When 4050 joules of heat were applied to 150g of aluminum, the final temperature was 50 degree Celsius. What was the initial temperature? Take specific heat capacity of aluminum as 900J/kg degree Celsius.

Answers

Answer 1

Answer:

[tex]\boxed {\boxed {\sf 20 \textdegree C}}[/tex]

Explanation:

We are asked to find the initial temperature of aluminum. We will use the following formula.

[tex]q= mc \Delta T[/tex]

Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, which is also the difference between the final and initial temperature.

[tex]q= mc (T_f-T_i)[/tex]

We know the heat energy applied is 4050 Joules, the mass is 150 grams, the final temperature is 50 degrees Celsius and the specific heat is 900 Joules per kilogram degree Celsius.

We must convert the mass to kilograms because the specific heat is in kilograms. 1 kilogram contains 1000 grams.

[tex]\frac { 1 \ kg }{1000 g }[/tex][tex]150 \ g *\frac{ 1 \ kg }{1000 g } = 150 * \frac {1}{1000} \ kg = 0.150 \ kg[/tex]

Substitute all the known values into the formula.

q= 4050 J m= 0.150 kg c = 900 J/g °C [tex]T_f[/tex]= 50°C

[tex]4050 \ J = (0.150 \ kg )(900 \ J/kg \textdegree C)(50 \textdegree C -T_i)[/tex]

We are solving for the initial temperature, so we must isolate the variable [tex]T_i[/tex]It is being multiplied by 0.150 kilograms and 900 Joules per kilogram degree Celsius. The inverse operation of multiplication is division, so we divide by both values.

[tex]\frac {4050 \ J}{ (0.150 \ kg )(900 \ J/kg \textdegree C)}= \frac{(0.150 \ kg )(900 \ J/kg \textdegree C)(50 \textdegree C -T_i)}{(0.150 \ kg )(900 \ J/kg \textdegree C)}[/tex]

[tex]\frac {4050 \ J}{ (0.150 \ kg )(900 \ J/kg \textdegree C)}=(50 \textdegree C -T_i)}[/tex]

The units of Joules and kilograms cancel.

[tex]\frac {4050 }{ (0.150 )(900 \ \textdegree C)}=(50 \textdegree C -T_i)}[/tex]

[tex]\frac {4050}{135} \textdegree C = (50 \textdegree C -T_i)[/tex]

[tex]30 \textdegree C = (50 \textdegree C -T_i)[/tex]

50 degrees Celsius is being added to [tex]-T_i[/tex]. The inverse operation of addition is subtraction. Subtract 50 degrees Celsius from both sides.

[tex]30 \textdegree C - 50 \textdegree C= 50 \textdegree C - 50 \textdegree C - T_i[/tex]

[tex]-20 \textdegree C = -Ti[/tex]

[tex]T_i[/tex] is being multiplied by -1. The inverse operation of multiplication is division. Divide both sides by -1.

[tex]\frac {-20 \textdegree C}{-1}= \frac{-T_i}{-1}[/tex]

[tex]20 \textdegree C = T_i[/tex]

The initial temperature of the aluminum was 20 degrees Celsius.


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Hi, There! The Correct Answer is Below!

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Some Extra Information! :)

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___________________________________________________________

-DarkSpirit-

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Answer:

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it is the standard electrolyte solution for alkaline cells

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Answers

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took quick check

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Answers

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We have that the Three  consequences of lack of basic services in community​ are

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Lack of basic services in community​

There are many consequences that result from the lack of basic services in a community​ but i shall focus on these three as they are very major impacts

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Answers

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Answers

Answer:

the anser is

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Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

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Please find attached photograph for your answer. Please do comment whether it is helpful or not.

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Answers

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Answer:

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Which option is a negatively charged ion?(1 point)

chlorate

chloride

chlorite

chlorine

Answers

Answer:

Explanation:

They all are except chlorine which has no charge.

chlorate is ClO3 -1

Chloride  Cl-1

Chlorite is ClO2 - 1

All of them are minus one. If you mean which has a chloride ion with a charge of -1 that would be the chloride ion.

Answer:

Chloride

Explanation:

All Answers

Chloride

Valence electrons increase by one

How many energy levels it has

1-

Potassium and iodine