A horizontal compression is identified by a factor inside the function, affecting the input variable, while a vertical compression is identified by a factor outside the function, affecting the output variable.
When examining the formula of a function that is the result of multiple transformations, a horizontal compression can be identified by a factor that appears inside the function, affecting the input variable (typically x). For example, if the original function is f(x) and the horizontal compression is by a factor of 2, the function would be written as f(x/2), indicating that the input values are being compressed horizontally.
On the other hand, vertical compression can be identified by a factor that appears outside the function, affecting the output variable (typically y). For example, if the original function is f(x) and the vertical compression is by a factor of 1/2, the function would be written as (1/2)f(x), indicating that the output values are being compressed vertically.
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For the circle with equation (x-2)² + (y+3)² = 9, what are the center coordinates?
Answer:
[tex]\large\boxed{(2, -3)}[/tex]
Step-by-step explanation:
[tex]\textsf{We are asked for the Center Coordinates given a circle.}[/tex]
[tex]\large\underline{\textsf{What is a Circle?}}[/tex]
[tex]\textsf{A Circle is a curved shape that is commonly used to present a equidistant (same}[/tex]
[tex]\textsf{distance apart) from a Center point.}[/tex]
[tex]\textsf{When we create an equation for a circle, we should keep in mind of what the}[/tex]
[tex]\textsf{coordinates of the center point are, and the Radius. For this problem an equation}[/tex]
[tex]\textsf{has been given to us.}[/tex]
[tex]\boxed{\begin{minipage}{20 em} \\ \underline{\textsf{\large Equation of a Circle (Standard Form);}} \\ \\ \tt \tt (x-h)^{2} + (\tt y-k)^{2} = r^{2} \\ \\ \underline{\textsf{\large Where;}} \\ \textsf{h represents the x-coordinate of the center.} \\ \textsf{k represents the y-coordinate of the center.} \\ \tt r^{2} \ \textsf{represents the radius of a circle squared.} \end{minipage}}[/tex]
[tex]\textsf{*Note that if we are given the formula, the radius is already squared, unless}[/tex]
[tex]\textsf{specified in the directions.}[/tex]
[tex]\tt (x-2)^{2} + (y+3)^{2} = 9[/tex]
[tex]\textsf{Our main focus should be h and k. Notice how both point values are negative.}[/tex]
[tex]\textsf{The Center Point is represented as the opposite given to us in the formula.}[/tex]
[tex]\underline{\textsf{Find the Opposite of -2 and 3;}}[/tex]
[tex]\tt -2 \rightarrow \boxed{2}[/tex]
[tex]3 \rightarrow \boxed{-3}[/tex]
[tex]\underline{\textsf{Center Coordinates;}}[/tex]
[tex]\large\boxed{(2, -3)}[/tex]
Reflect triangle ABC over the line y = 2. Translate the image by the directed line segment from (0,0) to (3,2). What are the coordinates of the vertices in the final image?
The coordinates of the triangle's image in the question serve as an example of transformation and are A(-2,4), B (-3,7), and C (0,6).
The triangle's coordinates are as follows:
(-6,-1), (-5,2) and (-3,0) (-3,0)
The new points are created when the triangle is mirrored over the line y = 2.
(-6,5), (-5,2) and (-3,4) (-3,4)
Then, we use the translation to translate the triangle's picture.
(x,y) -> (x + 3, y +2)
We thus have:
(-6,5) => (-6 + 3, 5 + 2) = (-3,7) (-3,7)
(-5,2) => (-5 + 3, 2 + 2) = (-2,4) (-2,4)
(-3,4) => (-3 + 3, 4 + 2) = (0,6) (0,6)
Hence, the triangle's image's coordinates are A(-2,4), B (-3,7), and C (0,6) respectively.
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Find the value of $x$ . Two segments start at a point outside the circle intersect the circle at two points that divide the segments. The length of the first segment is 45 units and length of the segment outside the circle is labeled x. The length of second segment is 50 units and length of the segment outside the circle is 27 units. $x\ =\ $
The value of x is 29.5 units. Since the segments inside the circle have the same length, we can set 52.5 - x = 23 and get the value of x.
What is radius?It is half of the diameter of the circle. The radius is used to calculate the area of a circle and the length of an arc or a circular sector.
In order to find the value of x, we need to first determine the radius of the circle.
In this problem, the first shorter side is 45 units, and the second shorter side is 27 units. Thus, we can find the radius of the circle by using the following method,
Radius of the circle = √(45² + 27²)
= √(2754) = 52.5 units
Now that we know the radius of the circle, we can use this information to find the value of x. We know that the total length of the first segment is 52.5 units. This means that the length of the segment outside the circle is x units and the length of the segment inside the circle is 52.5 - x units.
Similarly, the total length of the second segment is 50 units, so the length of the segment outside the circle is 27 units and the length of the segment inside the circle is
50 - 27 = 23 units.
Since the segments inside the circle have the same length, we can set 52.5 - x = 23 and solve for x.
52.5 - x = 23
x = 52.5 - 23
x = 29.5 units
Therefore, the value of x is 29.5 units.
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the following table contains figures on the monthly volume and unit costs for a random sample of 16 items from a list of 2,000 inventory items. the company classifies products with annual dollar volume of $10,000 or more as a items and products with annual dollar volume of $2,000 or less as c items. a) develop an abc classification for these items. a file labeled abc data.csv is available on t-learn. b) what is the percentage of items stocked in each classification group?
A: 75% of items are classified as C items, 18.75% as B items, and 6.25% as A items.
A-B-C examination is an instrument utilized for stock administration, which orders things into three classifications: A, B, and C, in light of their worth and significance. Classification A things have a high worth however a low volume, and their administration requires close consideration and control. Class B things have moderate worth and volume and require moderate control. Classification C things have a low worth yet a high volume, and their administration can be loose. The reason for the examination is to recognize which things need the most consideration and control, and which things can be dealt with less consideration and cost-actually. The examination assists in streamlining with reviewing levels, decreasing expenses, and expanding benefits.
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A builder was building a fence. In the morning, he worked for 25 of an hour. In the afternoon, he worked for 910 of an hour. How many times as long as in the morning did he work in the afternoon?
Write a division equation to represent this situation, then answer the question. Use "?" to represent the unknown quantity. Do not use parentheses in your equation.
Answer:
36.4
Step-by-step explanation:
In morning, builder worked for = 25 in a hour.
Let hour be ? hr.
then 25? = Time he worked in morning.
In afternoon,he worked for= 910 of ? hour = 910? hr
Times he worked more = 910?/25? = 36.4 times
25*6 =
An eyeglasses store is checking their inventory. The table shows the relationship between the number of days since the opening of the eyeglasses store and the total amount of sunglasses in their inventory.
Sunglasses Inventory:
Number of Days | Total Amount of Sunglasses
______
2 | 52
5 | 46
7 | 42
10 | 36
______
Which graph shows the relationship given in the table?
A) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 52 through the point 1
comma 50
B) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 56 through the point 1 comma
54
C) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 52 through the point 1
comma 49
D) graph with the x axis labeled number of days and the y axis labeled total amount
of sunglasses and a line going from the point 0 comma 56 through the point 1
comma 53
Therefore, the correct option is C). graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 52 through the point (1,49).
What is graph?mathematics, a graph is a data structure that represents a collection of vertices (also known as nodes) and edges between them.
A graph can be used to represent a wide range of real-world systems, such as social networks, transportation networks, and electrical circuits.
In a graph, vertices are usually represented as points or circles, and edges are represented as lines or arrows that connect pairs of vertices. Each edge can be directed (pointing from one vertex to another) or undirected (connecting two vertices without any specific direction).
Graphs can be classified in many ways, such as by their density (the ratio of edges to vertices), their connectivity (how many separate components the graph has), and their degree distribution (the distribution of the number of edges connected to each vertex). Graph theory, which is the study of graphs, has many practical applications in computer science, mathematics, and other fields.
Which graph shows the relationship given in the table?
A) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 52 through the point 1 comma 50.
B) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 56 through the point (1,54)
C) graph with the x axis labeled number of days and the y axis labeled total amount of
sunglasses and a line going from the point 0 comma 52 through the point (1,49)
D) graph with the x axis labeled number of days and the y axis labeled total amount
of sunglasses and a line going from the point 0 comma 56 through the point (1,53)
Based on the given data in the table, the inventory of sunglasses decreases as the number of days since the opening of the eyeglasses store increases. This suggests a negative correlation between the two variables.
To visualize this relationship, we can plot the data points on a scatter plot and draw a line of best fit. Based on the options provided, the closest graph to the relationship given in the table is option C) with the x-axis labeled as number of days, the y-axis labeled as the total amount of sunglasses, and a line going from the point 0,52 through the point 1,49.
Option A) has a decreasing trend, but the line does not pass through all the given data points.
Option B) has a similar decreasing trend, but the values on the y-axis are higher than those in the table.
Option D) has a decreasing trend, but the values on the y-axis are higher than those in the table, and the line does not pass through all the given data points.
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ANSWER QUICK ILL GIVE BRAINLIEST
(1.) What is the height of the cannon before it is launched, at t=0? Remember to include units.
(2.) A projectile's maximum height is shown by the vertex of the parabola. When does the cannonball reach its maximum height? Round to the nearest whole number and remember to include units.
(3.) What is the maximum height of the cannonball? Round to the nearest whole number and remember to include units.
(4.) How long does it take the cannonball to land on the ground? Round your answer to the nearest whole number and remember to include your units.
(5.) What would the equation be if the initial velocity was changed to 40.5 m/s but the initial height stays the same?
1. The cannonball is at 70 meters before it is launched.
2. The cannonball reaches its maximum height at about 3 seconds.
3. The maximum height of the cannonball is about 115 meters.
4. It takes about 8 seconds for the cannonball to reach the ground.
I don't know the answer to number 5 - sorry :(
I hope the rest are correct
need help asap thank youuu
Answer:
11/3
Step-by-step explanation:
2[tex]\frac{1}{5}[/tex] = 11/5
2[tex]\frac{1}{5}[/tex] ÷ [tex]\frac{3}{5}[/tex] = 11/5 · 5/3 = 55/15 = 11/3
f(x)=2x^5−x^4+4x^3−3x^2−31x−5
. Find f(−3/2)
.
Answer:
f(-3/2) = -411/16.
Since spring started, Kareem has been surveying the growth of leaves on his neighborhood trees. He goes out every day and computes the average number of leaves on a sample of trees. He created a scatter plot where the y-axis represents the average number of leaves on the trees, and the x-axis represents the number of weeks since spring started.
Use the 2 given points to write a linear equation that can be used to approximate the data distribution.
A
y = 1566.67x + 1716.67
B
y = 4700x + 1500
C
y = 3x + 2000
D
y = x + 1700
Based on the equation you created, what would be the expected average number of leaves on a tree 8 weeks after spring has started?
Answer:
a
Step-by-step explanation:
A tree should therefore have 38,900 leaves on average by the eighth week of spring.
what is linear equation ?An equation that depicts a linear model on a graph is referred to as a linear equation. This polynomial equation has a factor whose greatest power is one. The formula for a linear equation is y = mx + b, were x and y are factors, m is the line's gradient or slope, and b is the y-intercept, or the place where the line crosses the y-axis. The line's steepness is determined by its slope, and its point of intersection with the y-axis is indicated by its y-intercept. Science and mathematics both frequently model and examine relationships between variables using linear equations.
given
B is the right response for the linear equation y = 4700x + 1500, which can be used to approximate the data distribution.
We may enter x = 8 into the calculation to get the predicted average number of leaves on a tree 8 weeks after spring has begun:
y = 4700(8) + 1500
y = 38,900
A tree should therefore have 38,900 leaves on average by the eighth week of spring.
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PLS HELP! (I need to finish this today because it was due yesterday!)
Answer:
Step-by-step explanation:
Search up the area of both. rectangle is LxW therefore the area is 18. the other is trapezium therefore, ((a+b)xh)/2 therefore the area is 20. trapezium has larger area
Answer trapezoid has greater area
Step-by-step explanation: rec: 6*3= 8, trapezoid [ (6+2) * 5 ]1/2 = 20
suppose 56% of the population are more than 6 feet tall. if a random sample of size 643 is selected, what is the probability that the proportion of persons more than 6 feet tall will differ from the population proportion by more than 5% ? round your answer to four decimal places.
The probability that the proportion of persons more than 6 feet tall will differ from the population proportion by more than 5% is approximately 0.0456.
The standard error of the sample proportion is:
SE = √[(p × (1 - p)) / n]
where p is the population proportion, and n is the sample size.
Substituting the given values, we get:
SE = √[(0.56 × 0.44) / 643] ≈ 0.025
To find the probability that the sample proportion differs from the population proportion by more than 5%, we need to find the z-scores for the upper and lower bounds of the interval:
Lower bound: 0.56 - 0.05 = 0.51
Upper bound: 0.56 + 0.05 = 0.61
z_lower = (0.51 - 0.56) / 0.025 ≈ -2.00
z_upper = (0.61 - 0.56) / 0.025 ≈ 2.00
Using a standard normal distribution table or calculator, we can find the probabilities for these z-scores:
P(Z < -2.00) ≈ 0.0228
P(Z > 2.00) ≈ 0.0228
The probability that the sample proportion differs from the population proportion by more than 5% is the sum of these two probabilities:
P(|p - 0.56| > 0.05) = P(Z < -2.00) + P(Z > 2.00) ≈ 0.0456
Therefore, the probability that the proportion of persons more than 6 feet tall in a random sample of size 643 will differ from the population proportion by more than 5% is approximately 0.0456, rounded to four decimal places.
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Tamika got a raise in her hourly pay from 15.50 to 17.75 find the percent increase
Answer:
Step-by-step explanation:
14.516129%
5. From a stack of 100 paper plates,
42 were used at a picnic. What
portion of the paper plates were
used?
Step-by-step explanation:
42/100 = 21/50 about 42%
There are 78 Year 9 pupils in a music club, out of a total of 167 pupils.
Write this proportion as a percentage.
Give your answer correct to 1 decimal place when appropriate.
The proportion of Year 9 pupils in the music club is approximately 46.7%.
A ratio or value that may be stated as a fraction of 100 is called a percentage.
To find the proportion of Year 9 pupils in the music club as a percentage, follow these steps:
To get proportion as a percentage divied number of Year 9 pupils by total pupils multiplied by 100.
Proportion as a percentage = [tex]\frac{Year \:9 \:pupils}{total \:pupils} \times 100[/tex]
Divide the number of Year 9 pupils by the total number of pupils.
78 (Year 9 pupils) ÷ 167 (total pupils)
= 0.4671
Multiply the result by 100 to convert the proportion to a percentage.
0.4671 × 100
= 46.71%.
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Two geometric progressions have equal sums to infinity. Their first terms are 25 and 40 respectively. if the common ratio of the first is 1/2 what is the common ratio of the second point?
The common ratio of the second geometric progression is 1/5.
What is Geometric Progression?A geometric progression or a geometric sequence is the sequence, in which each term is varied by another by a common ratio. The next term of the sequence is produced when we multiply a constant (which is non-zero) to the preceding term. It is represented by:
a, ar, ar2, ar3, ar4, and so on.
Equation:Let the common ratio of the second geometric progression be r. Then the sum to infinity of the first progression is:
S1 = a1/(1 - r1), where a1 = 25 and r1 = 1/2
And the sum to infinity of the second progression is:
S2 = a2/(1 - r), where a2 = 40 and r is the common ratio of the second progression
We know that S1 = S2, so we can set the two expressions equal to each other:
S1 = S2
a1/(1 - r1) = a2/(1 - r)
Substituting the given values:
25/(1 - 1/2) = 40/(1 - r)
Simplifying:
50 = 40/(1 - r)
Multiplying both sides by (1 - r):
50 - 50r = 40
Subtracting 50 from both sides:
-50r = -10
Dividing both sides by -50:
r = 1/5
Therefore, the common ratio of the second geometric progression is 1/5.
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solve the equation
1. 4x^2-4x-24=0
2. 3p^2-5p-28=0
A new social media site is increasing its user base by approximately 3% per month. If the site currently has 37,030 users, what will the approximate user base be 7 months from now?
In exponential function , after 7 moths approximate user is 45542.
What is exponential function?
A mathematical function called an exponential function is employed frequently in everyday life. It is mostly used to compute investments, model populations, determine exponential decline or exponential growth, and so forth.
Here Number of current used = 37,030.
A new social media site is increasing its user base by approximately 3% per month then after 7 month,
Using exponential growth formula then,
=> f(x)=a([tex]1+r)^x[/tex]
=> 37030(1+3%[tex])^7[/tex]
=> 37030[tex](1+\frac{3}{100})^7[/tex]
=> 37030[tex](1+0.03)^7[/tex]
=> 37030[tex](1.03)^7[/tex]
=> 45542
Hence in 7 moths approximate user is 45542.
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Help!! Brandon wants to cut 12 pieces of old rubber in the size shown to make a patio mat. How much rubber will Brandon need for 12triangukar pieces?
Step-by-step explanation:
The area of a right triangle like this is area = 1/2 * base * height
base and height are the LEGS of the right triangle
this one pictured piece area is: 1/2 * 14 in * 11 in = 77 in^2
He needs 12 of them ....so total is then 12 * 77 in^2 = 924 in^2 needed
acellus algebra 2. piece wised functions.
find f(-2) for the piece wised function
[tex]f(-2) = -4[/tex] for the given piecewise function by using the equation [tex]f(x) = x - 2[/tex] if [tex]x < 3.[/tex]
What is the piecewise function?A piecewise function is a mathematical function that is defined differently on different parts of its domain.
Instead of having a single formula that applies to the entire domain, a piecewise function has multiple formulas, each applying to a specific interval or subset of the domain.
To find f(-2) for the given piecewise function, we need to determine which piece applies to the input value o [tex]f -2[/tex], which is less than 3. Therefore, we use the first piece of the function, which is[tex]f(x) = x - 2 if x < 3.[/tex]
Substituting x = -2 into this piece, we get:
[tex]f(-2) = (-2) - 2 = -4[/tex]
Therefore, f(-2) = -4 for the given piecewise function.
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There are c counters in a box
11 of the counters are green
Benedict takes out 20 counters at random from the box
4 of these counters are green
Work out an estimate for the value of c
Answer:
The answer to your problem is, There are total 55 counters out of which 11 are green and 44 are other color.
Step-by-step explanation:
This is a ratio and proportion question. There are c amount of counters in the box
same ratio as in the box
Green : total
4: 20
11: x
Use cross product rule
x * 4= 20 *11
x= 20*11/4
x= 55. Which is the answer.
So there are total 55 counters out of which 11 are green and 44 are other color. Benedict take 20 counters out of which 4 are green.
Thus the answer to your problem is, There are total 55 counters out of which 11 are green and 44 are other color.
unit 7 test polygons and quadrilaterals
3. The measure of angle S in the given pentagon is 155.33 degrees. 4. The value of x is 9. 5. The value of x is 40 degrees. 6. The value of angle C is 33 degrees. 7. The polygon has 30 sides.
What is pentagon?A polygon having 5 sides and 5 angles is called a pentagon. Two terms, Penta and Gonia, both of which denote five angles, combine to form the word "pentagon." End to end, the sides of a pentagon come together to form a shape. Every side of a regular pentagon has the same length, and its five angles are all the same size. A pentagon is said to as irregular if its side length and angle measurement are not equal.
The sum of angles of a pentagon is equal to 540 degrees.
Thus,
5x + 2 + 10x - 3 + 8x - 19 + 13x - 31 + 7x - 11 = 540
42x - 62 = 540
42x = 602
x = 14.33
The angle of s is:
13(x) - 31 = 13(14.33) - 31 = 155.33
Hence, the measure of angle S in the given pentagon is 155.33 degrees.
4. In a regular hexagon, each angle is equal, and the sum of all the angles is equal to 720 degrees.
6A = 720
A = 120
11x + 21 = 120
x = 9
5. The angle of a nonagon is 140 degrees.
Now, 140 + x = 180
x = 80 degrees.
6. For the given triangle we have:
exterior angle of C = D + E
Substituting the value of D and E as:
7x - 2 = 180 - 9x + 31 + 180 - 4x + 33
7x - 2 = 360 - 13x + 64
20x = 426
x = 21.3
Angle C = 180- (7(21.3) - 2) = 33 degrees.
7. single angle = (n-2) x 180 / n
168n = (n - 2) 180
168n = 180n - 360
360 = 12n
n = 30
The polygon has 30 sides.
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What are the coordinates of point P on the directed line
segment from R to Q such that P is the length of the
line segment from R to Q? Round to the nearest tenth,
if necessary.
Hence, point P's coordinates are (6, 3) as the midpoint of the line segment from R to Q, which is the precise halfway point between R and Q.
what is coordinates ?A point's location on a line or in space can be determined using a set of numbers called coordinates. An x-coordinate and a como, which denote the horizontal as well as vertical ranges from a bench mark known as the origin, are the two numbers that make up coordinates in two-dimensional space. Three numbers, the x, y, and z coordinates, which describe the distances from origin in the x, y, and g directions, respectively, might make up coordinates in three-dimensional space. Among other disciplines, coordinates are frequently employed in physics, arithmetic, and geometry.
given
The midpoint of the line segment from R to Q, which is the precise halfway point between R and Q, must be located in order to determine the coordinates of point P.
We can separately aver the x- and y-coordinates to get the middle.
The midpoint's x-coordinate is (4 + 8)/2, which equals 6.
(0 + 6)/2 = 3 is the midpoint's y-coordinate.
Hence, point P's coordinates are (6, 3) as the midpoint of the line segment from R to Q, which is the precise halfway point between R and Q.
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Answer:
(-3.5 , 2.3)
Step-by-step explanation:
I know
a chinese restaurant has a large goldfish pond. suppose that an inlet pipe and a hose together can fill the pond in hours. the inlet pipe alone can complete the job in one hour less time than the hose alone. find the time that the hose can complete the job alone and the time that the inlet pipe can complete the job alone.
So, the hose can complete the job alone in approximately 2.62 hours, and the inlet pipe can complete the job alone in approximately 1.62 hours.
Let the time it takes for the hose alone to fill the pond be H hours, and the time it takes for the inlet pipe alone be P hours. According to the given information:
1) P = H - 1 (The inlet pipe alone can complete the job in one hour less time than the hose alone)
2) In one hour, the hose fills 1/H of the pond, and the inlet pipe fills 1/P of the pond. Together, they can fill the pond in one hour, so: (1/H) + (1/P) = 1
Now, substitute the value of P from equation 1 into equation 2:
(1/H) + (1/(H-1)) = 1
To solve for H, first find a common denominator (H*(H-1)):
(H-1) + H = H*(H-1)
Combine the terms on the left:
2H - 1 = H^2 - H
Rearrange to form a quadratic equation:
H^2 - 3H + 1 = 0
Now, solve the quadratic equation using the quadratic formula:
[tex]H = (3 + sqrt(5))/2 or H = (3 - sqrt(5))/2[/tex]
However, since H > 0, the only valid solution is H = (3 + sqrt(5))/2 ≈ 2.62 hours.
Now, find the time it takes for the inlet pipe alone to complete the job:
P = H - 1 = 2.62 - 1 = 1.62 hours
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increase 15/16 by 3/4 of it. then increase the result by 3/5 of it
Increasing [tex]\frac{15}{16}[/tex] by [tex]\frac{3}{4}[/tex] of it and then increasing the result by [tex]\frac{3}{5}[/tex] of it gives us the fraction of [tex]\frac{45}{32}[/tex].
To increase [tex]\frac{15}{16}[/tex] by [tex]\frac{3}{4}[/tex] of it, we can multiply [tex]\frac{15}{16}[/tex] by [tex]\frac{3}{4}[/tex], which gives us:
[tex]\frac{15}{16}[/tex] × [tex]\frac{3}{4}[/tex] = [tex]\frac{45}{64}[/tex]
Adding this result to [tex]\frac{15}{16}[/tex], we get:
[tex]\frac{15}{16}[/tex] + [tex]\frac{45}{64}[/tex] = [tex]\frac{225}{256}[/tex]
Now, to increase this result by [tex]\frac{3}{5}[/tex] of it, we can multiply [tex]\frac{225}{256}[/tex] by 3/5, which gives us:
[tex]\frac{225}{256}[/tex] × [tex]\frac{3}{5}[/tex] = [tex]\frac{135}{256}[/tex]
Adding this result to [tex]\frac{225}{256}[/tex], we get the final answer:
[tex]\frac{225}{256}[/tex] + [tex]\frac{135}{256}[/tex] = [tex]\frac{360}{256}[/tex]
Simplifying this fraction, we get:
[tex]\frac{360}{256}[/tex] = [tex]\frac{45}{32}[/tex]
The problem involves increasing a fraction by a certain percentage twice. To solve the problem, we first find the increase in the fraction by multiplying it with the given percentage. We then add the result to the original fraction to get the new fraction. This process is repeated for the second increase. Finally, we simplify the resulting fraction if possible. In this specific problem, we are increasing [tex]\frac{15}{16}[/tex] by [tex]\frac{3}{4}[/tex] of it and then increasing the result by [tex]\frac{3}{5}[/tex] of it to find the resulting fraction [tex]\frac{45}{32}[/tex].
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Solve using substitution.
y = 5x - 9
y = -2x + 5
Answer:
(2,1) (2,1)
1=5(2)-9 1=-2(2)+5
1=10-9 1=-4+5
Step-by-step explanation:
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Find the surface area of the following figure by approximating pi as 3.14.
a. 314 in2
b. 315 in2
c. 316 in2
d. 317 in2
e. 318 in2
Answer:
A
Step-by-step explanation:
Given:
r (radius) = 5 in
h (height) = 5 in
Find: A (surface area) - ?
.
[tex]a(surface) = a(lateral) + a(2 \: bases)[/tex]
First, we have to find the lateral surface:
[tex]a(lateral) = 2\pi \times r \times h = 2 \times 3.14 \times 5 \times 5 = 157 \: {in}^{2} [/tex]
Then, we have to find the area of the base and multiply it by 2, since the shown figure is a cylinder, which has 2 identical bases:
[tex]a(2 \: bases) = 2 \times \pi {r}^{2} = 2 \times 3.14 \times {5}^{2} = 157 \: {in}^{2} [/tex]
Now, let's add everything together and we'll get the answer:
[tex]a(surface) = 157 + 157 = 314 \: {in}^{2} [/tex]
For the circle with equation (x-2)^2 + (y+3)^2 = 9, what is the radius?
Answer:
The equation of the given circle is (x-2)^2 + (y+3)^2 = 9, which is in the standard form of a circle: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.
Comparing the given equation with the standard form, we can see that the center of the circle is (2, -3) and the radius is 3.
Therefore, the radius of the circle is 3 units.
PART A: A can of cat food measures 1" tall and a diameter of 3.5". What is the volume of cat food in the can? To solve Give your answer in cubic inches. Round to the nearest hundredth.
PART B: Cat food is sold by ounces (weight).
If the can holds 5.8 ounces, write a ratio to show cubic inches (your answer from slide 3) to ounces.
Part A:The volume of cat food in the can is approximately 9.62 cubic inches.
Part B:The ratio of cubic inches to ounces is approximately 1.66:1.
What is volume?Volume is a measure of the amount of space occupied by an object or a substance. It is the quantity of three-dimensional space enclosed by a closed surface or bounded by a given set of points. Volume is typically measured in cubic units, such as cubic meters (m³) or cubic centimeters (cm³).
PART A:
The volume of a cylinder can be calculated using the formula V = πr²h, where V is the volume, r is the radius, and h is the height. Since the diameter of the can is 3.5 inches, the radius is half of that, or 1.75 inches. The height of the can is 1 inch.
Plugging these values into the formula, we get:
V = π(1.75)²(1)
V ≈ 9.62 cubic inches
Therefore, the volume of cat food in the can is approximately 9.62 cubic inches.
PART B:
To write a ratio of cubic inches to ounces, we need to divide the volume of the can (in cubic inches) by the weight of the cat food (in ounces):
Ratio = Volume of cat food in can (cubic inches) / Weight of cat food (ounces)
Ratio = 9.62 cubic inches / 5.8 ounces
Ratio ≈ 1.66 cubic inches per ounce
Therefore, the ratio of cubic inches to ounces is approximately 1.66:1.
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Question 6(Multiple Choice Worth 1 points) (05.05 LC) Which of the following inequalities matches the graph? Ox≤5 0x25 Oy≤5 Oy25 -6-4 4 6 8 10 ▷
The corresponding inequality for this graph is
0 <= x <= 5
What is inequality?An inequality is a statement that two values are not necessarily equal. In other words, it expresses a relation between two quantities that can be either less than, greater than, less than or equal to, or greater than or equal to each other. Inequalities are typically written using symbols such as "<" (less than), ">" (greater than), "≤" (less than or equal to), and "≥" (greater than or equal to).
The graph represents a shaded rectangle with sides on the x and y axes, and with one corner at the origin (0,0). The top-right corner of the rectangle is at the point (5,5), and the sides of the rectangle are parallel to the axes.
The corresponding inequality for this graph is 0 <= x <= 5, which can be read as "x is greater than or equal to 0 and less than or equal to 5".
Therefore, the correct answer is:
0 <= x <= 5
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The complete question is:
Which of the following inequalities matches the graph?
Ox≤5
0<=x<=5