why mean absolute deviation is a better approach to handle outliers in a data than standard deviation

The graph shows that the rise is 3 and the run is 3, and the hypotenuse is the length between the two points.

let hypotenuse = x

using Pythagorean theorem:

x^2= 3^2 + 3^2

x^2 = 9 + 9

x= sqrt 18

x = 4.2426....

rounding to the nearest 10th:

x = 4.2

Answer:

Step-by-step explanation:

This is a combination problem because the order in which the flower displays are chosen does not matter. We can use the formula for combinations, which is:

nCr = n! / r!(n-r)!

Where n is the total number of items (in this case, 10 flowers displays) and r is the number of items we want to choose (in this case, 3 flower displays).

Plugging in the numbers, we get:

10C3 = 10! / 3!7!

= (10 x 9 x 8) / (3 x 2 x 1)

= 120

Therefore, there are 120 different selections of 3 flower displays that Mainline can choose from her 10 best flowers displays.

Answer:

There are 120 different selections of 3 flower displays that Mainline can choose from her 10 best flowers displays.

Hope this helps you buddy!!!!!!!!!!

The calculated value of the area of the circle with radius 7 feet is 153.93 square feet.

To find the area of a circle with radius 7 feet, we can use the formula A = πr^2, where A is the area and r is the radius.

Substituting the given value of radius, we get:

A = π(7)^2

Simplifying this expression, we get:

A = 49π square feet

Evauate the expression

So, we have

A = 153.93 square feet

Therefore, the area of the circle with radius 7 feet is 153.93 square feet.

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Complete question

Find the area.

Remember: A = πr²

Round to the nearest hundredth.

Use 3.14 for π

Pr(total)=pr(blue)+pr(green)+pr(red)=4+1+2

=7

a) pr(blue)= pr(blue)/pr(total)=4/7

b) pr(green)= pr(green)/pr(total)=1/7

c) pr(not green)= pr(blue)+pr(red)= 4/7+2/7=6/7

d)pr(not purple)= ???

e)pr(red)=pr(red)/pr(total)=2/7

Question d seems like it is a problem cause we were not told that a purple ball was in the bag.

There can be any angles  like vertical, linear pair, supplemenatry which can be shown in the following figure.

(a) One pair of vertical angles:

Vertical angles are formed by the intersection of two lines. They are opposite to each other and are congruent. For example, in the following diagram, ∠1 and ∠6 are a pair of vertical angles, and ∠3 and ∠8 are another pair of vertical angles.

b) one pair of angles that form a linear pair:

A linear pair is formed by  pair of adjacent angles whose non-adjacent sides form a line.

In the figure the linear pair will be ∠4 and ∠8.Beacause they are adjacent angles whose non adjacent sides form a line.

c)one pair of angles that are supplementary:

Two are said to be supplementary if they add up to be 180 degrees.

So in the figure ∠4 and ∠8 can be supplementary and also ∠1 and ∠5 can be supplementary.

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The dimensions that maximize the enclosed area are L = 41.665 feet and W = 41.665 feet for each corral and the maximum area is 10868.09 square feet.

To find the dimensions that maximize the enclosed area, we need to use optimization techniques. Let's denote the length of each rectangular corral by L and the width by W. We can write the total enclosed area as A = 6LW.

The perimeter of each corral is given by P = 2L + 2W, and we have a total of 6 corrals, so the total length of fencing required is 6P = 12L + 12W.

We are given that we have 1,000 feet of fencing, so we can write 12L + 12W = 1000, or equivalently, L + W = 83.33 (rounded to two decimal places).

We can now use this equation to express one of the variables (say, W) in terms of the other: W = 83.33 - L.

Substituting this expression for W into the formula for the enclosed area, we get A = 6L(83.33 - L) = 499.98L - 6L^2.

To find the value of L that maximizes the area, we need to take the derivative of A with respect to L and set it equal to zero: dA/dL = 499.98 - 12L = 0. Solving for L, we get L = 41.665 (rounded to three decimal places).

Substituting this value back into the expression for W, we get W = 83.33 - L = 41.665.

The maximum area is A = 6LW = 10868.09 square feet (rounded to two decimal places).

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The sum of all positive integers k that satisfy the property is 1800.

To find the sum of all positive integers k that satisfy the property of the least common multiple of k and 720 being 3600, we need to use the concept of prime factorization and LCM. What is LCM?The least common multiple (LCM) of a set of numbers is the smallest number that is a multiple of all the given numbers. It is calculated by taking the common prime factors of the numbers and multiplying them by their highest powers.

Now mentioned in the question that  the LCM of k and 720 is 3600. Let's write 720 and 3600 in prime factorization form. 720 = 2⁴ × 3² × 5¹, 3600 = 2³ × 3² × 5²Let LCM of k and 720 be L. So, L = 2⁴ × 3² × 5²Let k = 2ᵃ × 3ᵇ × 5ᶜ. So, LCM of k and 720 = 2ⁿ × 3ᵐ × 5ᴬ, where, n = max (4, a) , m = max (2, b) , A = max (2, c)Given, LCM of k and 720 = 3600.So, 2ⁿ × 3ᵐ × 5ᴬ = 2⁴ × 3² × 5².

As we know, n = max (4, a) , m = max (2, b) , A = max (2, c)Thus, n = 4, m = 2, A = 2. Since, n = max (4, a) , a = 4 is the only possible solution And, m = max (2, b) , b = 2 is the only possible solution, And, A = max (2, c) , c = 2 is the only possible solution.So, the possible value of k is k = 2⁴ × 3² × 5²i.e. k = 1800. Sum of all possible values of k is 1800.Therefore, the sum of all positive integers k that satisfy the property is 1800.

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The exact value of the circle is 36π square feet. Option A

The formula used for calculating the area of a given circle is expressed with the equation;

A = π(d/2)^2

A = πr²

Such that the parameters are;

The formula for radius is given as;

radius = diameter/2

divide the values

radius = 6 feet

Substitute the values

Area = 3.14 ×6²

multiply the values

Area = 36π square feet

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It can be proven that a Rubik's cube will return to its original state if you repeat any algorithm for a number of times

To prove that a Rubik's cube will return to its original state if you repeat any algorithm for a number of times, follow these steps,

1. Choose an algorithm, Select any algorithm that can be applied to the Rubik's cube. For example, the R U R' U' algorithm.

2. Apply the algorithm repeatedly, Perform the chosen algorithm on the Rubik's cube multiple times. Keep track of the number of times the algorithm is applied.

3. Observe the cube's state, After each iteration, observe the state of the Rubik's cube to see if it returns to its original state.

4. Identify the cycle length, Eventually, the Rubik's cube will return to its original state after a certain number of repetitions of the algorithm. This number is the cycle length of the algorithm.

5. Generalize the proof, The proof holds true for any algorithm on the Rubik's cube, as every algorithm has a finite cycle length due to the finite number of possible configurations of the cube.

In conclusion, it can be proven that a Rubik's cube will return to its original state if you repeat any algorithm for a number of times, because every algorithm has a finite cycle length due to the finite number of possible configurations of the cube.

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The measure of angle J, m∠J = 41.2°.

angle mwasurement:

We can use trigonometry to find the measure of ∠J. Since we know the lengths of the two sides adjacent to ∠J (GH and GJ), we can use the tangent function, which is defined as the opposite side divided by the adjacent side:

tan(J) = opposite/adjacent = GH/GJ

We can solve for J by taking the inverse tangent (or arctan) of both sides:

J = [tex]tan^{-1}[/tex](GH/GJ)

Substituting the given values, we get:

J = [tex]tan^{-1}[/tex](14/16)

Using a calculator, we find:

J ≈ 41.186

Rounded to the nearest tenth, the measure of angle J is 41.2°.

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The patient will take 2 tablets of lanoxin each day based on strength of tablets for the measurement.

We need to know the strength of the lanoxin tablets in order to calculate how many the patient will take dail based on measurement. Assume that the amount of lanoxin in each tablet is 0.0625 mg.

Given that 2 * 0.0625 mg = 0.125 mg, we can provide the patient 2 pills to obtain a dose of 0.125 mg. The patient will therefore take 2 lanoxin tablets daily.

It's crucial to remember that in order to make sure the patient receives the proper dosage of medication, we must take the medication's potency and the recommended dose into account while calculating dosages. In this instance, we assumed that each pill contained 0.0625 mg of lanoxin, but it's vital to read the drug label twice or get confirmation from the prescribing healthcare provider before giving the patient the medication. To maintain the patient's safety and wellbeing, it's also critical to adhere to the right pharmaceutical delivery standards.

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The expression to describe how many seconds Tatenda spends more than Ciara during 4 weeks is 2800t - 3000c.

Let's start by calculating how many seconds it takes Attends and Ciara to mow one square meter of lawn

Attends takes t seconds per square meter

Ciara takes c seconds per square meter

To calculate how many seconds Tatenda spends more than Ciara during 4 weeks, we need to first calculate how many seconds each of them spends mowing lawns in 4 weeks.

Attends mows 700 square meters of lawn per week, so in 4 weeks, he will mow 700 x 4 = 2800 square meters of lawn.

Similarly, Ciara mows 750 square meters of lawn per week, so in 4 weeks, she will mow 750 x 4 = 3000 square meters of lawn.

Now, let's calculate how many seconds it takes each of them to mow their respective lawns:

Attends takes t seconds to mow one square meter of lawn, so to mow 2800 square meters of lawn, he will take 2800 x t seconds.

Ciara takes c seconds to mow one square meter of lawn, so to mow 3000 square meters of lawn, she will take 3000 x c seconds.

Finally, to calculate how many seconds Tatenda spends more than Ciara, we can subtract the time it takes Ciara from the time it takes Attends

= 2800t - 3000c

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The probability of obtaining an increasing (non-decreasing) sequence after 4 draws with replacement from 6 balls labelled 1-6 is 1/15.

To explain the answer, we can first consider the number of possible combinations of four numbers that can be drawn from the six numbers. Since each draw is done with replacement, each draw has the same probability and the same six numbers can be chosen. Thus, there are 6 x 6 x 6 x 6 = 1296 possible combinations.

Next, we can calculate the number of possible increasing (non-decreasing) sequences. If the first number drawn is 1, then the remaining three numbers must be greater than or equal to 1. Thus, the second number can be 1, 2, 3, 4, 5, or 6, the third number can be 1, 2, 3, 4, 5, or 6, and the fourth number must be 6. There are 6 x 6 x 1 = 36 possible increasing sequences if the first number drawn is 1. If the first number drawn is 2, then the second number can be 2, 3, 4, 5, or 6 and the remaining two numbers must be greater than or equal to 2. Thus, the third number can be 2, 3, 4, 5, or 6, and the fourth number must be 6. There are 5 x 5 x 1 = 25 possible increasing sequences if the first number drawn is 2. This process can be repeated for the remaining numbers, 3, 4, 5, and 6. The total number of increasing (non-decreasing) sequences is the sum of these possibilities, which is 36 + 25 + 15 + 6 + 1 = 83.

Therefore, the probability of obtaining an increasing (non-decreasing) sequence after 4 draws with replacement from 6 balls labelled 1-6 is 83/1296 = 1/15.

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In order to have a potential value of $12,000 at a simple rate of interest of 8.0% after 6 years, the current value you must invest is therefore approximately $8,108.11.

A formula called Simple Interest (S.I.) is used to determine how much interest will be charged on a certain principal sum of money at a specific interest rate. For instance, if a person borrows Rs. 5000 for two years at a rate of 10 p.a., they will be compelled to pay S.I. on the whole amount borrowed during those two years.

For simple interest, use the formula:

A = P(1 + rt)

where r is the interest rate, t is the amount of time in years, A represents the future value, P is indeed the present value, and so on.

This formula can be changed to account for P:

P = A / (1 + rt)

By entering the specified values, we obtain:

P = 12,000 / (1 + 0.08 x 6)

P = 12,000 / 1.48

P = $8,108.11

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Since Shay's sibling is 7 years younger than twice her age, Shay is therefore 29 years old.

Mathematicians use the unitary method, also referred to as the "single unit technique," to answer problems involving proportional relationships between two or more quantities. The unitary technique entails determining the value of a single unit or quantity and using that value to calculate the values of other quantities in relation to that unit or quantity. Problems requiring ratios, proportions, percentages, and other related ideas can be solved using this approach.

given

Shay's age will be denoted by the letter S, and her sister's age will be referred to as "Sister".

The first claim informs us of the following:

Sibling = 2S – 7

And based on the second assertion, we can infer that:

Sibling + S = 80

The result of putting the first equation into the second equation is:

S + (2S - 7) = 80

When we simplify this solution, we obtain:

3S - 7 = 80

7 added to both edges gives us:

3S = 87

When we multiply both parts by 3, we get:

S = 29

Since Shay's sibling is 7 years younger than twice her age, Shay is therefore 29 years old.

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Answer:

2=a

Step-by-step explanation:

2a+3+4=11

2a+7=11

2a=11-7

2a=4

a=2

The conditional probability of drawing a heart on the fourth draw, given that the first three cards are not hearts is 4.74%.

The conditional probability of drawing a heart on the fourth draw, given that the first three cards are not hearts, can be calculated using Bayes’ theorem:

P(heart on fourth draw | first three draws are not hearts) = P(heart on fourth draw and first three draws are not hearts) / P(first three draws are not hearts)

To calculate the numerator, we need to find the probability of drawing a heart on the fourth draw and the first three draws being not hearts. Since we are drawing without replacement, the probability of drawing a heart on the fourth draw is 13/49 (there are 13 hearts remaining out of 49 cards remaining). The probability of the first three draws being not hearts can be calculated as:

(39/52) x (38/51) x (37/50) = 0.4372

Therefore, the numerator is:

P(heart on fourth draw and first three draws are not hearts) = (13/49) x (39/52) x (38/51) x (37/50)

P(heart on fourth draw and first three draws are not hearts) =  0.0207

To calculate the denominator, we need to find the probability of the first three draws being not hearts. We already calculated this as 0.4372.

Therefore, the conditional probability of drawing a heart on the fourth draw, given that the first three cards are not hearts, is:

P(heart on fourth draw | first three draws are not hearts) = P(heart on fourth draw and first three draws are not hearts) / P(first three draws are not hearts)

P(heart on fourth draw | first three draws are not hearts) = 0.0207 / 0.4372

P(heart on fourth draw | first three draws are not hearts) ≈ 0.0474

So the probability of drawing a heart on the fourth draw, given that the first three cards are not hearts, is approximately 0.0474 or 4.74%.

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Answer:

[tex]\pi(r - a)(r + a)[/tex]

Step-by-step explanation:

Area of larger circle is

[tex]\pi {r}^{2} [/tex]

Area of smaller (yellow) circle is

[tex]\pi {a}^{2} [/tex]

So the area of the green region is

[tex]\pi {r}^{2} - \pi {a}^{2} [/tex]

[tex]\pi( {r}^{2} - {a}^{2} )[/tex]

[tex]\pi(r - a)(r + a)[/tex]

Answer:

k - 6

Step-by-step explanation:

I'm not sure if this is a mistake or not, or if you pressed enter a little too early, but for example:

let k = 16

6 [the number provided] less than 16 [k] is not 6 - 16, as that would be 16 less than 6. You can read the math problem from right to left, and 16 - 6 would read out as "six less than sixteen".

Honestly, you don't really need this, and it isn't a good way to do it, there are many better ways.

The volume of the solid obtained by rotating the region bounded by the given curves about the y-axis is 8π cubic units.

To find the volume of the solid obtained by rotating the region bounded by the curves y=x^2, y=0, x=0, and x=2 about the y-axis, we can use the disk method.

The steps are as follows:

STEP 1. Identify the radius of the disk:

Since the solid is obtained by rotating around the y-axis, the radius of the disk is the x-value.

To get the x-value in terms of y, solve the equation

y=x^2 for x: x = sqrt(y).

STEP 2. Set up the volume integral:

The volume of the solid is given by the integral of the cross-sectional area of the disks.

The area of a disk is A = πr^2, where r is the radius. In this case, r = sqrt(y), so A = π(sqrt(y))^2 = πy.

We will integrate this area function along the y-axis, from the lowest to the highest y-value on the curve.

The lowest y-value is y=0, and the highest y-value is given by y = (2)^2 = 4 (since x=2).

STEP 3. Evaluate the integral:

The volume integral is given by V = ∫[0, 4] πy dy.

To evaluate this, we find the antiderivative of πy:

(π/2)y^2.

Now, we apply the Fundamental Theorem of Calculus:
V = [(π/2)(4)^2] - [(π/2)(0)^2] = (π/2)(16) = 8π.

So, the volume of the solid obtained by rotating the region bounded by the given curves about the y-axis is 8π cubic units.

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To make 2 gallons of a 20% salt solution, combine 0.86 gallons of the 12% salt solution and 1.14 gallons of the 26% salt solution.

Let x be the amount of the 12% salt solution needed in gallons, and y be the amount of the 26% salt solution needed in gallons to make 2 gallons of a 20% salt solution.

Based on the provided data, we can construct the following system of two equations:

X + y = 2 (total volume of the mixture is 2 gallons)

0.12x + 0.26y = 0.2(2) (total salt content of the mixture is 20% of 2 gallons)

Simplifying the second equation, we get:

0.12x + 0.26y = 0.4

Multiplying the first equation by 0.12 and subtracting it from the second equation, we get:

0.14y = 0.16

Y = 1.14

Substituting y = 1.14 into the first equation, we get:

X + 1.14 = 2

X = 0.86

In order to create 2 gallons of a 20% salt solution, 0.86 gallons of the 12% salt solution and 1.14 gallons of the 26% salt solution must be combined.

The complete question is:-

How much of a 12% salt solution must combined with a 26% salt solution to make 2 gallons of a 20% salt solution?

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Answer:

the slope of these points is 8/3

The surface area of the triangular prism is 960 units squared.

The surface area of the triangular prism can be found as follows:

surface area of the triangular prism = bh + l(s₁ + s₂ + s₃)

where

Therefore,

surface area of the triangular prism = 24 × 16  + 9 (20 + 20 + 24)

surface area of the triangular prism = 384 + 9(64)

surface area of the triangular prism = 384 + 576

surface area of the triangular prism = 960 units²

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The equatiοns, 1 unit equals 10 οn the x-axis and 10 οn the y-axis.

Equatiοns are statements in mathematics that have twο algebraic expressiοns οn either side οf the equals (=) sign.

It shοws that the expressiοns printed οn the left and right sides have an equal relatiοnship.

In any mathematical equatiοn, we have LHS = RHS (left hand side = right hand side).

Equatiοns can be sοlved tο find the value οf an unknοwn variable that represents an unknοwn quantity.

If there is nο "equal tο" symbοl, a statement is nοt an equatiοn.

When twο expressiοns have equal values, a mathematical statement knοwn as an equatiοn includes the symbοl "equal tο" between them.

Accοrding tο οur questiοn-

Alsο, cοst οf 4 kg apples and 2 kg οf grapes are ₹ 300. can be represented as,

4x + 2y = 300

2(2x + y) = 300

2x + y = 150  ---  Equatiοn(2)

Therefοre, the algebraic representatiοn fοr equatiοn(1) is:

2x + y = 160

y = 160 - 2x

And, the algebraic representatiοn fοr equatiοn(2) is:

2x + y = 150

y = 150 - 2x

Hence, The equatiοns, 1 unit equals 10 οn the x-axis and 10 οn the y-axis.

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It will take 7.5 years for the population to triple, and 10 years for the population to quadruple.

The population of a community is known to increase at a rate proportional to the number of people present at time t. This means that the rate of increase is directly proportional to the population.

If an initial population of p0 has doubled in 5 years, we can calculate how long it will take to triple or quadruple the population.

To triple the population, we use the equation: t = (5 years x 3) / 2, where t is the amount of time it takes for the population to triple. This gives us t = 7.5 years.

To quadruple the population, we use the equation: t = (5 years x 4) / 2, giving us t = 10 years.

In summary, it will take 7.5 years for the population to triple, and 10 years for the population to quadruple.

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Explanation:

A strain of Mycobacterium tuberculosis that is deficient in nonhomologous end joining repair should be more sensitive to damage by X-rays.

Nonhomologous end joining is a DNA repair mechanism that can join two DNA fragments with little or no homology between them. X-rays, which are high-energy electromagnetic waves, can cause damage to DNA by breaking the strands of the double helix.

This damage can be repaired by mechanisms like nonhomologous end joining, so a strain of Mycobacterium tuberculosis that is deficient in this repair mechanism would be more sensitive to damage by X-rays.

UV radiation, glycosylase, and depurination are not directly related to nonhomologous end joining repair and would not have the same effect.

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The statement that creates an array of decimals named miles and assigns the values 27.2, 33.5, 12.8, and 56.4 to its elements is: `double[] miles = {27.2, 33.5, 12.8, 56.4}.

An array is a data structure that contains a group of elements of the same data type. It is a collection of variables with the same data type but with different values assigned to them. To create an array in Java, we specify the data type of the elements in the array and the size of the array.The code that creates an array of decimals named miles and assigns the values 27.2, 33.5, 12.8, and 56.4 to its elements is given as follows: double[] miles = {27.2, 33.5, 12.8, 56.4}: The `double[]` specifies the data type of the elements in the array, which is double. The name of the array is miles, and it contains four elements with values 27.2, 33.5, 12.8, and 56.4 respectively.

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DECIMAL MILES can create array of decimal miles.

In computer science, an array is a data structure consisting of a collection

of elements, of same memory size, each identified by at least one array

index or key. An array is stored such that the position of each element can

be computed from its index tuple by a mathematical formula. Two type of

array are there 2D array and 3D array. The following statement creates an

array of decimals named miles and assigns the values 27.2, 33.5, 12.8, and

56.4 to its elements:

decimal[] miles = {27.2, 33.5, 12.8, 56.4};

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According to Luban, moral injuries and physical injuries are similar in that they share most characteristics except for the pain and suffering caused by physical injuries.

Luban is an American lawyer and philosopher. He is known for his work on just war theory and international law. Luban argues that moral injuries and physical injuries are similar in that they share most characteristics except for the pain and suffering caused by physical injuries.

Moral injuries:

Moral injuries are injuries caused by actions that violate a person's moral or ethical values.

Physical injuries:

Physical injuries are injuries caused by physical trauma, such as a broken bone or a cut.

Moral injuries and physical injuries are similar in many ways. Both can cause pain and suffering, loss of functionality, and disfigurement. Both can also have long-lasting effects on a person's health and well-being.

                     However, moral injuries are different from physical injuries in one important way

they do not cause physical pain and suffering.Moral injuries are caused by actions that violate a person's moral or ethical values.

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In the following question, among the given options, The sum of the proportions for all categories of a variable will be (C.) "1.00."

What is proportion? Proportions are usually represented as a decimal numbers between 0 and 1. They can also be represented as a percentage between 0 and 100. Proportions show the relationship between a particular number and a whole group. The total sum of proportions will always be equal to 1.00, which represents the entire group or population. So the answer to the given question is c. 1.00.

ExplanationThe sum of the proportions for all categories of a variable will be 1.00 because of the following: Proportions of a categorical variable are used to analyze data in statistics. A proportion is a fraction of a whole group that represents a part of that group. Proportions are usually represented as a decimal numbers between 0 and 1. They can also be represented as a percentage between 0 and 100. The sum of the proportions for all categories of a variable will be 1.00 representing the whole group or population, which is equal to 100%. This is the same as saying that the proportions for all categories of a variable should add up to 100%.

Therefore, the correct answer to the question is c. 1.00.

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The combined resistance, R, of two resistors with resistances r and s connected in parallel can be calculated using the equation:
[tex]1/R = 1/r + 1/s[/tex]
When an electric current passes through these resistors, the combined resistance depends on the values of r and s. To analyze the behavior of R with respect to r, we can rewrite the equation as:
[tex]R = (rs)/(r + s)[/tex]
R is a function of r and s, and its behavior depends on the values of r and s. If r and s are positive, the function is neither increasing nor decreasing globally, as it depends on both r and s values. However, for specific values of r and s, the function can be either increasing or decreasing locally.
There is no global maximum or minimum for this function because it depends on the specific values of r and s, and it can take any positive value depending on these resistances. So, the answer is none for global maximum or minimum.
In summary, the behavior of the combined resistance R when an electric current passes through two resistors connected in parallel depends on the values of r and s. It is neither globally increasing nor decreasing and has no global maximum or minimum.

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