Which of the following elements are most likely to have similar chemical properties?

Answer: Temperature

Explanation:

The average kinetic energy of the particles in a gas is proportional to the temperature of the gas. Because the mass of these particles is constant, the particles must move faster as the gas becomes warmer.

"The kinetic energy of an object is the energy that it possesses due to its motion."

"The product of the half of the mass of each gas molecule and the square of RMS speed."

Know more about average kinetic energy here

https://brainly.com/question/1599923

#SPJ2

Answer:engineers developed and improved solutions in response to consumer demand for equal access for people with disabilities.

Explanation:

Apex

Answer:

(assume moving in the positive direction, vi = + 20 m/s)

Explanation:

Answer:

motion repeating itself is referred to as periodic or oscillatory motion. An object in such motion oscillates about an equilibrium position due to a restoring force or torque. ... This motion is important to study many phenomena including electromagnetic waves, alternating current circuits, and molecules.

Explanation:

Answer:

Moves to and from about it's mean position in a fixed time interval.

Answer:

66n

Explanation:

4376

Answer Yes you answered correctly.

Explanation:

Gases, such as the air or helium inside a balloon, take the shape of the containers they're in. They spread out so that the space is filled up evenly with gas molecules. The gas molecules are not connected.

Answer:

Yea ur right

Explanation:

Sounds like the shingle/ball is thrown from the roof horizontally, so that the distance it travels x after time t horizontally is

x = (7.2 m/s) t

The object's height y at time t is

y = 9.4 m - 1/2 gt²

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity, and its vertical velocity is

v = -gt

(a) The object hits the ground when y = 0:

0 = 9.4 m - 1/2 gt²

t² = 2 * (9.4 m) / (9.80 m/s²)

t ≈ 1.92 s

at which time the object's vertical velocity is

v = -g (1.92 s) = -18.8 m/s ≈ -19 m/s

(b) See part (a); it takes the object about 1.9 s to reach the ground.

(c) The object travels a horizontal distance of

x = (7.2 m/s) * (1.92 s) ≈ 13.8 m ≈ 14 m

Answer:

Can't really answer that for now. More context please?

Explanation:

I will answer it in a comment when you give some context.

Answer:

Falling from the Sears Tower

• After 5 seconds, the ball falling from the

Sears Tower will have fallen

distance = ½ • 32 ft/s2 • (5 s)2 = 16 • 25

= 400 feet.

• We can turn the formula around to figure

out how long it would take the ball to fall all

the way to the ground (1450 ft)

Ætime = square root of (2 x distance/g)

Explanation:

Answer:

energy

Explanation:

Energy can't be destroyed or created, just transferred.

Answer:

1, 1583.33 V/m

2, 4.72*10^-12 C

3, 39.2*10^-11 C

Explanation:

1

E = V / d

E = 8.55 / 5.4*10^-3

E = 8.55 / 0.0054

E = 1583.33 V/m

2

Capacitance, C = (k * e0 * A) / d, where k = 1

A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²

d = plate separation, 5.4 mm

e0 = Constant, 8.85*10^-12

Applying these, we have

C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 29.82*10^-16 / 0.0054

C = 5.52*10^-13 F

Since Q = CV, then

Q = 5.52*10^-13 * 8.55

Q = 4.72*10^-12 C

3

We are given that k = 83, so

Capacitance, C = (k * e0 * A) / d

C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 2.475*10^-13 / 0.0054

C = 4.58*10^-11 F

Q = CV

Q = 4.58*10^-11 * 8.55

Q = 39.2*10^-11 C

Answer:

Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.

Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.

Answer:

The 10X objective is use for the identification of actual size of histology tissues and 4X magnification is best for observation of most tissues slides

Explanation:

4X magnification is best for observation of most tissues slides because it has an objective lens that have lower power and have great high field overview which make it very easier to locate specimens on the slide. It is use to get the overview of histology slides. It is use to showcase more detailed observations about histology.

The 40X objective is use majorly to identify tissue , to observe the finer details and study tissue organization on the histology slide.

Answer:

nice cool math and jim jake jr as a baby and just jim jake baby and nice pfp d00d XD

Explanation:

Answer:

5 billion years ago...ends 4.9 billion years later

Answer:

That's correct... you can mark them brainliest now. You have to have both slots answered before you can mark them. So, you're welcome :)

Explanation:

Explanation:

(a) Given:

Δy = 0 m

v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s

aᵧ = -9.8 m/s²

Find: t

Use an equation that doesn't include final velocity, v.

Δy = v₀ᵧ t + ½ aᵧt²

0 m = (16.0 m/s) t + ½ (-9.8 m/s²) t²

0 = 16t − 4.9t²

0 = t (16 − 4.9t)

t = 3.26 s

(b) Given:

v₀ₓ = 20.0 m/s cos 53° = 12.0 m/s

aₓ = 0 m/s²

t = 3.26 s

Find: Δx

Use an equation that doesn't include final velocity, v.

Δx = v₀ₓ t + ½ aₓt²

Δx = (12.0 m/s) (3.26 s) + ½ (0 m/s²) (3.26 s)²

Δx = 39.24 m

(c) Given:

v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s

vᵧ = 0 m/s

aᵧ = -9.8 m/s²

Find: Δy

Use an equation that doesn't include t.

vᵧ² = v₀ᵧ² + 2aᵧ Δy

(0 m/s)² = (16.0 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 13.02 m

Alternatively, use t/2 = 1.63 seconds, and use an equation that doesn't include the final velocity, v.

Δy = v₀ᵧ t + ½ aᵧt²

Δy = (16.0 m/s) (1.63 s) + ½ (-9.8 m/s²) (1.63 s)²

Δy = 13.02 m

Answer:

6) False

7) True

8) False

9) False

10) False

11) True

12) True

13) True

14) True

Explanation:

The spacing between two energy levels in an atom shows the energy difference between them. Clearly, B has a greater value of ∆E compared to A. This implies that the wavelength emitted by B is greater than A while B will emit fewer, more energetic photons.

When atoms jump from lower to higher energy levels, photons are absorbed. The kinetic energy of the incident photon determines the frequency, wavelength and colour of light emitted by the atom.

The energy level to which an atom is excited is determined by the kinetic energy of the incident electron. As the voltage increases, the kinetic energy of the electron increases, the further the atom is from the source of free electrons, the greater the required kinetic energy of free electron. When electrons are excited to higher energy levels, they must return to ground state.

Answer:

29.4m/s

Explanation:

Given.

Time (t) = 3.0s

Required

Determine the final velocity

Since, it's a vertical motion, we make use of the following formula to solve for the final velocity (v).

v = u + gt

Where u = 0, g = 9.8m/s² and t = 3s

v = 0 + 9.8m/s² *3s

v = 0 + 29.4m/s

v = 29.4m/s

Hence, the final velocity is 29.4m/s

Answer:

Height = 1.54 m

Explanation:

Given:

Velocity = 41 m/s

Distance = 23 m

Find:

Height

Computation:

We know that

a = 9.8 m/s²

Time = Distance / Velocity

Time = 23 / 41

Time = 0.56 second

Height = (1/2)(9.8)(0.56)²

Height = 1.54 m

Answer:

a) [tex]\beta = 1.111\times 10^{-7}[/tex], b) [tex]\beta = 9\times 10^{-7}[/tex], c) [tex]\beta = 3.087\times 10^{-6}[/tex], d) [tex]\beta = 2.5\times 10^{-5}[/tex], e) [tex]\beta = 0.5[/tex], f) [tex]\beta = 0.877[/tex]

Explanation:

From relativist physics we know that [tex]c[/tex] is the symbol for the speed of light, which equal to approximately 300000 kilometers per second. (300000000 meters per second).

a) A car traveling 120 kilometers per hour:

At first we convert the car speed into meters per second:

[tex]v = \left(120\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 33.333\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 33.333\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{33.333\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 1.111\times 10^{-7}[/tex]

b) A commercial jet airliner traveling 270 meters per second:

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 270\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{270\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 9\times 10^{-7}[/tex]

c) A supersonic airplane traveling Mach 2.7:

At first we get the speed of the supersonic airplane from Mach's formula:

[tex]v = Ma\cdot v_{s}[/tex]

Where:

[tex]Ma[/tex] - Mach number, dimensionless.

[tex]v_{s}[/tex] - Speed of sound in air, measured in meters per second.

If we know that [tex]Ma = 2.7[/tex] and [tex]v_{s} = 343\,\frac{m}{s}[/tex], then the speed of the supersonic airplane is:

[tex]v = 2.7\cdot \left(343\,\frac{m}{s} \right)[/tex]

[tex]v = 926.1\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 926.1\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{926.1\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 3.087\times 10^{-6}[/tex]

d) The space shuttle, travelling 27000 kilometers per hour:

At first we convert the space shuttle speed into meters per second:

[tex]v = \left(27000\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 7500\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 7500\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{7500\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 2.5\times 10^{-5}[/tex]

e) An electron traveling 30 centimeters in 2 nanoseconds:

If we assume that electron travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 0.3\,m[/tex] and [tex]t = 2\times 10^{-9}\,s[/tex], then speed of the electron is:

[tex]v = \frac{0.3\,m}{2\times 10^{-9}\,s}[/tex]

[tex]v = 1.50\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 1.5\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{1.5\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.5[/tex]

f) A proton traveling across a nucleus (10⁻¹⁴ meters) in 0.38 × 10⁻²² seconds:

If we assume that proton travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 10^{-14}\,m[/tex] and [tex]t = 0.38\times 10^{-22}\,s[/tex], then speed of the electron is:

[tex]v = \frac{10^{-14}\,m}{0.38\times 10^{-22}\,s}[/tex]

[tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{2.632\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.877[/tex]

Answer:

the material

Explanation:

weight is defined as the amount of force on the object because of gravity. ping pong balls and bouncy balls are made out of different materials that are different weights. most bouncy balls are also not hollow, unlike ping pong balls. these factors affect the weight of these objects.

Answer:

ok can u m a e the question make more sense like break ot down cs i wanna give u a answer but i dont really understand the question

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

[tex]U_{g}= m\cdot g\cdot \Delta y[/tex]

Where:

[tex]U_{g}[/tex] - Gravitational potential energy, measured in Joules.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta y[/tex] - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that [tex]m = 0.5\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta y = 0.07\,m[/tex], the change in the potential energy of the mass as it goes up the incline is:

[tex]U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)[/tex]

[tex]U_{g} = 0.343\,J[/tex]

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

The change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

We know that

Potential energy = m*g*h

Here m means the mass = 0.5 kg

g means the gravity = 9.8

And, the h means the height  = 7cm = 0.07m

So, the change in the potential energy should be

=0.5*9.8*0.07

=0.343 J

hence, we can conclude that the  change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

Learn more about energy here: https://brainly.com/question/13203990

Answer:

A hypothesis is what you think will happen.

A conclusion is the results of an experiment summarized.

Hope this helps.

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

Answer:

The cell will have no electromotive force in it.

Explanation:

The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.