The wavelength of electromagnetic radiation that would be emitted most strongly by matter at the temperature of the core of a nuclear explosion of 10,000,000 k will be 2.898 × 10^-10 meters.
Wavelength of electromagnetic radiationThe wavelength of electromagnetic radiation emitted by matter at a certain temperature can be determined using Wien's displacement law, which states that the wavelength of maximum emission (λmax) is inversely proportional to the temperature of the object:
λmax = b / T
where b is a constant known as Wien's displacement constant, equal to 2.898 × 10^-3 m·K.
Substituting the given temperature of 10,000,000 K into this equation, we get:
λmax = (2.898 × 10^-3 m·K) / (10^7 K) = 2.898 × 10^-10 m
Therefore, the wavelength of electromagnetic radiation emitted most strongly by matter at the temperature of the core of a nuclear explosion is approximately 2.898 × 10^-10 meters, which corresponds to the ultraviolet region of the electromagnetic spectrum.
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a rock is thrown upward with a velocity of 13 meters per second from the top of a 38 meter high cliff, and it misses the cliff on the way back down. when will the rock be 11 meters from ground level? round your answer to two decimal places.
The rock will be 11 meters from the ground 2.97 seconds after it is thrown.
Let's start by using the kinematic equation,
h = vit + 0.5a*t^2
where h is the height, vi is the initial velocity, t is the time, and a is the acceleration due to gravity (-9.8 m/s^2).
At the highest point, the rock's velocity will be zero, so we can use this fact to find the time it takes to reach the highest point,
0 = 13 - 9.8*t_highest
t_highest = 1.33 seconds
Now we can use this time to find the height of the rock above the ground,
h = 38 + 131.33 - 0.59.8*(1.33)^2
h = 51.33 meters
So at its maximum height, the rock is 51.33 meters above the ground. To find when it will be 11 meters from the ground,
11 = 51.33 + 0 + 0.5*(-9.8)*t^2
t^2 = (51.33 - 11)/4.9
t^2 = 8.8367
t = 2.97 seconds (rounded to two decimal places)
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suupose that an aircraft's take-off speed is 120 moh at sea level.. what would be the take off speed for this aircraft at denver?
The takeoff speed for this aircraft at Denver would be approximately 116.85 moh if the speed of takeoff of the aircraft at sea level is 120 moh.
When an aircraft takes off, the atmosphere has a significant impact on its speed. In Denver, the air is thinner than at sea level, and the aircraft's takeoff speed must be adjusted as a result. As altitude rises, air density decreases, so the aircraft's takeoff speed must be increased to compensate.The formula for calculating takeoff speed with respect to altitude is given below:
Takeoff speed at altitude h = Takeoff speed at sea level x √(air density at altitude h / air density at sea level)
We know that the takeoff speed at sea level is 120 moh. Let us assume that air density at Denver is 0.91 times the air density at sea level.Hence, the takeoff speed at Denver can be calculated as:
Takeoff speed at Denver = 120 x √(0.91)≈ 116.85 moh.
Therefore, the takeoff speed for this aircraft at Denver would be approximately 116.85 moh.
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a particle travels 17 times around a 16-cm radius circle in 38 seconds. what is the average speed (in m/s) of the particle?
A particle travels 17 times around a 16-cm radius circle in 38 seconds.The average speed of the particle is approximately 14.21 m/s.
The particle's average speed can be calculated by dividing the distance travelled by the time taken.
The distance travelled by the particle is equal to the circumference of the circle, which is given by 2πr, where r is the radius of the circle. Therefore, the distance travelled by the particle is given by:
Distance travelled = 17 × 2π × 16 cm
= 17 × 32π cm
The time taken by the particle to travel this distance is given as 38 seconds.Therefore, the average speed of the particle is given by:
Average speed = Distance travelled /Time taken
= (17 × 32π) cm/38 s
= 17 × 32 × π/38 m/s
= 14.21 m/s (rounded to two decimal places).
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suppose that you are standing on a surface that is so slick that you can get no traction at all in order to begin moving across the surface. fortunately you are carrying a bag of oranges. how can you get yourself moving to the right?
You can get yourself moving to the right on a slick surface with no traction by throwing the oranges to the left.
Actions and reactionsOne possible way to get moving to the right on a slick surface with no traction is to throw the oranges to the left in a series of quick and forceful motions.
According to Newton's third law of motion, every action has an equal and opposite reaction. As you throw the oranges to the left, your body will experience a reactive force to the right, which can cause you to move in that direction.
By repeating this throwing motion with the oranges, you can continue to generate a reactive force that propels you in the desired direction.
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it is observed that 2.53 coulombs of charge flow through a light-bulb over the course of 2.39 minutes. there are three light bulbs in the circuit, lined up one after the other. determine the amount of charge flowing through the third light bulb over the course of 9.80 minutes.
The amount of charge flowing through the third light bulb over the course of 9.80 minutes is 6.069C.
Since we know the relation between current and charge and also current is same in case of series connection and here three bulb connected in series.
I = q / t
given:
I = ?
q = 2.06 C
t = 2.59 minutes = 155.4 sec
I = 2.06 / 155.4 A
We have to find charge flow in 7.63 minutes
q = I x t
q = 2.06 / 155.4 x 7.63 x 60
q = 6.069C
In the field of physics, charge refers to a fundamental property of matter that describes the amount of electrical force that an object possesses. Charge is quantized, meaning that it comes in discrete units, and it can be either positive or negative. Objects that have the same type of charge (either positive or negative) repel each other, while objects with opposite charges attract each other. This is the basis for the behavior of electrical circuits, as well as the functioning of electronic devices.
Charge is also conserved, meaning that it cannot be created or destroyed, only transferred from one object to another. This is why electrical devices are designed to use energy efficiently, as any charge lost due to resistance in the circuit will be converted into heat and cannot be recovered.
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an asteroid exerts a 360-n gravitational force on a nearby spacecraft. if the spacecraft moves to a position three times as far from the center of the asteroid, the force will be
The force between the asteroid and the spacecraft will be 40 N when the spacecraft moves to a position three times as far from the center of the asteroid.
The gravitational force between two objects of masses m1 and m2 separated by a distance r is given by the formula:
F = G(m₁m₂) / r²
where G is the gravitational constant.
In this problem, the asteroid exerts a gravitational force of 360 N on the spacecraft when they are at a certain distance r from each other. When the spacecraft moves to a position three times as far from the center of the asteroid, its distance from the asteroid will be 3r. To calculate the new force between them, we can use the same formula and plug in the new distance:
F' = G(m1m2) / (3r)^2
F' = G(m1m2) / 9r^2
Since the masses of the asteroid and spacecraft are constant, we can divide the second equation by the first to find the ratio of the new force to the original force:
F' / F = (G(m₁m₂) / r²) / 9r²) / (G(m₁m₂) / r²)
F' / F = (1 / 9)
F' = (1 / 9) * F
F' = (1 / 9) * 360 N
F' = 40 N
Therefore, the force will be 40 N.
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the grand coulee dam is 1270. m long and 170. m high. the electrical power output from generators at its base is approximately 2000. mw. how many cubic meters of water must flow from the top of the dam per second to produce this amount of power if 92% of the work done on the water by gravity is converted to electrical energy? (each cubic meter of water has a mass of 1000. kg .)
Hence, 127.2 m3/s per second is the required water flow rate from the dam's crest.
What is a second?A international unit system (SI) defines the metre per second as the speed of the a body covering a metre in one second, which is measured in terms of the both speed (a scalar number) and speed (a vector quantity with direction and magnitude). m/s, m/s1, m/s, or ms are the SI unit symbols.
How do you calculate a second?Distance times time is the same for all objects, including cars, when calculating speed and distance. So, a math becomes (60 x 5280) (60 x 60) ≈ 88 meters per second when trying to figure out how fast an automobile is traveling at 60 miles per hour.
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Seventh grade QQ.4 Commas with coordinate adjectives 5L5
Insert one comma to separate the coordinate adjectives.
Typical golf caddie responsibilities include carrying clubs, cleaning balls,
calculating distances and scores, and even replacing the divots-pieces of
grass and dirt that have been cut loose by the swift forceful strikes of golf
clubs.
Answer:
Typical golf caddie responsibilities include carrying clubs, cleaning balls,
calculating distances and scores, and even replacing the divots - pieces of
grass and dirt that have been cut loose by the swift, forceful strikes of golf
clubs.
a wooden block has a volume of 12.5 liters and a mass of 5.0 kg. what volume of water must be displaced if the wooden block is to float?
A wooden block has a volume of 12.5 litres and a mass of 5.0 kg. 5.0 litres of water must be displaced if the wooden block is to float.
What volume of water must be displaced if the wooden block is to float?The density of wood is less than the density of water. As a result, to float on water, an object made of wood must displace an amount of water greater than its weight.
The formula for calculating the density of an object is:
density = mass/volume
Rearranging this equation gives: v
olume = mass/density
From the information given in the question, the mass of the wooden block is 5.0 kg, and the volume is 12.5 liters.
Density is the mass divided by the volume:
density = mass/volume = 5.0 kg / 12.5 L = 0.4 kg/L
To float on water, the density of the wooden block must be less than the density of water, which is 1 kg/L.
Applying the formula above, we can solve for the volume of water displaced by the wooden block, which is equal to the volume of the block:
volume = mass/density = 5.0 kg / 1 kg/L = 5.0 L
Thus, 5.0 liters of water must be displaced if the wooden block is to float.
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an atom that has become charged by gaining or losing electrons
At the point when an atom gains/loses an electron, the atom becomes charged and is called an ion.
Acquiring an electron brings about a negative charge, so the atom is an anion.
Losing an electron brings about a positive charge, so an atom particle is a cation.
An atom is a nonpartisan molecule that contains an equivalent number of protons and electrons. A particle is an atom that has lost or acquired at least one electron and has a positive or negative charge subsequently. In this way, the principal contrast between an atom and a particle is that an atom has an impartial charge while a particle has a positive or negative charge.
A few instances of ions include:
Chloride anions (Cl - )
Sulfate anions (SO 42-)
Nitrate anions (NO 3-)
Calcium cation (Ca 2+)
Manganese (II) cation (Mn 2+)
Hypochlorite anion (ClO - )
Ammonium cation (NH 4+)
Ferric cation (Fe 3+)
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the density of air at moderate altitude on earth is 1 kg/m3 (this can be converted to 0.001 g/cm3). the density of the atmosphere near mars' surface is 0.02 kg/m3. how many m3 of mars atmosphere would it take to collect a mass of 1kg, the same mass as in one m3 on earth? group of answer choices
Option C, It would take 50 m³ of Mars' atmosphere to collect the same mass of air as one m³ on Earth. To calculate the volume of Mars' atmosphere required to collect a mass of 1kg, we need to use the density of the Martian atmosphere and the mass of the air on Earth.
The density of air at moderate altitude on Earth is given as 1 kg/m3. This means that 1 cubic meter of air on Earth has a mass of 1 kg. To convert this to grams per cubic centimeter, we can divide by 1000, which gives 0.001 g/cm3.
The mass of air in one m³ on Earth is 1 kg, while the density of the atmosphere near Mars' surface is 0.02 kg/m³. Therefore, to collect 1 kg of Mars' atmosphere, we need:
1 kg / 0.02 kg/m³ = 50 m³
So, it would take 50 m³ of Mars' atmosphere to collect the same mass of air as one m³ on Earth.
Complete question -
The density of air at moderate altitude on earth is 1 kg/m3 (this can be converted to 0.001 g/cm3). the density of the atmosphere near mars' surface is 0.02 kg/m3. how many m3 of mars atmosphere would it take to collect a mass of 1kg, the same mass as in one m3 on earth?
A. 1
B. 10
C. 50
D. 100
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and object is placed 16cm from a convex lens that has a focal length of 4cm. if the image is located at 5.33 cm high, how tall is the image?
The height of the image is approximately 1.066 cm, and since it is negative, it means that the image is inverted and smaller than the object.
Using the thin lens equation:
1/f = 1/d_o + 1/d_i
where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance.
Plugging in the given values, we get:
1/4 = 1/16 + 1/d_i
Solving for d_i, we get:
d_i = 3.2 cm
Using the magnification equation:
m = -d_i/d_o
where m is the magnification of the image.
Plugging in the given values, we get:
m = -3.2/16 = -0.2
Since the magnification is negative, the image is inverted.
Finally, using the equation:
m = h_i/h_o
where h_i is the height of the image, and h_o is the height of the object.
Plugging in the given values and solving for h_i, we get:
h_i = m * h_o = (-0.2) * 5.33 cm = -1.066 cm
Therefore, the height of the image is approximately 1.066 cm, and since it is negative, it means that the image is inverted and smaller than the object.
What is magnification of lens?
The magnification of a lens is a measure of how much larger or smaller an image appears relative to the object that is being viewed through the lens. It is the ratio of the height of the image formed by the lens to the height of the object.
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how many nuclear reactor incidents have been studied to determine the stoachasitc effects on the workers and exposed population
Nuclear reactor incidents have been studied in hundreds to determine the stochastic effects on the workers and exposed population.
The stochastic effect refers to radiation-induced effects that may occur in tissues or cells and that are subject to probabilistic relationships between exposure and reaction. The probability of developing cancer increases as a result of exposure to radiation. The greater the exposure dose, the greater the likelihood of developing cancer.The stochastic effect can occur even at low radiation doses.
This is opposed to deterministic effects, which only occur when a particular radiation dose threshold is surpassed. Stochastic effects are also referred to as random or probabilistic effects. They can happen in any tissue or organ in the body, including reproductive cells, which can lead to heritable genetic mutations. The probability of developing cancer increases as the radiation dose rises.
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gold has a specific gravity of almost 20. a 5-gallon bucket of water weighs 40 pounds. how much would a 5-gallon bucket of gold weigh? hint: if a mineral were twice as dense as water, its specific gravity would be two. water has a specific gravity of 1.
A 5-gallon bucket of gold would weigh 86.84 pounds.
A five-gallon bucket of water weighs 40 pounds. Gold has a specific gravity of almost 20.
If a mineral was twice as dense as water, its specific gravity would be two.
Water has a specific gravity of 1.
To determine the weight of a 5-gallon bucket of gold, you need to determine the weight of 5 gallons of water first.One gallon of water weighs approximately 8.33 pounds; hence 5 gallons of water weigh 41.65 pounds.
Now, divide the weight of 5 gallons of water (41.65) by the specific gravity of gold (20):41.65/20 = 2.0825
The weight of a five-gallon bucket of gold would be 2.0825 times greater than that of a five-gallon bucket of water, which equals to 86.84 pounds (40 pounds + 46.84 pounds).
Therefore, a 5-gallon bucket of gold would weigh approximately 86.84 pounds.
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(1 points) resistance of a wire is quantified by r. the wire is stretched to double its length, but the material maintains the same density. what is the new resistance in r?
The resistance of a wire is quantified by r. The wire is stretched to double its length, but the material maintains the same density.
When a wire's length is doubled, its resistance is doubled as well. When a wire's thickness is doubled, its resistance is decreased to one-half of its previous value. The formula for wire resistance is given by the following equation:
R = ρL / A
Since the wire's density is constant, the resistance is proportional to the wire's length and inverse to the cross-sectional area. As a result, doubling the wire's length would double its resistance.
So the new resistance in r would be twice the previous resistance, which is R.
Mathematically,
[tex]R_2[/tex] = 2R where R is the previous resistance of the wire.
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the words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of .
The words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of physical phenomena.
The words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of physical phenomena. Physical phenomena are observable events or occurrences that can be described using the scientific method. These phenomena can be observed using our senses, such as sight, touch, sound, taste, and smell, or measured using instruments, such as thermometers, scales, or cameras. For example, the wave of a hand is a physical phenomenon because it is an observable event that can be seen and measured. Similarly, the words on the pages of a textbook are physical phenomena because they are observable and can be seen and read.
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shows three edge views of a square loop with sides of length = 0.250 m in a magnetic field of magnitude 2.00 T. Calculate the magnetic flux through the loop oriented a. perpendicular to the magnetic field, b. 60.0° from the magnetic field, and c. parallel to the magnetic field
The magnetic flux through the loop is 0.125 Wb when oriented perpendicular to the magnetic field, 0.0625 Wb when oriented 60.0° from the magnetic field, and 0 Wb when oriented parallel to the magnetic field.
To calculate the magnetic flux through the loop, we can use the formula:
Magnetic flux (Φ) = B × A × cosθ
where B is the magnetic field magnitude, A is the area of the square loop, and θ is the angle between the magnetic field and the loop's normal vector.
a. Perpendicular to the magnetic field (θ = 0°)
In this case, cosθ = cos(0°) = 1.
Area (A) = (side length)² = (0.250 m)² = 0.0625 m²
Φ = B × A × cosθ = 2.00 T × 0.0625 m² × 1 = 0.125 Wb
b. 60.0° from the magnetic field (θ = 60°)
In this case, cosθ = cos(60°) = 0.5.
Φ = B × A × cosθ = 2.00 T × 0.0625 m² × 0.5 = 0.0625 Wb
c. Parallel to the magnetic field (θ = 90°)
In this case, cosθ = cos(90°) = 0.
Φ = B × A × cosθ = 2.00 T × 0.0625 m² × 0 = 0 Wb
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which of the following have wavelengths that are longer than visible light? question 3 options: 1) gamma rays 2) ultraviolet (uv) light 3) infrared radiation 4) x rays 5) a, b, and d
All of the following have wavelengths that are longer than visible light: Gamma Rays, Ultraviolet (UV) Light, Infrared Radiation, and X Rays (A, B, and D).
Gamma Rays have the shortest wavelength of all four, with a range of 10 picometers to 0.01 nanometers. Ultraviolet (UV) Light has a range of 10 nanometers to 400 nanometers. Infrared Radiation has a range of 700 nanometers to 1 millimeter. Finally, X Rays have a range of 0.01 nanometers to 10 nanometers.
All four of these forms of radiation are used for various applications, such as medical imaging and astronomical observations. Gamma Rays are used for medical imaging, such as PET scans, and are also used to study the structure of atoms and molecules. Ultraviolet (UV) Light is used in tanning beds and is also used to detect organic compounds in astronomical observations. Infrared Radiation is used to detect objects in the sky, such as stars and planets, as well as to detect gas clouds. Finally, X Rays are used in medical imaging, such as CT scans, and are also used to study the structure of atoms and molecules.
In conclusion, Gamma Rays, Ultraviolet (UV) Light, Infrared Radiation, and X Rays all have wavelengths that are longer than visible light.
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an observer is positioned 3 km away from a rocket launch pad. how fast is the distance between the rocket and the observer increasing, when the rocket is 4 km above the ground and is moving straight up at the speed of 300m/sec?
The distance between the rocket and the observer is increasing at a rate of about 186.6 m/s.
We can use the Pythagorean theorem to relate the distance between the rocket and the observer to the height of the rocket above the ground. Let d be the distance between the observer and the launch pad, and let h be the height of the rocket above the ground. Then,
d^2 = h^2 + 3^2 (1)
We can take the derivative of both sides of equation (1) with respect to time to get,
2d (dd/dt) = 2h (dh/dt) (2)
where (dd/dt) is the rate of change of distance between the observer and the rocket, and (dh/dt) is the rate of change of height of the rocket.
At the moment when the rocket is 4 km above the ground, h = 4 km = 4000 m, and (dh/dt) = 300 m/s.
Substituting these values into equation (2) and solving for (dd/dt),
dd/dt = (h/d) x (dh/dt) = (4000 m / √(4000^2 + 3000^2) m) x (300 m/s)
≈ 186.6 m/s
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A solid cylinder of mass M = 1.25 kg and radius R = 13.5 cm pivots on a thin fixed frictionless bearing a string wrapped around the cylinder pulls downward with a force of F = 7.259 N
What is the magnitude of the angular acceleration of the cylinder?
86.03259 rad/s^2
Consider that instead of force F, a block with mass 0.74 kg with force = 7.259 N is attached to the cylinder with a mass less string.
What is now the magnitude of the angular acceleration of the cylinder
39.3943 rad/s^2
How far does the mass M travel downward before T equals 0.49S and T equals 0.69 S.
0.62755 m
The cylinder is changed to one with the same mass and radius but a different moment of inertia starting from mass starting from rest. The mass is now moved. The distance of 0.448 mass in the time interval of 0.47 seconds.
Find the Inertia of the new cylinder
The inertia of the new cylinder is 0.0566 kgm². Other answers provided are correct.
How to find inertia?The moment of inertia of the new cylinder can be calculated using the formula:
I = (M × d²) / (4 × Δθ)
Where:
M = mass of the cylinder
d = distance moved by the mass
Δθ = change in angular displacement (in radians)
Substituting the given values:
I = (1.25 × 0.448²) / (4 × 0.47)
I = 0.0566 kgm²
Therefore, the moment of inertia of the new cylinder is 0.0566 kgm².
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if the average power requirement in your home is 4.0 kw k w and you can convert solar power to electric power with 14 % % efficiency, how large a collector area will you need to meet all your household energy requirements from solar energy? express your answer with the appropriate units.
To meet all your household energy requirements from solar energy with a 14% efficiency, you will need a solar collector area of approximately 28.57 square meters.
To determine the area of solar collector required to meet your household energy requirements, we can use the following formula:
Collector area = Power requirement / (Solar irradiance x Efficiency)
Where,
Power requirement = 4.0 kW
Efficiency = 14% = 0.14 (as given)
Solar irradiance = average solar irradiance on a surface perpendicular to the sun's rays is approximately 1000 W/m² (at sea level on a clear day)
Plugging in the values, we get:
Collector area = 4.0 kW / (1000 W/m² x 0.14)
Collector area = 28.57 m²
Solar energy refers to the radiant light and heat that is emitted by the sun and captured using various technologies such as solar panels and solar thermal collectors. This energy can then be converted into electricity or used directly for heating and cooling purposes.
Solar energy is a renewable and abundant source of energy, and it is a clean alternative to traditional fossil fuels that release harmful emissions into the environment. It also provides energy independence and reduces dependence on foreign oil.
Solar energy has many applications, ranging from powering homes and businesses to providing electricity for remote areas without access to traditional power grids. It is also used in the transportation sector, with solar-powered vehicles and charging stations becoming increasingly popular.
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A 5. 00-kg box slides across a rough horizontal floor, initially at 2. 50 m/s. If friction brings
the box to rest after 1. 50 s, determine the magnitude of the average rate in watts at which
friction dissipates the block’s mechanical energy
The magnitude of the average rate in watts at which friction dissipates the box's mechanical energy is 10.4 W.
KE = 1/2 mv²
KE = 1/2 (5.00 kg) (2.50 m/s)² = 15.6 J
Since the box comes to rest after 1.50 s, the average power dissipated by friction can be found using the equation:
P = E/t
P = 15.6 J / 1.50 s = 10.4 W
Mechanical energy is the sum of the potential energy and kinetic energy of an object. Potential energy is the energy that an object possesses by virtue of its position or configuration in a field of force, while kinetic energy is the energy that an object possesses by virtue of its motion.
The mechanical energy of an object is conserved when it is in a closed system, meaning that the total amount of mechanical energy remains constant. This is known as the law of conservation of mechanical energy. For example, if an object is dropped from a height, its potential energy is converted into kinetic energy as it falls, and the total mechanical energy remains constant. Mechanical energy plays an important role in many areas of physics, including mechanics, thermodynamics, and electromagnetism.
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if a 4.5 kg object is dropped from a height of 6.0 m, what will be its velocity when it is halfway toward the ground? (use g
The final answer are velocity of the object when it is midway to the ground is : v = u + at v = 0 + 9.81 x 0.78v = 7.658 m/s= 8.77 m/s (rounded to two decimal places)
At the midpoint, the velocity of the 4.5 kg item dropped from a height of 6.0 m is 8.77 m/s (use g = 9.81 m/s^2).
The weight of the object is the force acting on it that is proportional to its mass. The weight is represented by the formula W=mg. W = 4.5 x 9.81 m/s²W = 44.145 N, where N is the newton.
The object's initial velocity is zero, and it starts to fall. The speed of an object moving with constant acceleration is given by the formula v = u + at, where u is the initial velocity, t is the time taken, and a is the acceleration.
In this instance, the initial velocity u = 0. If the distance is halved, the time taken to reach the midpoint can be computed as follows: t = sqrt (2s / g)t = sqrt (2 x 3 / 9.81)t = sqrt (0.611) t = 0.78 s
The velocity of the object when it is midway to the ground is : v = u + at v = 0 + 9.81 x 0.78v = 7.658 m/s= 8.77 m/s (rounded to two decimal places)
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A net force of 200 N acts on a 100-kg boulder, and a force of thesame magnitude acts on a 130-g pebble. How does the rate of changeof the boulder’s momentum compare to the rate of change ofthe pebble’s momentum?
a. greater than
b. less than
c.equal to
The rate of change of the boulder's momentum is equal to the rate of change of the pebble's momentum. Option C is correct.
This is because the rate of change of an object's momentum is directly proportional to the net force acting on the object, and inversely proportional to the mass of the object. In this case, the net force acting on both the boulder and the pebble is the same, at 200 N. However, the mass of the boulder is much larger than the mass of the pebble.
Since the rate of change of momentum is inversely proportional to the mass of the object, the boulder will experience a smaller rate of change in momentum than the pebble. However, this will be exactly offset by the fact that the boulder has a larger mass, which will cause its momentum to change at the same rate as the pebble.
Therefore, the rate of change of the boulder's momentum is equal to the rate of change of the pebble's momentum, despite the large difference in their masses. The principle behind the rate of change of momentum is that the amount of momentum an object has is directly proportional to its mass and velocity. When a net force acts on an object, it causes the object's velocity to change, which in turn causes a change in the object's momentum.
The rate of change of an object's momentum is determined by the net force acting on the object, as well as its mass. Specifically, the rate of change of momentum is equal to the net force acting on the object divided by its mass. This principle is known as Newton's second law of motion.
In the case of the boulder and the pebble in the original question, both objects are subject to the same net force of 200 N. However, the boulder has a mass of 100 kg, while the pebble has a mass of 0.13 kg. Since the rate of change of momentum is inversely proportional to the mass of the object, the pebble will experience a much larger rate of change in momentum than the boulder. Option C is correct.
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numeade how much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 n?
Work done on the can of soup by the attendant is 3J.
A supermarket checkout attendant can do a considerable amount of work on a can of soup when they apply a force of 5.00 N over a distance of 0.600 m.
Work is defined as the product of force and displacement and is calculated by multiplying the force applied (5.00 N) by the distance moved (0.600 m). Therefore, the work done on the can of soup is:
5.00 N * 0.600 m = 3.00 Nm.
To understand this concept further, it's important to know that the unit of work, joule (J), is equal to 1 Newton meter (Nm). So, the 3.00 Nm of work done on the can of soup is also equal to 3.00 J.
The amount of work done on the can of soup by the checkout attendant is directly proportional to the amount of force and displacement applied. If either of the two is increased, then the total work done will increase.
For example, if the checkout attendant applies a force of 10.00 N over a distance of 0.600 m, then the total work done will be 10.00 N * 0.600 m = 6.00 Nm, or 6.00 J.
In conclusion, a supermarket checkout attendant can do a considerable amount of work on a can of soup when they apply a force of 5.00 N over a distance of 0.600 m. This work is equal to 3.00 Nm or 3.00 J.
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an 80-kg man on ice skates pushes a 40-kg boy also on skates with a force of 100 n. the force exerted by the boy on the man is
The force exerted by the boy on the man is also 100 N, according to Newton's Third Law of Motion.
Newton's Third Law of Motion is a fundamental principle in physics that describes the relationship between forces acting on objects. It states that for every action, there is an equal and opposite reaction.
This means that when an object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.
In this scenario, the man exerts a force of 100 N on the boy in the forward direction. As a result, the boy exerts an equal and opposite force of 100 N on the man in the backward direction.
This principle applies to all objects in motion and is essential for understanding the dynamics of physical systems.
Therefore, the force exerted by the boy on the man is also 100 N.
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How far apart are two charges if you know they each, are +2.0 C and the force between them is 8.5•10^8 N
The two charges would be 219.1 meters apart.
Distance between two chargesThe force between two charges is given by Coulomb's Law:
F = k * (q1 * q2) / r^2
where F is the force, k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
In this case, we have two charges with a magnitude of +2.0 C each and a force of 8.5 x 10^8 N between them. Substituting these values into Coulomb's Law, we get:
8.5 x 10^8 N = (9.0 x 10^9 N*m^2/C^2) * [(2.0 C)^2 / r^2]
Simplifying this expression, we get:
r^2 = [(2.0 C)^2 * (9.0 x 10^9 N*m^2/C^2)] / (8.5 x 10^8 N)
r^2 = 4.8 x 10^4 m^2
Taking the square root of both sides, we get:
r = 219.1 meters
Therefore, the two charges are 219.1 meters apart.
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what is the distance between fringes produced by a diffraction grating having 130 lines per centimeter for 580 nm light, if the screen is 1.50 m away?
A diffraction grating that has 130 lines per centimeter for 580 nm light, if the screens are 1.50 m apart, then the distance between the edges is 30.6 mm
The formula for the distance between fringes for a diffraction grating is given:
d sinθ = mλ,
where d is the spacing between the grating lines, θ is the angle between the incident beam and the diffracted beam, m is the order of the diffraction maximum, and λ is the wavelength of light.
It can also be expressed as
Δy = mλD/d,
where Δy is the distance between adjacent fringes on the screen, D is the distance from the grating to the screen, and d is the spacing between the grating lines.
Given data:
Spacing between grating lines, d = 1/130 cm = 0.00769 cm
The wavelength of light, λ = 580 nm = 580 × 10⁻⁹ m
Distance from grating to the screen, D = 1.50 m
The formula to calculate the distance between fringes produced by a diffraction grating is given:
Δy = mλD/d
Now, substituting the given values in the above formula we get,
Δy = (1)(580 × 10⁻⁹ m)(1.50 m)/(0.00769 × 10⁻⁴ m)
Δy = 0.0306 m = 30.6 mm
Therefore, the distance between fringes produced by a diffraction grating having 130 lines per centimeter for 580 nm light, if the screen is 1.50 m away is 30.6 mm.
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in a double slit experiment, the fringe spacing on a screen 100 cm behind the slits is 4 mm. what will the fringe spacing be if the screen distance is doubled to 200 cm?
On the screen, 200 cm behind the slits, the fringe spacing will be 8 mm.
How will the fringe spacing change as the distance from the screen grows?Due to its dependence on L, the spacings between various fringes get smaller as the distance between the slits gets more. The space between various fringes grows as the light's wavelength rises because this is a wavelength-dependent property.
The equation: gives the screen's fringe spacing in a double-slit experiment.
dsin(theta) = mlambda
The fringe spacing will therefore double if the screen distance is increased from 100 cm to 200 cm.
The new fringe spacing will be as follows:
2 * 4 mm = 8 mm
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Three infinite straight wires are fixed in place and aligned parallel to the z-axis as shown. The wire at (x,y) = (-15.5 cm, 0) carries current l1-3.4 A in the negative z-direction. The wire at (x,y) (15.5 cm, 0) carries current I2 = 0.5 A in the positive z-direction. The wire at (x.y) = (0, 26.8 cm) carries current I3 = 5.2 A in the positive z-direction. 1. What is Bx(0,0), the x-component of the magnetic field produced by these three wires at the origin? 2). What is By(0,0), the y-component of the magnetic field produced by these three wires at the origin? 3). What is Fx(1), the x-component of the force exerted on a one meter length of the wire carrying current I1? 4). What is Fyl), the y-component of the force exerted on a one meter length of the wire carrying current I1?
5). What is Fx(2), the x-component of the force exerted on a one meter length of the wire carrying current l2?
The x-component of the magnetic field produced by these three wires at the origin, Bx(0,0), is equal to zero since the wires are aligned parallel to the z-axis.
The y-component of the magnetic field produced by these three wires at the origin, By(0,0), is equal to μ0/2π times the sum of the currents, or 0.8 x 10-7 T.
The x-component of the force exerted on a one meter length of the wire carrying current I1, Fx(1), is equal to the product of the current, I1, and the y-component of the magnetic field, By(0,0). This is equal to -2.7 x 10-7 N.
The y-component of the force exerted on a one meter length of the wire carrying current I1, Fy(1), is equal to the product of the current, I1, and the x-component of the magnetic field, Bx(0,0). Since Bx(0,0) is equal to zero, the force is equal to zero.
The x-component of the force exerted on a one meter length of the wire carrying current I2, Fx(2), is equal to the product of the current, I2, and the y-component of the magnetic field, By(0,0). This is equal to 0.4 x 10-7 N.
In conclusion, the x-component of the magnetic field produced by these three wires at the origin, Bx(0,0), is equal to zero. The y-component of the magnetic field produced by these three wires at the origin, By(0,0), is equal to 0.8 x 10-7 T.
The x-component of the force exerted on a one meter length of the wire carrying current I1, Fx(1), is equal to -2.7 x 10-7 N. The y-component of the force exerted on a one meter length of the wire carrying current I1, Fy(1), is equal to zero. The x-component of the force exerted on a one meter length of the wire carrying current I2, Fx(2), is equal to 0.4 x 10-7 N.
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