Which of the following is the correct equation for the trend line in the scatter plot?

Answer:

[tex] \approx \: 198.1 \: {cm}^{2} [/tex]

Step-by-step explanation:

Given figure consists of a parallelogram and two semicircles with diameters 14 cm and 8 cm

(Opposite sides of a parallelogram are equal in measure and they are the diameters of the semicircles)

Therefore,

Area of the figure = Area of the parallelogram with base 8 cm and height 12 cm + Area of semicircle with radius (14/2 = 7) 7 cm + Area of the semicircle with radius (8/2 =4) 4 cm

[tex] = b \times h + \frac{1}{2} \times \pi {(7)}^{2} + \frac{1}{2} \times \pi {(4)}^{2} \\ \\ = 8 \times 12 + \frac{1}{2} \pi(49 + 16) \\ \\ = 96 + \frac{1}{2} \times 3.14 \times 65 \\ \\ = 96 + 102.05 \\ \\ = 198.05 \\ \\ \approx \: 198.1 \: {cm}^{2} [/tex]

Answer:

3

Step-by-step explanation:

2,082/694 = 3

Answer:

3

Step-by-step explanation:

2,082/694 = 3

The linear equation in this case is . The [tex]$3 x^2+4 x+4=0$[/tex] answer is [tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex] and [tex]$3 y^2+2 x+4=0: \quad$[/tex]: quadratic [tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex] , is the solution.

[tex]$3 x^2+4 x+4=0 \quad: \quad x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}$[/tex]

[tex]$3 x^2+4 x+4=0$[/tex]

Apply the quadratic formula to the problem. [tex]$x_{1,2}=\frac{-4 \pm \sqrt{4^2-4 \cdot 3 \cdot 4}}{2 \cdot 3}$[/tex]

Simplify [tex]$\sqrt{4^2-4 \cdot 3 \cdot 4}: \quad 4 \sqrt{2} i$\\[/tex]

[tex]$x_{1,2}=\frac{-4 \pm 4 \sqrt{2} i}{2 \cdot 3}$[/tex]

Distinguish the answers

[tex]x_1=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}, x_2=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}\\x=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}\\x=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

The following are the quadratic equation's solutions:

[tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

2) [tex]$3 y^2+2 x+4=0: \quad$[/tex] A parabola with a focal length of and a vertex at (h,k)=(-2, 0) [tex]$|p|=\frac{1}{6}$[/tex]

[tex]$3 y^2+2 x+4=0$[/tex]

[tex]$4 p(x-h)=(y-k)^2$[/tex] is the common formula for a right-to-left parabola with a vertex at (h, k) and a focal length of |p|.

Rewrite [tex]$3 y^2+2 x+4=0$[/tex]  using the proper form: [tex]$4\left(-\frac{1}{6}\right)(x-(-2))=(y-0)^2$[/tex]

The following are characteristics of parabolas:

[tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex]

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System of equations y = 5x + 11 and y = 5x has no solution,  y = 6x + 3 and y = 3x has one solution and x + 4y = 8 and y = -1/4x + 2 no solution.

Two or more expressions with an Equal sign is called as Equation.

The given system of equations are

a. y = 5x + 11 and y = 5x

Substitute the y value in first equation

5x=5x+11

So the system of equations y = 5x + 11 and y = 5x has no solution.

b. y = 6x + 3 and y = 3x

Substitute the y value in first equation

3x=6x+3

-3x=3

x=-1

y=-3

The system of equations has one solution

c. x + 4y = 8 and y = -1/4x + 2

x+4(-1/4x + 2)=8

x-x+2=8

The  system of equations has one solution has no solution

Hence, system of equations y = 5x + 11 and y = 5x has no solution,  y = 6x + 3 and y = 3x has one solution and x + 4y = 8 and y = -1/4x + 2 no solution.

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Answer:

The aircraft when empty weighs 4,817.48 kilograms.

Step-by-step explanation:

Since a bomber aircraft on take-off carries twelve dozen bombs, each weighing ten kilos; and the aircraft takes off for Warsaw, the international center of Jews bombing the town, and on take-off with all the bombs on board and a fuel tank containing 1000 kilos of fuel, the aircraft weighed about eight tons, while when it returns from the crusade, there are still 230 kilos of fuel left, to determine what is the weight of the aircraft when empty, the following calculation must be performed:

1 ton = 907.185 kg

8 x 907.185 = 7,257.48

7,257.48 - (12x12x10) - 1000 = X

7,257.48 - 1,440 - 1000 = X

7,257.48 - 2,440 = X

4,817.48 = X

Therefore, the aircraft when empty weighs 4,817.48 kilograms.

Answer:

50 weeks

Step-by-step explanation:

Answer:

it would be a rectangular pyramid

Answer:

1

Step-by-step explanation:

Answer:

I believe it is 1

Step-by-step explanation:

Answer:the interest would be $3,500

Step-by-step explanation:  you have to multiply all of the numbers together but change the 3.5% to a decimal of 0.035

So there's 30 people or slots. The odds that Fatheya will be chosen to perform first is 1/30. But now there's one less slot.

Now with Fatema, there's 29 slots, so there's a 1/29 chance. Then combine these values by multiplying them:

1/30 * 1/29 = 1/870

All done!

Answer:

I think 72 would be the answer

Answer:

36 estimated amount of people

Hope this helps!!!! Love the pig pic btw ^-^

Answer: “Rate of change” just means “slope”. All of calculus is just ways to find the slope for curves. Find y at -5 and at -4 and calculate the slope.

Step-by-step explanation:

Answer:

Hey do you have a more clear picture

Step-by-step explanation:

I will be able to help if you have a better picture

Answer:

Option H

Step-by-step explanation:

y = 3x - 4

this is the correct answer.

Answer:

H- y=3x-4

The reason I answered this is because the equations are in slope-intercept format (y=mx+b), the slope(m), is 3. The y intercept(b) is -4. Hope this helped :)

volume of cone

= ⅓πr²h

= ⅓ × 3.14 × 9 × 9 × 12

= 3.14 × 3 × 108

= 3.14 × 324

= 1017.36 cm³

Answer:

She would need a minimum of 15 pans for 10 people

Step-by-step explanation:

12(5) = 60 12(10) = 120

8(?) = 120

120/8 = 15

Answer:

C) -24 and shaded circle

Step-by-step explanation:

You can simplify -6(5 - 1) by distributing -6, which would be -30 + 6. Then, you can add the numbers up to get -24. The inequality can be written as p ≤ −24.

Answer: To find the image of a figure under a translation, you need to apply the same translation to every point in the figure.

In this case, the image of hexagon DEFGHI is hexagon D′E′F′G′H′I′. To find the image of each point, you can apply the translation that maps point D to point D′.

For example, to find the image of point E under the translation, you can apply the same translation that maps point D to point D′:

Point D is located at (2, 5).

Point D′ is located at (-6, -2).

The translation that maps point D to point D′ is a translation 6 units to the left and 2 units down.

To find the image of point E under this translation, you can apply the same translation to point E:

Point E is located at (5, 5).

The image of point E is located at (5 - 6, 5 - 2) = (-1, 3).

You can follow the same process to find the images of the other points under the translation.

Alternatively, you can use the coordinates of point D and point D′ to find the translation vector that describes the translation. The translation vector is a displacement that describes the change in position of a point under the translation.

In this case, the translation vector is given by the displacement from point D to point D′:

Point D is located at (2, 5).

Point D′ is located at (-6, -2).

The translation vector is given by the displacement (-6 - 2, -2 - 5) = (-8, -7).

To find the image of any point under the translation, you can add the translation vector to the coordinates of the point. For example, to find the image of point E under the translation, you can add the translation vector to the coordinates of point E:

Point E is located at (5, 5).

The translation vector is (-8, -7).

The image of point E is located at (5 - 8, 5 - 7) = (-3, -2).

You can follow the same process to find the images of the other points under the translation.

Step-by-step explanation:

Answer:

Ah and mc are parallel segments

The total number of corn dogs sold is 28 corn dogs and number of hotdogs is 53

Total cost is the overall expense incurred for a particular product, service, or project. It includes both fixed and variable costs, such as materials, labor, and overhead. It is often used in business and economic analysis as a measure of the efficiency and profitability of a particular venture. The total cost of a product or service can also be used to set prices and make pricing decisions.

According to question:-

step1

h = number of hotdogs

c = number of corndogs.

cost of hotdog = $3

corn dog = $1.50

The equation:

3h + 1.50c = 201 (1)

h = 2c - 3 (2)

step2

substitute (2) into (1)

3(2c - 3) + 1.50c = 201

6c - 9 + 1.50c = 201

7.50c - 9 = 201

7.50c = 201 + 9

7.50c = 210

c = 210/7.50

c = 28

Therefore,

h = 2c - 3

= 2(28) - 3

= 56 - 3

= 53

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Step-by-step explanation:

d = 30m, so r = 15m

h = 20m

We know,

= (22×15×15×20)/7 [Taking π = 22/7]

= 14142.86m^3

= 14142875.14 litres

Answer:

Choice B 2 and -2

Step-by-step explanation:

2 would be opposite of -2

Mark brainliest

Step-by-step explanation:

Lets first find the remainder when p(x) is divided by x-2

p(2)=2(2)³+b(2)²+3(2)-5

p(2)=16+4b+6-5

p(2)=4b+17

Now let's find the remainder when q(x) is divided by x-2

q(2)=(2)³+(2)²-4(2)-b

q(2)=8+4-8-b

q(2)=4-b

Now let's equate both of them

4b+17=4-b

4b+b=4-17

5b=-13

b=-13/5 as required

Answer:

11.4

Step-by-step explanation:

Its a right triangle so we can use the Pythagorean Theorem to solve it

Answer:

Answer: [tex]10,724.28[/tex]

Step-by-step explanation:

Given

Distance traveled on each consecutive day is given as

[tex]10150,10211,10424,10769,10884,11155,11477[/tex]

Mean is given by the sum of the observations divided by the total no of observations.

There are 7 observations in total, so the mean is

[tex]\Rightarrow \mu =\dfrac{10150+10211+10424+10769+10884+11155+11477}{7}\\\\\Rightarrow \mu=\dfrac{75,070}{7}\\\\\Rightarrow \mu =10,724.28[/tex]

thus, the mean is [tex]10,724.28[/tex]

The mean distance Ling travels each day is [tex]10724.28 \: \rm miles[/tex] approximately.

The mean value of the data set is the ratio of sum of data set's values to number of values it has.

If the data set consists of values [tex]x_1, x_2, ..., x_n[/tex], then we get the mean value as:

[tex]\overline{x} = \dfrac{x_1 + x_2 + \cdots + x_n}{n}[/tex]

For this case, we have to find the average distance(in miles) from the distance Ling traveled for 7 days.

Thus, we get the average distance he traveled as:

[tex]\overline{d} = \dfrac{10150 + 10211 + 10424 + 10769 + 10884 + 11155 + 11477 }{7}\\\\\overline{d} = \dfrac{75070}{7} \approx 10724.28 \: \rm miles[/tex]

Thus, the mean distance Ling travels each day is [tex]10724.28 \: \rm miles[/tex] approximately.

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