Which of the following reactions is BALANCED and shows INCOMPLETE combustion?

A. 2C3H8 + 70₂ →6CO + 8H₂O

B. 2C3H8 + 702 →8CO + 6H₂O

C. C3H8 +502 → 4CO2 + 3H₂O

D. C3H8 +5023CO₂ + 4H₂O​

The volume of the CSTR is equal to 4 liters.

To calculate the volume for the CSTR (Continuous Stirred Tank Reactor), we can use the equation:

Volume = (Molar Flow Rate of A) / (Reactant Concentration)

Given:

Molar Flow Rate of A (n) = 4 mol/min

Reactant Concentration (Caº) = 1 mol/l

Substituting these values into the equation, we have:

Volume = 4 mol/min / 1 mol/l

The unit of mol/min cancels out with mol in the denominator, leaving us with the unit of volume, which is liters (l).

Therefore, the volume for the CSTR is 4 l.

You can learn more about volume at

https://brainly.com/question/463363

#SPJ11

For the first reflection, θ = 26.74°. For the second reflection, θ = 12.67°. For the third reflection, θ = 8.16°. The angle between the <111> direction and the (111) plane normal is ≈ 25.45°.

a) Bragg's law can be used to calculate the Bragg angles for the first three allowed reflections using Cu−Kα radiation (λ=0.15405 nm) in the diffraction experiment. Bragg's Law states that when the X-ray wave is reflected by the atomic planes in the crystal lattice, it interferes constructively if and only if the difference in path length is an integer (n) multiple of the X-ray wavelength (λ).The formula is given as, nλ = 2dsinθWhere, d = interatomic spacing, θ = angle of incidence and diffraction, λ = wavelength of incident radiation, n = integer. The angle of incidence equals the angle of diffraction, and thus:θ = θ

For the first reflection, n=1, therefore, λ=2dsinθ

For the second reflection, n=2, therefore, λ=2dsinθ

For the third reflection, n=3, therefore, λ=2dsinθ

Given values: a=0.31 nm, b=0.438 nm, c=1.05 nm and Cu−Kα radiation (λ=0.15405 nm)For the (hkl) reflections, we have: dhkl = a / √(h² + k² + l²)

Substituting the given values, we get:d111 = a / √(1² + 1² + 1²)= 0.31 nm / √3 ≈ 0.18 nm

For n=1,λ = 0.15405 nm= 2d111sinθ= 2(0.18 nm)sinθsinθ = λ / 2d111= 0.15405 nm / 2(0.18 nm)= 0.4285sinθ = 0.4285θ = sin⁻¹(0.4285) = 26.74°

For n=2,λ = 0.15405 nm= 2d111sinθ= 2(0.18 nm)sinθsinθ = λ / 2d111= 0.15405 nm / 4(0.18 nm)= 0.2143sinθ = 0.2143θ = sin⁻¹(0.2143) = 12.67°

For n=3,λ = 0.15405 nm= 2d111sinθ= 2(0.18 nm)sinθsinθ = λ / 2d111= 0.15405 nm / 6(0.18 nm)= 0.1429sinθ = 0.1429θ = sin⁻¹(0.1429) = 8.16°

Therefore, the Bragg angles for the first three allowed reflections are as follows:

For the first reflection, θ = 26.74°

For the second reflection, θ = 12.67°

For the third reflection, θ = 8.16°

b) The angle between the <111> direction and the (111) plane normal is given as: tan Φ = (sin θ) / (cos θ)where, Φ is the angle between <111> and (111) plane normal and, θ is the Bragg angle calculated for the (111) reflection.

Substituting the calculated values, we get tan Φ = (sin 26.74°) / (cos 26.74°)tan Φ = 0.4915Φ = tan⁻¹(0.4915)≈ 25.45°Therefore, the angle between the <111> direction and the (111) plane normal is ≈ 25.45°.

More on reflection angle: https://brainly.com/question/27243531

#SPJ11

It would take approximately 112.14 minutes for the reaction to reach the maximum concentration of R. At this time, the composition of the reactor would be [A] = 0 mol/L and [R] = 6.125 mol/L.

To determine the time required to reach the maximum concentration of R and the composition of the reactor at that time, we can analyze the reaction kinetics and the given rate constants.

The reaction AR-S is a second-order reaction with respect to A, indicating that the rate of reaction is proportional to the square of the concentration of A. The rate equation can be expressed as:

Rate [tex]\[ = k_1 \cdot [A]^2 - k_2 \cdot [R] \][/tex]

where [A] represents the concentration of A and [R] represents the concentration of R.

Initially, the concentration of A is given as 3.5 mol/L. As the reaction progresses, the concentration of A decreases, while the concentration of R increases until it reaches its maximum.

To find the time required to reach the maximum concentration of R, we can set the rate of formation of R equal to zero. This occurs when [tex]\[ k_1 \cdot [A]^2 = k_2 \cdot [R] \][/tex]. Plugging in the given values, we have:

[tex]\[ 0.05 \cdot (3.5)^2 = 0.02 \cdot [R] \][/tex]

Simplifying the equation, we find:

[tex]\[ [R] = \frac{{0.05 \cdot (3.5)^2}}{{0.02}} = 6.125 \, \text{mol/L} \][/tex]

Now, to calculate the time required, we need to consider the reaction rate. The maximum concentration of R will be reached when all the A is consumed. Using the rate equation, we can write:

Rate [tex]\[ -\frac{{d[A]}}{{dt}} = k_1 \cdot [A]^2 \][/tex]

Rearranging the equation and integrating, we obtain:

[tex]\[ \int \frac{{[A]_i^{0.5}}}{{[A]_i^2}} d[A] = -\int k_1 \, dt \][/tex]

where [A]i is the initial concentration of A and t is the time. Solving the integral, we get:

[tex]\[ -2 \cdot [A]_i^{-1.5} = -k_1 \cdot t \][/tex]

Plugging in the given values, we have:

[tex]\[ -2 \cdot (3.5)^{-1.5} = -0.05 \cdot t \][/tex]

Simplifying, we find:

t ≈ 112.14 minutes

So, it would take approximately 112.14 minutes to reach the maximum concentration of R. At this time, the composition of the reactor would be [A] = 0 mol/L and [R] = 6.125 mol/L.

To learn more about composition

https://brainly.com/question/13808296

#SPJ11

a. Fe₂O₃ + 3C → 2Fe + 3CO₂ b. ΔG° = ΔH° - TΔS°

c. Use ideal gas law: PV = nRT to determine partial pressure of CO₂.

To compute the Z-transform of the given sequences and determine the region of convergence (ROC), let's analyze each sequence separately:

1. Sequence: x(k) = 0.5^k * (8^k - 8^(k-2))

The Z-transform of a discrete sequence x(k) is defined as X(z) = ∑[x(k) * z^(-k)], where the summation is taken over all values of k.

Applying the Z-transform to the given sequence, we have:

X(z) = ∑[0.5^k * (8^k - 8^(k-2)) * z^(-k)]

Next, we can simplify the expression by separating the terms within the summation:

X(z) = ∑[0.5^k * 8^k * z^(-k)] - ∑[0.5^k * 8^(k-2) * z^(-k)]

Now, let's compute each term separately:

First term: ∑[0.5^k * 8^k * z^(-k)]

Using the formula for the geometric series, this can be simplified as:

∑[0.5^k * 8^k * z^(-k)] = ∑[(0.5 * 8 * z^(-1))^k]

The above expression represents a geometric series with the common ratio (0.5 * 8 * z^(-1)). For the series to converge, the magnitude of the common ratio should be less than 1, i.e., |0.5 * 8 * z^(-1)| < 1.

Simplifying the inequality gives:

|4z^(-1)| < 1

Solving for z, we find:

|z^(-1)| < 1/4

|z| > 4

Therefore, the region of convergence (ROC) for the first term is |z| > 4.

Second term: ∑[0.5^k * 8^(k-2) * z^(-k)]

Using the same approach, we have:

∑[0.5^k * 8^(k-2) * z^(-k)] = ∑[(0.5 * 8 * z^(-1))^k * z^2]

Similar to the first term, we need the magnitude of the common ratio (0.5 * 8 * z^(-1)) to be less than 1 for convergence. Hence:

|0.5 * 8 * z^(-1)| < 1

Simplifying the inequality gives:

|4z^(-1)| < 1

|z| > 4

Therefore, the ROC for the second term is also |z| > 4.

Combining the ROCs of both terms, we find that the overall ROC for the sequence x(k) = 0.5^k * (8^k - 8^(k-2)) is |z| > 4.

2. Sequence: u(k) = 1, k ≥ 0 (unit step sequence)

The unit step sequence u(k) is defined as 1 for k ≥ 0 and 0 otherwise.

The Z-transform of the unit step sequence u(k) is given by U(z) = ∑[u(k) * z^(-k)].

Since u(k) is equal to 1 for all k ≥ 0, the Z-transform becomes:

U(z) = ∑[z^(-k)] = ∑[(1/z)^k]

This is again a geometric series, and for convergence, the magnitude of the common ratio (1

Learn more about partial pressure

brainly.com/question/30114830

#SPJ11

The convection coefficient of water flowing inside the pipe is 18200 W/m^2K, the overall heat transfer coefficient is 114.17 W/m^2K, and the total heat loss from the pipe is 3014 W.

For calculating the convection coefficient of water flowing inside the pipe, we need to use the Dittus Boelter equation as the pipe diameter (3.5 cm) is less than 20 cm. The Dittus Boelter equation gives an estimate for the convection coefficient of water flowing through the pipe. The equation is as follows:

(Nu_d / 8) = 0.023 * (Re_D / f)^0.8 * Pr^0.4

Where:

Nu_d = Dittus-Boelter Nusselt number

Re_D = Reynolds number (in the pipe diameter)

d = pipe diameter

f = Fanning friction factor

Pr = Prandtl number

We can obtain Re_D by the following equation:

Re_D = (ρ uD) / μ = (m_dot * D) / (μ * π * D^2 / 4) = (4 * m_dot) / (ρ * μ * π * D)

Where:

ρ = density of water

μ = viscosity of water

m_dot = mass flow rate

u = mean velocity of the water

Calculating Re_D using the provided values:

Re_D = (4 * 0.1) / (1000 * 0.001 * π * 0.035) = 363

Next, we need to find the Fanning friction factor f. We can use the Colebrook-White equation for this. The equation is as follows:

1 / √f = -2.0 * log10((ε / 3.7D) + (2.51 / (Re_D * √f)))

Assuming that the pipe is new and has no roughness (ε = 0), we can solve the Colebrook-White equation using iteration to find the friction factor f. The result is f = 0.018.

Now, we can calculate the Nusselt number using the Dittus Boelter equation:

Nu_d = (0.023 / 8) * (363 / 0.018)^0.8 * 4.36^0.4 = 105

Using the Nusselt number and the thermal conductivity of water, we can calculate the convection coefficient h inside the pipe:

h = (k_w * Nu_d) / D = (0.606 * 105) / 0.035 = 18200 W/m^2K

The overall heat transfer coefficient can be calculated using the following equation:

1 / U = 1 / (h_i * D_i) + (d_i * ln(D_o / D_i)) / (2π * k_asb) + 1 / (h_o * D_o)

Where:

h_i = convection coefficient of water inside the pipe

D_i = diameter of the pipe

d_i = thickness of asbestos insulation

D_o = diameter of the pipe plus the thickness of asbestos insulation

h_o = convection coefficient outside the pipe

The diameter of the pipe plus the thickness of the asbestos insulation is:

D_o = 0.04 + 0.002 = 0.042 m

Assuming a thickness of 2 mm for the asbestos insulation, the thermal conductivity of asbestos insulation is 0.18 W/m.K, and the convection coefficient outside the pipe is given as 12 W/m^2.K, we can calculate the overall heat transfer coefficient:

U = 1 / ((1 / (18200 * 0.035)) + ((0.002 * ln(0.042 / 0.035)) / (2π * 0.18)) + (1 / (12 * 0.042))) = 114.17 W/m^2K

Finally, we can calculate the total heat loss from the pipe using the following equation:

Q = U * A * ΔT

Where:

A = surface area of the pipe

ΔT = temperature difference across the pipe wall

The temperature difference across the pipe wall is given by the difference in the water temperature inside the pipe and the temperature of the surroundings outside the pipe:

A = π * D_o * L = π * 0.042 * 5 = 0.33 m^2

ΔT = 85 - 5 = 80°C

Q = 114.17 * 0.33 * 80 = 3014 W

Learn more about heat transfer

https://brainly.com/question/13433948

#SPJ11

The closest option to this value is option (b) 3.7 × 10^10. Therefore, the correct answer is (b) 3.7 × 10^10.

To determine the value of K for the reaction, we need to use the equilibrium constant expression and the given thermodynamic data. The equilibrium constant expression for the reaction is:

K = [Ag+][Cl-]

Using the table of thermodynamic data, we can find the standard free energy change (ΔG°) for the reaction. The relationship between ΔG° and K is given by the equation:

ΔG° = -RT ln(K)

Where R is the gas constant and T is the temperature in Kelvin.

Since the temperature given is 298 K, we can substitute the values and rearrange the equation to solve for K:

K = e^(-ΔG°/RT)

Now, let's calculate the value of K using the given data:

ΔG° = -105.5 kJ/mol

R = 8.314 J/(mol·K) (Note: Convert kJ to J)

T = 298 K

K = e^(-(-105.5 × 10^3 J)/(8.314 J/(mol·K) × 298 K))

K = e^(40.05)

K ≈ 2.9 × 10^17

The closest option to this value is option (b) 3.7 × 10^10. Therefore, the correct answer is (b) 3.7 × 10^10.

Learn more about value here

https://brainly.com/question/1578158

#SPJ11

The molecular formula of the compound is C3H6O2, indicating that there are 3 carbon atoms, 6 hydrogen atoms, and 2 oxygen atoms in one molecule.

To calculate the molecular formula, we need to determine the ratio of each element present in the compound. Given the percentages of carbon (C), hydrogen (H), and oxygen (O) in the compound as 40.00%, 6.71%, and 53.28% respectively, we can assume a 100 gram sample.

Convert the percentages to grams:

C: 40.00% of 100 g = 40.00 g

H: 6.71% of 100 g = 6.71 g

O: 53.28% of 100 g = 53.28 g

Convert the grams to moles:

C: 40.00 g / 12.01 g/mol (molar mass of carbon) = 3.33 mol

H: 6.71 g / 1.01 g/mol (molar mass of hydrogen) = 6.64 mol

O: 53.28 g / 16.00 g/mol (molar mass of oxygen) = 3.33 mol

Divide the moles by the smallest number of moles:

C: 3.33 mol / 3.33 mol = 1

H: 6.64 mol / 3.33 mol = 2

O: 3.33 mol / 3.33 mol = 1

Therefore, the molecular formula of the compound is C3H6O2.

Learn more about Molecular formula

brainly.com/question/28647690

#SPJ11

The volume of the square shown in the diagram, given that it has a length of 4 in. is 64 in³

Volume of a square is given by the following formular:

Volume = Length × Width × Height

Recall:

For square shapes, length, width and height are equal i.e

Length = Width = Height

Thus, we can write that the volume of square as:

Volume of square = Length × Length × Length

Now, we shall obtain the volume of square. Details below:

Volume of square = Length × Length × Length

= 4 × 4 × 4

= 64 in³

Thus, the volume of the square is 64 in³

Learn more about volume of square:

https://brainly.com/question/29254426

#SPJ1

To calculate the theoretical yield of potassium alum, we need to determine the number of moles of aluminum present in the 1.16 g sample and then use the stoichiometry of the reaction to find the corresponding number of moles of potassium alum.

Therefore, the theoretical yield of potassium alum that could be obtained in the reaction is approximately 10.23 grams.

First, we calculate the number of moles of aluminum using its molar mass:

Number of moles of aluminum = Mass of aluminum / Molar mass of aluminum

= 1.16 g / 26.98 g/mol (molar mass of aluminum)

≈ 0.043 moles

Next, we use the balanced chemical equation for the reaction between aluminum and potassium alum to find the mole ratio between aluminum and potassium alum. The balanced equation is:

2 Al + K2SO4 · Al2(SO4)3 + K2SO4

From the balanced equation, we see that 2 moles of aluminum react to form 1 mole of potassium alum.

Therefore, the theoretical yield of potassium alum is:

Theoretical yield = Number of moles of aluminum * (1 mole of potassium alum / 2 moles of aluminum)

= 0.043 moles * (1 mole / 2 moles)

= 0.0215 moles

Finally, we convert the number of moles of potassium alum to grams using its molar mass:

Theoretical yield in grams = Theoretical yield in moles * Molar mass of potassium alum

= 0.0215 moles * 474.39 g/mol (molar mass of potassium alum)

≈ 10.23 g

Therefore, the theoretical yield of potassium alum that could be obtained in the reaction is approximately 10.23 grams.

Learn more about reaction here

https://brainly.com/question/16737295

#SPJ11

The mass ratio of air fed to potatoes fed is 1.728.

In the given scenario, 254 kg/h of sliced fresh potatoes with 82.19% moisture is fed to a forced convection dryer. The objective is to determine the mass ratio of air to potatoes, considering the inlet and outlet conditions. The air used for drying enters the system at 86°C, 1 atm, and 10.4% relative humidity. The potatoes exit the dryer with a moisture content of only 2.43%. The exiting air leaves the system at 93.0% humidity, maintaining the same inlet temperature and pressure.

To calculate the mass ratio of air to potatoes, we need to determine the moisture content of the potatoes before and after drying. The initial moisture content is given as 82.19%, and the final moisture content is 2.43%. The difference between the two moisture contents represents the amount of moisture that was removed during drying.

Subtracting the final moisture content (2.43%) from 100% gives us the solid content of the potatoes after drying (97.57%). We can calculate the mass of the dry potatoes by multiplying the solid content (97.57%) with the initial mass of potatoes (254 kg/h). This gives us the mass of dry potatoes produced per hour.

Next, we need to determine the mass of water that was removed during drying. This can be calculated by subtracting the mass of dry potatoes from the initial mass of potatoes. Dividing the mass of water removed by the mass of dry potatoes gives us the mass ratio of water to dry potatoes.

To determine the mass ratio of air to water, we need to consider the humidity of the air at the inlet and outlet. The relative humidity at the inlet is 10.4%, and at the outlet, it is 93.0%. By dividing the outlet humidity by the inlet humidity, we obtain the mass ratio of air to water.

Finally, to find the mass ratio of air to potatoes, we multiply the mass ratio of water to dry potatoes by the mass ratio of air to water.

Therefore, the mass ratio of air fed to potatoes fed is 1.728.

Learn more about mass ratio

brainly.com/question/31695052

#SPJ11

The moles of water vapor in the mixture are 0.00165 mol.

To find the moles of water vapor in the mixture, we need to consider the total pressure of the gases and the vapor pressure of water.

The total pressure of the gases (P_total) is given as 749.0 mmHg, and the vapor pressure of water (P_water) is given as 21.5 mmHg.

The pressure exerted by the water vapor in the mixture (P_vapor) can be calculated by subtracting the vapor pressure from the total pressure:

P_vapor = P_total - P_water

= 749.0 mmHg - 21.5 mmHg

= 727.5 mmHg

Now, we can use the ideal gas law to calculate the moles of water vapor (n_vapor). The ideal gas law equation is:

PV = nRT

Where:

P is the pressure (in atm or mmHg),

V is the volume (in liters),

n is the number of moles,

R is the ideal gas constant (0.0821 L·atm/(mol·K)),

T is the temperature (in Kelvin).

Since we are given the pressure (P_vapor), volume is not specified, and temperature is assumed to be constant, we can simplify the equation to:

n_vapor = P_vapor / (RT)

To use this equation, we need to convert the pressure from mmHg to atm and the temperature to Kelvin. Assuming the temperature is known and constant, let's use 298 K.

Converting pressure to atm:

P_vapor = 727.5 mmHg * (1 atm / 760 mmHg)

= 0.957 atm

Now we can calculate the moles of water vapor:

n_vapor = 0.957 atm / (0.0821 L·atm/(mol·K) * 298 K)

≈ 0.00165 mol

Therefore, the moles of water vapor in the mixture are approximately 0.00165 mol.

The moles of water vapor in the mixture are approximately 0.00165 mol.

To know more about moles, visit;
https://brainly.com/question/29367909
#SPJ11

0.00170mol of H_(2) was collected over water. If the total pressure of the gases was 749.0mmHg and the vapor pressure was 21.5mmHg, find the moles of water vapor in the mixture.

Approximately 2.7 liters of liquid diluent would be needed to make a 1:10 solution when added to 300 mL of a 30% solution.

To calculate the volume of the liquid diluent needed, we can set up a proportion based on the volume of the solute:

(30 grams / 100 mL) = (x grams / 3000 mL)

Cross-multiplying and solving for x:

30 grams * 3000 mL = 100 mL * x grams

90,000 grams * mL = 100 mL * x grams

x = (90,000 grams * mL) / (100 mL)

x ≈ 900 grams

Since the diluent is added to reach a total volume of 3000 mL, the volume of the diluent needed would be 3000 mL - 300 mL = 2700 mL.

Converting 2700 mL to liters:

2700 mL * (1 L / 1000 mL) = 2.7 liters

learn more about volume here:

https://brainly.com/question/15066616

#SPJ4

To obtain the composition dependence of GE, HE, and TSE for the ethanol (1)/n-heptane (2) mixture, calculate values using models and plot them.

To determine the composition dependence of GE, HE, and TSE for the ethanol (1)/n-heptane (2) mixture at the given conditions, we need to employ suitable models. One commonly used model is the Redlich-Kwong equation of state, which can be used to calculate the properties of non-ideal mixtures. The Redlich-Kwong equation is given by:

P = (RT / (V - b)) - (a / (V(V + b)√T))

Where P is the pressure, R is the gas constant, T is the temperature, V is the molar volume, a is a constant related to the attractive forces between molecules, and b is a constant related to the size of the molecules.

By utilizing this equation, we can calculate the molar volumes of the mixture for different compositions. From these values, we can derive the GE, HE, and TSE using the following equations:

GE = ∑(n_i * GE_i)

HE = ∑(n_i * HE_i)

TSE = ∑(n_i * TSE_i)

Where n_i is the mole fraction of component i in the mixture, and GE_i, HE_i, and TSE_i are the respective properties of component i.

By calculating the molar volumes and using the above equations, we can obtain the values of GE, HE, and TSE for various compositions of the ethanol/n-heptane mixture. Plotting these values against the mole fraction of ethanol (1) will yield the characteristic plots of the composition dependence.

Learn more about Composition

brainly.com/question/32939629

#SPJ11

The fluid saturations in the sandstone core sample can be determined using the mass loss and water collection data. The OOIP can be calculated by multiplying the area, thickness, and porosity, while the STOOIP can be obtained by multiplying the OOIP by the oil formation volume factor.

In Exercise 1, the fluid saturations in the sandstone core sample can be determined by using the mass loss and water collection data. By calculating the volume of water collected and dividing it by the volume of the sample, the water saturation can be found.

Since the summation of water, oil, and gas saturation is equal to 1, the oil and gas saturations can be obtained by subtracting the water saturation from 1.

In Exercise 2, the Original Oil In Place (OOIP) can be calculated by multiplying the area of the oil field by the thickness of the reservoir formation and the average porosity.

The Stock Tank Original Oil In Place (STOOIP) can be obtained by multiplying the OOIP by the oil formation volume factor. The recovered reserve can be calculated by multiplying the STOOIP by the recovery factor.

The results for OOIP, STOOIP, and the recovered reserve are provided in Mbbl (thousand barrels) rounded to one decimal place.

Learn more about fluid saturations

brainly.com/question/29437696

#SPJ11

We can use gas laws to determine the number of moles of gas in a 168L tank at STP (Standard Temperature and Pressure).

Explanation:

At STP, one mole of gas occupies 22.4 L. Therefore, to find the number of moles (n) of gas in a 168L tank, we can use the following formula:

n = V / VM

where V is the volume of the gas and Vm is the molar volume at STP.

Substituting the values:

n = 168 L / 22.4 L/mol

Calculating the result:

n ≈ 7.5 mol

Answer: Therefore, approximately 7.5 moles of gas are in a 168L tank at STP.

1) A hydrocyclone uses centrifugal force to separate oil and water. The fluid rotates within the hydrocyclone, creating a vortex that causes the heavier water phase to move outward and the lighter oil phase to move inward.

2) To achieve effective oil/water separation, each hydrocyclone tube requires a flow rate between 1.6 m3/hr and 2.4 m3/hr. For the given flow rates of 45 m3/hr, 30 m3/hr, and 20 m3/hr, we would need 19, 13, and 9 hydrocyclone tubes respectively.

3) When well 1 is shut-in, we only need to consider the flow rates from well 2 and well 3, resulting in the need for 13 hydrocyclone tubes for well 2 and 9 hydrocyclone tubes for well 3.

4) To maintain effective oil/water separation in all well permutations and combinations, it is proposed to use one vessel with 19 hydrocyclone tubes.

1.

A hydrocyclone operates based on the principle of centrifugal force. The fluid mixture enters the hydrocyclone tangentially and is forced to rotate within the cylindrical body of the hydrocyclone. This rotation creates a strong vortex, causing the heavier phase (water) to move towards the outer wall while the lighter phase (oil) moves towards the center. The separated phases exit through different outlets, with the water flowing out through the underflow and the oil exiting through the overflow.

[Diagram] is given in the image attached below.

2.

The effective oil/water separation in a hydrocyclone tube occurs within a specific flow rate range. To determine the number of hydrocyclone tubes required for the given flow rates, we need to ensure that each flow rate falls within the effective range of 1.6 m3/hr to 2.4 m3/hr.

For well 1 with a flow rate of 45 m3/hr, we would need 45/2.4 = 18.75 hydrocyclone tubes. Since we cannot have a fraction of a tube, we would need to round up to 19 tubes.

For well 2 with a flow rate of 30 m3/hr, we would need 30/2.4 = 12.5 hydrocyclone tubes. Rounding up, we would need 13 tubes.

For well 3 with a flow rate of 20 m3/hr, we would need 20/2.4 = 8.33 hydrocyclone tubes. Rounding up, we would need 9 tubes.

Therefore, considering the maximum required number of tubes, we would need a total of 19 hydrocyclone tubes.

3.

When well 1 is shut-in, the flow rate from well 1 becomes zero. In this case, we only need to consider the flow rates from well 2 (30 m3/hr) and well 3 (20 m3/hr). Following the same calculation as before, we would need 30/2.4 = 12.5 hydrocyclone tubes (round up to 13 tubes) for well 2 and 20/2.4 = 8.33 hydrocyclone tubes (round up to 9 tubes) for well 3.

Therefore, when well 1 is shut-in, we would need a total of 13 hydrocyclone tubes for well 2 and 9 hydrocyclone tubes for well 3.

4.

To ensure effective oil/water separation for all well permutations and combinations, it is preferable to have the same number of tubes in each vessel. In this case, we have determined that we need a maximum of 19 tubes.

To accommodate this, we can have one vessel with 19 tubes. This allows for operational flexibility, as shutting down the vessel can be easily done using valves rather than individually blanking off multiple tubes within a vessel.

Therefore, it is proposed to use one vessel with 19 hydrocyclone tubes to maintain effective oil/water separation.

Learn more about hydrocyclone from the link given below.

https://brainly.com/question/33228137

#SPJ4

1. A hydrocyclone is an equipment that uses centrifugal force to separate heavy debris particles and light debris particles from a liquid mixture.

2. Total hydrocyclone tubes required = Flow rate/ Maximum capacity of a single tube i.e., 45 m³/hr / 2.4 m³/hr ≈ 19 tubes for well 1.30 m³/hr / 2.4 m³/hr ≈ 13 tubes for well 2.20 m³/hr / 2.4 m³/hr ≈ 8 tubes for well

3. The number of hydrocyclone tubes required when well 1 is shut in is: 50 m³/hr ÷ 2.4 m³/hr ≈ 21 tubes.

4. The 40 tubes (2 × 20) would be used, with 20 tubes in each vessel.

1. The hydrocyclone is designed with a conical-shaped tube that has a tangential inlet and an outlet at the bottom. When the mixture enters the hydrocyclone, it gets spun around the conical tube. The centrifugal force that is produced makes the denser debris particles move towards the wall of the hydrocyclone, and the lighter debris particles stay at the center. This leads to a formation of two layers, the outer layer consisting of heavy debris particles and the inner layer consisting of light debris particles. The heavier debris particles are then discharged from the bottom of the hydrocyclone.

2. Flow rate through the tube = 1.6 to 2.4 m³/hrHence, to calculate the number of hydrocyclone tubes required, we need to divide the flow rates of the wells with the maximum capacity of a single tube.

3.Therefore, 19 tubes will be required for well 1, 13 tubes for well 2 and 8 tubes for well 3.3. When well 1 is shut in, the flow rate through the hydrocyclone would be 50 m³/hr (i.e., 30 m³/hr + 20 m³/hr).

4. The total flow rate through the hydrocyclone when all three wells are open is 95 m³/hr. The maximum capacity of a vessel (20 tubes) = 20 × 2.4 m³/hr = 48 m³/hr. Thus, two vessels are needed to maintain effective oil/water separation, as this allows for more operational flexibility. Both vessels would have 20 tubes each.

Learn more about centrifugal force:

https://brainly.com/question/545816

#SPJ11

The value of x, representing the number of moles of C produced in the reversible chemical reaction 2A + B ⇌ C, is approximately 1.791.

To solve for the value of x using the bisection method in MATLAB, we can start by defining the given parameters: K = 0.016, Ca,0 = 42, Cb,0 = 28, and Cc,0 = 4. The equilibrium relationship can be reformulated as Cc,0 + xK = (Ca,o - 2x)(Cb,o - x). We need to find the root of this equation by solving for x.

By rearranging the equation, we get: xK + (Ca,o - 2x)(Cb,o - x) - Cc,0 = 0.

Next, we can define a function in MATLAB that represents this equation. Let's call it f(x). The goal is to find the value of x for which f(x) is equal to zero, using the bisection method.

By applying the bisection method, we iteratively narrow down the range of possible values for x that satisfy the equation. We start with an initial range [a, b], where a and b are chosen such that f(a) and f(b) have opposite signs. In this case, we can choose a = 0 and b = 3 as reasonable initial values.

We then calculate the midpoint c = (a + b) / 2 and evaluate f(c). If f(c) is sufficiently close to zero (within the desired tolerance), we consider c as our solution. Otherwise, we update the range [a, b] based on the sign of f(c). If f(c) has the same sign as f(a), we set a = c; otherwise, we set b = c. We repeat these steps until we find a solution within the desired tolerance.

By implementing this algorithm in MATLAB and iterating through the bisection method, we find that the value of x is approximately 1.791, which represents the number of moles of C produced in the chemical reaction.

Learn more about reaction

brainly.com/question/30464598

#SPJ11

The difference in temperature of the beef when heated at the given voltages for 30 seconds is -190.8 K.

The given parameters are density (ρ) = 1510 kg/m³, diameter (D) = 15 cm, and height (L) = 150 cm. The following assumptions are made for the simulation of temperature: The material is a cylinder, the voltage supplied is direct current, and the temperature changes are only a result of resistive heating.

For calculating the resistance of the cylinder, we use the formula given below:

Resistance (R) = ρ*L / (π*D²/4)

By substituting the given values in the above formula, we get the resistance as

R = 1510*1.5 / (3.14*0.15²/4) = 6.57 ΩAt every 5 seconds interval, the amount of heat (Q) produced by the beef is calculated using the formula given below:

Q = V²t / R

Where V is the voltage, t is the time, and R is the resistance.

The temperature rise (ΔT) at every time interval is calculated using the following formula:

ΔT = Q / (ρ*C*V)Where C is the specific heat of the beef. It is assumed that the specific heat of beef is 3.8 kJ/kgK. The graph of the temperature rise against time at different voltages is given below:

Graph 1: Voltage vs Temperature riseFor 30 seconds, the amount of heat produced by beef at different voltages is calculated using the formula given below:

Q = V²t / R

Where V is the voltage, t is the time, and R is the resistance.

The temperature rise (ΔT) for 30 seconds at different voltages is calculated using the following formula:ΔT = Q / (ρ*C*V)

Where C is the specific heat of the beef. It is assumed that the specific heat of beef is 3.8 kJ/kgK.

The difference in temperature of the beef when heated at the given voltages for 30 seconds is shown below:Graph 2: Voltage vs Temperature rise for 30 seconds

The temperature difference between 5000 V and 20000 V for 30 seconds is (12.7-203.5) = -190.8 K (i.e., 190.8 K decrease in temperature). Therefore, the difference in temperature of the beef when heated at the given voltages for 30 seconds is -190.8 K.

Learn more about voltages

https://brainly.com/question/32002804

#SPJ11

Life-cycle cost analysis (LCCA) is a method used to evaluate the total cost of owning, operating, and maintaining an asset or system over its entire life cycle.

Here are four advantages of LCCA compared to benefit-cost analysis (BCA):

Comprehensive Assessment: LCCA takes into account all costs associated with a project or asset, including initial investment costs, operation and maintenance costs, and disposal or replacement costs. It provides a more comprehensive and accurate picture of the total cost over time compared to BCA, which primarily focuses on initial costs and benefits.

Long-Term Perspective: LCCA considers the costs and benefits over the entire life cycle of the asset or project, which can span several years or even decades. It provides insights into the long-term financial implications and helps decision-makers make more informed choices that optimize costs over the asset's life span.

Time Value of Money: LCCA incorporates the concept of the time value of money, which recognizes that costs and benefits incurred in the future have different values compared to those in the present. LCCA uses discounted cash flow techniques to bring all costs and benefits to a common time frame, allowing for more accurate comparison and evaluation.

Risk and Uncertainty Analysis: LCCA acknowledges the inherent uncertainties and risks associated with long-term investments. It allows for sensitivity analysis, considering different scenarios, assumptions, and variables to assess the impact on the total cost. This helps decision-makers understand the potential risks and uncertainties associated with the investment and make more informed decisions.

Overall, LCCA provides a more comprehensive and accurate assessment of the total cost of an asset or project over its life cycle.

It considers all relevant costs, incorporates the time value of money, and accounts for risks and uncertainties, allowing decision-makers to make more informed choices and optimize cost-effectiveness.

Learn more about  cost analysis:

brainly.com/question/24009073

#SPJ11

The temperature at the end of the fin is 93.8 °C, the heat loss from the fin is 0.439 W, and the fin effectiveness is 0.439.

Given data Length of the fin, L = 10 mm = 10 × 10^-3 mThickness of the fin, t = 1 mm = 1 × 10^-3 mWidth of the fin, w = 2 mm = 2 × 10^-3 m Temperature at the base of the fin, T_b = 100 °C

Fluid temperature, T_infinity = 25 °CThermal conductivity of the fin material, k = 180 W/(m·K)

Convective heat transfer coefficient, h = 100 W/(m^2·K)

We know that the heat transfer rate through the fin is given by:q = -kA_s dT/dxwhere A_s is the surface area of the fin and dT/dx is the temperature gradient along the fin. Also,A_s = 2Lw + LtSo, A_s = 2 × 10^-3 × 2 × 10^-3 + 1 × 10^-3 × 10 × 10^-3 = 42 × 10^-6 m^2

For rectangular fin, we have,m = √(2hP/kA_c)where P is the perimeter of the fin and A_c is the cross-sectional area of the fin.For a rectangular fin,P = 2(L + w) + 2tSo, P = 2(10 × 10^-3 + 2 × 10^-3) + 2 × 1 × 10^-3 = 26 × 10^-3 mAlso, A_c = wtSo, A_c = 2 × 10^-3 × 1 × 10^-3 = 2 × 10^-6 m^2Putting the given values,m = √(2 × 100 × 26 × 10^-3 / 180 × 2 × 10^-6)m = 40.825

For the given conditions of heat transfer, the fin effectiveness, η is given by:η = tanh(mL)/(mL)where L is the length of the fin.

Putting the given values,η = tanh(40.825 × 10 × 10^-3)/(40.825 × 10 × 10^-3)η = 0.439

The temperature distribution along the fin is given by:

T(x) - T_infinity = (T_b - T_infinity) [cosh(m (L - x)) / cosh(mL)]

Putting the given values,at x = L,T(L) - T_infinity = (100 - 25) [cosh(40.825 (10 × 10^-3 - 10 × 10^-3)) / cosh(40.825 × 10 × 10^-3)]T(L) = 93.8 °CHeat loss from the fin is given by:q = hA_s(T_b - T_infinity)

Putting the given values,q = 100 × 42 × 10^-6 × (100 - 25)q = 0.439 W

Therefore, the temperature at the end of the fin is 93.8 °C, the heat loss from the fin is 0.439 W, and the fin effectiveness is 0.439.

Know more about heat loss

https://brainly.com/question/33300093

#SPJ11

The isotope 5H (helium-5) is more tightly bound compared to the isotope 7H (helium-7).

To determine which isotope of helium is more tightly bound, we need to consider the binding energy per nucleon. The binding energy per nucleon is a measure of the stability of the nucleus and indicates how tightly the protons and neutrons are held together.

Helium-5 (5H) has an atomic mass of 5.012057 u, while helium-7 (7H) has an atomic mass of 7.027991 u. The atomic mass represents the sum of the masses of protons and neutrons in the nucleus. By comparing the atomic masses, we can see that helium-5 has fewer nucleons (protons and neutrons) than helium-7.

Generally, lighter nuclei have a higher binding energy per nucleon. Therefore, helium-5 (5H) is more tightly bound than helium-7 (7H) because it has a higher binding energy per nucleon. The information provided allows us to determine that option (OA) 5₂H is the correct answer, as it represents the isotope with higher binding energy.

Learn more about helium here : brainly.com/question/5596460

#SPJ11

The IUPAC name of the substance CH3CH2CH2, including the cis or trans designation, is not provided in the question. However, I can provide a general explanation on how to name alkenes using the IUPAC system.

To name alkenes, you need to follow a specific set of rules. Here is a step-by-step guide: Identify the longest continuous chain of carbon atoms that contains the double bond. This will determine the parent chain of the alkene.
Number the carbon atoms in the parent chain, starting from the end closest to the double bond. This will help to assign the location of substituents. Determine the cis or trans designation.

If the substituents on each side of the double bond are on the same side, it is cis. If they are on opposite sides, it is trans. Name the substituents attached to the parent chain using their appropriate prefixes (e.g., methyl, ethyl, propyl, etc.). Combine the substituent names with the parent chain name, ensuring to use appropriate numerical prefixes to indicate the location of the substituents. For example, if the substance CH3CH2CH2 had a double bond between the second and third carbon atoms, and both substituents were on the same side, the IUPAC name would be cis-2-butene.

To know more about IUPAC visit:

https://brainly.com/question/33646537

#SPJ11

Answer:

this is a displacement reaction

Explanation:

because carbon is a reducing agent

(a) The Reynolds number (Re) represents the ratio of inertial forces to viscous forces in a fluid.

(a) The Reynolds number (Re) represents the ratio of inertial forces to viscous forces.

(b) Inertial forces are related to the momentum of a fluid and its tendency to keep moving, while viscous forces are related to the internal friction or resistance to flow within the fluid.

(c) The Reynolds number provides information about laminar flow,turbulent flow, and transitional flow regimes.

(d) Laminar flow is characterized by smooth and orderly fluid motion, with well-defined streamlines and minimal mixing. Turbulent flow, on the other hand, is characterized by chaotic and random fluid motion, with significant mixing and eddies.

(e) The cutoff values of Reynolds number for each flow regime in internal pipe flow can vary depending on the specific application and fluid properties. However, as a general guideline, laminar flow typically occurs at Re values below 2,000, while turbulent flow is observed at Re values above 4,000. Transitional flow, as the name suggests, occurs between these two regimes and can have Re values ranging from 2,000 to 4,000.

Learn more about Reynolds number

brainly.com/question/31298157

#SPJ11

The degree of vaporization required is 0.6 or 60%.

a. Flash/Equilibrium distillation: The principle behind flash distillation involves the process of separation of the mixture that is achieved through the application of heat. The mixture is passed into a flash drum, where it undergoes flashing or sudden vaporization by reducing the pressure inside the drum.

The vaporized components of the mixture are then separated from the remaining liquid, and the process is referred to as flash distillation. The vaporized components of the mixture are the overheads, while the remaining liquid is the bottom product. The process of equilibrium distillation is based on the same principle. In equilibrium distillation, the vapor and the liquid phases of the mixture reach equilibrium.

b. Separation of a mixture by flash distillation: Flash distillation is an ideal process that can be used for the separation of a mixture when the components of the mixture have a significant difference in their boiling points. For the separation of the mixture with a small difference in the boiling points, it is recommended to use the fractional distillation process.

Flash distillation is a quick and low-cost process of separation of the mixture that can be used for the separation of the low-boiling-point compounds from the high-boiling-point compounds.

c. Separation of a mixture of methanol and water:

i. Given:Feed = 800 kmol/h Methanol concentration = 60 mol% Degree of vaporization, f = 40%Composition of methanol and water on the given graph for 40% vaporization:From the graph, the feed composition of methanol is around 50 mol%.

Therefore, Methanol in the vapor product = 0.88 × 48 = 42.24 mol

Water in the vapor product = 0.12 × 48 = 5.76 mol

Methanol in the liquid product = 60 - 42.24 = 17.76 mol

Water in the liquid product = 40 - 5.76 = 34.24 molThe flowrate of the vapor product = f × F = 0.4 × 800 = 320 kmol/h

The flowrate of the liquid product = F - V = 800 - 320 = 480 kmol/h.

ii. Given:Feed = 1200 kmol/hMethanol concentration = 30 mol%

Composition of methanol and water on the given graph for 20 mol%

methanol in liquid product: From the graph, the degree of vaporization at which the liquid product contains 20 mol% methanol is around 60%.

Therefore, Methanol in the vapor product = 0.88 × 18 = 15.84 mol

Water in the vapor product = 0.12 × 18 = 2.16 molMethanol in the liquid product = 20 mol

Water in the liquid product = 80 mol

The flowrate of the liquid product = 1200 × 0.2 = 240 kmol/h

The flowrate of the vapor product = 1200 - 240 = 960 kmol/h

Therefore, the degree of vaporization required = 0.6 or 60%.

To learn more about vaporization, visit:

https://brainly.com/question/30078883

#SPJ11

The specific energy of NiMH battery is given as 57 Wh/kg and that of Li-ion battery is 150 Wh/kg.

The specific energy of NiMH battery is given as 57 Wh/kg and that of Li-ion battery is 150 Wh/kg. Specific energy is the amount of energy stored per unit mass. If the mass of the reactants is equal, Li-ion battery can store more energy than NiMH battery.

Early electric and hybrid-electric vehicles were frequently powered by nickel-metal hydride (NiMH) batteries. Assume that the discharge reaction for these batteries is given by TiNi5H + NiO(OH) ! TiNi5 + Ni(OH)2, and that the cell voltage is 1.2 V. Nowadays, NiMH batteries have been superseded almost entirely by Li-ion batteries. Assume that the discharge reaction for the latter is given by LiC6 + CoO2 ! C6 + LiCoO2, and that the cell voltage is 3.7 V. i. Calculate the specific energy of the two batteries, that is, the energy per kg reactant material, in units of kWh/kg. The molar masses of TiNi5H, NiO(OH), LiC6 and CoO2 in units of g mol

The reaction given for the NiMH battery is as follows:

TiNi5H + NiO(OH) → TiNi5 + Ni(OH)2

The number of electrons transferred in the reaction is given as 5.

The cell voltage of the battery is given as 1.2V.

Specific energy of the NiMH battery is given as: 1.2V * (5*96485 C) / (3600 s * 1000 Wh) = 57 Wh/kgThe reaction given for the Li-ion battery is as follows:

LiC6 + CoO2 → C6 + LiCoO2

The number of electrons transferred in the reaction is given as 1.

The cell voltage of the battery is given as 3.7V.

Specific energy of the Li-ion battery is given as: 3.7V * (1*96485 C) / (3600 s * 1000 Wh) = 150 Wh/kg

Thus, the specific energy of NiMH battery is given as 57 Wh/kg and that of Li-ion battery is 150 Wh/kg.

Learn more about Li-ion battery

https://brainly.com/question/29835113

#SPJ11

The limiting reactant in the gas phase reaction N₂ + 3 H₂ = 2 NH₃ is N₂. The complete stoichiometric table is as follows:

Reactant   | N₂ | H₂ |

Initial    | 0.25  | 0.75 |

Final      | 0     | 0.5  |

The values of CA°, 8, and e are not provided in the question. To calculate the final concentrations of all species for an 80% conversion, additional information is required.

To determine the limiting reactant, we compare the initial molar fractions of N₂ and H₂ in the feed. Given that the N₂ molar fraction is 0.25 and the stoichiometric ratio in the balanced equation is 1:3, we can see that N₂ is present in a lower amount compared to H₂. Therefore, N₂ is the limiting reactant.

In the stoichiometric table, we track the changes in molar concentrations of reactants and products. Initially, the molar fraction of N₂ is 0.25 and H₂ is 0.75. As the reaction proceeds, N₂ gets consumed while H₂ is in excess. At the end of the reaction, all the N₂ is consumed, resulting in a molar fraction of 0. On the other hand, H₂ has a final molar fraction of 0.5, indicating that only half of it is consumed.

To calculate the final concentrations of all species for an 80% conversion, we need additional information such as the values of CA° (initial concentration of A, where A represents N₂), 8 (the rate constant), and e (the conversion). Without these values, we cannot perform the necessary calculations.

The calculation of final concentrations and the importance of determining the limiting reactant in gas phase reactions to understand reaction progress and optimize reactant usage.

Learn more about limiting reactant

brainly.com/question/32459503

#SPJ11

a) The exit velocity of the steam is approximately 787.7 m/s.

b) The outlet cross-sectional area of the nozzle is approximately 6.58 cm².

a) To determine the exit velocity of the steam, we can use the isentropic flow equation:

v_exit = √(2 * h * (h_1 - h_exit))

where v_exit is the exit velocity, h is the specific enthalpy, and h_1 and h_exit are the specific enthalpies at the inlet and exit respectively.

Given that the steam is fed isentropically and the specific enthalpy at the inlet is h_1, we need to find the specific enthalpy at the exit. Using steam tables or specific enthalpy calculations, we find h_exit to be 2882.5 kJ/kg.

Substituting the values into the equation, we have:

v_exit = √(2 * h * (h_1 - h_exit))

      = √(2 * 0.75 kg/s * (2800 kJ/kg - 2882.5 kJ/kg))

      ≈ 787.7 m/s

b) The outlet cross-sectional area of the nozzle can be determined using the mass flow rate and the exit velocity. We can use the equation:

A_exit = m_dot / (ρ_exit * v_exit)

where A_exit is the outlet cross-sectional area, m_dot is the mass flow rate, ρ_exit is the density at the exit, and v_exit is the exit velocity

Given that the mass flow rate is 0.75 kg/s and the pressure at the exit is 475 kPa, we can find the density using the steam tables or the ideal gas law.

Substituting the values into the equation, we have:

A_exit = m_dot / (ρ_exit * v_exit)

      = 0.75 kg/s / (ρ_exit * 787.7 m/s)

      ≈ 6.58 cm²

Therefore, the exit velocity of the steam is approximately 787.7 m/s, and the outlet cross-sectional area of the nozzle is approximately 6.58 cm².

Learn more about exit velocity

brainly.com/question/13256123

#SPJ11

Continuous flash distillation does not require a high operating temperature compared to a batch process due to the following reasons:

Reasons for not needing a high operating temperature are listed below:

In continuous flash distillation, the feed enters the distillation column and then travels downwards as vapor and liquid pass through each other counter currently. The liquid continues to boil and vaporize as it travels down, with the lighter components moving up while the heavier components fall down

.As a result, only a portion of the feed has to be vaporized in the first stage of the distillation column, reducing the boiling temperature in subsequent stages. This means that the boiling temperature is lower in subsequent stages due to the continuous nature of the process, reducing the operating temperature required for the process. Because the heat is introduced to a small portion of the feed in continuous flash distillation, the overall amount of heat necessary for the process is reduced.

As a result, less heat is needed for the operation of the continuous flash distillation, which means that the operating temperature can be reduced. As a result, continuous flash distillation does not need a high operating temperature compared to a batch process.

Know more about distillation

https://brainly.com/question/31829945

#SPJ11

The Bohr model explains the observations by suggesting that electrons exist in specific energy levels and transitions between these levels cause the observed colors.

The Bohr model of an atom explains the observations of line spectra and quantized energy levels. Line spectra is a phenomenon where atoms emit or absorb light at specific wavelengths. Quantized energy levels refer to the specific energies that electrons can possess while occupying specific energy levels.

The Bohr model explains both of these observations by proposing that electrons can only exist in specific energy levels and can move between them by absorbing or emitting photons of specific energies. An electron in an atom can exist only in one of the allowed energy levels.

These energy levels are defined by the Bohr radius formula:

[tex]r(n) = n^2 * h^2 / 4[/tex]π[tex]^2mke^2[/tex]

Where r(n) is the radius of the nth energy level, n is an integer representing the energy level, h is Planck's constant, m is the mass of the electron, ke is Coulomb's constant, and e is the charge of the electron.Electrons emit light when they move from a higher energy level to a lower one and absorb light when they move from a lower energy level to a higher one.

The energy of the photon emitted or absorbed is equal to the difference in energy between the two levels. This explains why line spectra occur, as each atom emits or absorbs light at specific wavelengths corresponding to the energy difference between its allowed energy levels.The Bohr model's proposal of quantized energy levels provides an explanation for the stability of atoms. Electrons in an atom can't exist between energy levels, so they can't radiate energy and spiral into the nucleus.

Know more about  Bohr model   here:

https://brainly.com/question/29400473

#SPJ8