Wildfires displace many animals and leave behind ash and soot-covered habitats for the animals that
survive. If a wildfire
occurred in the Everglades, which insect would be the
most likely to survive
predators in an ash and soot-covered habitat? (SC.5.L. 15.1)
A. Red dragonfly
B. Green grasshopper
C. Brightly colored butterfly
D. Gray-colored speckled moth
7. A group of students is using models to explore the relationship between the shape of a bird's beak
the type of food it eats. The students design an investigation using classroom items as beaks. Each

Apply Charles law

The total number of Ca2+ ions and F- ions that are present in the cubic unit cell will be 4 and 8 respectively.

From the complete information, the number of Ca2+ at corners will be (8 × 1/8 = 1) and those a the center will be (6 × 1/2 = 3). Therefore, the total number of Ca2+ will be:

= 1 + 3 = 4

The total number of F- ions will be:

= 4 × 2 = 8

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Answer:

C

Explanation:

Answer: D. Friction between two rock surfaces grinding away minerals.

Explanation: chemical weathering involves erosion from rocks/materials

An online version is the availability of the application on the web and the internet. The online version of the logo designer is advantageous as it provides more customization choices.

A logo design is a method to create logos that represent the brand of the business corporation or any other organization, it represents the company and brand.

Online software for logo designing provides more choices for customization as more fonts, styles, graphics, colors, and effects are present in online software.

The use of online software can be disadvantageous as it can be copied. The same tool and online data can be used to create the same logo and can be harmful to the company.

Therefore, using online software for logo designing can be both advantageous and disadvantageous.

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#SPJ1

Answer:

Explanation:first one

Answer: can hydrogen produce as much energy as burning fossil fuels?

Explanation:

Answer:

1. lava

2. caldera

3. true

4. true

5. before

The molarity of a new solution that has a volume of 25.0 mL of a 2.00 M HCl solution and diluted to 2.00 L is 0.025M.

The molarity of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

2 × 25 = 2000 × C2

50 = 2000C2

C2 = 50 ÷ 2000

C2 = 0.025M

Therefore, the molarity of a new solution that has a volume of 25.0 mL of a 2.00 M HCl solution and diluted to 2.00 L is 0.025M.

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Answer:

Option B: Oxygen.

Explanation:

Hope this helped.

Answer:

The answer is c.........

Answer:The larva might form a cocoon or a chrysalis.

Explanation:

Without conducting an experiment, one can determine if a species in a solution is acidic or basic by using a litmus paper.

Acidic species would turn a blue litmus paper to red but have no effects on red litmus paper.

Basic species would turn a red litmus paper to blues but have no effects on blue litmus paper.

Thus, in order to determine if a species in a solution is acidic or basic without conducting any experiment, dipping a litmus paper into the solution would give an indication.

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Answer:

Your answer is Answer thank me later :) <3

Explanation:

Answer:

B + C ARE INCORRECT FROM THE ABOVE GIVEN CONVERSIONS.

Answer:

All of the above :D

Explanation:

When rain falls, if it doesn't get absorbed by the dirt, it will go into streams, rivers, and ponds. That is actually how flooding is caused!!! :D

Have an amazing day!!

Please rate and mark brainliest!!

Answer:

About 4.63.

Explanation:

The reaction between ethanoic acid (CH₃COOH) and sodium hydroxide (NaOH) can be described by the following net ionic equation:

[tex]\displaystyle \text{CH$_3$COOH}_\text{(aq)} + \text{OH}^-_\text{(aq)}\longrightarrow \text{CH$_3$COO}^-_\text{(aq)} + \text{H$_2$O}_\text{($\ell$)}[/tex]

40.0 mL of 0.040 M NaOH contains:
[tex]\displaystyle 40.0\text{ mL} \cdot \frac{0.040\text{ mol NaOH}}{1000\text{ mL}} = 0.0016\text{ mol NaOH}[/tex]

Because NaOH is a strong base, it dissociates completely. Hence, the amount of OH⁻ present is 0.0016 mol. Na⁺ acts as a spectator ion.

50.0 mL of 0.075 M CH₃COOH contains:
[tex]\displaystyle 50.0\text{ mL} \cdot \frac{0.075\text{ mol CH$_3$COOH}}{1000\text{ mL}} = 0.0038\text{ mol CH$_3$COOH}[/tex]

OH⁻ is the limiting reagent of the reaction. Therefore, as the reaction proceeds to completion:

Note that all species present are in a one-to-one ratio.

To find pH, we can use the Henderson-Hasselbalch equation:

[tex]\displaystyle \text{pH} = \text{p}K_a + \log\frac{[\text{Base}]}{[\text{Acid}]}[/tex]

The total volume of the solution is 40.0 mL + 50.0 mL = 90.0 mL.

Hence, find [CH₃COOH]:

[tex]\displaystyle \left[\text{CH$_3$COOH}\right] = \frac{0.0022\text{ mol}}{90.0\text{ mL}} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 0.024\text{ L}[/tex]

Find [CH₃COO⁻]:
[tex]\displaystyle \left[\text{CH$_3$COO}^-\right] = \frac{0.0016\text{ mol}}{90.0\text{ mL}}\cdot \frac{1000\text{ mL}}{1\text{ L}} = 0.018\text{ M}[/tex]

Therefore, the pH of the resulting solution is:
[tex]\displaystyle \begin{aligned}\text{pH} & = \text{p}K_a + \log\frac{[\text{Base}]}{[\text{Acid}]} \\ \\ & = (4.75) + \log \frac{(0.018)}{(0.024)} \\ \\ & = 4.75 + (-0.12) \\ \\ & = 4.63\end{aligned}[/tex]

In conclusion, the pH of the resulting solution is about 4.63.

Answer:

C

Explanation:

It has the lowest Ksp, so it will have the lowest Molar Solubility

Answer:

Cl2

Explanation:

Chlorine is a diatomic element  so it is   Cl 2

 the others are MOLECULES  (made up of atoms of ELEMENTS)

Here are the balanced equations

Done!

Answer:

b, and d

Explanation:

if the student did not aim correctly, and for d if the light waves travelled differently

For yogurt production, probiotic bacteria and the Streptococcus thermophilus strain work together to produce a stable balance of bacteria in the culture.

Answer:

MAthhh

Explanation:

Give me a brainly

Answer:

My favorite subject in school is P.E or Language arts

Explanation:

Answer:

the interest applied on the end of day balance.

Explanation:

Step 1: Write the balanced "molecular equation:

[tex]2HI(aq) + CrCO₃ (s) → CrI₂ (s) + H₂O(l) + CO₂(g)[/tex]

Step 2: Carbon dioxide and water are written in molecular form. Consult the solubility and net ionic equation rules on the information page to determine which of the other substances will dissociate:

[tex]2HI(aq) + CrCo₃ (s) → Crl₂ (s) +H₂O(l)+CO₂(g)[/tex]

yes no yes

Step 3: Dissociate all soluble salts, strong acids, and strong bases (except calcium hydroxide), Leave together all "not soluble" salts and weak acids or bases:

[tex] {2H₂O}^{ + } (aq) + {2I}^{ - } (aq) + CrCO₃ (s)→ {Cr}^{2 + } (aq) + {2I}^{ - }(aq) + 3H₂O(l) + CO₂(g)[/tex]

Step 4: Cross out "spectator lons that appear on both sides of the reaction (these lons do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients:

[tex] {2H₂O}^{ + } (aq) + CrCO₃ (s) →3H₂O + CO₂ + {Cr}^{2 + } [/tex]

Answer:

Something like table salt (NaCl) is a compound because it is made from more than one kind of element (sodium and chlorine), but it is not a molecule because the bond that holds NaCl together is an ionic bond. If you like, you can say that sodium chloride is an ionic compound.

Explanation:

Answer:

.018 M

Explanation:

Mole weight of NaCl (from periodic chart) = 58.44 g /mole

4 g / 58.44 gm/mole = .06845 mole

.06845 mole / (3.8 liter ) = .018 M

Do you mean scientific theory? If so, then scientific theories and laws are principles which can be used to better understand the world and space around us.

Answer:

This means that one mole of water molecules has a mass of 18.015g.

42.3g * 1 mole H2O/18.015g

= 2.3480 moles H2O

We are using the avogadros number to find the number of molecules of water

2.3480 H2O * 6.022*10^ 23moles/ 1mole of H2O

That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O

Number of molecules = 1.4140 *10^24 molecules

Answer:

a) The molecular formula of oleic acid is: [tex]C_{18}H_{34}O_{2}[/tex]

b) There are 5.74 x 10^21 molecules of oleic acid in a 3.00 mL sample.

Explanation:

a)

First, let's determine the empirical formula of oleic acid from the percentage composition provided by the question:

- Assuming a 100g sample of oleic acid, the correspondent mass of C, H and O would be:

mass of C = 76.54g

mass of H = 12.13g

mass of O = 11.33g

- We must determine the number of moles contained in each of the masses determined above. For that, let's use the atomic masses of C (12.01 u), H (1.007 u) and O (15.99 u) and the following equation:

[tex]number of moles = \frac{mass of sample}{molar mass}[/tex]

number of moles of C = 76.54g / 12.01 g/mol = 6.373 mol C

number of moles of H = 12.13g / 1.007 g/mol = 12.04 mol H

number of moles of O = 11.33g / 15.99 g/mol = 0.7086 mol O

- Next, we'll try to find whole-number ratios by dividing each number of moles obtained by the smallest value obtained (0.7086):

C = 6.373 / 0.7086 = 8.994 ≅ 9

H = 12.04 / 0.7086 = 16.99 ≅ 17

O = 0.7086 / 0.7086 = 1.000

- Now, we can write the empirical formula of oleic acid as: [tex]C_{9}H_{17}O[/tex]

Now that we have the empirical formula for oleic acid (C9H17O), let's check its molar mass and compare it to the experimental value provided by the question (282 g/mol):

molar mass (C9H17O) = 9 * 12.01 + 17 * 1.007 + 1 * 15.99 = 141.9 g/mol

Note that the molar mass obtained from the empirical formula (141.9 g/mol) and the experimental molar mass (282 g/mol) are different, thus we need to find an integer multiple to determine the molecular formula (keep in mind that molecular formulas always present kind and number of atoms of each element present in the molecular compound, while the empirical formula presents the smallest coefficients for each atom).

Molecular formula = n × Empirical formula

This integer multiple, n, can  be obtained by dividing the molar mass,  MM , of the compound by the empirical formula mass,  EFM  (the molar mass represented by the empirical formula):

n = MM / EFM

n = 282 / 141.9

n = 1.987 ≅ 2

Since the integer multiple is 2, we can multiply all coefficients in the empirical formula by 2 to find the molecular formula of oleic acid:

C9 H17 O x 2 = C18 H34 O2

Therefore, the molecular formula of oleic acid is: [tex]C_{18}H_{34}O_{2}[/tex]

b)

We need to calculate the amount of molecules of oleic acid in a 3.00mL sample, considering the density as 0.895 g/mL.

From the density provided, we can calculate the mass, in grams, of oleic acid contained in 3.00 mL of this compound:

1 mL ----------------------- 0.895 g oleic acid

3.00 mL ----------------- x

Solving for x, we have that there are 2.69 g of oleic acid in a 3.00 mL sample.

Next, considering the molar mass of oleic acid (282 g/mol), we can calculate the number of moles contained in 2.685g of the acid:

282 g -------------------- 1 mol oleic acid

2.69 g ----------------- y

Solving for y, we have that there are 0.00953 moles of oleic acid in a 3.00 mL sample.

Now, using the Avogadro's number (6.022 x 10^23 particles/mol), we can calculate the amount of molecules of oleic acid in the sample:

1 mol oleic acid ------------------------------- 6.022 x 10^23 molecules oleic acid

0.00953 mol oleic acid ------------------- z

Solving for z, we have that there are 5.74 x 10^21 molecules of oleic acid in a 3.00 mL sample.

From the balanced equation of the reaction, the coefficients of the reactants and products are 1:2:1.

A balanced equation of a chemical reaction is an equation which balances the atoms of each element on the reactants as well as the products side of a chemical reaction.

The balanced equation of the reaction that occurs when magnesium bromide is heated is shown below:

[tex]MgBr_2 \rightarrow Br_2+Mg [/tex]

Therefore, the coefficients of the reactants and products are 1:2:1.

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