Your Gps shows that your friends house is 10.0 km away, as shown in the image below. but there is a big hill between your house and you dont want to bike the directly. You know your friends street is 6.0km north of your street. How far do you have to ride before turning north to get to your friends house?

[tex]\\ \rm\Rrightarrow Perimeter=2(L+B)[/tex]

[tex]\\ \rm\Rrightarrow Perimeter=2(2\sqrt{6}+\sqrt{6})[/tex]

[tex]\\ \rm\Rrightarrow Perimeter=2(3\sqrt{6})[/tex]

[tex]\\ \rm\Rrightarrow Perimeter=6\sqrt{6}[/tex]

The perimeter of the rectangle will be 6√6 units.

Let W be the rectangle's width and L its length. The perimeter of the rectangle will be defined as the total length of all of its sides. So the rectangle's perimeter will be given as,

Perimeter of the rectangle = 2(L + W) units

A rectangle has a length of 2√6 and a width of √6. Then the perimeter of the rectangle is given as,

P = 2 (2√6 + √6)

Simplify the equation, then we have

P = 2 (2√6 + √6)

P = 2 (3√6)

P = 6√6 units

The perimeter of the rectangle will be 6√6 units.

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Hi! I'm happy to help!

To solve for the area of a semi-circle, we just need to find the area of a circle, and divide it by 2.

The equation for area of a circle is A=[tex]\pi[/tex]r²

It says we can use 3.14 for pi, so we can write our equation like this:

A=3.14(r²)

Since we are dealing with half of a circle, we can  write this as:

A=[tex]\frac{1}{2}[/tex](3.14(r²))

Our radius is a straight line going from the edge of the circle to the center. We have the diameter, which is just the radius doubled (because it goes from the edge to the center point then back to the edge). So, we divide our diameter by 2 to get our radius.

14÷2=7

Our radius is 7, so we can plug that into our equation:

A=[tex]\frac{1}{2}[/tex](3.14(7²))

Now all we have to do, is solve:

A=[tex]\frac{1}{2}[/tex](3.14(49))

A=[tex]\frac{1}{2}[/tex](153.86)

A=76.93

So, our area is 76.93 units².

I hope this was helpful, keep learning! :D

Answer:

-5/9

Step-by-step explanation:

The exact point at which the lines cuts the axis are unclear so I used the closest round number to substitute into the gradient formula. From the answer I noticed two things

Firstly it was a negative gradient...therefore the second and the fourth option wouldn't work

Secondly (if I were to ignore the operation) the number is less than 1 which would mean that it couldnt be an improper fraction where the numerator is greater than the denominator.

If you take what you notice about both the operation and the size of the number you would find that -5/9 fits the criteria the best and is therefore the answer to your question.

[tex] \frac{y2 - y1}{x2 - x1} \\ = \frac{0 - ( - 1)}{ - 2 - 0} \\ = - \frac{1}{2} [/tex]

Answer:

f(t)=-16t^2+8t+2

Step-by-step explanation:

You take f(t)=-16t^2, and for vt look at the initial velocity which was 8 and for s look at the height which was 2

Answer:

D

Step-by-step explanation:

I think its D because you multiple the number that is out of the the bracket with the numerators..

so its

a^4/b^12

It looks like the differential equation is

[tex] \left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0[/tex]

Check for exactness:

[tex]\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x[/tex]

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

[tex] \mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0[/tex]

*is* exact. If this modified DE is exact, then

[tex]\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}[/tex]

We have

[tex]\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu[/tex]

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

[tex]x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}[/tex]

The modified DE,

[tex]\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0[/tex]

is now exact:

[tex]\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}[/tex]

So we look for a solution of the form F(x, y) = C. This solution is such that

[tex]\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}[/tex]

Integrate both sides of the first condition with respect to x :

[tex]F(x,y) = -e^{-x}y - \dfrac1x + g(y)[/tex]

Differentiate both sides of this with respect to y :

[tex]\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C[/tex]

Then the general solution to the DE is

[tex]F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}[/tex]

Answer:

{(6, -6), (-9,2), (6, -1), (-8, -9)}

Step-by-step explanation:

The angle between vectors is given by

[tex]\cos{\theta} = \dfrac{\vec{\textbf{a}}\cdot \vec{\textbf{b}}}{|\vec{\textbf{a}}||\vec{\textbf{b}}|}[/tex]

The magnitudes for the vectors are as follows:

[tex]|\vec{\textbf{a}}| = \sqrt{a_x^2 + a_y^2 + a_z^2}[/tex]

[tex]\:\:\:\:\:\:\:=\sqrt{(2)^2 +(-5)^2 + (3)^2} = 6.16[/tex]

[tex]|\vec{\textbf{b}}| = \sqrt{b_x^2 + b_y^2 + b_z^2}[/tex]

[tex]\:\:\:\:\:\:\:= \sqrt{(3)^2 + (1)^2 + (4)^2} = 5.10[/tex]

The dot product between the vectors is

[tex]\vec{\textbf{a}}\cdot \vec{\textbf{b}} = (2)(3) + (-5)(1) + (3)(4) = 13[/tex]

Therefore, the angle between the two vectors is

[tex]\cos{\theta} = \dfrac{\vec{\textbf{a}}\cdot \vec{\textbf{b}}}{|\vec{\textbf{a}}||\vec{\textbf{b}}|} = \dfrac{13}{(6.16)(5.10)}[/tex]

or

[tex]\theta = 65.56°[/tex]

Answer:

Step-by-step explanation:

4(x-3) =16

4x- 12=16

4x=28

8x=56

Answer:

8x = 56

Step-by-step explanation:

Solve for x by isolating it.

Divide both sides by 4

(x-3) = 4

Add 3 to both sides

x = 7

Now plug 7 in for x

8(7) = 56

Answer:

There are 5 red ✎ pencils

Step-by-step explanation:

fraction of green pencils:

[tex] = 1 - \frac{1}{3} \\ \\ = \frac{2}{3} [/tex]

let total pencils be x :

[tex] \frac{2}{3} \: of \: x = 10 \: green \: pencils \\ \\ \frac{2}{3} \times x = 10 \\ \\ 2x = 3 \times 10 \\ x = \frac{3 \times 10}{2} \\ \\ x = 15 \: pencils[/tex]

Total pencils = 15

Red pencils:

[tex] = 15 - 10 \\ = 5 \: pencils[/tex]

Answer:

97.6 + 77.8

Step-by-step explanation:

97.6-(-77.8)

= 97.6+77.8

97.6+77.8= 175.4

97.6-(-77.8) = 175.4

Answer:

100 rows

Step-by-step explanation:

9514 1404 393

Answer:

  I and III only

Step-by-step explanation:

The graph is symmetrical about the y-axis, so is an even function.

The function is decreasing in the 1st quadrant, so is not increasing everywhere.

The values of the function approach y=0 for extreme values of x, so the graph shows that as a horizontal asymptote.

  I and III only

Answer:

1

Step-by-step explanation:

The GCF of 24 and 97 can be obtained like this:

Answer:

The answer is 705,000

Step-by-step explanation:

pls mark brainlest

The value of (7 ten thousand 5 hundreds) x 10 is 705,000.

Here,

The written expression is,

(7 ten thousand 5 hundreds) x 10

We have to find the value of given written expression.

What is Mathematical expression?

Mathematical expression is a finite combination of symbols that is well-formed according to the rules.

Now,

The written expression is,

⇒ (7 ten thousand 5 hundreds) x 10 = 70, 500 x 10 = 705,000

Hence,

The value of (7 ten thousand 5 hundreds) x 10 is 705,000.

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Answer:

158.733 that's the answer

9514 1404 393

Answer:

  about 159 pounds

Step-by-step explanation:

The exact conversion factor from kilograms to pounds is ...

  1 lb = 0.45359237 kg

So, to find the number of pounds, you multiply:

  [tex]72\text{ kg}\times\dfrac{1\text{ lb}}{0.45359237\text{ kg}}\approx\boxed{158.7328\text{ lb}}[/tex]

The conversion is often approximated by 1 kg = 2.2 lb, which gives an answer that is about 0.21% low.

9514 1404 393

Answer:

  x = 50°

Step-by-step explanation:

The angle marked 73° is the average of the arcs marked 96° and x.

  (x +96°)/2 = 73°

  x = 2(73°) -96° . . . . solve for x

  x = 50°

__

Additional comment

Then z = 360° -50° -114° -96° = 100°.

Answer:

what are we finding

Are we to derive an equation of a straight line

Answer:

malai thaxaina

Answer:

Step-by-step explanation:

Given:

We can see that:

Since 2² and 5² are perfect squares we get:

[tex]\\ \sf\longmapsto \sqrt{8}+\sqrt{50}[/tex]

[tex]\\ \sf\longmapsto \sqrt{2(2)(2)}+\sqrt{2(5)(5)}[/tex]

[tex]\\ \sf\longmapsto 2\sqrt{2}+5\sqrt{2}[/tex]

[tex]\\ \sf\longmapsto (2+5)\sqrt{2}[/tex]

[tex]\\ \sf\longmapsto 7\sqrt{2}[/tex]

Answer:

a function of x, the number of miles driven in a year.

Step-by-step explanation:

The slope of the line represents the cost of the maintenance and the cost of the fuel. Then the correct option is D.

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

In addition to fuel and maintenance, Rachel pays $1,000 a year for insurance. The equation will be

C = (0.05 + 0.14)x + 1000

C = 0.19x + 1000

Then the slope of the line will be

Slope = 0.19

The slope of the line represents the cost of the maintenance and the cost of the fuel.

More about the linear system link is given below.

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Answer:

y = |x| – 4

Step-by-step explanation:

If we substitute x as 0, we get -4 therefore this is the answer.

Answer:

r+58=c

(r= remaining, c= total coffee)

Step-by-step explanation:

Answer:  [tex]\sqrt{75}[/tex]

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Explanation:

Square both 8 and 9 to get

Since 75 is between 64 and 81, this means [tex]\sqrt{75}[/tex] is between 8 and 9

Put another way, we can say this:

[tex]64 < 75 < 81\\\\\sqrt{64} < \sqrt{75} < \sqrt{81}\\\\\sqrt{8^2} < \sqrt{75} < \sqrt{9^2}\\\\8 < \sqrt{75} < 9\\\\[/tex]

Or we could use a calculator to find that:

Which is another way to see why [tex]\sqrt{75}[/tex] is between 8 and 9.

Step-by-step explanation:

everything can be found in the picture

Answer:

It is 1. A(n) =3(3^n-1)

Step-by-step explanation:

It is a geometric progression

General recursive formular:

[tex]a_{n} = a( {r}^{n-1} )[/tex]

a » first term, a = 3

r » common difference, r = 9 ÷ 3 = 3

n » number of terms

[tex]A(n) = 3( {3}^{n-1} )[/tex]

______________end_____________________

further more:

[tex]A(n) = {3}^{(n)} [/tex]

Answer:

-2 and 6

Step-by-step explanation:

[tex] - 4 + 8 - 2[/tex]

[tex] - 6 + 8[/tex]

[tex] = - 2[/tex]

○●○●○●○●○●○●○●○●○●○●○●○●○●○

[tex]8 - ( - 3) - 5[/tex]

[tex]8 + 3 - 5[/tex]

[tex] = 6[/tex]