Step-by-step explanation:
Check the attached photo out
Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given the number of pairs of data n and the significance level α.
n = 40, α = 0.01
r = 0.402
r = ±0.312
r = 0.43
r = ±0.402
Answer:
r= 0.402
Step-by-step explanation:
X Find the length and width of a rectangle whose width is 10 cm shorter
than its length and whose area is 200 cm squared. What is the SUM of
the length and width?
Answer:30
Step-by-step explanation: length is 20, Width is 20-10 =10
Area = 20×10=200
A regular decagon has a radius of 8 cm. what is the approximate area of the decagon? recall that a decagon is a polygon with 10 sides.
The approximate area of the decagon with a side of 8cm is 492.37 cm².
Given side of the regular decagon = 8cm
What is a regular decagon?A decagon is a polygon with 10 equal sides.
We know that area of a regular decagon with side a is given by:
[tex]A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }[/tex]
So, the area A of the regular decagon with a side of 8cm=[tex]\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }[/tex]
[tex]A=160\sqrt{5+2\sqrt{5} }[/tex]
A=492.37 cm²
Therefore, the approximate area of the decagon is 492.37 cm².
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A rectangular tarp is 2 times as long as it is
wide. Its width is 8 yards. What is the area
of the tarp?
24 sq. yards
hope it helps...!!!
HELP HEELP
The diagram shows a cone of height 8 units and base radius 6 units.
What is the surface area of its side?
Answer:
Option A :- if finding lateral surface area
Other information
radius r = 6 m
height h = 8 m
slant height s = 10 m
volume V = 301.592895 m3
lateral surface area L = 188.495559 m2
base surface area B = 113.097336 m2
total surface area A = 301.592895 m2
Step-by-step explanation:
Using the formulas
A=πrl+πr²
l=√r²+h²
Solving forA
A=πr(r+√h²+r²)=π · 6 · (6+√8²+6²)≈301.59289
Please, help me. anyone?
What is the value of loge 36?
O
-6
-2
2
6
Answer:
B) -2
Step-by-step explanation:
[tex]log_{6} \frac{1}{36}[/tex] ORIGINAL
[tex]log_{6} 6^{-2}[/tex] REWRITE 1/36
-2 LOG RULE - 6's CANCEL
Hope this helsp!
Solve for x
3(3x-2)=39
Answer:
3(3x-2)=39
9x-6=39
9x=39-6
9x=33
x=33/9
x=11/3
Answer:
x=5
Step-by-step explanation:
First, distribute the left side. 3(3x-2)=39 3 x 3x=9x 3 x -2=-6 m So, we get 9x-6=39
Next, we add six to both sides. We get 9x=45.
Lastly , we divide both sides by 9 and get x=5.
Plug x=5 into the place where x is to check your work. 3(3(5) - 2)=39
3(15-2)=39 3(13)=39 39=39 Since 39 is equal to 39, the equation is true.
Answer number 7 please thank you
Answer:
[tex] \frac{25}{100} \times 1.20[/tex]
A railroad crew can replace 360 meters of rails in 6 days. How many kilometers of rail can they repair in 25days
The railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days
What is a fraction?Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
We have:
A railroad crew can replace 360 meters of rails in 6 days.
Let's suppose the x kilometers of rail they can repair in 25v days
Per day they repair = 360/6 = 60 km/day
Then the x can be found:
x = 60×25
x = 1500 km
Thus, the railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days.
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Alice was sitting on a dock looking at a lake. She picked up a stone and through it in the air and out
toward the lake. It seemed like it was in the air for a long time. The equation that can be used to
model the height of the stone (in feet) as it relates to the time in the air in seconds) is given by
h(t) = 5 + 50 - 16t2. In order to solve for how long the stone was in the air, Alice will need to use the
quadratic equation which is:
|-bb4ac
2a
X
A quadratic equation is in the form of ax²+bx+c. The time for which the stone was in the air is 3.526.
What is a quadratic equation?A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.
It is written in the form of ax²+bx+c.
As the height of the stone will be zero or can say that the stone will be at the ground in only two conditions. When the stone will be just thrown and when the stone will complete its flight. Therefore, we can substitute the value of heigh h in the function as 0 to get those two timings.
[tex]h(t) = 5 + 50t - 16t^2\\\\0 = 5+50t - 16t^2[/tex]
Substitute the quadratic equation in the formula of the root of the quadratic function,
[tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-50\pm\sqrt{(50)^2-4(-16)(5)}}{2(-16)}\\\\t= -0.089, 3.526[/tex]
Hence, the time for which the stone was in the air is 3.526.
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The area of a trapezoid is 260 cm2. If the bases have lengths of 12 and 14, what is the height?
a 10
b 15
c 20
d 13
three and seven ninths multiplied by five.
Answer:
22
Step-by-step explanation:
Answer:
18 8/9
Step-by-step explanation:
3 7/9 =[ (3*9) + 7] / 9
= 34/9
So we have 5 * 34/9
= 170/9
= 18 8/9.
Enter and solve an equation to find the complement of an angle that measures 38º.
Use x as your variable.
An equation is
The measure of x is
Answer:
52°
Step-by-step explanation:
The sum of an angle and its complement is 90°.
__
The sum of 38° and its complement, x, is 90°:
38 +x = 90 . . . . . an equation to find the complement of 38°
x = 90 -38 . . . . subtract 38 from both sides
x = 52 . . . . degrees
The measure of x is 52°.
Write the expression 6
7
12
in radical form.
To write the expression [tex]6 \frac{7}{12}[/tex] in radical form.
To express the radical form in simplest it just means simplifying the radical so that there are further no more square root, cube root etc.
Use the rule:
[tex]a\frac{x}{y}[/tex] = [tex]\sqrt[y]{a^{2} }[/tex]
Apply this rule on the the given expression:
[tex]6\frac{7}{12} = \sqrt[12]{6^{7} }[/tex]
Therefore, the expression in radical form is [tex]\sqrt[12]{6^{7} }[/tex]
The manager of a restaurant chain wants to know how many times per month diners come to his restaurant. The table shows the number of visits in one month for three samples of 10 randomly chosen diners.
A table with three rows. Title. Text that reads: Number of visits to restaurant in one month. Row one. Text that reads: Sample 1. 5, 2, 6, 4, 4, 7, 2, 1, 2, 3. Total = 36. Row two. Text that reads: Sample 2. 2, 6, 1, 3, 4, 5, 2, 1, 5, 4. Total = 33. Row three. Text that reads: sample 3. 3, 3, 6, 4, 1, 5, 3, 4, 4, 5.
Answer the questions to find the means, compare the samples, and make a prediction.
1. What are the means of Samples 1 and 2? Show your work. (3 points)
2. What is the mean of Sample 3? Show your work. (3 points)
3. Based on the data, would you predict that, in one month, the average diner would visit the restaurant fewer than 3 times, 3 or 4 times, or, about 4 times? Explain your reasoning. (4 points)
The means of samples 1 and 2 is 3.45. The mean of sample 3 is 3.8. Based on the data, the average diner would visit the restaurant 3 or 4 times.
What is the mean of a sample?The mean of a sample is the average of all the data sets given in the sample. The mean of a sample is useful in calculating population averages, central tendency, standard deviation, etc.
Mathematically, the mean of a sample can be expressed as:
[tex]\mathbf{\overline X =\dfrac{sum \ of \ the \ terms }{no \ of \ terms } }[/tex]
[tex]\mathbf{\overline X =\dfrac{\sum X}{N} }[/tex]
The mean of sample 1 is given = 36The mean of sample 2 is given = 33Thus, the means of samples 1 and 2 is:
[tex]\mathbf{\overline X =\dfrac{36+33}{20} }[/tex]
[tex]\mathbf{\overline X =3.45}[/tex]
The mean of sample 3 is:
[tex]\mathbf{\overline X =\dfrac{3+3+6+4+1+5+3+4+4+5}{10} }[/tex]
[tex]\mathbf{\overline X =3.8}[/tex]
Based on the data, the average diner would visit the restaurant 3 or 4 times, because the mean of the samples lies between 3 to 4.
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Write the domain and range of the graph below…
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's see what's the domain and range for the given function ~
[tex]\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ] [/tex]
or
[tex]\qquad \tt \dashrightarrow \: - 5 \leqslant x \leqslant 4[/tex]
Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]
[tex]\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ][/tex]
or
[tex]\qquad \tt \dashrightarrow \: - 4 \leqslant y \leqslant 9[/tex]
Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]
20 POINTS!!!! ill mark brainliest! The hypotenuse of the triangle measures 18, what is the radius of circle A? Is the radius the same all around?
Answer:
The radius is 3 and it is the same all around
Step-by-step explanation:
Since The hypotenuse equals the two other sides squared, let's find out what those are.
[tex]\sqrt{9} + \sqrt{9} = \sqrt{18}[/tex]
Now, let's find the square root of those 9s.
[tex]\sqrt{9} = 3[/tex]
Those other sides we talked about (more specifically the base of the triangle) are the radius of the circle because of how they extend to the exterior of the circle, which means since their length is 3, the radius is also 3.
The radius is always constant so it is supposed to be the same all around.
100 points pls :/ Using the two-way table, what percentage of the students that like to travel out of state do not like camping? Round to the nearest whole percent.
Likes Traveling Out of State Does Not Like Traveling Out of State Row totals
Likes Camping 52 38 90
Does Not Like Camping 36 74 110
Column totals 88 112 200
30%
33%
36%
41%
Answer:
41%
Step-by-step explanation:
step one to determine what the fraction would be you just read the question: first you have to see what they want to calculate the percentage of. In this case it's students who like traveling out of state but don't like camping. 88 students like traveling out of state and 36 of those students don't like camping so the fraction you have to use is 36/88 step two next you multiply your fraction by 100 to calculate your percentage 36/88×100= 40.9% step three since you have to round to the nearest whole percent your answer would be 41%
Is my answer correct?
Answer:
[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]
Step-by-step explanation:
We want to write a rule for the transformation shown.
We can see that ΔA'B'C' is the figure ΔABC shifted rightwards 3 units and upwards 1 unit.
In other words, all x-coordinates of ABC is increased by 3, and all y-coordiantes of ABC is increased by 1.
Therefore, the rule for the x-coordinate is:
[tex]\displaystyle x \longrightarrow x + 3[/tex]
And the rule for the y-coordinate is:
[tex]\displaystyle y \longrightarrow y + 1[/tex]
In conclusion, we have that:
[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]
Thang decided to borrow $5000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of 9%. How much interest will Thang pay?
Answer:
$1350
Step-by-step explanation:
Simple Interest = Deposit ×Rate/100×Time
SI=5000×9/100×3
=$1350
Tammy received a $70 gift card for a coffee store. She used it in buying some coffee that cost $8.41 per pound. After buying the coffee, she had $19.54 left on her card. How many pounds of coffee did she buy?
Total money Tammy has = $70
Money she is left with now = $19.54
Therefore, the money she used on coffee =
70 - 19.54 = $50.46
Now,
1 pound coffee costs $8.41
Pounds of coffee she bought = 50.46 ÷ 8.41
= 6 pounds
1335+0540 what is the answer
Answer:
1875
Step-by-step explanation:
1335 + 0540 = 1875
Answer:
1,875
Step-by-step explanation:
[tex]1335 + 540 = 1,875[/tex]
Hope this helps! : )
Triangles A B C and A D C share common side A C. The lengths of A B and A D are congruent.
Could ΔABC be congruent to ΔADC by SSS? Explain.
Yes, but only if AB ≅ DC.
Yes, but only if BC ≅ DC.
No, because AB is not congruent to AC.
No, because AB ≅ DA.
Answer:
d
Step-by-step explanation:
god a 100 on edg
ΔABC cannot be congruent to ΔADC by SSS?l because D. No, because AB ≅ DA.
How to depict the triangle?It should be noted that when the three corresponding sides of the figures have the same length, it can be concluded that the triangles are congruent by SSS.
In this case, ΔABC cannot be congruent to ΔADC by SSS?l because AB is not equal to DA.
Therefore, the correct option is D.
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42+5t=8t
Solve the equation
WHAT DO I DO????!!!
It costs the same to produce both packages, so the company wants to reduce the amount of wasted space, or space not taken by the balls. which package should the company choose? the cylinder because it has about 27.5 in.3 less wasted space than the prism the cylinder because it has about 61 in.3 less wasted space than the prism the prism because it has about 22.5 in.3 less wasted space than the cylinder the prism because it has about 67 in.3 less wasted space than the cylinder
The package which the company should choose if it costs the same to produce the two products is the cylinder because it has about 27.5 in.3 less wasted space than the prism.
What is the Cost of Production?The term "cost of production" refers to all the costs that are involved when a company offers a service or manufactures a product.
Costs of production relate to the different expenses that a firm faces in producing a good or service.
This refers to the amount which is used to produce a good.
With this in mind, we can see that there are the given dimensions for the square prism and cylinder from the complete question.
Hence, because they cost the same, choosing the cylinder is the best choice because of the less wasted space than the prism.
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Answer:
It's A
Step-by-step explanation:
SYSTEN
REV.
REF. DWG. OR B/M
DATE:
Adrian and Jeremy are running around a track. It takes Adrian 15 minutes to
run around the track one time. It takes Jeremy 18 minutes to run around the
track once. How many minutes would it take for both boys to return to the
starting point at the same time?
How do I solve this?
Using the least common factor, it is found that it would take 90 minutes for both boys to return to the starting point at the same time.
How do we find the least common factor of two amounts?To find the least common factor, we factor the numbers by prime factors, and then multiply these factors.
The lcm represents the periodicy, that is, when two periodic amounts will be at the same value.
In this problem, the periods are of 15 minutes and 18 minutes, hence:
15 - 18|2
15 - 9|3
5 - 3|3
5 - 1|5
1 - 1
Hence:
lcm(15,18) = 2 x 3 x 3 x 5 = 90.
It would take 90 minutes for both boys to return to the starting point at the same time.
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Which rules of exponents will be used to evaluate this expression? select three options. startfraction left-brace (negative 8) superscript 4 baseline right-brace superscript negative 5 baseline over (negative 8) superscript 6 baseline endfraction fractional exponent quotient of powers power of a power power of a product negative exponent zero exponent
The 3 rules that we need to use to simplify the expression are:
Exponent of an exponent rule.Quotient of powers.Negative exponent.Which rule of exponents must we use?
As I understand, the expression that we have is:
[tex]\frac{((-8)^4)^{-5}}{(-8)^6}[/tex]
The first rule we need to use, is the exponent of an exponent rule, it says that:
[tex](a^n)^m = a^{n*m}[/tex]
If we apply that to the denominator, we get:
[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6}[/tex]
Now we need to use the quotient of powers:
[tex]\frac{a^m}{a^n} = a^{m - n}[/tex]
Using that we get:
[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-20 - 6} = (-8)^{-26}[/tex]
Finally, we use the rule for a negative exponent:
[tex]a^{-n} = \frac{1}{a^n}[/tex]
So we get the simplified form:
[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-26} = \frac{1}{(-8)^{26}}[/tex]
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Answer:
B, C, and E
Step-by-step explanation:
Similar Shapes and Scale Drawings
Practice and Problem Solving: C
Compare the process of solving |x – 1| 1 < 15 to that of solving |x – 1| 1 > 15.
The final answer of the solution is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15] and x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R.
What is inequality?Inequality is defined as the relation which makes a non-equal comparison between two given functions.
For |x - 1 | + 1 < 15 , we should first break the modulus function .
Two cases are possible for this inequality ,
case 1 - when x ≥ 1
x - 1 + 1 < 15 ⇒ x < 15
putting the number line both x ≥ 1 and x≤ 15
Then, x∈ [1, 15)
case 2 - when x < 1
-x + 1 + 1 < 15
⇒ -x + 2 < 15
⇒ -x < 13 ⇒ x > -13
putting the number line both x > -13 and x < 1
then, x∈ (-13, 1)
now, answer is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15]
Again, for |x - 1| + 1 > 15
Similarly z there are two cases possible for this
case 1 :- when x ≥ 1
x - 1 + 1 > 15 ⇒ x > 15
Putting the number line both x ≥ 1 and x > 15
then, x ∈ [1, ∞)
case 2 - when x < 1
-x + 1 + 1 > 15 ⇒ x < -13
putting the number line both x < 1 and x < -13
Then, x∈ (-∞, 1)
hence, final answer is x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R
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