cos α = 1- 1.14 *10^-10

α = 0.80

A 0.480 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.05 s

Answers

The mass added to the object to change the period to 2.05 s is 0.42 kg

What is the time period of an oscillation?

The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle.

Given :

A 0.480-kg mass suspended from a spring oscillates with a period of 1.50 s.

The formula of the time period is given by:

 [tex]T=2\pi \sqrt{m/K}[/tex] ------(1)

where m is the mass and K is the spring constant.

The new time period is given by:

[tex]T'=2\pi \sqrt{m^{'} /K[/tex]-----(2)

where m' is the total mass after the addition and K is the spring constant.

Dividing equation (1) by equation (2).

[tex]T/T'=\sqrt{m/m'}[/tex]

Now, substitute the known terms in the above expression.

[tex]\frac{1.50}{2.05} =\sqrt{0.480/m'}[/tex]

[tex]m'=\frac{0.480}{0.5329}[/tex]

[tex]m'=0.9[/tex] kg

Now, the mass added to the object to change the period to 2.05 s is given by:

m" = 0.9 - 0.480

m" = 0.42 Kg

Thus, 0.42kg of mass must be added to the object to change the period to 2.05s.

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Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
A) 15,000
B) 1,500
C) 1000
D) 150

Answers

The answer is B 1,500 meters since 1 kilometer to meters is 1,000 and u add the 500

A standing wave is set up in a pipe with both ends open. The frequency of its first harmonic is 300 Hz. What is the length of the pipe? Take the speed of sound to be 340 m s–1. Give your answer in meters

Answers

When the frequency of a standing wave set up in a pipe (with both ends open) first harmonic is 300 Hz, the length of pipe is 0.567 metres.

Therefore the answer is 0.567 m.

The speed of sound in air is approximately 340 m/s, and the wavelength of the first harmonic of a standing wave in an open pipe is twice the length of the pipe. Therefore, if the frequency of the first harmonic is 300 Hz, the wavelength can be calculated as:

wavelength = speed of sound / frequency

wavelength = (340 m/s) / (300 Hz)

The length of the pipe can be calculated as half the wavelength:

L = wavelength/2

L = (340 m/s) / (2×300 Hz)

L ≈ 0.567 m

So the length of the pipe is 0.68 m

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For a science experiment, each student needs 5 grams of salt. If there are 26 students in the class how many milligrams of salt will they need? What is the main function of motor oil? *a. Improve the sealing of piston ringsb. Clean the engine from sludge and varnishc. Reduce friction and wear on moving partsd. Neutralize acids Describing Name two types of dwellings for which the Ancient Puebloans are known. how does the us constitution reflect the principle of democracy? Question 3 A student solved a quadratic equation as shown here Read this excerpt from an essay. What is the authors main purpose?My first day of high school was a total nightmare. I will never forget that day. I was a skinny, freckled, 14-year-old nobody. I just wanted to blend in, but I somehow spent the entire day being noticed for the wrong reasons. I messed everything up. I forgot my books. I went to the wrong classes. So when I went to the wrong lunch session and ended up in a room full of seniors, I wasnt surprised. Luckily, someone came to my rescue. Sensing my anxiety, one girl pointed out that I was lucky to be lost in that room because it was the meeting place of the schools new Community Service Council. She volunteered to take me to the food court and told me to ask her if I ever needed help. Beneath the red, white, and blue school banners, I watched her skip away to help another boy who had dropped his tray. Apparently, I wasnt the only one having a bad day. The Community Service Council ended up having a huge effect on my high school life. I just wish I could have found it in a less embarrassing way.A.to inform readers about a normal day at high schoolB.to persuade readers to join the Community Service CouncilC.to entertain readers with a funny story about the first day of schoolD.to express an opinion about the importance of community service A jar of coins contains only quarters and dimes. The total amount of money in the jar is $4.40, and there are 23 coins.A. Write a system of equations that can be used to find d, the number of dimes, and q, the number of quarters, in the jar.B. How many quarters are in the jar? find the indicated sum Answer to the question in the picture a car weighs 3600 kg is traveling at 21.0 m/s. the driver doesn?t notice a red light and rear-ends another car at rest. both cars stick together and move with a speed of 9.0 m/s. what is the mass of the car that was at rest? As the earth rotates on its axis, the constellations and stars in them appear to hey i need help with these thanks show work help plz fast!! please true or false: the state capital is always the city with the largest population in the state Which of the following is NOT one of the three basic ways inventories are reported?A. average aggregate inventory valueB. inventory turnoverC. weeks of supplyD. material cost of goods sold Can someone check my answer?Offering 50 points. Twelve out of Sixty students are trying out for the spring musical. What is the percentage of students trying out for the musical? The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s and Object 2 accelerates at 5m/s. Which object has the greater mass? Determine the value of x.A) 23 B) 63 C) 12 D) 123 What did the British Raj bring to India?