electrons
Revolving around the nucleus at a distance is a cloud of particles called electrons. Each electron has a negative charge.
Answer:
Electron
Explanation:
Because electrons are negatively charge particles
How many bonds could each of the following chelating ligands form with a metal ion?
a. acetylacetone(acacH)
b. dirthylenetriamine
c. Salen
d. porphine
a. Acetylacetone(acacH) can form up to 4 bonds with a metal ion.
b. Dirthylenetriamine can form up to 4 bonds with a metal ion.
c. Salen can form up to 6 bonds with a metal ion.
d. Porphine can form up to 8 bonds with a metal ion.
Learning Task 3: Why can a car run faster on a smooth
rood than on a rough roade (5points).
Answer:
it is easy to push a car on smooth road than on a rough road because friction is less in smooth road than on rough roads.
Answer:
Why can a car run faster on a smooth
rood than on a rough road it is because friction is less in smooth roads than in rough road....
Explanation:
hope it helps..stay safe!
which of the following compounds contains the Iron (III) ion?
A) FeN
B)FeS
C)FeCl2
D)FeS
Answer:
(A)
Explanation:
All the Fe ions in the other choices have +2 valences. Since the N ion has a -3 valence, the compound FeN can only be formed if Fe has a +3 valence.
Use information from the reaction to design an experiment that could be used to remove the tarnish (Ag2S) from a silver fork
Line a basin with foil, add a teaspoon of bicarbonate of soda and a sprinkle of salt, and then pour in hot water. The tarnished silver object may then be immersed in water, ensuring sure it comes into touch with the aluminum foil, as well as the silver sulphide tarnish will quickly dissipate.
Tarnish is caused by a chemical interaction between silver and sulfur-containing compounds in the air. Silver sulphide is formed when silver combines with sulphur. Silver sulphide is a dark substance. A thin layer of silver sulphide grows on the surface of silver, darkening it.
Experimental design is a technique that enables scientists and engineers to efficiently assess the effect of multiple inputs, or factors, on measures of performance, or responses. A bone density research, for example, contains three experimental groups: a control group, the stretching exercise group, as well as a jumping exercise group. In a between-subjects experiment, investigators allocate each participant to one of three groups at random. While silver is the most commonly linked with tarnishing, it may occur on almost every metal, including aluminum, copper, and brass.
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when 8 moles of nh3 was used in a reaction how many mole of o2 needs to be used
Answer: Uhmmmm what dude i dont know what to say how the heck so i solve this?
Explanation:
1. isostasy subduction 2. deepest ocean depths fjord 3. drowned glaciated valley plate tectonics 4. theory of crustal structure trench 5. oceanic plate going down buoyancy
The isostasy is relates to the buoyancy , the deepest oceans depths relates to the trench, the theory of the crustal structure relates to the plate tectonics.
The match the following for the given options are given below as follows :
1 ) isostasy buoyancy
2) deepest ocean depths trench
3) drowned glaciated valley fjord
4) theory of crustal structure tectonic plates
5) oceanic plate going down subduction
The above are the correct order for the given following relations. these given options are related to the earth movement. like isostasy is the rising or the settling of the part of the earth's lithosphere.
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A bank robber i driving north on Catchem Lane at 90 mph to avoid be arreted. Peed
velocity
acceleration
The robber is driving at a constant velocity of 90 mph and is not accelerating/decelerating, which means their acceleration is 0 mph/sec.
What is velocity?A vector quantity that has magnitude and direction is velocity. In time, it is the rate at which the displacement changes. You can calculate speed using the formula speed = distance/time. This is a way of measuring how fast something is moving in a particular direction. Acceleration, or the rate at which an object's velocity changes, is closely related to velocity. As a vector quantity, velocity has both direction and magnitude. To maintain constant velocity, the object must be moving in the same direction at a constant velocity.
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The complete question is as follows:
A bank robber is driving north on Catchem Lane at 90 mph to avoid be arrested. Calculate:
Speed
Velocity
Acceleration
What is the type of mutation represented by the amino acid sequence below?
Correct sequence: Leucine – Alanine – Glycine – Leucine
Mutated sequence: Leucine – Alanine – Valine – Leucine
Answer:
Substitution mutation
Explanation:
A substitution mutation is a type of mutation in which one or more nucleotide base is replaced by another in a sequence. This will result in the replacement of one or more amino acid in the amino acid sequence.
This is the case in this question where the original amino acid sequence was given as: Leucine – Alanine – Glycine – Leucine. After mutation, the following mutated sequence was produced: Leucine – Alanine – Valine – Leucine.
As illustrated above, one would notice that there is replacement of GLYCINE amino acid by VALINE in the mutated sequence, hence, it is an example of SUBSTITUTION MUTATION.
What is the hydroxide [OH-] concentration of a solution that has a pOH of 4.90? 14 14 1.26 x10-5 1.26 x10, -5 9.1 9.1 7.94 x 104
Answer:
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):
pOH= -log [OH-]
A solution has a pOH of 4.90. Replacing in the definition of pOH:
4.90= -log [OH-]
Solving:
-4.90= log [OH-]
1.26*10⁻⁵ M= [OH-]
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
A mixture contains only NaCl and Al2(SO4)3. A 1.68-g sample of the mixture is dissolved in water and an excess of NaOH is added, producing a precipitate of Al(OH)3. The precipitate is filtered, dried, and weighed. The mass of the precipitate is 0.116 g. What is the mass percent of Al2(SO4)3 in the sample
The precipitate is collected, filtered, dried, and weighed.. The mass of the precipitate is 0.116 g.
What is dissolved?Dissolved refers to a solute that is completely dissolved in a solvent, resulting in a homogeneous mixture. When a solute, such as a salt, is dissolved in a solvent, such as water, the molecules of each component are dispersed evenly throughout the mixture. This process can be reversed by evaporating the solvent, leaving the solute behind. The amount of solute that can be dissolved in a particular solvent is known as its solubility.
Mass of Al2(SO4)3= Mass of sample- Mass of precipitate
Mass of Al2(SO4)3= 1.68-0.116=1.564 g
Percent of Al2(SO4)3= (1.564/1.68)*100= 93.45 %
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At one sewage treatment plant, bacteria cultures produce 1000 L of methane gas per day at 1.0 atm pressure. What volume tank (V2) would be needed to store one day's amount of gas at a pressure of 5.0 atm?
At a pressure of 5.0 atm, IS 200 L of gas would need to be stored in the volume tank (V2).
How to find the volume?The mass of a body can be calculated from its volume using density, and vice versa. The mass is equal to the volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). Use a laboratory scale to weigh the masses, or use the density formula D = m/V to convert the solvent volume to mass. Find your ultimate volume by multiplying the solute and solvent masses.Volume, which is measured in cubic units, is the area in three dimensions that matter occupies or that is encircled by a surface. Cubic metres (m3), a derived measure, are used as the SI unit of volume.To learn more about volume, refer to:
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Shown below is the phase diagram for a typical liquid mixture of two components, A and B. a What is the significance of the horizontal line between points X and Y? O The length of the line XY corresponds to the difference in boiling point of components A and B. O A boiling liquid with composition X will produce vapor with composition Y. O The point X gives the vapor composition of the less volatile component and Y gives the vapor composition of the more volatile component. The line gives the difference. O A boiling liquid with composition Y will produce a vapor with composition X. b Using the phase diagram, determine the molar composition of the vapor in equilibrium with a boiling liquid that has a composition of 40% A and 60.% B. Percentage vapor composition A= 10 % Percentage vapor composition B 90 % What is the boiling point of this liquid? Boiling point 100 °C
The line between points X and Y represents the difference in boiling points of components A and B. A boiling liquid with a composition of 40% A and 60% B will produce a vapor with a composition of 10% A and 90% B, and have a boiling point of 100°C.
The significance of the horizontal line between points X and Y on the phase diagram is that it represents the difference in boiling points of components A and B. This line indicates the point at which the vapor and liquid phases are in equilibrium. On the diagram, point X gives the vapor composition of the less volatile component, while point Y gives the vapor composition of the more volatile component.
By looking at the phase diagram, we can determine the molar composition of the vapor in equilibrium with a boiling liquid that has a composition of 40% A and 60% B. The vapor composition of the less volatile component (X) is 10%, while the vapor composition of the more volatile component (Y) is 90%. The boiling point of this liquid is 100°C.
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Which example is the site of reduction when the dry cell is operating
Answer:
A battery contains electrochemical cells that can store chemical energy to be converted to electrical energy. A dry-cell battery stores energy in an immobilized electrolyte paste, which minimizes the need for water. Common examples of dry-cell batteries include zinc-carbon batteries and alkaline batteries.
Explanation: i hope this helps sorry if it didnt
Answer:
Your answer would Graphite Rod I got this correct on my quiz
that is of course if you had the multiple choice answer like how I did on my quiz.
Sorry if its late, Hope this helps!
m
4. You are carrying your 9-kg backpack to school. If your mass is 64 kg and you are walking with an acceleration of 2.5
what is your force?
O 160 N
29.2 N
2 183 N
O 22.5 N
Answer:
183N
Explanation:
183N we have to add both mass
Answer:
184N is my force wen carting a backpack
lead can react with oxygen gas. If lead (IV) oxide is the product of the reaction, how would the reaction be classified
Answer:
this reaction is an oxidation reaction
The chemical reactions involving both oxidation and reduction are known as redox reactions. The oxidation involves the loss of electrons. The reaction of lead with oxygen is an example of oxidation reaction.
What is oxidation reaction?According to the classical concept, oxidation is defined as a process which involves the addition of oxygen or electronegative element or the removal of hydrogen or electropositive element.
During electron transfer, the species which loses electrons is said to be oxidized and the species which gains electrons is said to be reduced.
The lead (IV) oxide is the formula of PbO₂. Here the oxidation state of lead is +4. The lead (IV) oxide is used in manufacturing dyes and also used to make explosives. It is a corrosive outcome that can evolve in lead pipes that are used for drinking water.
The formation of lead (IV) oxide is given as:
Pb (s) + O₂ (g) → PbO₂ (g)
Thus the reaction is an oxidation reaction.
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Given that 1 kWh = 3. 6 MJ and that 1 Btu = 1055 J, show that 1 kWh = 3412 Btu.
Given that 1 kWh = 3. 6 MJ and that 1 Btu = 1055 J, It is shown that 1 kWh = 3412 Btu.
1 kilowatt (kWh) = 3.6 mega Joules (MJ)
1 British thermal unit (Btu) = 1055 Joules (J)
As we know that:
1 MJ = 1000000 J
Since
1 kWh = 3.6 x 1000000 J
Calculate for 1 J
1 J = 1 ÷ 1055 Btu
1 kWh = 3.6 x 1000000 x (1 ÷ 1055) Btu
1 kWh = 3412.32 Btu
So it is calculated that 1 kilowatt (kWh) is equal to 3412 British thermal units (Btu).
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How does the urinary system maintain homeostasis?
Answer:
here is ur ans Lilly
Explanation:
In addition to maintaining fluid homeostasis in the body, the urinary system controls red blood cell production by secreting the hormone erythropoietin. The urinary system also plays a role in maintaining normal blood pressure by secreting the enzyme renin.hope it's helpful for you mark brainlest where you from , age
Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. If there are 39.24 grams of sucrose in a 12.0 fluid oz. can of this Coke, what is the molarity of sucrose in the Coke
Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. The molarity of sucrose in the Coke is 0.32 mol/L.
Coca-Cola is making a version of Coke that uses sucrose (C12H22O11) instead of high fructose corn syrup. If there are 39.24 grams of sucrose in a 12.0 fluid oz. can of this Coke, what is the molarity of sucrose in the Coke.
To find the molarity of sucrose in the Coke, we first need to find the number of moles of sucrose present in the can. We can use the mass of sucrose (39.24 g) and the molar mass of sucrose (342.3 g/mol) to find the number of moles of sucrose:
= (39.24 g) / (342.3 g/mol)
= 0.114 mol
Next, we need to find the volume of the can in liters. We can convert the volume in fluid oz. to liters using the conversion factor 1 fluid oz.
= 0.0295735 L:
= (12.0 fluid oz.) x (0.0295735 L/fluid oz.)
= 0.354882 L
Finally, we can use the formula for molarity (moles of solute / liters of solution) to find the molarity of sucrose in the Coke:
= molarity
= (0.114 mol) / (0.354882 L)
= 0.32 mol/L
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spectroscopy
There is something strange about Star 3’s spectrum.
Explain what this is called and what it means about this star.
A 16. 81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21. 33 grams of CO2 and 5. 822 grams of H2O are produced. In a separate experiment, the molar mass is found to be 104. 1 g/mol. Determine the empirical formula and the molecular formula of the organic compound
A 16. 81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21. 33 grams of CO₂ and 5. 822 grams of H₂O are produced. In a separate experiment, the molar mass is found to be 104. 1 g/mol. The empirical formula is CH₃ and molecular formula is C₇H₇O₂₁
The empirical formula can be calculate as follows:
The reaction can be write
CxHyOz → CO₂ + H₂O
As a result, we may state that there are two O-atoms for every one C-atom (12g) in CO2 (32g).
This indicates that the ratio is 12g C/32g O.
The molar mass of CO₂ is 44 g/mole.
(12/44) x 33 = 9 g
There are 9 grams of carbon in every 33 grams of CO₂
The same can be done for water:
In H₂O, each element is represented by two H atoms and one O atom. 2 g H and 16 g O.
[2 g H / 18 g H2O] are present in 5. 822 g of water
(2/18)x 5.822= 0.6468 g
The initial sample had 14.16 g of sample, 9 g of C, and 0.6468 g of H, which resulted in 34.3532g of oxygen.
Determine the amount of moles.
C: 9.0 g / 12.0 g/mol = 0.75 mol
H: 0.6468 g / 1.0 g/mol = 0.6468 mol
O: 34.3532g / 16.0 g/mol = 2.14 mol
Then we divide by the smallest number
C: 0.75 mol / 0.6468 mol = 1
H: 0.6468 mol / 0.6468 mol= 1
O: 2.14 mol/ 0.6468 mol = 3
so the empirical formula will be CH₃
Determine the molecular formula
mass molecular formula / mass of empirical formula = n
We have to multiply the empirical formula by n to get the molecular formula.
104.1 /15 = 7= n
This means the molecular formula = C₇H₇O₂₁
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Calculate ΔS∘ for Ti(s)+2Cl2(g)→TiCl4(g)
Express your answer using four significant figures.
ΔS∘ for Ti(s)+2Cl2(g)→TiCl4(g) is 659.6J/mol.. It is important to note that, as a general rule, a positive ΔS° indicates an increase in disorder and a negative ΔS° indicates a decrease in disorder.
The change in entropy (ΔS) for a chemical reaction can be calculated using the standard entropies (S°) of the reactants and products.
ΔS° = S°(products) - S°(reactants). For the reaction Ti(s) + 2Cl2(g) → TiCl4(g)S° of Ti(s) = 29.1 J/mol·K, S° of Cl2(g) = 223.1 J/mol·K, S° of TiCl4(g) = 167.4 J/mol·K. Therefore, ΔS° = (S°(TiCl4) + 2S°(Cl2)) - S°(Ti)ΔS° = (167.4 + 2*223.1) - 29.1 = 659.6 J/mol·K. So the ΔS∘ for Ti(s) + 2Cl2(g) → TiCl4(g) is 659.6 J/mol·K with four significant figures. It is important to note that, as a general rule, a positive ΔS° indicates an increase in disorder and a negative ΔS° indicates a decrease in disorder. So in this case, the process of going from solid titanium and gaseous chlorine to gaseous titanium tetrachloride increases disorder, which is consistent with a positive ΔS°.
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What is the relative rate of diffusion of CH4 and NO2?
The ratio of effusion rates of Sulphur dioxide and methane is 0.5
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
Rate of Diffusion ∝ 1 ÷ √molar mass of the gas
We are given:
Molar mass of Sulphur dioxide = 64.066 g/mol
Molar mass of methane = 16.04 g/mol
By taking their ratio, we get:
Rate of SO₂ ÷ Rate of CH₄ = √MCH₄ ÷ √MSO₂
Rate of SO₂ ÷ Rate of CH₄ = √16.04 ÷ √64.066
Rate of SO₂ ÷ Rate of CH₄ = 0.5
Hence, the ratio of rate of effusion of Sulphur dioxide and methane will be 0.5
Diatomic elements are important. what makes them different from other elemental substances?
Diatomic elements are elements that exist as pairs of atoms. Unlike other elemental substances, diatomic elements cannot exist as single atoms, but must exist as a pair of atoms bound together.
What is elemental?Elemental refers to an element or substance made up of one kind of atom, such as oxygen, carbon, or hydrogen. Elements are the basic building blocks of matter, and they are combined in different ways to form the molecules of different materials. Elemental substances are the most basic form of matter, and they are essential for life on Earth. There are currently 118 known elements, and they are found in nature and in many products. Each element has unique properties, and they can be used in different ways. For example, oxygen is essential for human respiration, while carbon is found in many materials, such as plastics and diamonds.
Examples of diatomic elements include nitrogen (N2), oxygen (O2), hydrogen (H2), chlorine (Cl2), fluorine (F2), and bromine (Br2).
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At 125 C the pressure of a sample of oxygen (O2) is 2.25 atm. What will the
pressure be at 25°C in closed (constant volume) container?
Answer:
1.68 atm
Explanation:
Applying
P/T = P'/T'................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.
Make P' The subject of the equation
P' = PT'/T.............. Equation 2
From the question,
Given: P = 2.25 atm, T = 125°C = (125+273) K = 398 K, T' = 25°C = (25+273) K = 298 K.
Substitute these values into equation 2
P' = (2.25×298)/398
P' = 1.68 atm
What is the energy of each of the following photons in kilojoules per mole? Express the energy in kilojoules per mole to three significant digits.
Part A: ν=5.95×1019s−1
Part B: ν=20.00×103s−1
Part C: λ=2.57×102m
The energy of a photon can be calculated using the formula: E = hν = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 Js), ν is the frequency, c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength which is 6.53 x 10^-38 kJ/mol
Part A: ν = 5.95 x 10^19 s^-1
E = hν = (6.626 x 10^-34 Js) x (5.95 x 10^19 s^-1) = 3.948 x 10^-14 J/photon
To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol)E = (3.948 x 10^-14 J/photon) / (6.022 x 10^23 photons/mol) = 6.53 x 10^-38 kJ/mol
Part B: ν = 20.00 x 10^3 s^-1
E = hν = (6.626 x 10^-34 Js) x (20.00 x 10^3 s^-1) = 1.325 x 10^-31 J/photon
To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol). E = (1.325 x 10^-31 J/photon) / (6.022 x 10^23 photons/mol) = 2.20 x 10^-55 kJ/mol. Part C: λ = 2.57 x 10^2 m. E = hc/λ = (6.626 x 10^-34 Js) x (2.998 x 10^8 m/s) / (2.57 x 10^2 m) = 3.948 x 10^-14 J/photon. To convert to kilojoules per mole, we need to divide by Avogadro's number (6.022 x 10^23 photons/mol) .E = (3.948 x 10^-14 J/photon) / (6.022 x 10^23 photons/mol) = 6.53 x 10^-38 kJ/mol. In all the parts, the energy is expressed in kilojoules per mole to three significant digits.
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Help please help me
Answer:
Strong acids are defined by their pKa. The acid must be stronger in aqueous solution than a hydronium ion, so its pKa must be lower than that of a hydronium ion. Therefore, strong acids have a pKa of <-174. Strong acids can be organic or inorganic.
Explanation:
Bond Strength
Strong acids have mostly ions in solution, therefore the bonds holding H and A together must be weak. Strong acids easily break apart into ions. Weak acids exist mostly as molecules with only a few ions in solution, therefore the bonds holding H and A together must be strong.
i think it will help you
how many grams of KNO3 that should be placed in the airbag to fully react with the Na.
10 Na + 2KNO: > 1K20 + 5Naz0 + 1 N2 (g)
NaN3→ Na + 32N2 1 mole of sodium azide gives 32 moles of N2
How much nitrogen is in an airbag?
37 gallons
The amount of nitrogen gas produced by a handful (130 grammes) of sodium azide is 67 litres, which is sufficient to inflate a typical air bag. An air bag can be inflated in as little as 0.03 SECOND. There is another chemistry at play.
Even though we don't typically link chemistry with cars, a lot of chemistry happens in a functioning car, such as the chemical processes that take place in the battery to produce electricity and the burning of gasoline to power the engine. Another reaction includes the air bag, which is one that most drivers would much rather not experience firsthand.
Instead of using compressed gas, air bags are inflated using the byproducts of a chemical reaction. Sodium azide, often known as NaN3, is the principal chemical involved in the air bag reaction
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In the last minute rush to assemble the demonstration, your teacher spills the lead chloride all over their sandwich and is left with 57.2 grams in the bottle. How much potassium iodide should be weighed out to convert all of the lead chloride to product?
Answer: Magnesium is being oxidized, and the chloride ion is being reduced. ... solutions of the reactants lead(II) nitrate and potassium iodide.
Explanation:
Counting Atoms in Chemical Equations Nitrogen gas reacts with hydrogen to produce ammonia. Use the chemical equation to complete the statements. N2 + 3H2 → 2NH3
Answer:
There are 2 nitrogen atoms on the product side.
There are 6 hydrogen atoms on the reactant side.
Explanation:
Answer:
There are 2 nitrogen atoms on the product side.
There are 6 hydrogen atoms on the reactant side.
Explanation:
As seen in the picture below,
15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.90 atm. What is the new volume in litres
The new volume in litres is 13.29 L.
Given,
Temperature 1 (T₁) = 298 K
Volume 1 (V₁) = 15 L
Temperature 2 (T₂) = 383 K
Pressure 1 (P₁) = 3.36 atm
Pressure 2 (P₂) = 4. atm
By Ideal Gas Equation,
P₁V₁/T₁ = P₂V₂/T₂
⇒ (3.36*15)/298 = (4.90*V₂)/383
⇒50.4/298 = 4.90V₂/383
⇒ (50.4*383) / (298*4.90) = V₂
⇒ 19303.2/1460.2 = V₂
⇒13.29 L = V₂
New Volume will be 13.29 L.
Ideal gas law is a precise approximation of the behavioral of several gases under various situations in thermodynamics. The Ideal Gas Equation is a mathematical formula that combines empirical laws such as Charle's law, Boyle's law, Gay-law, Lussac's and Avogadro's law.
The equation characterizing the states of hypothetical gases stated mathematically by combinations of empirical or physical constants is known as the Ideal Gas Equation. It's also known as the universal gas equation. It is defined as follows:
"The ideal gas law seems to be the equation of state for a fictitious perfect gas. It is a decent approximation of the behavioral of various gases under numerous situations, while it has significant limitations".
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